Select name, Subject, Score from Class
Tables
name | Subject | Score
-----------------------
Ola maths 20
Ola pop 15
Ola eng 74
Dodo maths 21
Dodo pop 19
Dodo eng 54
Please any idea on how to make it display like this:
name | Subject | Score
-----------------------
Ola maths 20
pop 15
eng 74
Dodo maths 21
pop 19
eng 54
Please any assistant will be appreciated
if you absolutely have to do this in SQL:
with cte as
(
select rn=row_number() over (partition by name order by 1)
,*
from [table]
)
select n = case when rn=1 then name else '' end, Subject, Score
from cte
order by name,rn
But if you do this then you are losing the ability to use this data again.
As previous people have already comment, this might not be your best approach but the following query returns your expected result:
create table Class (Name varchar(10), Subject varchar(10), Score int)
insert into Class
values ('Ola', 'maths', 20),
('Ola', 'pop', 15),
('Ola', 'eng', 15),
('Dodo', 'maths', 20),
('Dodo', 'pop', 15),
('Dodo', 'eng', 15)
select
case when Row# = 1 then t.Name else null end,
Subject,
Score
from (
select
ROW_NUMBER() OVER(PARTITION BY Name ORDER BY Name ASC) AS Row#,
Name,
Subject,
Score
from Class) t
drop table Class
Related
Hi all I am quite new to SQL. I have a table (TABLE1) with two columns as below
Name age
--------
jim 18
jim 21
dave 18
dave 18
john 23
john 41
I need to create a view in SSMS which lists distinct ages for each name in a separate column as below
Jim Dave John
---------------
18 18 23
21 41
I have tried a sub query like
SELECT DISTINCT AGE FROM TABLE1 WHERE NAME = JIM
But I encountered a sub query cannot return more than one value.
You can use row_number() & do aggregation :
select max(case when name = 'jim' then age end) as jim,
max(case when name = 'dave' then age end) as dave,
max(case when name = 'john' then age end) as john
from (select t.*, row_number() over (partition by name order by age) as seq
from table t
) t
group by seq;
I have a large SQL table called 'allscores' similar to the following:
user score quiz_id high_score
Bob 90 math 1
John 80 math 0
John 85 math 1
Steve 100 math 1
Bob 95 reading 0
Bob 100 reading 1
John 80 reading 1
The 'high_score' field is in the table to begin with and is always set to '1' for the row where a user's score is the highest for them for that quiz.
What I want is a SQL query that I can run on an individual user to pull their highest score from each of the two quizzes ('math' and 'reading') along with their overall rank among scores for that quiz. What I have so far is the following:
SELECT `user`, `score`, `quiz_id` FROM `allscores` WHERE `user`="Bob" AND `high_score`="1"
Which will output the following:
user score quiz_id
Bob 90 math
Bob 100 reading
This query is simply pulling the highest score for Bob from each quiz - what I want to add is the ranking of the score among the scores in that particular quiz - so an output like the following:
user score quiz_id rank
Bob 90 math 2
Bob 100 reading 1
Bob's rank is '2' for the math quiz as Steve has a higher score, but he is ranked '1' for reading as he has the highest score.
How would I add this ranking column to my existing query?
This uses MS T-SQL syntax, but if your flavor of SQL uses window functions, it should be similar.
SQL Fiddle
MS SQL Server 2017 Schema Setup:
CREATE TABLE t (
[user] varchar(10)
, score int
, quiz_id varchar(10)
, high_score bit
) ;
INSERT INTO t ([user], score, quiz_id, high_score)
VALUES
( 'Bob',90,'math',1 )
, ( 'John',80,'math',0 )
, ( 'Steve',100,'math',1 )
, ( 'Bob',95,'reading',0 )
, ( 'Bob',100,'reading',1 )
, ( 'John',85,'math',1 )
, ( 'John',80,'reading',1 )
;
MAIN QUERY:
SELECT s1.[user]
, s1.score
, s1.quiz_id
, s1.high_score
--, s1.isUserHighScore
, s1.ranking
FROM (
SELECT
t.[user]
, t.score
, t.quiz_id
, t.high_score
--, ROW_NUMBER() OVER (PARTITION BY t.[user],t.quiz_id ORDER BY t.score DESC) AS isUserHighScore
, DENSE_RANK() OVER (PARTITION BY t.quiz_id ORDER BY t.score DESC ) AS ranking
FROM t
) s1
WHERE s1.[user]='Bob'
--AND s1.isUserHighScore = 1
AND s1.high_score = 1
Results:
| user | score | quiz_id | high_score | isUserHighScore | ranking |
|------|-------|---------|------------|-----------------|---------|
| Bob | 90 | math | true | 1 | 2 |
| Bob | 100 | reading | true | 1 | 1 |
I use ROW_NUMBER() to determine the highest score in a quiz for a user, then use DENSE_RANK() to figure out the rank of a users score versus others. The difference between DENSE_RANK() and RANK() is essentially that DENSE_RANK() won't leave any gaps in the ranking. Example: 2 people scored a 90 and 1 scored an 80, then with DENSE_RANK() the 90s would both be Rank 1 and the 80 would be Rank 2. With RANK(), the 90s would be Rank 1 and the 80 would be Rank 3.
I have a table like this.
Id Name Test Subject Marks
----------------------------
1 Alex 1 Maths 40
1 Alex 2 Maths 80
1 Alex 1 Sociology 55
1 Alex 2 Sociology 70
1 Alex 3 Sociology 60
2 Mark 1 Maths 30
2 Mark 2 Maths 60
2 Mark 1 Sociology 40
2 Mark 2 Sociology 50
2 Mark 3 Sociology 30
What I need is a group by on Id, Name, Subject and sum(Marks) in a single row, to give a result like:
Id Name Maths Sociology
-----------------------
1 Alex 120 185
2 Mark 90 120
I can get this as:
Id Name Marks
--------------
1 Alex 120
2 Mark 90
or:
Id Name Marks
-------------
1 Alex 185
2 Mark 120
I tried multiple options but I'm getting multiple rows for each ID.
The query below is not working:
select
Id, Name, Sum(Marks) where Subject = 'Maths' as Maths,Sum(Marks ) where Subject = 'Sociology' as Sociology
from
Table
group by
Id, Name;
I get this error:
"Error while compiling statement: FAILED: ParseException line 3:66 missing EOF at 'as' near ''Maths''
You are looking for PIVOT. Try :
create table #tbl(Id int, Name varchar(20), Test int, Subject varchar(20), Marks int)
insert into #tbl values
(1,'Alex',1,'Maths', 40 ),
(1,'Alex',2,'Maths', 80 ),
(1,'Alex',1,'Sociology', 55),
(1,'Alex',2,'Sociology', 70),
(1,'Alex',3,'Sociology', 60),
(2,'Mark',1,'Maths', 30 ),
(2,'Mark',2,'Maths', 60 ),
(2,'Mark',1,'Sociology', 40),
(2,'Mark',2,'Sociology', 50),
(2,'Mark',3,'Sociology', 30)
--select * from #tbl
SELECT ID,Name,Maths,Sociology
FROM(
SELECT ID, Name, Subject, Marks
FROM #tbl
) tbl
PIVOT(
SUM(Marks) FOR Subject IN (Maths, Sociology)
) piv
output:
ID Name Maths Sociology
----------- ---- ------------ -----------
1 Alex 120 185
2 Mark 90 120
You can use a case expression to effectively filter the values going into your sum:
select Id
,Name
,sum(case when Subject = 'Maths' then Marks else 0 end) as Maths
,sum(case when Subject = 'Sociology' then Marks else 0 end) as Sociology
from Table
group by Id
,Name;
If you are looking to do this across a lot of different subject values however, you will need to look at using pivot:
select Id
,[Name]
,[Maths]
,[Sociology]
from (select Id, [Name], [Subject], Marks from #t) as t
pivot(sum(Marks)
for [Subject] in(Maths,Sociology)
) as p;
Another solution using PIVOT operator:
SELECT
ID
,Name
,Maths
,Sociology
FROM(
SELECT
ID
,Name
,Subject
,Marks
FROM your_table
) tbl
PIVOT(
SUM(Marks) FOR Subject IN (Maths, Sociology)
) pvt
You can use below query :
select id,name,maths_marks,sociology_marks
from
(select id,name,test,subject,marks
from table)
pivot(sum(marks) for subject in ('Maths' as Maths_marks,'Sociology' as Sociology_marks);
I have a table abc which have many records with columns col1,col2,col3,
dept | name | marks |
science abc 50
science cvv 21
science cvv 22
maths def 60
maths abc 21
maths def 62
maths ddd 90
I need to order by dept and name with ranking as ddd- 1, cvv - 2, abc -3, else 4 then need to find out maximum mark of an individual. Expected result is
dept | name | marks |
science cvv 22
science abc 50
maths ddd 90
maths abc 21
maths def 62
. How may I do it.?
SELECT
dept,
name,
MAX(marks) AS mark
FROM
yourTable
GROUP BY
dept,
name
ORDER BY
CASE WHEN name = 'ddd' THEN 1
name = 'cvv' THEN 2
name = 'abc' THEN 3
ELSE 4 END
Or, preferably, have another table that includes the sorting order.
SELECT
yourTable.dept,
yourTable.name,
MAX(yourTable.marks) AS mark
FROM
yourTable
INNER JOIN
anotherTable
ON yourTable.name = anotherTable.name
GROUP BY
yourTable.dept,
youtTable.name
ORDER BY
anotherTable.sortingOrder
This should work:
SELECT Dept, Name, MAX(marks) AS mark
FROM yourTable
GROUP BY Dept, Name
ORDER BY CASE WHEN Name = 'ddd' THEN 1
WHEN Name = 'cvv' THEN 2
WHEN Name = 'ABC' THEN 3
ELSE 4 END
I have a query that return below data structure :
Course Math Science Computer Chemistry
------ ---- ------- -------- ---------
CI101 98
CI101 87
CI101 78
CI101 102
CI101 23
CI101 56
CI101 89
CI101 45
How can have it be in the following structure using SQL:
Course Math Science Computer Chemistry
------ ---- ------- -------- ---------
CI101 98 78 23 45
CI101 87 102 56
CI101 89
Here is SQL I tried:
select course,
case
when subject = 'MATH' then
count
end as MATH,
case
when subject = 'SCIENCE' then
count
end as SCIENCE,
case
when subject = 'COMPUTER' then
count
end as COMPUTER,
case
when subject = 'CHEMISTRY' then
count
end as CHEMISTRY
from t_course
GROUP BY course, subject, count
Table Structure :
Course Subject Count
------ ------- -----
CI101 Math 98
....
Thanks ahead.
try this:
As I dont have Oracle and I didnt see any answer for this question, I have done this in sql server. This can be easily converted to Oracle sql.
I think, the only part requires conversion is ROW_NUMBER() over(order by [count]) as row_num which is basically to give a sequence number to each set
select CO.course,MA.count as 'MATH',SC.count as 'SCIENCE',CO.count as 'COMPUTER',CH.count as 'CHEMISTRY' from
(select course,[count],ROW_NUMBER() over(order by [count]) as row_num from t_course where subject = 'MATH')MA full outer join
(select course,[count],ROW_NUMBER() over(order by [count]) as row_num from t_course where subject = 'SCIENCE')SC on SC.row_num=MA.row_num full outer join
(select course,[count],ROW_NUMBER() over(order by [count]) as row_num from t_course where subject = 'COMPUTER')CO on CO.row_num=SC.row_num full outer join
(select course,[count],ROW_NUMBER() over(order by [count]) as row_num from t_course where subject = 'CHEMISTRY')CH on CO.row_num=CH.row_num
Please see the SQL fiddle Demo here