I need help How can I merge the column into a single column, here is my code, is this method is correct. I want to get the count of the selected row in the table for the columns.
SELECT
CAT_MGR,
SUM ( case when CAT_MGR = 'A' THEN 1 else 0 end ) AS DESIGN,
sum (case when CAT_MGR = 'b' THEN 1 else 0 END) AS DESIGN,
sum (case when CAT_MGR = 'c' THEN 1 else 0 END) AS DESIGN
from Table_A
GROUP BY
CAT_MGR
Can you guys help me I'm a beginner at SQL.
Thank you in advance
If you want just one row in the resultset, then remove the group by clause. Then, if you want to count the three cat mgr together, you can use in:
select
sum(case when cat_mgr = 'a' then 1 else 0 end ) as design_a,
sum(case when cat_mgr = 'b' then 1 else 0 end ) as design_b,
sum(case when cat_mgr = 'c' then 1 else 0 end ) as design_c,
sum(case when cat_mgr in ('a', 'b', 'c') then 1 else 0 end ) as design
from Table_a
You just need to make addion like below in order to get one column "Design"
SELECT
CAT_MGR,
SUM (case when CAT_MGR = 'A' THEN 1 else 0 end )
+ sum (case when CAT_MGR = 'b' THEN 1 else 0 END)
+ sum (case when CAT_MGR = 'c' THEN 1 else 0 END)
AS DESIGN
from TJD_CORE_CATPB_TB
GROUP BY
CAT_MGR
Related
I have a table (tbl2) i have 4 columns with feedback attributes listed. I need to generate a pivot table like syntax in mysql. Need output somewhat like this pivot table. I am currently trying this
INSERT INTO 1 (`BAD/GOOD`, `PRICE YES`, `PRICE NO`, `TOTAL PRICE`) SELECT "BAD",COUNT(*) WHERE tbl2.PRICE="BAD" AND tbl2.Churn="YES",COUNT(*) WHERE tbl2.PRICE="BAD" AND tbl2.Churn="NO",COUNT(*) WHERE tbl2.PRICE="BAD" FROM tbl2_customers_churn
and also tried insert into as values
INSERT INTO 1 VALUES ("BAD",COUNT(*) FROM tbl2 WHERE tbl2.PRICE="BAD" AND tbl2.Churn="YES",COUNT(*) FROM tbl2 WHERE tbl2.PRICE="BAD" AND tbl2.Churn="NO",COUNT(*) FROM tbl2 WHERE tbl2.PRICE="BAD")
for bad and good count separately
Any advise on how to tackle this in SQL?
I think you want logic more like this:
INSERT INTO 1 (`BAD/GOOD`, `PRICE YES`, `PRICE NO`, `TOTAL PRICE`)
SELECT 'BAD',
SUM(CASE WHEN tbl2.PRICE = 'BAD' AND tbl2.Churn = 'YES' THEN 1 ELSE 0 END),
SUM(CASE WHEN tbl2.PRICE = 'BAD' AND tbl2.Churn = 'NO' THEN 1 ELSE 0 END),
SUM(CASE WHEN tbl2.PRICE = 'BAD' THEN 1 ELSE 0 END)
FROM tbl2_customers_churn tbl2;
Or a little more simply:
SELECT 'BAD',
SUM(CASE WHEN tbl2.Churn = 'YES' THEN 1 ELSE 0 END),
SUM(CASE WHEN tbl2.Churn = 'NO' THEN 1 ELSE 0 END),
COUNT(*)
FROM tbl2_customers_churn tbl2
WHERE tbl2.PRICE = 'BAD'
I have a column , says name Student_name and its values lets say, A, B, C, D, E, F and so on..
Now i have to convert this column into row with each alias.
select A.counts from (
select count(b.ATTND_FLAG) as counts , b.ATTND_FLAG as ATTND_FLAG
from hr_emp_notifications a, v_emp_attendance b
where a.emp_id=b.emp_id
and a.emp_id=90327
and b.ATTND_FLAG is not null
group by b.ATTND_FLAG )A
my query showing one column which has multiple values in rows.
i have to convert these values into row.
I would use conditional aggregation:
select sum(case when ea.attnd_flag = 'A' then 1 else 0 end) as num_a,
sum(case when ea.attnd_flag = 'B' then 1 else 0 end) as num_b,
sum(case when ea.attnd_flag = 'C' then 1 else 0 end) as num_c,
sum(case when ea.attnd_flag = 'D' then 1 else 0 end) as num_d,
sum(case when ea.attnd_flag = 'E' then 1 else 0 end) as num_e,
sum(case when ea.attnd_flag = 'F' then 1 else 0 end) as num_f
from v_emp_attendance ea
where ea.emp_id = 90327;
If you want multiple employees, use group byea.emp_id`.
Notice that the join is not needed.
It seems you need a pivot clause here -
SELECT *
FROM (SELECT NAME, ATTND_FLAG
FROM v_emp_attendance)
PIVOT (COUNT(ATTND_FLAG)
FOR NAME IN ('A' AS A, 'B' AS B, 'C' AS C /* AND SO ON */)
)
This question already has answers here:
How can I get multiple counts with one SQL query?
(12 answers)
Closed 4 years ago.
I am counting specific things in a SQL Server table. I am using multiple count queries, but I am wondering if it's possible to combine them into a single query with the column name and count numbers in a single table for display.
My queries are:
select count(*) as Ask_Count
from Pld_OpenSalesOrdersLines
where left(C_Item_ID, 1) = '*'
select count(*) as M_Count
from Pld_OpenSalesOrdersLines
where (left(C_Item_ID, 1) = 'M' and len(C_Item_ID) = 1)
select count(*) as MN_Count
from Pld_OpenSalesOrdersLines
where (left(C_Item_ID, 2) = 'MN' and len(C_Item_ID) = 2)
I tried a couple stupid things to combine them, but they were a failure. I honestly can't even begin to think how to combine them, maybe it's not possible?
Thanks!
You could use CASE expression to perform conditional aggregation:
select
COUNT(CASE WHEN LEFT(C_Item_ID,1)='*' THEN 1 END) AS Ask_Count,
COUNT(CASE WHEN LEFT(C_Item_ID,1)='M' AND LEN(C_Item_ID)=1 THEN 1 END) M_Count,
COUNT(CASE WHEN LEFT(C_Item_ID,2)='MN' AND LEN(C_Item_ID)=2 THEN 1 END) MN_Count
from Pld_OpenSalesOrdersLines
Use conditional aggregation:
select sum(case when LEFT(C_Item_ID,1) = '*' then 1 else 0 end) as count_1,
sum(case when LEFT(C_Item_ID,1) = 'M' AND LEN(C_Item_ID)=1 then 1 else 0 end) as count_2,
sum(case when LEFT(C_Item_ID,2) = 'MN' AND LEN(C_Item_ID)=2 then 1 else 0 end) as count_3
from Pld_OpenSalesOrdersLines;
I would write the logic like this, though:
select sum(case when C_Item_ID like '*%' then 1 else 0 end) as count_1,
sum(case when C_Item_ID = 'M' then 1 else 0 end) as count_2,
sum(case when C_Item_ID = 'MN' then 1 else 0 end) as count_3
from Pld_OpenSalesOrdersLines;
Doing a left() on a column and then checking the length is redundant. Just use =.
I usually use sum(case) to get sum of some columns:
i.e. SUM(CASE WHEN over05 = 'OK' THEN 1 ELSE 0 END) AS OK_05
and this is perfect when I have a column with two values, but when I have a column where I have three values:
i.e. over 05 = '1' or 'X' or '2'
how can I do a sum(case)?
If you want all three values to return the same thing, you should use IN():
SUM(
CASE
WHEN over05 IN ('1', 'X', '2') THEN 1
ELSE 0 END
) AS OK_05
If you want each value to return something different, you should use multiple WHEN ... THEN :
SUM(
CASE
WHEN over05 = '1' THEN 1
WHEN over05 = 'X' THEN 2
WHEN over05 = '2' THEN 3
ELSE 0 END
) AS OK_05
how i can result like this ?
in my mind i can query = >
select id, count(no1, no2, no3) where no1='B',no2='B',no3='B'
thank's very much.
Use Case Statement
select id,
case when no1='B' then 1 else 0 END +
case when no2='B' then 1 else 0 END +
case when no3='B' then 1 else 0 END As Count_All
From yourtable
Use Case When statements with Count aggregate. Lastly, Group them with id:
Select id,
count(case when no1='B' then 1 END) +
count(case when no2='B' then 1 END) +
count(case when no3='B' then 1 END) AS count_all
From yourtable
Group by id