If we have query for creating table like this..
create table if not exists food
(
id int not null auto_increment,
user_id int,
name varchar(30),
constraint pk_food primary key(id,name),
foreign key(user_id) references userss(id)
);
What does pk_food mean in this example? I know this is a constraint name, but for what we should be give a name for constraint, if its working without?
create table if not exists food
(
id int not null auto_increment,
user_id int,
name varchar(30),
primary key (id, name),
foreign key (user_id) references userss(id)
);
I mean.. how to use these names and for what we need it?
You gives constraints names for basically two reasons:
You can better understand the error message when the constraint is violated.
You can more easily find the constraint if you want to delete it.
Related
I have a question about foreign keys.
How does it work when I want to add a foreign key to the first table that I make that references to the primary key of the second table I create?
CREATE TABLE table1
(
name_id INT NOT NULL,
team TEXT REFERENCES table2(team_id),
PRIMARY KEY(name_id)
);
CREATE TABLE table2
(
team_id INT NOT NULL,
teamname TEXT,
PRIMARY KEY(team_id)
);
If I try the code above I get the following error:
ERROR: relation "" does not exist
Thanks in advance.
Either create the second table first. Or use alter table. That is, create the first table without the reference and then do:
alter table table1 add constraint fk_table1_team
foreign key (team_id) REFERENCES table2(team_id);
The declaration for table1 would be:
CREATE TABLE table1 (
name_id INT NOT NULL,
team_id INT,
PRIMARY KEY(name_id)
);
The reference between the tables should be on the primary key and certainly not on a character column, if an integer is available.
here's the syntax of creating a table with Foreign key:
CREATE TABLE table11
(
name_id INT NOT NULL,
team INT,
PRIMARY KEY(name_id),
foreign key(team) references table22(team_id)
);
CREATE TABLE table22
(
team_id INT NOT NULL,
teamname TEXT,
PRIMARY KEY(team_id)
);
but there was another problem. a foreign key from a child table cannot reference to a primary key from a parent folder if they do not contain the same type. in your code team was of TEXT and team_id was of INT which cannot be.
I am new in SQL and trying to understand Foreign key syntax. I know this was asked in multiple questions but each question I found did not seem to teach me what I am doing wrong here.
This is my SQL code:
CREATE TABLE Customer
(
id int primary key,
name varchar(30),
age int,
gender bool
);
CREATE TABLE Minor
(
FOREIGN KEY (parent_id) REFERENCES Customer(id)
);
CREATE TABLE Adult
(
FOREIGN KEY (parent_id) REFERENCES Customer(id)
);
CREATE TABLE Shop
(
id int primary key
);
CREATE TABLE Drink
(
name varchar(30) primary key
);
CREATE TABLE AlcoholicDrink
(
FOREIGN KEY (name) REFERENCES Drink(name)
);
CREATE TABLE NonAlcoholicDrink
(
FOREIGN KEY (name) REFERENCES Drink(name)
);
And this is the error I am getting:
ERROR: column "parent_id" referenced in foreign key constraint does not exist
SQL state: 42703
You need to add fields in your tables to make the reference. Something like this :
CREATE TABLE Customer
(
id int primary key,
name varchar(30),
age int,
gender bool
);
CREATE TABLE Minor
(
minor_id serial primary key,
parent_id int,
other_fields text etc.
FOREIGN KEY (parent_id) REFERENCES Customer(id)
);
This is simply the reason why it's not working.
Like this
CREATE TABLE Customer
(
id int primary key,
name varchar(30),
age int,
gender bool
);
CREATE TABLE Minor
(
parent_id int ,
FOREIGN KEY (parent_id) REFERENCES Customer(id)
);
To add an answer without just a code snippet:
You've got the right idea with FOREIGN KEY (parent_id) REFERENCES Customer(id). This bit adds a constraint or a "rule" to your table. This constraint ensures that parent_id holds a real id in your Customer table.
The error message told us that column "parent_id" referenced in foreign key constraint does not exist. The confusion comes, understandably, from mistaking the constraint declaration for a column declaration.
As others have pointed out, we need to both 10 declare the foreign key constraint and 2) declare the column.
CREATE TABLE Customer
(
id int primary key,
name varchar(30),
age int,
gender bool
);
CREATE TABLE Minor
(
parent_id int, -- Declare the column
FOREIGN KEY (parent_id) REFERENCES Customer(id) -- Declare the constraint
);
I have created PERSON table in Oracle by this SQL syntax:
Create table person
(
p_id int not null,
personName char(5) not null );
Then I am trying to create ORDERS table with the following syntax:
CREATE TABLE Orders
(
O_Id int NOT NULL,
OrderNo int NOT NULL,
P_Id int,
PRIMARY KEY (O_Id),
CONSTRAINT fk_PerOrders FOREIGN KEY (P_Id)
REFERENCES person(p_id) );
But I am getting the following error .
No matching unique or primary key for this column-list.
What is the problem ? How can I solve this ?
Add primary key to person table:
CREATE TABLE person(
p_id int not null,
personName char(5) not null,
PRIMARY KEY (p_ID)
);
SqlFiddleDemo
Foreign keys enforce a one-to-many relationship. That is, however many records there are in the dependent table they can only reference a single record in the parent table. This means the referenced column(s) in the parent table must be constrained by a PRIMARY or UNIQUE key.
The error message is telling you that there is no such constraint on person(p_id). And lo! if we compare the two DDL statements you have posted we can see that you have created a primary key for ORDERS but not for PERSON.
The solution is simple: constrain P_ID by adding a primary key to PERSON. You can either drop and re-create the table, or you can use an alter table statement to add a primary key.
You should add primary key to person table.
try this:
ALTER TABLE Person
ADD CONSTRAINT p_id PRIMARY KEY (p_id);
I have a problem with something in SQL, let's see an example of database :
CREATE TABLE person( //Employee
pe_id PRIMARY KEY NOT NULL AUTO_INCREMENT,
pe_name VARCHAR(20),
pe_office VARCHAR(20)
);
CREATE TABLE project( //Mission
pr_id PRIMARY KEY NOT NULL AUTO_INCREMENT,
pr_name VARCHAR(20),
pr_status VARCHAR(15)
);
CREATE TABLE techno( //Programming language
te_id PRIMARY KEY NOT NULL AUTO_INCREMENT,
te_name VARCHAR(20)
);
CREATE TABLE job( //developer, manager, ...
jo_id PRIMARY KEY NOT NULL AUTO_INCREMENT,
jo_name VARCHAR(20)
);
I would like to assign persons on projects for a job using technos.
For example, Rob works as a developer and project manager on the projet #13 with AngularJS and HTML.
So I created this table :
CREATE TABLE assignment(
pe_id INT,
pr_id INT,
te_id INT,
jo_id INT,
as_days INT, //Days of work
PRIMARY KEY(pe_id, pr_id, tr_id, jo_id),
CONSTRAINT fk_as_pe_id FOREIGN KEY(pe_id) REFERENCES person(pe_id),
CONSTRAINT fk_as_pr_id FOREIGN KEY(pr_id) REFERENCES project(pr_id),
CONSTRAINT fk_as_te_id FOREIGN KEY(te_id) REFERENCES techno(te_id),
CONSTRAINT fk_as_jo_id FOREIGN KEY(jo_id) REFERENCES job(jo_id)
);
I would like to have the ability to assign a developer with somes technos to a project without knowing who exaclty, like this:
INSERT INTO assignment(pr_id,te_id,jo_id,as_days) VALUES(1,2,3,4); //No person!
We suppose that this values exists in project, techno and job tables.
But it seems that I can not insert this, probably because I do not define person's ID (which is in the primary key).
How can I do this ?
Hope I'm understandable :)
You solve this problem by not having this as a primary key. Primary keys cannot be NULL or, if they're composite primary keys, cannot contain NULL. Make it a unique index instead. Create an autonumber field for the primary key. I think this is better solution in your case
Primary Key:
Can be only one in a table
It never allows null values
Primary Key is unique key identifier and can not be null and must be unique.
Unique Key:
Can be more than one unique key in one table.
Unique key can have null values(only single null is allowed).
It can be a candidate key
Unique key can be null and may not be unique.
Maybe you should do this:
Before insert disable constraint:
ALTER INDEX fk_as_pe_id ON assignment
DISABLE;
After insert enable it:
ALTER INDEX fk_as_pe_id ON assignment
REBUILD;
Another alternate way is, if it is possible to alter table structure, just exclude pe_id from the composite primary key in assignment table
I'm not sure why these have to be unique, but from reading the MySQL forums it appears that they do. However, I think it has something more to do with the INDEX name. I have two tables that have foreign key constraints referencing the same primary key on a third table. If it helps, I'm using MySQL workbench to design the schema.
I usually name my foreign key on each table the same name as the primary key it references. I guess this isn't possible. It will create the first table with the foreign key constraint, but when it tries to create the second table it throws an error. Here is the second table it throws the error on:
CREATE TABLE IF NOT EXISTS `joe`.`products_to_categories` (
`product_to_category_id` INT NOT NULL AUTO_INCREMENT ,
`category_id` INT NOT NULL ,
`product_id` INT NOT NULL ,
PRIMARY KEY (`product_to_category_id`) ,
INDEX `category_id` (`category_id` ASC) ,
INDEX `product_id` (`product_id` ASC) ,
CONSTRAINT `category_id`
FOREIGN KEY (`category_id` )
REFERENCES `joe`.`categories` (`category_id` )
ON DELETE CASCADE
ON UPDATE NO ACTION,
CONSTRAINT `product_id`
FOREIGN KEY (`product_id` )
REFERENCES `joe`.`products` (`product_id` )
ON DELETE CASCADE
ON UPDATE NO ACTION)
ENGINE = InnoDB;
I want the foreign key names to be the same as the primary key in both of the other tables. What should I remove here so that I can use these names. What is the best practice here.
It is not possible because you would have a conflict in the filename for the file that is used for the index IIRC. I probably would name the key < tablename >_< column_name > or something like that.
You are creating an index (constraint) by the name of product_id via:
INDEX product_id
Then you are going and creating another constraint (for the foreign key) with the same name:
CONSTRAINT product_id
What you need to do is allow the server to provide a default, unique constraint name by removing the
CONSTRAINT product_id
See this URL: http://dev.mysql.com/doc/refman/5.1/en/innodb-foreign-key-constraints.html
"If the CONSTRAINT symbol clause is given, the symbol value must be unique in the database. If the clause is not given, InnoDB creates the name automatically."
In PostgreSQL, the default for naming indexes is to append "_pkey" and "_fkey" to the name of the primary and foreign key, respectively. So your case would look like:
INDEX `product_id_fkey` (`product_id` ASC) ,
UPDATE: I just tried this and it worked. See if that's what you had in mind.
use test;
create table if not exists test.product
(
product_id int not null auto_increment,
name varchar(80) not null,
primary key(product_id)
);
create table if not exists test.category
(
category_id int not null auto_increment,
name varchar(80) not null,
primary key(category_id)
);
create table if not exists test.product_category
(
product_id int,
category_id int,
primary key(product_id, category_id),
constraint product_id_fkey
foreign key(product_id) references product(product_id)
on delete cascade
on update no action,
constraint category_id_fkey
foreign key(category_id) references category(category_id)
on delete cascade
on update no action
);
insert into test.product(name) values('teddy bear');
insert into test.category(name) values('toy');
insert into test.product_category
select p.product_id, c.category_id from product as p, category as c
where p.name = 'teddy bear' and c.name = 'toy';