I have a table abc which have many records with columns col1,col2,col3,
dept | name | marks |
science abc 50
science cvv 21
science cvv 22
maths def 60
maths abc 21
maths def 62
maths ddd 90
I need to order by dept and name with ranking as ddd- 1, cvv - 2, abc -3, else 4 then need to find out maximum mark of an individual. Expected result is
dept | name | marks |
science cvv 22
science abc 50
maths ddd 90
maths abc 21
maths def 62
. How may I do it.?
SELECT
dept,
name,
MAX(marks) AS mark
FROM
yourTable
GROUP BY
dept,
name
ORDER BY
CASE WHEN name = 'ddd' THEN 1
name = 'cvv' THEN 2
name = 'abc' THEN 3
ELSE 4 END
Or, preferably, have another table that includes the sorting order.
SELECT
yourTable.dept,
yourTable.name,
MAX(yourTable.marks) AS mark
FROM
yourTable
INNER JOIN
anotherTable
ON yourTable.name = anotherTable.name
GROUP BY
yourTable.dept,
youtTable.name
ORDER BY
anotherTable.sortingOrder
This should work:
SELECT Dept, Name, MAX(marks) AS mark
FROM yourTable
GROUP BY Dept, Name
ORDER BY CASE WHEN Name = 'ddd' THEN 1
WHEN Name = 'cvv' THEN 2
WHEN Name = 'ABC' THEN 3
ELSE 4 END
Related
Hi all I am quite new to SQL. I have a table (TABLE1) with two columns as below
Name age
--------
jim 18
jim 21
dave 18
dave 18
john 23
john 41
I need to create a view in SSMS which lists distinct ages for each name in a separate column as below
Jim Dave John
---------------
18 18 23
21 41
I have tried a sub query like
SELECT DISTINCT AGE FROM TABLE1 WHERE NAME = JIM
But I encountered a sub query cannot return more than one value.
You can use row_number() & do aggregation :
select max(case when name = 'jim' then age end) as jim,
max(case when name = 'dave' then age end) as dave,
max(case when name = 'john' then age end) as john
from (select t.*, row_number() over (partition by name order by age) as seq
from table t
) t
group by seq;
I'm trying to match and align data, or resaid, count occurrences and then list for which values those occurrences occur.
Or, in a question: "How many times does each ID value occur, and for what names?"
For example, with this input
Name ID
-------------
jim 123
jim 234
jim 345
john 123
john 345
jane 234
jane 345
jan 45678
I want the output to be:
count ID name name name
------------------------------------
3 345 jim john jane
2 123 jim john
2 234 jim jane
1 45678 jan
Or similarly, the input could be (noticing that the ID values are not aligned),
jim john jane jan
----------------------------
123 345 234 45678
234 123 345
345
but that seems to complicate things.
As close as I am to the desired results is in SQL, as
for ID, count(ID)
from table
group by (ID)
order by count desc
which outputs
ID count
------------
345 3
123 2
234 2
45678 1
I'll appreciate help.
You seem to want a pivot. In SQL, you have to specify the number of columns in advance (unless you construct the query as a string).
But the idea is:
select ID, count(*) as cnt,
max(case when seqnum = 1 then name end) as name_1,
max(case when seqnum = 2 then name end) as name_2,
max(case when seqnum = 3 then name end) as name_3
from (select t.*,
row_number() over (partition by id order by id) as seqnum -- arbitrary ordering
from table t
) t
group by ID
order by count desc;
If you have an unknown number of columns, you can aggregate the values into an array:
select ID, count(*) as cnt,
array_agg(name order by name) as names
from table t
group by ID
order by count desc
the query would look similar to this if that's what you're looking for.
SELECT
name,
id,
COUNT(id) as count
FROM
dataSet
WHERE
dataSet.name = 'input'
AND dataSet.id = 'input'
GROUP BY
name,
id
In my Oracle DB, I have two tables in a one-to-many relationship: Managers and Employees.
+------------+-------+------------+
| Manager_ID | Name | Department |
+------------+-------+------------+
| 1 | Steve | Sales |
| 2 | Ben | Sales |
| 3 | Molly | Accounts |
+------------+-------+------------+
+-------------+------------+--------+-----+
| Employee_ID | Manager_ID | Name | Age |
+-------------+------------+--------+-----+
| 1 | 1 | Kyle | 25 |
| 2 | 1 | Gary | 31 |
| 3 | 2 | Renee | 31 |
| 4 | 2 | Oliver | 32 |
+-------------+------------+--------+-----+
How do I select only those Managers where every one of his Employees is over the age of 30?
In my example data, the only Manager who meets this condition is Ben, because both of his employees are over 30.
I thought something like this would do it, but it's wrong:
SELECT m.manager_id
FROM managers m
WHERE m.manager_id IN (SELECT e.manager_id
FROM employees e
GROUP BY e.manager_id
HAVING e.age > 30)
Use not exists :
select m.*
from manager m
where not exists (select 1
from Employees e
where e.Manager_ID = m.Manager_ID and e.Age < 30
) and
exists (select 1 from Employees e where e.Manager_ID = m.Manager_ID)
The only thing I don't like about Yogesh's answer (which I upvoted, since it's probably the way I'd write it) is that you have to go to the employees table a second time, to make sure the manager actually has at least one employee.
On the plus side, the NOT EXISTS that Yogesh used will allow Oracle to stop looking at a manager's employees once it finds one that is too young. So, maybe it's a toss-up.
I'll offer this alternative. It is shorter than the NOT EXISTS and does not have to go to the employees table a second time.
SELECT m.*
FROM manager m
CROSS APPLY (
SELECT min(age) min_age
FROM employee e
WHERE e.manager_id = m.manager_id ) ma
where ma.min_age >= 30;
Using sub-query for counts
SQL> WITH manager(Manager_ID, Name, Department) AS (
2 SELECT 1, 'Steve', 'Sales' FROM dual UNION ALL
3 SELECT 2, 'Ben', 'Sales' FROM dual UNION ALL
4 SELECT 3, 'Molly', 'Accounts' FROM dual),
5 employee(Employee_ID, Manager_ID, Name, Age) AS (
6 SELECT 1 , 1, 'Kyle', 25 FROM dual UNION ALL
7 SELECT 2 ,1, 'Gary', 31 FROM dual UNION ALL
8 SELECT 3, 2, 'Renee', 31 FROM dual UNION ALL
9 SELECT 4, 2 , 'Oliver', 32 FROM dual)
10 ---------------------------
11 --- End of data preparation
12 ---------------------------
13 SELECT m.name
14 FROM manager m
15 JOIN (SELECT manager_id,
16 COUNT(1) total,
17 COUNT(CASE WHEN age > 30 THEN 1 ELSE NULL END) age_30_above
18 FROM employee
19 GROUP BY manager_id) ee
20 ON m.manager_id = ee.manager_id
21 WHERE total = age_30_above;
Output
NAME
-----
Ben
Your query will be:
SELECT m.name
FROM manager m
JOIN (SELECT manager_id,
COUNT(1) total,
COUNT(CASE WHEN age > 30 THEN 1 ELSE NULL END) age_30_above
FROM employee
GROUP BY manager_id) ee
ON m.manager_id = ee.manager_id
WHERE total = age_30_above;
SELECT manager_id
FROM employees -- managers
minus
select manager_id
from employees
where age <= 30
You can use ALL function like this:
SELECT m.manager_id
FROM managers m
WHERE (30 <= ALL (SELECT e.age FROM employees e WHERE e.manager_id = m.manager_id));
You might want to reverse the conditions, select all managers, who dont have any employee below 30
select * from managers
where manager_id not in (select manager_id
from employees
where age < 30)
I have a table like this.
Id Name Test Subject Marks
----------------------------
1 Alex 1 Maths 40
1 Alex 2 Maths 80
1 Alex 1 Sociology 55
1 Alex 2 Sociology 70
1 Alex 3 Sociology 60
2 Mark 1 Maths 30
2 Mark 2 Maths 60
2 Mark 1 Sociology 40
2 Mark 2 Sociology 50
2 Mark 3 Sociology 30
What I need is a group by on Id, Name, Subject and sum(Marks) in a single row, to give a result like:
Id Name Maths Sociology
-----------------------
1 Alex 120 185
2 Mark 90 120
I can get this as:
Id Name Marks
--------------
1 Alex 120
2 Mark 90
or:
Id Name Marks
-------------
1 Alex 185
2 Mark 120
I tried multiple options but I'm getting multiple rows for each ID.
The query below is not working:
select
Id, Name, Sum(Marks) where Subject = 'Maths' as Maths,Sum(Marks ) where Subject = 'Sociology' as Sociology
from
Table
group by
Id, Name;
I get this error:
"Error while compiling statement: FAILED: ParseException line 3:66 missing EOF at 'as' near ''Maths''
You are looking for PIVOT. Try :
create table #tbl(Id int, Name varchar(20), Test int, Subject varchar(20), Marks int)
insert into #tbl values
(1,'Alex',1,'Maths', 40 ),
(1,'Alex',2,'Maths', 80 ),
(1,'Alex',1,'Sociology', 55),
(1,'Alex',2,'Sociology', 70),
(1,'Alex',3,'Sociology', 60),
(2,'Mark',1,'Maths', 30 ),
(2,'Mark',2,'Maths', 60 ),
(2,'Mark',1,'Sociology', 40),
(2,'Mark',2,'Sociology', 50),
(2,'Mark',3,'Sociology', 30)
--select * from #tbl
SELECT ID,Name,Maths,Sociology
FROM(
SELECT ID, Name, Subject, Marks
FROM #tbl
) tbl
PIVOT(
SUM(Marks) FOR Subject IN (Maths, Sociology)
) piv
output:
ID Name Maths Sociology
----------- ---- ------------ -----------
1 Alex 120 185
2 Mark 90 120
You can use a case expression to effectively filter the values going into your sum:
select Id
,Name
,sum(case when Subject = 'Maths' then Marks else 0 end) as Maths
,sum(case when Subject = 'Sociology' then Marks else 0 end) as Sociology
from Table
group by Id
,Name;
If you are looking to do this across a lot of different subject values however, you will need to look at using pivot:
select Id
,[Name]
,[Maths]
,[Sociology]
from (select Id, [Name], [Subject], Marks from #t) as t
pivot(sum(Marks)
for [Subject] in(Maths,Sociology)
) as p;
Another solution using PIVOT operator:
SELECT
ID
,Name
,Maths
,Sociology
FROM(
SELECT
ID
,Name
,Subject
,Marks
FROM your_table
) tbl
PIVOT(
SUM(Marks) FOR Subject IN (Maths, Sociology)
) pvt
You can use below query :
select id,name,maths_marks,sociology_marks
from
(select id,name,test,subject,marks
from table)
pivot(sum(marks) for subject in ('Maths' as Maths_marks,'Sociology' as Sociology_marks);
I could get the minimum percentage of two values, but I need only the name, and ID in the select.
ID NAME CITY ONE TWO
--------------------------------------------------
2 Morales Los Angeles 40 10
1 John New York 60 20
4 Mary San Diego 10 10
I need to get the min value of one/two, and to only appear this as a result:
ID NAME
---------
4 Mary
Select ID, NAME
from MYTABLE
where least(ONE,TWO) = (select min(least(ONE,TWO)) from MYTABLE);
If you don't want Morales, then you can do this :
Select ID, NAME
from MYTABLE
where id =
(select id from
(select id from MYTABLE order by least(ONE,TWO), ONE*TWO)
where rownum <= 1);