I'm trying to make sure the dates stay together and not break across lines.
The replacement text should have two non breaking spaces, one between \1 April, and one between April \2.
Sub SarahDates()
‘ Supposed to put a non breaking space between day, month and year.
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = “([0-9]) April ([0-9])”
.Replacement.Text = “\1 April \2”
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
What is the correct text in .Replacement.Text so that non-breaking spaces are shown in macro.
the following macro will reformat all your dates in one go.
Sub SarahDates()
Application.ScreenUpdating = False
With ActiveDocument.Range.Find
.ClearFormatting
.Replacement.ClearFormatting
.Text = "(<[0-9]{1,2}) ([JFMASOND][abceghilmnoprstuvy]{2,8}) ([12][0-9]{3}>)"
.Replacement.Text = "\1^s\2^s\3"
.Forward = True
.Format = False
.Wrap = wdFindContinue
.MatchWildcards = True
.Execute Replace:=wdReplaceAll
End With
Application.ScreenUpdating = True
End Sub
Related
I am using Microsoft Visual Basic on Word. I want to limit the find and replace function to operate only on certain pages of the document. How do I do it?
As of now, it will execute it the whole document which is not preferred.
Sub X_entity()
'
' Replaces lower and greater than symbols to html entity
'
'
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = ">"
.Replacement.Text = ">"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
With Selection.Find
.Text = "<"
.Replacement.Text = "<"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
Instead of using Selection (which is poor practice anyway), you should point to the range of each page in turn, using Find/Replace on the designated range only. For example:
Sub ProcessPages()
Application.ScreenUpdating = False
Dim i As Long, ArrPgs()
' Define the pages to process
ArrPgs = Array("7", "4", "3", "2")
For i = 0 To UBound(ArrPgs)
' Process the defined pages
With ActiveDocument.Range.GoTo(What:=wdGoToPage, Name:=ArrPgs(i)).GoTo(What:=wdGoToBookmark, Name:="\page").Find
.ClearFormatting
.Replacement.ClearFormatting
.Forward = True
.Wrap = wdFindStop
.Format = False
.MatchCase = False
.MatchWildcards = False
.Text = ">"
.Replacement.Text = ">"
.Execute Replace:=wdReplaceAll
.Text = "<"
.Replacement.Text = "<"
.Execute Replace:=wdReplaceAll
End With
Next i
Application.ScreenUpdating = True
End Sub
With the above code, the pages are processed in reverse order in case the Find/Replace messes with the pagination.
For some odd reason, my code does not work in all instances. It does not catch every instance where there is only 1 space after a period. I was wondering if anyone knows why this may be. I went through every line and I can't figure out why it won't work. It's pretty basic of a code.
The goal behind this code:
period with 1 space goes to period with 2 spaces
period with 2 spaces stay the same
any double spaces in the document that do not follow a period are changed to 1 space.
Mr., Mrs., Miss., Ms. only have 1 space after them.
Sub Space_corrections()
' two spaces go to one space entire doc
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = " "
.Replacement.Text = " "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
' One space after periods goes to two spaces
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = ". "
.Replacement.Text = ". "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
' Three spaces after periods goes to two spaces
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = ". "
.Replacement.Text = ". "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
' Two spaces after Mr. goes to one space
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "Mr. "
.Replacement.Text = "Mr. "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
' Two spaces after Mrs. goes to one space
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "Mrs. "
.Replacement.Text = "Mrs. "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
' Two spaces after Ms. goes to one space
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "Ms. "
.Replacement.Text = "Ms. "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
' Two spaces after Miss. goes to one space
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "Miss. "
.Replacement.Text = "Miss. "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub```
UPDATE/EDIT:
I changed over to this code, but it does to change all of the instances. I am not sure what the cause is.
There is no special font on them or anything. They are sentences that are contained by a list format, but every other instance that was changed was also contained in a list format.
These are the instances that went unchanged:
**"shipped. According"
"materials. The"**
updated code:
Sub Space_corrections_123()
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "(.)( {1,})"
.Replacement.Text = "\1 "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = True
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
You can simplify the find and replace for the Mr/Mrs/Miss/Ms/Dr/Professor etc by using a wildcard search
.findtext="([rs])(. )"
.replacementText="\1. "
Which will find any word ending in a r or s followed by a point and two spaces and replace with the found character plus point and one space.
You can also do a wildcard search to consolidate the replacement of . by to . two spaces using
.findtext="(.)( {1,})"
.replacementText="\1 "
Try:
Sub Demo()
Application.ScreenUpdating = False
With ActiveDocument.Range
With .Find
.ClearFormatting
.Replacement.ClearFormatting
.Forward = True
.Format = False
.Wrap = wdFindContinue
.MatchWildcards = True
.Text = "([ ^s]){2,}"
.Replacement.Text = "\1"
.Execute Replace:=wdReplaceAll
.Text = "(. )"
.Replacement.Text = "\1 "
.Execute Replace:=wdReplaceAll
.Text = "([DM][irs]{1,3}.)[ ]{2,}"
.Replacement.Text = "\1 "
.Execute Replace:=wdReplaceAll
End With
End With
Application.ScreenUpdating = True
End Sub
Note the 'D' in '[DM]'. That allows you to find Dr., & Drs. as well (in case there's more than one). You can delete the 'D' if it's unnecessary.
The following code works, but it performs everything on the entire document. I'd like to highlight a block of text, then when I run the macro only have it work on the highlighted text. How do I do that? Thanks...
Sub DoCodeNumberStyle(numchars As String)
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "(^13)([0-9]{" + numchars + "}) "
.Replacement.Text = "\1###\2$$$ "
.Forward = True
.Wrap = wdFindAsk
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
Selection.Find.Replacement.Style = ActiveDocument.Styles("CodeNumber")
With Selection.Find
.Text = "###([0-9]{" + numchars + "})$$$"
.Replacement.Text = "\1"
.Forward = True
.Wrap = wdFindAsk
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
Sub CodeNumberStyle()
DoCodeNumberStyle ("1")
DoCodeNumberStyle ("2")
End Sub
PostScript:
One additional thing I've discovered: if you do more than one find on a Selection, the first find loses/changes the Selection, so the others are no longer bounded by the original Selection (and a wdReplaceAll will continue to the end of the document). To fix this, capture the Selection into a Range. Here's the final version of my method, which now does everything I need, is restricted to the original highlighted selection (even with 3 find-and-replacements), and has also been minimized, code-wise:
Sub AAACodeNumberStyleHighlightedSelection()
With Selection.Range.Find
.ClearFormatting
.Style = ActiveDocument.Styles("Code")
.Replacement.ClearFormatting
.Forward = True
.Wrap = wdFindStop
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
' First line:
.Text = "1 //"
.Replacement.Text = "###1$$$ //"
.MatchWildcards = False
.Execute Replace:=wdReplaceAll
' Rest of lines:
.Text = "(^13)([0-9]{1,2}) "
.Replacement.Text = "\1###\2$$$ "
.MatchWildcards = True
.Execute Replace:=wdReplaceAll
' Now style the line numbers:
.Text = "###([0-9]{1,2})$$$"
.Replacement.Text = "\1"
.Replacement.Style = ActiveDocument.Styles("CodeNumber")
.MatchWildcards = True
.Execute Replace:=wdReplaceAll
End With
End Sub
Change .Wrap to wdFindStop and this should work for you. I think this might be a minor Word bug; the documentation says that the Wrap value
sets what happens if the search begins at a point other than the beginning of the document and the end of the document is reached (or vice versa if Forward is set to False) or if the search text isn't found in the specified selection or range.
But it seems like it forces the Find to go to the end of the document rather than taking the selection into account. Anyway, there's no need for wdFindAsk if you only plan to run this on selections.
I, too, found that even when beginning a FIND loop on a range, the range is redefined by FIND, and so continuous loop on .execute goes beyond the original range to the end of the document. wdFindStop stops only at the end of the document, not at the end of the original range.
So, I inserted an IF statement:
do while .find.found
...
If .find.parent.InRange(doc.Bookmarks("BODY").Range) = False Then Exit Do
...
.execute
loop
Set myRange = Selection.Range
myRange.Select
With Selection.Find
.Text = "Apple"
.Replacement.Text = "Banana"
.Forward = True
.Wrap = wdFindStop
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
'.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
myRange.Select
With Selection.Find
.Text = "red"
.Replacement.Text = "yellow"
.Forward = True
.Wrap = wdFindStop
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
'.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
I cannot execute a find in VBA for word to find "If..." Word doesn't seem to like finding the "If." part. Any ideas?
Sub Macro2()
Selection.Find.ClearFormatting
Selection.Find.Highlight = False
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "If..."
.Replacement.Text = "If..."
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
Chances are Word replaced the three periods with the single character ellipsis.
As a bonus, the ellipsis should have a space before and after it, it can be a half or thin space, but certainly a non breaking space so it won't be forced onto a new line.
in my word file there are hundrens of paragraph which like the format below. There is a single letter Y here. It can be other letter except "A","T","C","G". I want to remove the white space in it then create a new line.
AAATGGGCCC CACAGAAGTG AGAATGGGTG AAGTCAGAAT TCCTGGTAAT GAAGTGCTTG
AACTTGGATT CCTCCCGACA TGTGCAGTAC AATGAGATGA TTTTCTCCTT AATGAGATTA
GGAAATTCTA TTAGCGCTCC CAGCTGCTGA CCCGATTCCA TGAGGCTGAG GCTCCAGGGC
TGAACCTGCC TGGTT
Y
AGTGTTCCTG GAAACTAGAC ACCCCACCCT TCAGATGGGC CAGGGCCTCC CCAGCTCTAC
CTAAAGCTGT GGTCTGCCCC CAGGGGTGCC CAGTTTCCTC CCTTCACCCT GTGCTCCAGA
GGAGTGTGGG GCCCTGGGCA TTCTGCAGTG TACCCCAGGA TCCTCACTCC TTCCTGCTTA
The new line's format is
AAATGGGCCCCACAGAAGTGAGAATGGGTGAAGTCAGAATTCCTGGTAATGAAGTGCTTGAACTTGGATTCCTCCCGACATGTGCAGTACAATGAGATGATTTTCTCCTTAATGAGATTAGGAAATTCTATTAGCGCTCCCAGCTGCTGACCCGATTCCATGAGGCTGAGGCTCCAGGGCTGAACCTGCCTGGTT[Y]AGTGTTCCTGGAAACTAGACACCCCACCCTTCAGATGGGCCAGGGCCTCCCCAGCTCTACCTAAAGCTGTGGTCTGCCCCCAGGGGTGCCCAGTTTCCTCCCTTCACCCTGTGCTCCAGAGGAGTGTGGGGCCCTGGGCATTCTGCAGTGTACCCCAGGATCCTCACTCCTTCCTGCTTA
Notice Y becomes [Y].
The final result will be saved as a text file. Thanks for help.
You don't need to write a program. The “Replace” tool is sufficient for this:
Replace Y with [Y] (EDIT: see the comments below, because it's a little more complex than that indeed)
Replace ^w with nothing (^w means whitespace)
Replace ^p with nothing (^p means paragraph markers)
EDIT: if you need a macro, just do the above once while recording a macro.
EDIT: by applying the method discussed in the comments, I get the following VBA macro:
Sub ProcessATCG()
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "([!ACGT^13^32])"
.Replacement.Text = "[\1]"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
With Selection.Find
.Text = "[^13^32]"
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub