Replacing a string pattern - SQL Server - sql

Question

I have a VARCHAR Column called CompanyInformation that contains some Json data inside of it, here is a example of what is being stored inside of this column.
{
"tradeName": "example",
"corporateName": "example",
"phone": "example",
"nationalExpansions": [
{
"id": 0,
"nameFranchise": "example",
"phoneNumber": "example",
"mobileNumber": "example",
"email": "example#example.com.br"
},
{
"id": 0,
"nameFranchise": "example",
"phoneNumber": "example",
"mobileNumber": "example",
"email": "example"
},
What i have to do is replace all emails inside of this file to one specific email, i was trying to use the REPLACE function to do that, but i don`t know exactly how to do pattern matching in SQL.
UPDATE MyExampleTable SET CompanyInformation = REPLACE(CONVERT(VARCHAR(MAX), CompanyInformation), '"email": "%%"', '"email": "tests#gmail.com.br"')
But it doesn't work, the UPDATE gets executed, but he never replace the email information because he doesn't find any matching pattern.

Answer 1

After some research and thanks to the help of a teammate, we've managed to find a solution to this problem, so i will post here to help anyone with the same problem.
This is the script:
DECLARE #text VARCHAR(max)
DECLARE #start INT = 0
DECLARE #begin INT = 0
DECLARE #end INT = 0
DECLARE #Id INT
DECLARE curEmail CURSOR
FOR
SELECT Id, CompanyInformation
FROM MyExampleTable
--WHERE id = 1
OPEN curEmail
FETCH NEXT FROM curEmail INTO #Id, #text
WHILE ##FETCH_STATUS = 0
BEGIN
SELECT #start = CHARINDEX('"email":"', #text) + 9;
SET #begin = #start
WHILE 1 = 1
BEGIN
--print 'end='+cast(#end as varchar(4))
SELECT #start = CHARINDEX('"email":"', #text, #end) + 9;
IF #begin <= #start
SET #begin = #start
ELSE
BREAK
SELECT #end = CHARINDEX('"', #text, #start)
SET #text = STUFF(#text, #start, #end - #start, 'tests#gmail.com.br')
END
print #text
update MyExampleTable set CompanyInformation= #text where id =#id
FETCH NEXT FROM curEmail INTO #Id, #text
END
CLOSE curEmail
DEALLOCATE curEmail