Retrieve email ids from multiple full Email Address using SQL query - sql

Question

Using SQL-server
Am trying to retrieve email id from list of full email addresses
Example
Input
"ABCD"<abcd#gmail.com>;"TEST" <test#outlook.com>;
Needed output
abcd#gmail.com,test#outlook.com
i have tried the below query but it is giving only one email id not all.Some help will be greatly appreciated.
SELECT (CASE WHEN to_address LIKE '%<%'
THEN SUBSTRING(to_address, CHARINDEX('<',to_address)+1, CHARINDEX('>',to_address) - CHARINDEX('<',to_address)-1)
ELSE to_address
END) AS ToAddress
from test

Answer 1

In SQL Server, you can use string_split():
select replace(stuff(s.value, 1, charindex('<', s.value), ''), '>', '')
from t cross apply
string_split(t.list, ';') s
If you want to re-concatenate them:
select s.emails
from t cross apply
(select string_agg(replace(stuff(s.value, 1, charindex('<', s.value), ''), '>', ''), ';') as email
from string_split(t.list, ';') s
) s;
EDIT:
Another approach which works with earlier versions of SQL Server is a recursive CTE:
with cte as (
select convert(varchar(max), null) as email,
convert(varchar(max), emails) as rest,
convert(varchar(max), '') as output_emails, 0 as lev
from (values ('"ABCD"<abcd#gmail.com>;"TEST" <test#outlook.com>; ')
) v(emails)
union all
select replace(stuff(v.el, 1, charindex('<', v.el), ''), '>;', ''),
stuff(rest, 1, charindex(';', rest), ''),
concat(output_emails,
replace(stuff(v.el, 1, charindex('<', v.el), ''), '>;', ''),
';'),
lev + 1
from cte cross apply
(values (left(rest, charindex(';', rest)))) v(el)
where rest <> '' and lev < 5
)
select output_emails
from (select cte.*, row_number() over (order by lev desc) as seqnum
from cte
) cte
where seqnum = 1;
Here is a db<>fiddle.