I have a table t which looks like this
key fill store end_date status
1 123 1 2019-04-30 0
2 1234 1 2019-04-30 0
3 123 1 2019-05-01 0
Now I need to update the first record and set status=1 as the third record has same fill, store value and it is latest.
Output:
key fill store end_date status
1 123 1 2019-04-30 1
2 1234 1 2019-04-30 0
3 123 1 2019-05-01 0
I tried calculating row_number and tried to update the column based on it but unable to figure out how to use the result in the update clause.
update t set
status = 1
from (
select *
from (
select *
, row_number() over (partition by fill, store order by end_dt desc) as row_num from t
) a
where row_num = 2
) b
This query is updating all the records, what should change in my query to get the expected result?
I think that you want:
with cte as (
select status, row_number() over(partition by fill, store order by end_date desc) rn
from t
)
update cte set status = 1 where rn > 1
In the common table expression, row_number() ranks records having the same fill and store by descending end_date. Then, the outer query sets status to 1 on rows that were not ranked first.
You can do a correlated subquery:
update my_table a
set status = 1
where exists (
select 1
from my_table b
where b.fill = a.fill
and b.store = a.store
and b.end_date > a.end_date
)
Related
I have a table and i want to know the minimum date since the last change grouped by 2 columns
in the data, I want to know the lates PartNumberID by location, with the min date since the last change.
*Expected row it's not part of the table
DATA:
Location
RecordAddedDate
PartNumberID
ExpectedRow
7
2022-06-23
1
I want this row
8
2022-06-23
1
I want this row
8
2022-06-24
1
8
2022-06-25
1
9
2022-06-23
1
I want this row
15
2022-06-23
1
15
2022-06-24
1
15
2022-06-25
2
15
2022-06-26
1
I want this row
15
2022-06-27
1
Expected output:
Location
RecordAddedDate
PartNumberID
7
2022-06-23
1
8
2022-06-23
1
9
2022-06-23
1
15
2022-06-26
1
I'm on sql
I have tried with but I dont know how to stop when the value change
with cte as (
select t.LocationID, t.RecordAddedDate, t.PartNumberID
FROM mytable t
INNER JOIN (select PL.LocationID, PL.RecordAddedDate, PL.PartNumberID
FROM mytable PL INNER JOIN
(SELECT PSCc.LocationID, MAX(PSCc.RecordAddedDate) AS DateSetup
FROM mytable PSCc
WHERE PSCc.RecordDeleted = 0
GROUP BY PSCc.LocationID) AS PSCc ON PSCc.LocationID = PL.LocationID AND PSCc.DateSetup = RecordAddedDate) as tt on t.RecordAddedDate<=tt.RecordAddedDate and t.LocationID= tt.LocationID and t.PartNumberID= tt.PartNumberID
)
select *
from cte c
where not exists(
select 1 from cte
where cte.LocationID = c.LocationID
and cte.PartNumberID=c.PartNumberID
and cte.RecordAddedDate<c.RecordAddedDate
)
order by LocationID,RecordAddedDate
Thank you
use lag() to find the last change (order by RecordAddedDate desc) in PartNumberID.
cumulative sum sum(isChange) to group the related rows under same group no. grp = 0 with be the rows of the last change
To get the min - RecordAddedDate, use row_number()
with
cte1 as
(
select *,
isChange = case when PartNumberID
= isnull(lag(PartNumberID) over (partition by Location
order by RecordAddedDate desc),
PartNumberID)
then 0
else 1
end
from mytable
),
cte2 as
(
select *, grp = sum(isChange) over (partition by Location order by RecordAddedDate desc)
from cte1
),
cte3 as
(
select *, rn = row_number() over (partition by Location order by RecordAddedDate)
from cte2 t
where t.grp = 0
)
select *
from cte3 t
where t.rn = 1
db<>fiddle demo
I've a table that stores the historical data, what i'm trying to do is trying to capture the max seq record. i can do that, but i need to include the tr_type, then i'll use the outupt to join with another table. below is ex of my data
CLM_NO SEQ SUB TR_TYPE
12345 1 1 50
12345 1 2 50
12345 2 1 60
12345 2 2 60
i want to return only the last row
You can try to use exists and correlated subquery
SELECT *
FROM T t1
WHERE exists(
SELECT 1
FROM T tt
GROUP BY tt.CLM_NO
HAVING MAX(tt.SEQ) = t1.SEQ AND MAX(tt.SUB) = t1.SUB
)
EDIT
You can try to use ROW_NUMBER window function.
SELECT * FROM (
SELECT *,ROW_NUMBER() OVER(PARTITION BY CLM_NO ORDER BY TRAN_SEQ DESC,TRAN_SUB DESC) rn
FROM TBL t1
)t1
where rn = 1
I have two columns of interest ID and Deadline:
ID Deadline (DD/MM/YYYY)
1 01/01/2017
1 05/01/2017
1 04/01/2017
2 02/01/2017
2 03/01/2017
2 06/02/2017
2 08/03/2017
Each ID can have multiple (n) deadlines. I need to select all rows where the Deadline is second lowest for each individual ID.
Desired output:
ID Deadline (DD/MM/YYYY)
1 04/01/2017
2 03/01/2017
Selecting minimum can be done by:
select min(deadline) from XXX group by ID
but I am lost with "middle" values. I am using Rpostgresql, but any idea helps as well.
Thanks for your help
One way is to use ROW_NUMBER() window function
SELECT id, deadline
FROM (
SELECT *, ROW_NUMBER() OVER (PARTITION BY id ORDER BY deadline) rn
FROM xxx
) q
WHERE rn = 2 -- get only second lowest ones
or with LATERAL
SELECT t.*
FROM (
SELECT DISTINCT id FROM xxx
) i JOIN LATERAL (
SELECT *
FROM xxx
WHERE id = i.id
ORDER BY deadline
OFFSET 1 LIMIT 1
) t ON (TRUE)
Output:
id | deadline
----+------------
1 | 2017-04-01
2 | 2017-03-01
Here is a dbfiddle demo
Using ROW_NUMBER() after taking distinct records will eliminate the chance of getting the lowest date instead of second lowest if there are duplicate records.
select ID,Deadline
from (
select ID,
Deadline,
ROW_NUMBER() over(partition by ID order by Deadline) RowNum
from (select distinct ID, Deadline from SourceTable) T
) Tbl
where RowNum = 2
I need to select data base upon three conditions
Find the latest date (StorageDate Column) from the table for each record
See if there is more then one entry for date (StorageDate Column) found in first step for same ID (ID Column)
and then see if DuplicateID is = 2
So if table has following data:
ID |StorageDate | DuplicateTypeID
1 |2014-10-22 | 1
1 |2014-10-22 | 2
1 |2014-10-18 | 1
2 |2014-10-12 | 1
3 |2014-10-11 | 1
4 |2014-09-02 | 1
4 |2014-09-02 | 2
Then I should get following results
ID
1
4
I have written following query but it is really slow, I was wondering if anyone has better way to write it.
SELECT DISTINCT(TD.RecordID)
FROM dbo.MyTable TD
JOIN (
SELECT T1.RecordID, T2.MaxDate,COUNT(*) AS RecordCount
FROM MyTable T1 WITH (nolock)
JOIN (
SELECT RecordID, MAX(StorageDate) AS MaxDate
FROM MyTable WITH (nolock)
GROUP BY RecordID)T2
ON T1.RecordID = T2.RecordID AND T1.StorageDate = T2.MaxDate
GROUP BY T1.RecordID, T2.MaxDate
HAVING COUNT(*) > 1
)PT ON TD.RecordID = PT.RecordID AND TD.StorageDate = PT.MaxDate
WHERE TD.DuplicateTypeID = 2
Try this and see how the performance goes:
;WITH
tmp AS
(
SELECT *,
RANK() OVER (PARTITION BY ID ORDER BY StorageDate DESC) AS StorageDateRank,
COUNT(ID) OVER (PARTITION BY ID, StorageDate) AS StorageDateCount
FROM MyTable
)
SELECT DISTINCT ID
FROM tmp
WHERE StorageDateRank = 1 -- latest date for each ID
AND StorageDateCount > 1 -- more than 1 entry for date
AND DuplicateTypeID = 2 -- DuplicateTypeID = 2
You can use analytic function rank , can you try this query ?
Select recordId from
(
select *, rank() over ( partition by recordId order by [StorageDate] desc) as rn
from mytable
) T
where rn =1
group by recordId
having count(*) >1
and sum( case when duplicatetypeid =2 then 1 else 0 end) >=1
I have a history of records (multiple records per update all with the exact same datetime) that share an IdString.
I want a query to determine which of these records are part of the most recent update group.
This query will show me one of the records having the most recent update date, but for each partition, I need all the records with that max date.
;with cte as(
select ROW_NUMBER() over (partition by IdString order by UpdateDate desc) as [rn], *
from MyTable
)
select CASE WHEN (cte.rn = 1) THEN 0 ELSE 1 END [IsOld], *
from MyTable m
inner join cte on cte.RecordId= m.RecordId
Would someone please help me figure out an appropriate query?
EDIT: Sample
(IsOld is the desired calculated value)
IsOld RecordId IdString UpdateDate
1 1 ABC 2011-06-16
1 2 ABC 2012-05-30
1 3 ABC 2008-12-31
0 4 ABC 2012-06-08
1 5 ABC 2011-01-16
0 6 ABC 2012-06-08
1 7 ABC 2012-06-07
1 8 XYZ 2001-01-16
1 9 XYZ 2013-01-30
0 10 XYZ 2001-01-31
1 11 XYZ 2013-06-01
1 12 XYZ 2001-05-04
0 13 XYZ 2013-01-30
SELECT CASE WHEN updateDate = maxDate THEN 0 ELSE 1 END isOldRecord, RecordID, IDString, UpdateDate
FROM
(
select m.RecordID, m.IDString, m.updateDate, MAX(UpdateDate) OVER (PARTITION BY IDString) maxDate
from MyTable m
) A
Try this -
;WITH cte AS(
SELECT RANK() OVER(PARTITION BY IdString ORDER BY UpdateDate DESC) AS [row_num], *
FROM MyTable
)
SELECT CASE WHEN m.[row_num] = 1 THEN 0 ELSE 1 END isOld, *
from cte m