Comparing two nvarchar in a function - sql

Question

In a function I want to check whether passed value is equal to a predefined value (#ValX)
I have wrote following function:
ALTER Function IsNotInReview(#Val NVARCHAR(MAX))
RETURNS BIT
AS
BEGIN
DECLARE #ValX NVARCHAR(MAX)
SET #ValX = '
{
"httpCode" : 200,
"message" : "OK",
"result" : {
"items" : {
"items" : [ ]
}
}
}
'
IF LTRIM(RTRIM(#Val)) = LTRIM(RTRIM(#ValX))
BEGIN
RETURN 1
END
ELSE
BEGIN
RETURN 0
END
RETURN 0
END
When I test call the function, I am always getting false value
SELECT dbo.IsNotInReview('
{
"httpCode" : 200,
"message" : "OK",
"result" : {
"items" : {
"items" : [ ]
}
}
}
')--should return true
SELECT dbo.IsNotInReview('test')
UPDATE
I have updated my SP but still getting the same 'false' return value
ALTER Function IsNotInReview(#Val NVARCHAR(MAX))
RETURNS BIT
AS
BEGIN
DECLARE #ValX NVARCHAR(MAX)
SET #ValX = '
{
"httpCode" : 200,
"message" : "OK",
"result" : {
"items" : {
"items" : [ ]
}
}
}
'
DECLARE #ReturnVal BIT
IF LTRIM(RTRIM(#Val)) = LTRIM(RTRIM(#ValX))
BEGIN
SET #ReturnVal = 1
END
ELSE
BEGIN
SET #ReturnVal = 0
END
RETURN #ReturnVal
END
SELECT dbo.IsNotInReview('{
"httpCode" : 200,
"message" : "OK",
"result" : {
"items" : {
"items" : [ ]
}
}
}') --Return false which is unexpected

Answer 1

You are not comparing identical strings. Look at the indentation. I cannot imagine that this is what your intention is, i.e. comparing not only relevant content but also indentation.
A possible solution is to remove all white spaces, line breaks etc. in the string, while skipping over sections enclosed in double quotes.
Edit: Here is a little function which might be useful for you. It removes white spaces from your string while skipping quoted regions. Please test thoroughly, I only wrote it and testet it a bit (I have to go to work now)
create function RemoveWhiteSpaces (#String nvarchar(max))
returns nvarchar(max)
as
begin
declare #result nvarchar(max), #i int, #n int, #inQuotes bit,
declar #c0 nchar(1), #c nchar(1)
set #i=1
set #n=len(#string)
set #result=''
set #inQuotes=0
set #c='x'
while #i <= #n begin
set #c0=#c
set #c=substring(#string,#i,1)
if #c='"' and #c0 != '\'
set #inQuotes= 1 - #inQuotes
if #inQuotes = 1 or
(#inQuotes = 0 and #c not in (' ',char(13), char(10),char(8)))
set #result = #result + #c
set #i=#i+1
end
return #result
end