I have a table (tbl2) i have 4 columns with feedback attributes listed. I need to generate a pivot table like syntax in mysql. Need output somewhat like this pivot table. I am currently trying this
INSERT INTO 1 (`BAD/GOOD`, `PRICE YES`, `PRICE NO`, `TOTAL PRICE`) SELECT "BAD",COUNT(*) WHERE tbl2.PRICE="BAD" AND tbl2.Churn="YES",COUNT(*) WHERE tbl2.PRICE="BAD" AND tbl2.Churn="NO",COUNT(*) WHERE tbl2.PRICE="BAD" FROM tbl2_customers_churn
and also tried insert into as values
INSERT INTO 1 VALUES ("BAD",COUNT(*) FROM tbl2 WHERE tbl2.PRICE="BAD" AND tbl2.Churn="YES",COUNT(*) FROM tbl2 WHERE tbl2.PRICE="BAD" AND tbl2.Churn="NO",COUNT(*) FROM tbl2 WHERE tbl2.PRICE="BAD")
for bad and good count separately
Any advise on how to tackle this in SQL?
I think you want logic more like this:
INSERT INTO 1 (`BAD/GOOD`, `PRICE YES`, `PRICE NO`, `TOTAL PRICE`)
SELECT 'BAD',
SUM(CASE WHEN tbl2.PRICE = 'BAD' AND tbl2.Churn = 'YES' THEN 1 ELSE 0 END),
SUM(CASE WHEN tbl2.PRICE = 'BAD' AND tbl2.Churn = 'NO' THEN 1 ELSE 0 END),
SUM(CASE WHEN tbl2.PRICE = 'BAD' THEN 1 ELSE 0 END)
FROM tbl2_customers_churn tbl2;
Or a little more simply:
SELECT 'BAD',
SUM(CASE WHEN tbl2.Churn = 'YES' THEN 1 ELSE 0 END),
SUM(CASE WHEN tbl2.Churn = 'NO' THEN 1 ELSE 0 END),
COUNT(*)
FROM tbl2_customers_churn tbl2
WHERE tbl2.PRICE = 'BAD'
Related
I need help How can I merge the column into a single column, here is my code, is this method is correct. I want to get the count of the selected row in the table for the columns.
SELECT
CAT_MGR,
SUM ( case when CAT_MGR = 'A' THEN 1 else 0 end ) AS DESIGN,
sum (case when CAT_MGR = 'b' THEN 1 else 0 END) AS DESIGN,
sum (case when CAT_MGR = 'c' THEN 1 else 0 END) AS DESIGN
from Table_A
GROUP BY
CAT_MGR
Can you guys help me I'm a beginner at SQL.
Thank you in advance
If you want just one row in the resultset, then remove the group by clause. Then, if you want to count the three cat mgr together, you can use in:
select
sum(case when cat_mgr = 'a' then 1 else 0 end ) as design_a,
sum(case when cat_mgr = 'b' then 1 else 0 end ) as design_b,
sum(case when cat_mgr = 'c' then 1 else 0 end ) as design_c,
sum(case when cat_mgr in ('a', 'b', 'c') then 1 else 0 end ) as design
from Table_a
You just need to make addion like below in order to get one column "Design"
SELECT
CAT_MGR,
SUM (case when CAT_MGR = 'A' THEN 1 else 0 end )
+ sum (case when CAT_MGR = 'b' THEN 1 else 0 END)
+ sum (case when CAT_MGR = 'c' THEN 1 else 0 END)
AS DESIGN
from TJD_CORE_CATPB_TB
GROUP BY
CAT_MGR
I am counting in two tables some stuff and want one aggregated result (one row). I write this SQL for this purpose:
SELECT sum (Amount_New) Amount_New,
sum(Import_Dropout) Import_Dropout,
sum(Import)Import,
sum(Processing)Processing,
sum(Processing_Dropout)Processing_Dropout,
sum(Matching)Matching,
sum(Matching_Dropout)Matching_Dropout,
sum(Export)Export,
sum(Exported)Exported,
sum(Rejected)Rejected,
sum(AmountSubTotal)AmountSubTotal,
sum(AmountTotal)AmountTotal
FROM (
SELECT COUNT(CASE WHEN ProcessStatus='_New' THEN 1 ELSE null END) AS Amount_New,
COUNT(CASE WHEN ProcessStatus='Import_Dropout' THEN 1 ELSE null END) AS Import_Dropout,
COUNT(CASE WHEN ProcessStatus='Import' THEN 1 ELSE null END) AS Import,
COUNT(CASE WHEN ProcessStatus='Processing' THEN 1 ELSE null END) AS Processing,
COUNT(*) AS AmountTotal,
0 as Processing_Dropout,
0 as Matching,
0 as Matching_Dropout,
0 as Export,
0 as Export_Dropout,
0 as Exported,
0 as Rejected,
0 as AmountSubTotal,
0 as UnionOrder
FROM "fileimport$marketscanimportcsv"
WHERE ft_boekdat like '%2018%'
UNION
SELECT 0 AS Amount_New,
0 AS Import_Dropout,
0 AS Import,
COUNT(CASE WHEN ProcessStatus='Processing_Dropout' THEN 1 ELSE null END) AS Processing_Dropout,
COUNT(CASE WHEN ProcessStatus='Processing' THEN 1 ELSE null END) AS Processing,
COUNT(CASE WHEN ProcessStatus='Matching' THEN 1 ELSE null END) AS Matching,
COUNT(CASE WHEN ProcessStatus='Matching_Dropout' THEN 1 ELSE null END) AS Matching_Dropout,
COUNT(CASE WHEN ProcessStatus='Export' THEN 1 ELSE null END) AS Export,
COUNT(CASE WHEN ProcessStatus='Export_Dropout' THEN 1 ELSE null END) AS Export_Dropout,
COUNT(CASE WHEN ProcessStatus='Exported' THEN 1 ELSE null END) AS Exported,
COUNT(CASE WHEN ProcessStatus='Rejected' THEN 1 ELSE null END) AS Rejected,
COUNT(CASE WHEN ProcessStatus!= '_New' and ProcessStatus!= 'Import_Dropout' and ProcessStatus!= 'Import' THEN 1 ELSE null END) AS AmountSubTotal,
COUNT(*) AS AmountTotal,
1 as UnionOrder
FROM "matching$marketscanmovement"
WHERE date_part ('year', BookingDate_BA_MS)= 2018
) SK GROUP by unionorder order by unionorder asc
1) The result is 2 rows, which is not one value as total of that column.
Why is this query not summarizing the unioned same column values? How should it be written?
2) When I try sum "(Amount_New1+Amount_New2) Amount_New" (and changing the subquery column names to amount_new1 / amount_new2) it is not working neither. Why?
If you want to return a single row, conceptually representing an aggregate over the entire union table, then remove GROUP BY:
SELECT SUM(Amount_New) Amount_New,
SUM(Import_Dropout) Import_Dropout,
SUM(Import) Import,
SUM(Processing) Processing,
SUM(Processing_Dropout) Processing_Dropout,
SUM(Matching) Matching,
SUM(Matching_Dropout) Matching_Dropout,
SUM(Export) Export,
SUM(Exported) Exported,
SUM(Rejected) Rejected,
SUM(AmountSubTotal) AmountSubTotal,
SUM(AmountTotal) AmountTotal
FROM
(
-- ... your current query
) SK;
You also may want to remove the UnionOrder computed column, since there is no need to sort a single row result set.
I have folllowing select query
SELECT
Table.ID
SUM(CASE WHEN Table.Status = 1 THEN 1 ELSE null END) AS NormalCount,
SUM(CASE WHEN Table.status = 2 THEN 1 ELSE null END) AS AbnormalCount
FROM Table
GROUP BY Table.ID
I want to get above results and generate new result set with following conditions
IF(NormalCount > 0 or AbnormalCount == NULL)
SELECT
Table.ID
Table.Status AS "Normal"
FROM Table
GROUP BY Table.ID
ELSE IF ( AbnormalCount > 0)
SELECT
Table.ID
Table.Status AS "Abnormal"
SUM(CASE WHEN Header.status = 2 THEN 1 ELSE null END) AS AbnormalCount
FROM Table
GROUP BY Table.ID
I think the logic you want is to label each ID group as being abnormal if it has one or more abnormal observation. If so, then you can use another CASE statement to check the conditional abnormal sum and label the status appropriately. Normal groups would have the characteristic of having an abnormal count of zero, but this count would appear for all groups.
SELECT t.ID,
CASE WHEN SUM(CASE WHEN t.status = 2 THEN 1 ELSE 0 END) > 0
THEN "Abnormal"
ELSE "Normal" END AS Status,
SUM(CASE WHEN t.status = 2 THEN 1 ELSE 0 END) AS AbnormalCount
FROM Table t
GROUP BY t.ID
I'm using PostgreSQl and this is my table in database:
how can I write a query that gives me this result :
or you can write query like
select id_salarie,
max(case when date_pointage = '2015-01-01' then round(nb_heures::numeric,2) else null end) as "2015-01-01",
max(case when date_pointage = '2015-01-02' then round(nb_heures::numeric,2) else null end)as "2015-01-02",
max(case when date_pointage = '2015-01-03' then round(nb_heures::numeric,2) else null end) as "2015-01-03"
from my_table where id_salarie = 1
group by id_salarie;
Query looks huge and terrible but works for cubes
I need help to write correct SQL query for my DB tables.
Now I have two simple tables:
Is it possible?
SELECT mainobjectid,name,
MAX(CASE WHEN ColumnNAme='ColumnName1' THEN ColumnContent ELSE 0 END)as ColumnName1,
MAX(CASE WHEN ColumnNAme='ColumnName2' THEN ColumnContent ELSE 0 END)as ColumnName2,
MAX(CASE WHEN ColumnNAme='ColumnName3' THEN ColumnContent ELSE 0 END)as ColumnName3
FROM t1 JOIN t2
ON t1.mainobjectid=t2.mainobjectid
GROUP BY t1.mainobjectid
Should work on most popular databases.