Im running a sql search query to bring up records that match a post code
say i have a postcode:
'CB4 1AB'
if the database has (with and without a space)
cb41ab
cb4 1ab
or i search with (with and without a space)
cb41ab
cb4 1ab
i want it to bring back the record
How can i do it?
select addr1, addr2, postcode
from addresses p
where p.postcode LIKE 'cb%'
Thanks
You can try something like this:
select addr1, addr2, postcode
from addresses p
where replace(p.postcode, ' ', '') LIKE 'cb41ab'
So, it sounds like you're going for this. Expanding on other answers:
DECLARE #input VARCHAR(50)
SET #input = 'CB4 1AB'
SELECT addr1, addr2, postcode
FROM addresses p
WHERE REPLACE(p.postcode, ' ', '') = REPLACE(#input, ' ', '')
EDIT: I removed the "LIKE" since this should cover all above cases.
The question is unclear to me so I have multiple answers:a) If you look for a specific UK post code, do it like this: LIKE 'cb4%1ab'. Both versions will return ("spaced" and wo. space ones).b) If you use LIKE 'cb%' that won't give any trouble either. Field will return the value either it has or has no space in it.c) If you want to find a post code, specifically having or not having space say LIKE 'cb4_1%' for post codes with space and LIKE 'cb41%' for post codes not having space - or even better to look for field size instead (6 chars long or 7) so LENGTH([fieldname]) = 6 [or 7]d) The user enters a postcode and you don't know if value has or has no space in it: I'd say code revise is needed, shouldn't be sorted out on SQL/Server side. If it's not possible REPLACE added by others is just fine. If both "d" and "a" is true in your case, use REPLACE to change space into "%", so whatever the input was and whatver is stored in db (field value has or has no space), you'll get the resultLast but not least, just an advice: if you have the chance to 'uniformize' the field's value, do it (set field max length to 6 and/or update the table and remove space from values)Hope this helps!
[EDIT: added 'd' option :) ]
Related
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The name column has both first and last name in one column.
Look at the 'rep' column. How do I filter only those rep names where the last name is starting with 'K'?
The way that table is defined won't allow you to do that query reliably--particularly if you have international names in the table. Not all names come with the given name first and the family name second. In Asia, for example, it is quite common to write names in the opposite order.
That said, assuming you have all western names, it is possible to get the information you need--but your indexes won't be able to help you. It will be slower than if your data had been broken out properly.
SELECT rep,
RTRIM(LEFT(LTRIM(RIGHT(rep, LEN(rep) - CHARINDEX(' ', rep))), CHARINDEX(' ', LTRIM(RIGHT(rep, LEN(rep) - CHARINDEX(' ', rep)))) - 1)) as family_name
WHERE family_name LIKE 'K%'
So what's going on in that query is some string manipulation. The dialect up there is SQL Server, so you'll have to refer to your vendor's string manipulation function. This picks the second word, and assumes the family name is the second word.
LEFT(str, num) takes the number of characters calculated from the left of the string
RIGHT(str, num) takes the number of characters calculated from the right of the string
CHARINDEX(char, str) finds the first index of a character
So you are getting the RIGHT side of the string where the count is the length of the string minus the first instance of a space character. Then we are getting the LEFT side of the remaining string the same way. Essentially if you had a name with 3 parts, this will always pick the second one.
You could probably do this with SUBSTRING(str, start, end), but you do need to calculate where that is precisely, using only the string itself.
Hopefully you can see where there are all kinds of edge cases where this could fail:
There are a couple records with a middle name
The family name is recorded first
Some records have a title (Mr., Lord, Dr.)
It would be better if you could separate the name into different columns and then the query would be trivial--and you have the benefit of your indexes as well.
Your other option is to create a stored procedure, and do the calculations a bit more precisely and in a way that is easier to read.
Assuming that the name is <firstname> <lastname> you can use:
where rep like '% K%'
Thank you for your help.
How do I get data that contains a space at the front or the back?
For example: (see .png)
enter image description here
I tried:
select* from customer_table where customer like '% %'
but:
it gave me all of them because name contains a space in between.
I need to get the ones that have a white-space at the front.
thank you!
I think you want:
where customer like ' %' or customer like '% '
like patterns match the entire string. So the first gets spaces at the begging and the second spaces at the end. If you wanted both, you can do that in a single patter:
where customer like ' % '
Use TRIM function on the column to fit you select condition, for instance
WHERE LTRIM([CUSTOMER]) = 'Joe'
This example is for Microsoft SQL Server but I believe all DBMS have a similar function you can use trim as the keyword to search.
i've got a problem with transferring "real-World" data into my schema.
It's actually a "project" for my Database course and they gave us ab table with dog race results. This Table has a column which contains the name of the Dog (which itself consists of the actuall name and the name of the breeder) and informations about the Birthcountry, actual living Country and the birth year.
Example filed are "Lillycette [AU 2012]" or "Black Bear Lee [AU/AU 2013]" or "Lemon Ralph [IE/UK 1998]".
I've managed it to get out the first word and save it in the right column with split_part like this:
INSERT INTO tblHund (rufname)
SELECT
split_part(name, ' ', 1) AS rufname,
FROM tblimport;
tblimport is a table where I dumped the data from the csv file.
That works just as it should.
Accessing the second part of the Name with this fails because sometimes there isn't a second part and sometimes times there second part consists of two words.
And this is the where iam stuck right now.
I tried it with substring and regular expressions:
INSERT INTO tblZwinger (Name)
SELECT
substring(vatertier from E'[^ ]*\\ ( +)$')AS Name
FROM tblimport
WHERE substring(vatertier from E'[^ ]*\\ ( +)$') != '';
The above code is executed without errors but actually does nothing because the SELECT statement just give empty strings back.
It took me more then 3h to understand a bit of this regular Expressions but I still feel pretty stupid when I look at them.
Is there any other way of doing this. If so just give me a hint.
If not what is wrong with my expression above?
Thanks for your help.
You need to use atom ., which matches any single character inside capturing group:
E'[^ ]*\\ (.+)$'
SELECT
tblimport.*,
ti.parts[1] as f1,
ti.parts[2] as f2, -- It should be the "middle part"
ti.parts[3] as f3
FROM
tblimport,
regexp_matches(tblimport.vatertier, '([^\s]+)\s*(.*)\s+\[(.*)\]') as ti(parts)
WHERE
nullif(ti.parts[2], '') is not null
Something like above.
I don't recall ever seeing a field like this before, but it combines the city, state, and zipcode into a single string of varchar2. Fortunately, I believe most of the fields are in the same city space state, space zipcode format, but I started finding a few that deviated from that norm.
Right now I'm trying to identify all these distinct conditions
in the database with over 5 million rows and my queries aren't working for what I wanted.
I started with:
SELECT PROJECT_CTY_ST_ZIP FROM PAYMENT WHERE PROJECT_CTY_ST_ZIP LIKE '%' || CHR(32) || '%';
Then tried:
SELECT PROJECT_CTY_ST_ZIP FROM PAYMENT WHERE PROJECT_CTY_ST_ZIP LIKE '% %' AND PROJECT_CTY_ST_ZIP LIKE '% %' AND PROJECT_CTY_ST_ZIP LIKE '% %';
but they are both pulling based on leading and trailing spaces and I was really wanted to find spaces in the inside of the text. I don't want to remove them, just identify them with a query so I can parse them properly in my java code and then do an insert later to put them into city, state, and zipcode fields in another table.
While it doesn't show it here, I found this field in IA with no leading spaces, then one leading space and then two leading spaces. I fixed the leading spaces with trim.
WEST LIBERTY, IA 52776
This last one I wasn't expecting and I wanted to see if there are other conditions that might be unusual, but my query doesn't find them as the spaces are in the middle of the text:
TRUTH OR CONSEQUENCE, NM 87901
How would I go about a query to find these kinds of distinct records?
This query replaces each of the spaces with a dot (.) so you can see them
SELECT
REGEXP_REPLACE(PROJECT_CTY_ST_ZIP,
'([[:space:]])',
'.') spaces_or_now_dots
FROM PAYMENT
This query finds the ones that have one or more spaces.
SELECT PROJECT_CTY_ST_ZIP
FROM PAYMENT
where REGEXP_LIKE(PROJECT_CTY_ST_ZIP,
'[[:space:]]'
)
I have not considered the cases of spaces in the beginning and end, because you have already taken care of them.
I have a Company table in SQL Server and I would like to retrieve list of data related to particular companies and list of companies is very huge of around 200 company names and I am trying to use IN clause of T-SQL which is complicating the retrieval as few the companies have special characters in their name like O'Brien and so its throwing up an error as it is obvious.
SELECT *
FROM COMPANY
WHERE COMPANYNAME IN
('Archer Daniels Midland'
'Shell Trading (US) Company - Financial'
'Redwood Fund, LLC'
'Bunge Global Agribusiness - Matt Thibodeaux'
'PTG, LLC'
'Morgan Stanley Capital Group'
'Vitol Inc.'..
.....
....
.....)
Above is the script that is not working for obvious reasons, is there any way I can input those company names from an excel file and retrieve the data?
The easiest way would be to make a table and join it:
CREATE TABLE dbo.IncludedCompanies (CompanyName varchar(1000)
INSERT INTO dbo.IncludedCompanies
VALUES
('Archer Daniels Midland'),
('PTG, LLC')
...
SELECT *
FROM Company C
JOIN IncludedCompanies IC
ON C.CompanyName = IC.CompanyName
I do not think that mysql knows how to handle excel format, but you can fix your query.
Check how complicated names are stored in database (check if they have escape characters in them or anything else".
Replace all ' with \' in your query and it will take care of the ' characters
mysql> select now() as 'O\'Brian'; returns
O'Brian
2014-03-17 15:06:39
So i'm guessing you have a excel sheet with a column containing these names, and you want to use this in your where clause. In addition, some of the values have special characters in them, which needs to be escaped.
First thing you do is to escape the '-characters. You do this in excel, with a search replace for all occurences of ' with '' (the escaped version in sqlserver (\' in MySQL.)) Then, create a new column on each side side of your companies column, and in the first row input a ' on the left hand side, and ', on the right. Then use the copy cell functionality (the little square in the bottom right of the cell when you select it) to copy the cells to the left and right to all the rows, as far as the company list goes (just grab the square and pull it downwards..)
Then, take your list, now containing three columns and x rows and paste it into your favorite text editor. It should look something like this:
' Company#1 ',
' Company with special '' char ',
[...]
' Last company ',
Now, you will have some whitespace to get rid of. Use search replace and replace two space characters with nothing, and repeat (or take the space from the first ' to the start of the text and replace this with nothing.
Now, you should have a list of:
'Company#1',
'Company with special '' char',
[...]
'Last company',
Remove the last comma, and you'll have a valid list of parameters to your in-clause (or a (temporary) table if you want to keep your query a bit cleaner.)