I have two tables which name shoes_type and shoes_list. The shoes_type table includes shoes_id, shoes_size, shoes_type, date, project_id. Meanwhile, on the shoes_list table, I have shoes_quantity, shoes_id, shoes_color, date, project_id.
I need to get the sum of shoes_quantity based on the shoes_type, shoes_size, date, and also project_id.
I get how to sum the shoes_quantity based on color by doing:
select shoes_color, sum(shoes_quantity)
from shoes_list group by shoes_color
Basically what I want to see is the total quantity of shoes based on the type, size, date and project_id. The type and size information are available on shoes_type table, while the quantity is coming from the shoes_list table. I expect to see something like:
shoes_type shoes_size total quantity date project_id
heels 5 3 19/10/02 1
sneakers 5 3 19/10/02 1
sneakers 6 1 19/10/05 1
heels 7 5 19/10/03 1
While for the desired result, I have tried:
select shoes_type, shoes_size, date, project_id, sum(shoes_quantity)
from shoes_type st
join shoes_list sl
on st.project_id = sl.project_id
and st.shoes_id = sl.shoes_id
and st.date = sl.date
group by shoes_type, shoes_size, date, project_id
Unfortunately, I got an error that says that the column reference "date" is ambiguous.
How should I fix this?
Thank you.
The date column exists in both tables, so you have to specify where to select it from. Replace date with shoes_type.date or shoes_list.date
Qualify all column references to remove the "ambiguous" column error:
select st.shoes_type, st.shoes_size, st.date, st.project_id, sum(slshoes_quantity)
from shoes_type st join
shoes_list sl
on st.project_id = sl.project_id and
st.shoes_id = sl.shoes_id and
st.date = sl.date
group by st.shoes_type, st.shoes_size, st.date, st.project_id;
If you want all columns from shoes_type, you might find that a correlated subquery is faster:
select st.*,
(select sum(slshoes_quantity)
from shoes_list sl
where st.project_id = sl.project_id and
st.shoes_id = sl.shoes_id and
st.date = sl.date
)
from shoes_type st;
Related
I have run into an issue I don't know how to solve. I'm working with a MS Access DB.
I have this data:
I want to write a SELECT statement, that gives the following result:
For each combination of Project and Invoice, I want to return the record containing the maximum date, conditional on all records for that combination of Project and Invoice being Signed (i.e. Signed or Date column not empty).
In my head, first I would sort the irrelevant records out, and then return the max date for the remaining records. I'm stuck on the first part.
Could anyone point me in the right direction?
Thanks,
Hulu
Start with an initial query which fetches the combinations of Project, Invoice, Date from the rows you want returned by your final query.
SELECT
y0.Project,
y0.Invoice,
Max(y0.Date) AS MaxOfDate
FROM YourTable AS y0
GROUP BY y0.Project, y0.Invoice
HAVING Sum(IIf(y0.Signed Is Null,1,0))=0;
The HAVING clause discards any Project/Invoice groups which include a row with a Null in the Signed column.
If you save that query as qryTargetRows, you can then join it back to your original table to select the matching rows.
SELECT
y1.Project,
y1.Invoice,
y1.Desc,
y1.Value,
y1.Signed,
y1.Date
FROM
YourTable AS y1
INNER JOIN qryTargetRows AS sub
ON (y1.Project = sub.Project)
AND (y1.Invoice = sub.Invoice)
AND (y1.Date = sub.MaxOfDate);
Or you can do it without the saved query by directly including its SQL as a subquery.
SELECT
y1.Project,
y1.Invoice,
y1.Desc,
y1.Value,
y1.Signed,
y1.Date
FROM
YourTable AS y1
INNER JOIN
(
SELECT y0.Project, y0.Invoice, Max(y0.Date) AS MaxOfDate
FROM YourTable AS y0
GROUP BY y0.Project, y0.Invoice
HAVING Sum(IIf(y0.Signed Is Null,1,0))=0
) AS sub
ON (y1.Project = sub.Project)
AND (y1.Invoice = sub.Invoice)
AND (y1.Date = sub.MaxOfDate);
Write A SQL query, which should be possible in MS-Access too, like this:
SELECT
Project,
Invoice,
MIN([Desc]) Descriptions,
SUM(Value) Value,
MIN(Signed) Signed,
MAX([Date]) "Date"
FROM data
WHERE Signed<>'' AND [Date]<>''
GROUP BY
Project,
Invoice
output:
Project
Invoice
Descriptions
Value
Signed
Date
A
1
Ball
100
J.D.
2022-09-20
B
1
Sofa
300
J.D.
2022-09-22
B
2
Desk
100
J.D.
2022-09-23
Note: for invoice 1 on project A, you will see a value of 300, which is the total for that invoice (when grouping on Project='A' and Invoice=1).
Maybe I should have used DCONCAT (see: Concatenation in between records in Access Query ) for the Description, to include 'TV' in it. But I am unable to test that so I am only referring to this answer.
Try joining a second query:
Select *
From YourTable As T
Inner Join
(Select Project, Invoice, Max([Date]) As MaxDate
From YourTable
Group By Project, Invoice) As S
On T.Project = S.Project And T.Invoice = S.Invoice And T.Date = S.MaxDate
I´m having issues with the following query. I have two tables; Table Orderheader and table Bought. The first query I execute gives me, for example, two dates. Based on these two dates, I need to find Production data AND, based on the production data, I need to find the Bought data, and combine those data together. Lets say I do the following:
Select Lotdate From Orderheader where orhsysid = 1
This results in two rows: '2019-02-05' and '2019-02-04'. Now I need to do two things: I need two run two queries using this result set. The first one is easy; use the dates returned and get a sum of column A like this:
Select date, SUM(Amount) from Orderheader where date = Sales.date() [use the two dates here]
The second one is slighty more complicated, I need to find the last day where something has been bought based on the two dates. Production is everyday so Productiondate=Sales.date()-1. But Bought is derived from Productionday and is not everyday so for every Productionday it needs to find the last Boughtday. So I can't say where date = Orderheader.date. I need to do something like:
Select date, SUM(Amount)
FROM Bought
WHERE date = (
SELECT top 1 date
FROM Bought
WHERE date < Orderheader.date)
But twice, for both the dates I got.
This needs to result in 1 table giving me:
Bought.date, Bought.SUM(AMOUNT), Orderheader.date, Orderheader.SUM(AMOUNT)
All based on the, possible multiple, Lotdate(s) I got from the first query from Sales table.
I've been struggling with this for a moment now, using joins and nested queries but I can't seem to figure it out!
Example sample:
SELECT CONVERT(date,ORF.orfDate) as Productiedatum, SUM(orlQuantityRegistered) as 'Aantal'
FROM OrderHeader ORH
LEFT JOIN OrderFrame ORF ON ORH.orhFrameSysID = ORF.orfSysID
LEFT JOIN OrderLine ORL ON ORL.orhSysID = ORH.orhSysID
LEFT JOIN Item ON Item.itmSysID = ORL.orlitmSysID
where CONVERT(date,ORF.orfDate) IN
(
SELECT DISTINCT(CONVERT(date, Lot.lotproductiondate)) as Productiedatum
FROM OrderHeader ORH
LEFT JOIN Registration reg ON reg.regorhSysID = ORH.orhSysID
LEFT JOIN StockRegistration stcreg ON stcreg.stcregRegistrationSysID = reg.regSysID
LEFT JOIN Lot ON Lot.lotSysID = stcregSrclotSysID
WHERE ORH.orhSysID = 514955
AND regRevokeRegSysID IS NULL
AND stcregSrcitmSysID = 5103
)
AND ORL.orlitmSysID = 5103
AND orldirSysID = 2
AND NOT orlQuantityRegistered IS NULL
GROUP BY Orf.orfDate
Sample output:
Productiedatum Aantal
2019-02-05 20
2019-02-06 20
Here I used a nested subquery to get the results from 'Production' (orderheader) because I just can use date = date. I'm struggling with the Sales part where I need to find the last date(s) and use those dates in the Sales table to get the sum of that date.
Expected output:
Productiedatum Aantal Boughtdate Aantal
2019-02-04 20 2019-02-01 55
2019-02-05 20 2019-02-04 60
Try this.
IF OBJECT_ID('tempdb..#Production') IS NOT NULL DROP TABLE #Production
IF OBJECT_ID('tempdb..#Bought') IS NOT NULL DROP TABLE #Bought
CREATE table #Production(R_NO int,ProductionDate datetime,ProductionAmount float)
CREATE table #Bought(R_NO int,Boughtdate datetime,Boughtamount float)
insert into #Production(ProductionDate,ProductionAmount,R_NO)
select p.date ProductionDate,sum(Amount) ProductionAmount,row_number()over (order by p.date) R_NO
from Production P
join Sales s on p.date=S.date-1
where orhsysid=1
group by p.date
declare #loop int,#ProdDate datetime
select #loop =max(R_NO) from #Production
while (1<=#loop)
begin
select #ProdDate=ProductionDate from #Production where r_no=#loop
insert into #Bought(Boughtdate,Boughtamount,R_NO)
select Date,Sum(Amount),#loop R_NO from Bought where date=(
select max(date) from bought B
where B.Date<#ProdDate)
group by Date
set #loop=#loop-1
end
select ProductionDate,ProductionAmount,Boughtdate,Boughtamount from #Bought B
join #Production p on B.R_NO=P.R_NO
I am using Terdata SQL Assistant connected to an enterprise DW. I have written the query below to show an inventory of outstanding items as of a specific point in time. The table referenced loads and stores new records as changes are made to their state by load date (and does not delete historical records). The output of my query is 1 row for the specified date. Can I create a stored procedure or recursive query of some sort to build a history of these summary rows (with 1 new row per day)? I have not used such functions in the past; links to pertinent previously answered questions or suggestions on how I could get on the right track in researching other possible solutions are totally fine if applicable; just trying to bridge this gap in my knowledge.
SELECT
'2017-10-02' as Dt
,COUNT(DISTINCT A.RECORD_NBR) as Pending_Records
,SUM(A.PAY_AMT) AS Total_Pending_Payments
FROM DB.RECORD_HISTORY A
INNER JOIN
(SELECT MAX(LOAD_DT) AS LOAD_DT
,RECORD_NBR
FROM DB.RECORD_HISTORY
WHERE LOAD_DT <= '2017-10-02'
GROUP BY RECORD_NBR
) B
ON A.RECORD_NBR = B.RECORD_NBR
AND A.LOAD_DT = B.LOAD_DT
WHERE
A.RECORD_ORDER =1 AND Final_DT Is Null
GROUP BY Dt
ORDER BY 1 desc
Here is my interpretation of your query:
For the most recent load_dt (up until 2017-10-02) for record_order #1,
return
1) the number of different pending records
2) the total amount of pending payments
Is this correct? If you're looking for this info, but one row for each "Load_Dt", you just need to remove that INNER JOIN:
SELECT
load_Dt,
COUNT(DISTINCT record_nbr) AS Pending_Records,
SUM(pay_amt) AS Total_Pending_Payments
FROM DB.record_history
WHERE record_order = 1
AND final_Dt IS NULL
GROUP BY load_Dt
ORDER BY 1 DESC
If you want to get the summary info per record_order, just add record_order as a grouping column:
SELECT
load_Dt,
record_order,
COUNT(DISTINCT record_nbr) AS Pending_Records,
SUM(pay_amt) AS Total_Pending_Payments
FROM DB.record_history
WHERE final_Dt IS NULL
GROUP BY load_Dt, record_order
ORDER BY 1,2 DESC
If you want to get one row per day (if there are calendar days with no corresponding "load_dt" days), then you can SELECT from the sys_calendar.calendar view and LEFT JOIN the query above on the "load_dt" field:
SELECT cal.calendar_date, src.Pending_Records, src.Total_Pending_Payments
FROM sys_calendar.calendar cal
LEFT JOIN (
SELECT
load_Dt,
COUNT(DISTINCT record_nbr) AS Pending_Records,
SUM(pay_amt) AS Total_Pending_Payments
FROM DB.record_history
WHERE record_order = 1
AND final_Dt IS NULL
GROUP BY load_Dt
) src ON cal.calendar_date = src.load_Dt
WHERE cal.calendar_date BETWEEN <start_date> AND <end_date>
ORDER BY 1 DESC
I don't have access to a TD system, so you may get syntax errors. Let me know if that works or you're looking for something else.
If I have following table in Postgres:
order_dtls
Order_id Order_date Customer_name
-------------------------------------
1 11/09/17 Xyz
2 15/09/17 Lmn
3 12/09/17 Xyz
4 18/09/17 Abc
5 15/09/17 Xyz
6 25/09/17 Lmn
7 19/09/17 Abc
I want to retrieve such customer who has placed orders on 2 consecutive days.
In above case Xyz and Abc customers should be returned by query as result.
There are many ways to do this. Use an EXISTS semi-join followed by DISTINCT or GROUP BY, should be among the fastest.
Postgres syntax:
SELECT DISTINCT customer_name
FROM order_dtls o
WHERE EXISTS (
SELEST 1 FROM order_dtls
WHERE customer_name = o.customer_name
AND order_date = o.order_date + 1 -- simple syntax for data type "date" in Postgres!
);
If the table is big, be sure to have an index on (customer_name, order_date) to make it fast - index items in this order.
To clarify, since Oto happened to post almost the same solution a bit faster:
DISTINCT is an SQL construct, a syntax element, not a function. Do not use parentheses like DISTINCT (customer_name). Would be short for DISTINCT ROW(customer_name) - a row constructor unrelated to DISTINCT - and just noise for the simple case with a single expression, because Postgres removes the pointless row wrapper for a single element automatically. But if you wrap more than one expression like that, you get an actual row type - an anonymous record actually, since no row type is given. Most certainly not what you want.
What is a row constructor used for?
Also, don't confuse DISTINCT with DISTINCT ON (expr, ...). See:
Select first row in each GROUP BY group?
Try something like...
SELECT `order_dtls`.*
FROM `order_dtls`
INNER JOIN `order_dtls` AS mirror
ON `order_dtls`.`Order_id` <> `mirror`.`Order_id`
AND `order_dtls`.`Customer_name` = `mirror`.`Customer_name`
AND DATEDIFF(`order_dtls`.`Order_date`, `mirror`.`Order_date`) = 1
The way I would think of it doing it would be to join the table the date part with itselft on the next date and joining it with the Customer_name too.
This way you can ensure that the same customer_name done an order on 2 consecutive days.
For MySQL:
SELECT distinct *
FROM order_dtls t1
INNER JOIN order_dtls t2 on
t1.Order_date = DATE_ADD(t2.Order_date, INTERVAL 1 DAY) and
t1.Customer_name = t2.Customer_name
The result you should also select it with the Distinct keyword to ensure the same customer is not displayed more than 1 time.
For postgresql:
select distinct(Customer_name) from your_table
where exists
(select 1 from your_table t1
where
Customer_name = your_table.Customer_name and Order_date = your_table.Order_date+1 )
Same for MySQL, just instead of your_table.Order_date+1 use: DATE_ADD(your_table.Order_date , INTERVAL 1 DAY)
This should work:
SELECT A.customer_name
FROM order_dtls A
INNER JOIN (SELECT customer_name, order_date FROM order_dtls) as B
ON(A.customer_name = B.customer_name and Datediff(B.Order_date, A.Order_date) =1)
group by A.customer_name
I am trying to select max date record for each service_user_id for each finance_charge_id and the amount that is linked the highest date
select distinct
s.Finance_Charge_ID, MAX(s.start_date), s.Amount
from
Service_User_Finance_Charges s
where
s.Service_User_ID = '156'
group by
s.Finance_Charge_ID, s.Amount
The issue is that I receive multiple entries where the amount is different. I only want to receive the amount on the latest date for each finance_charge_id
At the moment I receive the below which is incorrect (the third line should not appear as the 1st line has a higher date)
Finance_Charge_ID (No column name) Amount
2 2014-10-19 1.00
3 2014-10-16 500.00
2 2014-10-01 1000.00
Remove the Amount column from the group by to get the correct rows. You can then join that query onto the table again to get all the data you need. Here is an example using a CTE to get the max dates:
WITH MaxDates_CTE (Finance_Charge_ID, MaxDate) AS
(
select s.Finance_Charge_ID,
MAX(s.start_date) MaxDate
from Service_User_Finance_Charges s
where s.Service_User_ID = '156'
group by s.Finance_Charge_ID
)
SELECT *
FROM Service_User_Finance_Charges
JOIN MaxDates_CTE
ON MaxDates_CTE.Finance_Charge_ID = Service_User_Finance_Charges.Finance_Charge_ID
AND MaxDates_CTE.MaxDate = Service_User_Finance_Charges.start_date
This can be done using a window function which removes the need for a self join on the grouped data:
select Finance_Charge_ID,
start_date,
amount
from (
select s.Finance_Charge_ID,
s.start_date,
max(s.start_date) over (partition by s.Finance_Charge_ID) as max_date,
s.Amount
from Service_User_Finance_Charges s
where s.Service_User_ID = 156
) t
where start_date = max_date;
As the window function does not require you to use group by you can add any additional column you need in the output.