I have two tables i'm working with:
comporder(quantity,cod(Fk on cod(product),cod_ship);
product(cod(Pk),price);
I need to produce a query that will give me the sum of the prices of the products that are in the comporder table for each cod_ship;
I came up with this query:
SELECT sum(p.price),c.cod_ship
FROM product as p JOIN comporder as c
ON(p.cod=c.cod)
GROUP BY c.cod_ship;
However I am not allowed to use the GROUP BY function and I can't seem to have the price where the quanity is above one.
For exampe if in my comporder table I have:
quantity cod cod_ship
2 "1234567890" 27
3 "1234567890" 28
2 "7894561230" 28
1 "5678324515" 28
4 "1234567890" 27
1 "1234567890" 27
And if in my product table I have:
cod price
"1234567890" 20.00
"7894561230" 19.99
"5678324515" 25.99
If I apply my query the result will be:
sum cod_ship
60 27
65.979 28
When te actual result should be, based on the quantity of the products in the table comporder:
sum // cod_ship//
140 // 27//
125,97 //28//
So I can't seem to figure out how to get the sum also based on the quantity of the product and witouth the GROUP BY function, I should just show the sum as "output", can somebody help me out understand how can I do it?
REPLYING TO COMMENTS:
I cannot use group by due to an assignment.
I am using PostgreSQL 12.1
As requested by the OP in the comments here is a solution using GROUP BY:
SELECT SUM(price * quantity) as sum, cod_ship FROM comporders
INNER JOIN products ON products.cod = comporders.cod
GROUP BY cod_ship;
Edit:
Here is the solution without GROUP BY:
SELECT DISTINCT
(
SELECT SUM(price * quantity)
FROM products
INNER JOIN comporders ON products.cod = comporders.cod
WHERE cod_ship = results.cod_ship
) AS sum,
cod_ship
FROM comporders AS results;
It works by first selecting a unique list of cod_ship ids (what we previously grouped the query by).
Then we execute a subquery using the cod_ship id to calculate the sum for each column. We use the table alias results in order to reference the values in the parent query of the subquery.
SQL Fiddle Link
You can do aggregation in subselect like this:
SELECT (
SELECT SUM(p.price)
FROM product AS p
WHERE p.cod = c.cod
) AS price, c.cod_ship
FROM comporder AS c
Related
I have two tables which name shoes_type and shoes_list. The shoes_type table includes shoes_id, shoes_size, shoes_type, date, project_id. Meanwhile, on the shoes_list table, I have shoes_quantity, shoes_id, shoes_color, date, project_id.
I need to get the sum of shoes_quantity based on the shoes_type, shoes_size, date, and also project_id.
I get how to sum the shoes_quantity based on color by doing:
select shoes_color, sum(shoes_quantity)
from shoes_list group by shoes_color
Basically what I want to see is the total quantity of shoes based on the type, size, date and project_id. The type and size information are available on shoes_type table, while the quantity is coming from the shoes_list table. I expect to see something like:
shoes_type shoes_size total quantity date project_id
heels 5 3 19/10/02 1
sneakers 5 3 19/10/02 1
sneakers 6 1 19/10/05 1
heels 7 5 19/10/03 1
While for the desired result, I have tried:
select shoes_type, shoes_size, date, project_id, sum(shoes_quantity)
from shoes_type st
join shoes_list sl
on st.project_id = sl.project_id
and st.shoes_id = sl.shoes_id
and st.date = sl.date
group by shoes_type, shoes_size, date, project_id
Unfortunately, I got an error that says that the column reference "date" is ambiguous.
How should I fix this?
Thank you.
The date column exists in both tables, so you have to specify where to select it from. Replace date with shoes_type.date or shoes_list.date
Qualify all column references to remove the "ambiguous" column error:
select st.shoes_type, st.shoes_size, st.date, st.project_id, sum(slshoes_quantity)
from shoes_type st join
shoes_list sl
on st.project_id = sl.project_id and
st.shoes_id = sl.shoes_id and
st.date = sl.date
group by st.shoes_type, st.shoes_size, st.date, st.project_id;
If you want all columns from shoes_type, you might find that a correlated subquery is faster:
select st.*,
(select sum(slshoes_quantity)
from shoes_list sl
where st.project_id = sl.project_id and
st.shoes_id = sl.shoes_id and
st.date = sl.date
)
from shoes_type st;
I have the following table structure for the table "products":
id amount number
1 10 M6545
2 32 M6424
3 32 M6545
4 49 M6412
... ... ...
I want to select the sum of amounts of all rows with the same number. The rows with the same number should be summed up to one sum. That means:
M6545 -> Sum 42
M6424 -> Sum 32
M6421 -> Sum 49
My query looks like the following and still does not work:
SELECT SUM(amount) as SumAm FROM products WHERE number IN ('M6412', 'M6545')
I want to find a way where I can only select the sum ordered by the numbers in the "IN" statement. That means, the result table should look like:
SumAm
49
42
The sums should not be ordered in some way. It should match the order of numbers in the IN clause.
use group by number
SELECT number, SUM(amount) as SumAm FROM products
--WHERE number IN ('M6412', 'M6545') i think you dont need where clause
group by number
But if you want just for 'M6412', 'M6545' then you need where clause that you showed in your 2nd output sample
Use group by and aggregation
SELECT SUM(amount) as SumAm FROM products
WHERE number IN ('M6412', 'M6545')
group by number
You can't order by results based directly on the order of the IN clause.
What you can do is something like this:
SELECT SUM(amount) as SumAm
FROM products
WHERE number IN ('M6412', 'M6545')
GROUP BY number -- You must group by to get a row for each number
ORDER BY CASE number
WHEN 'M6412' THEN 1
WHEN 'M6545' THEN 2
END
Of course, the more items you have in your IN clause the more cumbersome this query will get. Therefor another solution might be more practical - joining to a table variable instead of using IN:
DECLARE #Numbers AS TABLE
(
sort int identity(1,1), -- this will hold the order of the inserted values
number varchar(10) PRIMARY KEY -- enforce unique values
);
INSERT INTO #Numbers (number) VALUES
('M6412'),
('M6545')
SELECT SUM(amount) as SumAm
FROM products As p
JOIN numbers As n ON p.Number = n.Number
-- number and sort have a 1 - 1 relationship,
-- so it's safe to group by it instead of by number
GROUP BY n.sort
ORDER BY n.sort
Your requirement is non-sense... this is not how IN is designed to work. Having said that, the following will give you the result in the desired order:
SELECT SUM(amount)
FROM (VALUES
('M6545', 1),
('M6412', 2)
) AS va(number, sortorder)
INNER JOIN sumam ON va.number = sumam.number
GROUP BY va.number, va.sortorder
ORDER BY va.sortorder
It is somewhat better than writing a CASE statement when you would need to add a WHEN condition for each number.
I have a select statement that divides the count of sales by country, priceBanding (see example below)
The select statement looks like follows:
SELECT p.[Price Band]
,t.[Country]
,o.COUNT([Order]) as [Order Count]
FROM #price p (temp table)
INNER JOIN country t ON p.CountryCode = t.countryCode
INNER JOIN sales o ON o.salesValue >= p.startPrice and s.salesValue < p.endPrice
What i want to be able to do is based on this result i want to get an avg of the unit count i.e. For all orders that are under 20 what is the avg unit counts and the same for all others. How can i do this?
Its most likely simple but I cant think through it.
What I am after:
So as you can see, in the price band <20 in UK the order count is 50, and the avg Units of that is 2. As i mentioned earlier, I want the Avg Units of all orders that are under 20 (which is 50 in the picture).
Is that clearer?
Thanks in advance.
EDIT:
The first table: assume it to be the source
And the second table gets the avg, that's what I am after.
Wouldn't you just use avg()?
SELECT p.[Price Band], t.[Country],
o.COUNT(*) as [Order Count],
AVG(Items)
FROM #price p INNER JOIN
country t
ON p.CountryCode = t.countryCode INNER JOIN
sales o
ON o.salesValue >= p.startPrice and s.salesValue < p.endPrice
GROUP BY p.[Price Band], t.[Country]
ORDER BY t.[Country], p.[Price Band]
Note: SQL Server does integer division of integers (so 3/2 = 1 not 1.5) and similarly for AVG(). It is more accurate to use a decimal point number. An easy way is to use AVG(items * 1.0).
I have a resturant db and I need to total up the total value of all the items sold individually. So if I sold a hamburger that has a base price of $10.00 with bacon which costs $1.00 and a hambuger(again $10.00) with avacado that costs $0.50 I need to get $21.50 returned. My invoice table looks like this:
invoice_num item_num price item_id parent_item_id
111 hmbg 10.00 guid_1 ''
111 bacn 1.00 guid_2 guid_2
112 hmbg 10.00 guid_3 ''
112 avcd 0.50 guid_4 guid_3
I can get the sum of all the parent items like this:
SELECT item_num, SUM(price) FROM invoices WHERE parent_item_id = ''
it is the adding of the toppings that is confusing me. I feel like I need to add a subquery in the SUM but I'm not sure how to go about doing it and referencing the original query to use the item_id.
SELECT item_num, sum(i.price) + sum(nvl(x.ingred_price,0))
FROM invoices i
LEFT OUTER JOIN
(SELECT parent_item_id
, sum(price) ingred_price
FROM invoices
WHERE parent_item_id IS NOT NULL
GROUP BY parent_item_id) x
ON x.parent_item_id = i.item_id
WHERE i.parent_item_id IS NULL
GROUP BY item_num
Here's a SQL Fiddle that proves the above code works. I used Oracle, but you should be able to adapt it to whatever DB you are using.
Assumption: You don't have more than one level in a parent child relationship. E.g. A can have a child B, but B won't have any other children.
Not clear based on your question (see my comment) but as I understand it a simple group by will give you what you want. If not please explain (in the original question) why does this query does not work --- what is it missing from your requirements?
SELECT item_num, SUM(price)
FROM invoices
GROUP BY item_num
Hard to say, but looks like you need recursive cte.
Here's example for PostgreSQL:
with recursive cte as (
select
t.invoice_num, t.price, t.item_id, t.item_num
from Table1 as t
where t.parent_item_id is null
union all
select
t.invoice_num, t.price, t.item_id, c.item_num
from Table1 as t
inner join cte as c on c.item_id = t.parent_item_id
)
select invoice_num, item_num, sum(price)
from cte
group by invoice_num, item_num
sql fiddle demo
I've used null for empty parent_item_id (it's better solution than using empty strings), but you can change this to ''.
I would like to get the following data (and more) into a single view.
SELECT Price FROM dbo.OrderItems WHERE OrderItemTypeId = 0
And
SELECT SUM (Price) AS ShippingTotal FROM dbo.OrderItems WHERE OrderItemTypeId = 1
I can’t seem to figure out how to do this with my weak SQL skills. Anybody know how I could do this?
You can use UNION statement:
SELECT Price FROM dbo.OrderItems WHERE OrderItemTypeId = 0
UNION
SELECT SUM (Price) AS ShippingTotal FROM dbo.OrderItems WHERE OrderItemTypeId = 1
But what is the semantic behind this ... In the first statement you have only one row with id = 0, in the second an aggregate function grouped by the same column (which suppose that there are more than one record with id=1). It will be helpful to show us the sample data for you table.
To improve your skills about UNION, see here: http://www.w3schools.com/sql/sql_union.asp
To cover all OrderItemTypeId...
SELECT OrderItemTypeId, SUM(Price) AS ShippingTotal
FROM dbo.OrderItems
GROUP BY OrderItemTypeId
One way would be like this:
SELECT Price, 0 AS OrderItemTypeId FROM dbo.OrderItems WHERE OrderItemTypeId = 0
UNION ALL
SELECT SUM(Price) AS Price, 1 AS OrderItemTypeId FROM dbo.OrderItems
WHERE OrderItemTypeId = 1
The 2nd column I've added to the results allows you to determine the different rows.