My table looks something like this:
I want to get the record for the MAX Date. So after querying, my output should only contain this:
A correlated subquery is a simple method:
select t.*
from t
where t.update_date = (select max(t2.update_date) from t t2 where t2.number = t.num);
Use row_number() with top (1) with ties available for SQL Server (which was initially tagged) :
select top (1) with ties t.*
from table t
order by row_number() over (partition by no order by date desc);
You can also use subquery :
select t.*
from (select t.*, row_number() over (partition by no order by date desc) as seq
from table t
) t
where seq = 1;
Related
I need to select the data of all my customers with the records displayed in the image. But I need to get the most recent record only, for example I need to get the order # E987 for John and E888 for Adam. As you can see from the example, when I do the select statement, I get all the order records.
You don't mention the specific database, so I'll answer with a generic solution.
You can do:
select *
from (
select t.*,
row_number() over(partition by name order by order_date desc) as rn
from t
) x
where rn = 1
You can use analytical function row_number.
Select * from
(Select t.*,
Row_number() over (partition by customer_id order by order_date desc) as rn
From your_table t) t
Where rn = 1
Or you can use not exists as follows:
Select *
From yoir_table t
Where not exists
(Select 1 from your_table tt
Where t.customer_id = tt.custome_id
And tt.order_date > t.order_date)
You can do it with a subquery that finds the last order date.
SELECT t.*
FROM yoir_table t
JOIN (SELECT tt.custome_id,
MAX(tt.order_date) MaxOrderDate
FROM yoir_table tt
GROUP BY tt.custome_id) AS tt
ON t.custome_id = tt.custome_id
AND t.order_date = tt.MaxOrderDate
I have table with rows that look like this:
DateTime, Field1, Field2, Field3
I want to get the TOP 3 records by date, by day. For one record I would execute
SELECT TOP(3) *
FROM tum
I need that for each day. I am assuming I would use partition or cross apply, but the actual syntax for this is not clear to me.
You would use row_number():
select t.*
from (select t.*,
row_number() over (partition convert(date, datetime) order by ?) as seqnum
from t
) t
where seqnum <= 3;
How can I get the Latest amount, I already had some queries but instead it shows two records ,Im expecting to show only the the '7370' current amount
you can use correlated subquery
select * from tablename a where lasttime in (select max(lasttime) from tablename b where a.id=b.id)
OR you can use row_number()
select * from
(
select *,row_number() over(partition by id order by lasttime desc) as rn from tablename
)A where rn=1
Just add Top 1 before your fields.
Select TOP 1 fields from table
SELECT TOP 1 currentBalance FROM DBO.tbl_billing ORDER BY [date]
So I have a table that looks something like this:
Now, I want the max totalcst for both days, something like this:
I tried using different variations of max and the Row_number funtion but still can't seem to get the result I want. My query:
select date,pid,max(quan*cst), totalcst
from dbo.test1
group by date, pid
But this returns all the records. So if somebody can point me towards the right direction, that would be very helpful.
Thanks in advance!
ROW_NUMBER should work just fine:
WITH CTE AS
(
SELECT *,
RN = ROW_NUMBER() OVER(PARTITION BY [date] ORDER BY totalcst)
FROM dbo.YourTable
)
SELECT [date],
pid,
totalcst
FROM CTE
WHERE RN = 1
;
Here is one simple way:
select t.*
from test1 t
where t.totalcst = (select max(t2.totalcst) from test1 t2 where t2.date = t.date);
This often has the best performance if you have an index on (date, totalcst). Of course, row_number()/rank() is also a very acceptable solution:
select t.*
from (select t.*, row_number() over (partition by date order by totalcst desc) as seqnum
from test1
) t
where seqnum = 1;
I have a SQL query that does some ranking, like this:
SELECT RANK() OVER(PARTITION BY XXX ORDER BY yyy,zzz,oooo) as ranking, *
FROM SomeTable
WHERE ranking = 1 --> this is not possible
I want to use that ranking in a WHERE condition at the end.
Now I nest this query in another query and do filtering on the ranking there, but is there no easier or faster way to filter on such values from the SELECT statement?
Use a CTE (Common Table Expression) - sort of an "inline" view just for the next statement:
;WITH MyCTE AS
(
SELECT
RANK() OVER(PARTITION BY XXX ORDER BY yyy,zzz,oooo) as ranking,
*
FROM SomeTable
)
SELECT *
FROM MyCTE
WHERE ranking = 1 --> this is now possible!
Sorry for the former posting, i forgot : windowing functions can only be used in select or order by clauses.
You'll have to use a sub query:
SELECT * FROM
(
SELECT RANK() OVER(PARTITION BY XXX ORDER BY yyy,zzz,oooo) as ranking, *
FROM SomeTable
) t
WHERE ranking = 1
OR A CTE.
select * from (
select RANK() OVER(PARTITION BY name ORDER BY id) as ranking, *
from PostTypes
) A
where A.ranking = 1
https://data.stackexchange.com/stackoverflow/query/edit/59515