Thank you for your help.
How do I get data that contains a space at the front or the back?
For example: (see .png)
enter image description here
I tried:
select* from customer_table where customer like '% %'
but:
it gave me all of them because name contains a space in between.
I need to get the ones that have a white-space at the front.
thank you!
I think you want:
where customer like ' %' or customer like '% '
like patterns match the entire string. So the first gets spaces at the begging and the second spaces at the end. If you wanted both, you can do that in a single patter:
where customer like ' % '
Use TRIM function on the column to fit you select condition, for instance
WHERE LTRIM([CUSTOMER]) = 'Joe'
This example is for Microsoft SQL Server but I believe all DBMS have a similar function you can use trim as the keyword to search.
Related
I have a clob column with a long string.
like "great job done today. good "
I want to retrieve all the records which has both the words great and good .
both the position is not fixed.
It's not clear what "which has both the words great and good " actually means.
If you mean you want to check if the string has both patterns of words, then it is simple as
where lower(col) like '%good%' AND lower(col) like '%great%'
If you mean they should contain true words good and great, then for simpler cases something like should do
where ' ' || lower(col) || ' ' LIKE '% good %' AND ' ' || lower(col) || ' ' LIKE '% great %'
However, this will not match a sentence ending with the word and having a full stop. It gets lengthy if you want to simply use LIKE to handle such scenarios.
REGEXP functions give more flexibility, but could be less performant.
WHERE REGEXP_LIKE ( s, '(^|\W)good(\W|$|\.)') AND REGEXP_LIKE ( s, '(^|\W)great(\W|$|\.)')
This searches for word boundaries, i.e. the word surrounded by non-word characters and start and end including an ending dot. If you want to ignore case, add ,'i' as 3rd argument to it.
I think this is the basic logic you want:
where lower(col) like '%good%' and lower(col) like '%great%'
In clobs, you can't quite use like:
where dbms_lob.instr(col, 'good') and dbms_log.instr(col, 'great')
Try this and let me know if it works for you.
SELECT *
FROM clob_table
WHERE DBMS_LOB.INSTR(clob_text,'great')>0
AND DBMS_LOB.INSTR(clob_text,'good')>0;
Remember put the names of your table and columns.
Here my results,
I don't recall ever seeing a field like this before, but it combines the city, state, and zipcode into a single string of varchar2. Fortunately, I believe most of the fields are in the same city space state, space zipcode format, but I started finding a few that deviated from that norm.
Right now I'm trying to identify all these distinct conditions
in the database with over 5 million rows and my queries aren't working for what I wanted.
I started with:
SELECT PROJECT_CTY_ST_ZIP FROM PAYMENT WHERE PROJECT_CTY_ST_ZIP LIKE '%' || CHR(32) || '%';
Then tried:
SELECT PROJECT_CTY_ST_ZIP FROM PAYMENT WHERE PROJECT_CTY_ST_ZIP LIKE '% %' AND PROJECT_CTY_ST_ZIP LIKE '% %' AND PROJECT_CTY_ST_ZIP LIKE '% %';
but they are both pulling based on leading and trailing spaces and I was really wanted to find spaces in the inside of the text. I don't want to remove them, just identify them with a query so I can parse them properly in my java code and then do an insert later to put them into city, state, and zipcode fields in another table.
While it doesn't show it here, I found this field in IA with no leading spaces, then one leading space and then two leading spaces. I fixed the leading spaces with trim.
WEST LIBERTY, IA 52776
This last one I wasn't expecting and I wanted to see if there are other conditions that might be unusual, but my query doesn't find them as the spaces are in the middle of the text:
TRUTH OR CONSEQUENCE, NM 87901
How would I go about a query to find these kinds of distinct records?
This query replaces each of the spaces with a dot (.) so you can see them
SELECT
REGEXP_REPLACE(PROJECT_CTY_ST_ZIP,
'([[:space:]])',
'.') spaces_or_now_dots
FROM PAYMENT
This query finds the ones that have one or more spaces.
SELECT PROJECT_CTY_ST_ZIP
FROM PAYMENT
where REGEXP_LIKE(PROJECT_CTY_ST_ZIP,
'[[:space:]]'
)
I have not considered the cases of spaces in the beginning and end, because you have already taken care of them.
I have column store_name (varchar). In that column I have entries like prime sport, best buy... with a space. But when user typed concatenated string like primesport without space I need to show result prime sport. how can I achieve this? Please help me
SELECT *
FROM TABLE
WHERE replace(store_name, ' ', '') LIKE '%'+#SEARCH+'%' OR STORE_NAME LIKE '%'+#SEARCH +'%'
Well, I don't have much idea, and even I am searching for it. But may be what I know works for you, You can achieve this by performing different type of string operations:
Mike can be Myke or Myce or Mikke or so on.
Cat an be Kat or katt or catt or so on.
For this you should write a function to generate number of possible strings and then form a SQL Query using all these, and query the database.
A similar kind of search in known as Soundex Search from Oracle and Soundex Search from Microsoft. Have a look of it. this may work.
And overall make use of functions like upper and lower.
Have you tried using replace()
You can replace the white space in the query then use like
SELECT * FROM table WHERE replace(store_name, ' ', '') LIKE '%primesport%'
It will work for entries like 'prime soft' querying with 'primesoft'
Or you can use regex.
Im running a sql search query to bring up records that match a post code
say i have a postcode:
'CB4 1AB'
if the database has (with and without a space)
cb41ab
cb4 1ab
or i search with (with and without a space)
cb41ab
cb4 1ab
i want it to bring back the record
How can i do it?
select addr1, addr2, postcode
from addresses p
where p.postcode LIKE 'cb%'
Thanks
You can try something like this:
select addr1, addr2, postcode
from addresses p
where replace(p.postcode, ' ', '') LIKE 'cb41ab'
So, it sounds like you're going for this. Expanding on other answers:
DECLARE #input VARCHAR(50)
SET #input = 'CB4 1AB'
SELECT addr1, addr2, postcode
FROM addresses p
WHERE REPLACE(p.postcode, ' ', '') = REPLACE(#input, ' ', '')
EDIT: I removed the "LIKE" since this should cover all above cases.
The question is unclear to me so I have multiple answers:a) If you look for a specific UK post code, do it like this: LIKE 'cb4%1ab'. Both versions will return ("spaced" and wo. space ones).b) If you use LIKE 'cb%' that won't give any trouble either. Field will return the value either it has or has no space in it.c) If you want to find a post code, specifically having or not having space say LIKE 'cb4_1%' for post codes with space and LIKE 'cb41%' for post codes not having space - or even better to look for field size instead (6 chars long or 7) so LENGTH([fieldname]) = 6 [or 7]d) The user enters a postcode and you don't know if value has or has no space in it: I'd say code revise is needed, shouldn't be sorted out on SQL/Server side. If it's not possible REPLACE added by others is just fine. If both "d" and "a" is true in your case, use REPLACE to change space into "%", so whatever the input was and whatver is stored in db (field value has or has no space), you'll get the resultLast but not least, just an advice: if you have the chance to 'uniformize' the field's value, do it (set field max length to 6 and/or update the table and remove space from values)Hope this helps!
[EDIT: added 'd' option :) ]
Does anyone have a LIKE pattern that matches whole words only?
It needs to account for spaces, punctuation, and start/end of string as word boundaries.
I am not using SQL Full Text Search as that is not available. I don't think it would be necessary for a simple keyword search when LIKE should be able to do the trick. However if anyone has tested performance of Full Text Search against LIKE patterns, I would be interested to hear.
Edit:
I got it to this stage, but it does not match start/end of string as a word boundary.
where DealTitle like '%[^a-zA-Z]pit[^a-zA-Z]%'
I want this to match "pit" but not "spit" in a sentence or as a single word.
E.g. DealTitle might contain "a pit of despair" or "pit your wits" or "a pit" or "a pit." or "pit!" or just "pit".
Full text indexes is the answer.
The poor cousin alternative is
'.' + column + '.' LIKE '%[^a-z]pit[^a-z]%'
FYI unless you are using _CS collation, there is no need for a-zA-Z
you can just use below condition for whitespace delimiters:
(' '+YOUR_FIELD_NAME+' ') like '% doc %'
it works faster and better than other solutions. so in your case it works fine with "a pit of despair" or "pit your wits" or "a pit" or "a pit." or just "pit", but not works for "pit!".
I think the recommended patterns exclude words with do not have any character at the beginning or at the end. I would use the following additional criteria.
where DealTitle like '%[^a-z]pit[^a-z]%' OR
DealTitle like 'pit[^a-z]%' OR
DealTitle like '%[^a-z]pit'
I hope it helps you guys!
Surround your string with spaces and create a test column like this:
SELECT t.DealTitle
FROM yourtable t
CROSS APPLY (SELECT testDeal = ' ' + ISNULL(t.DealTitle,'') + ' ') fx1
WHERE fx1.testDeal LIKE '%[^a-z]pit[^a-z]%'
If you can use regexp operator in your SQL query..
For finding any combination of spaces, punctuation and start/end of string as word boundaries:
where DealTitle regexp '(^|[[:punct:]]|[[:space:]])pit([[:space:]]|[[:punct:]]|$)'
Another simple alternative:
WHERE DealTitle like '%[^a-z]pit[^a-z]%' OR
DealTitle like '[^a-z]pit[^a-z]%' OR
DealTitle like '%[^a-z]pit[^a-z]'
This is a good topic and I want to complement this to someone how needs to find some word in some string passing this as element of a query.
SELECT
ST.WORD, ND.TEXT_STRING
FROM
[ST_TABLE] ST
LEFT JOIN
[ND_TABLE] ND ON ND.TEXT_STRING LIKE '%[^a-z]' + ST.WORD + '[^a-z]%'
WHERE
ST.WORD = 'STACK_OVERFLOW' -- OPTIONAL
With this you can list all the incidences of the ST.WORD in the ND.TEXT_STRING and you can use the WHERE clausule to filter this using some word.
You could search for the entire string in SQL:
select * from YourTable where col1 like '%TheWord%'
Then you could filter the returned rows client site, adding the extra condition that it must be a whole word. For example, if it matches the regex:
\bTheWord\b
Another option is to use a CLR function, available in SQL Server 2005 and higher. That would allow you to search for the regex server-side. This MSDN artcile has the details of how to set up a dbo.RegexMatch function.
Try using charindex to find the match:
Select *
from table
where charindex( 'Whole word to be searched', columnname) > 0