SQL Server : Pivot Table Odd result, - sql

So, full disclosure, this is my first time using a pivot table and the result set has multiple columns as a result. In this example, we will use the result set without a pivot table applied.
This student has taken multiple courses. What the ideal end result would be, is to count how many courses this student has taken. So if I look I see that the Student has taken Algebra 1 5 times, English 1 2 times and Geometry 2 times.
The Next image is the query with the pivot applied, oh and to make things complicated, its a monster query before trying to attempt the pivot.
So we see in this, that Algebra 1 has a count of 0, Geometry has a count of 2 and English has a count of 0. This is the same query as before but just using this student.
Query:
SELECT *
FROM
(SELECT
[StudentNumber], psat.MathScaledScore, psat.EBRWScore,
SCReady.MathScaleScore, SCReady.ReadingScaleScore,
SpringMap.MathPercentile, SpringMap.ReadingPercentile,
Coursework.Course_name
FROM
[OnlineApplications].[dbo].[Users] U
LEFT JOIN
[OnlineApplications].[dbo].ContactInfoes C ON C.ContactInfoId = U.UserId
LEFT JOIN
(SELECT *
FROM [DOENRICH-SQL].[enrich_prod].dbo.HCS_view_Most_Recent_PSAT_Scores Scores) AS psat ON U.StudentNumber = psat.number
LEFT JOIN
(SELECT
stud.Number, sc.DateTaken,
CASE sc.ELALev
WHEN 'E8AE0E4D-AD36-41D8-AC89-627D19661803' THEN 'Exceeds Expectations'
WHEN 'C9F2CDA2-D904-438B-9DD3-94EFC9111A0E' THEN 'Approaches Expectations'
WHEN '9B39E28F-89C8-44AD-A8F2-1463192F88F1' THEN 'Does Not Meet Expectation'
WHEN '87247DB1-4A57-419E-9619-7B43B02B1135' THEN 'Meets Expectations'
END ELALev,
sc.ELASS AS ELAScaleScore, sc.elavss AS VerticalScaleScore,
sc.elassread AS ReadingScaleScore,
sc.ELARS10 AS RawScoreStandard10, sc.elASPR AS ELAStatePercentileRank,
MathLev = CASE MathLev
WHEN 'E8AE0E4D-AD36-41D8-AC89-627D19661803' THEN 'Exceeds Expectations'
WHEN 'C9F2CDA2-D904-438B-9DD3-94EFC9111A0E' THEN 'Approaches Expectations'
WHEN '9B39E28F-89C8-44AD-A8F2-1463192F88F1' THEN 'Does Not Meet Expectation'
WHEN '87247DB1-4A57-419E-9619-7B43B02B1135' THEN 'Meets Expectations'
END,
sc.MATHSS AS MathScaleScore, sc.MathVSS AS MathVerticalScaleScore,
sc.mathspr AS MathStatePercentileRank
FROM
[DOENRICH-SQL].[enrich_prod].dbo.t_sc_ready sc
JOIN
[DOENRICH-SQL].[enrich_prod].dbo.Student stud ON sc.StudentID = stud.ID
WHERE
DateTaken = '2019-05-17') AS SCReady ON SCReady.number = U.studentnumber
LEFT JOIN
(
select stud.Number, max(map.readingPercentile) as ReadingPercentile, max(map.mathPercentile) as MathPercentile
from [DOENRICH-SQL].[ENRICH_PROD].[dbo].t_map map
join [DOENRICH-SQL].[ENRICH_PROD].[INFORM].[Map_GradeLevelID] mapping on map.GradeLevelID = mapping.DestID
JOIN [DOENRICH-SQL].[ENRICH_PROD].[dbo].[Student] stud on map.StudentID = stud.ID
where DateTaken >= '2018-08-01'
group by stud.Number
) as SpringMap on SpringMap.number = U.Studentnumber
left join (
SELECT * FROM OPENQUERY(PSPROD,'
Select B.STUDENT_NUMBER , A.COURSE_NAME, A.GRADE_LEVEL, A.SCHOOLNAME, A.GRADE
from PS.STOREDGRADES A
join PS.STUDENTS B ON A.STUDENTID = B.ID
AND STORECODE in (''Q1'',''Q2'',''Q3'',''Q4'',''F1'')
AND (COURSE_NAME LIKE ''%Algebra 1%'' OR COURSE_NAME LIKE ''%Geometry Honors%'' OR COURSE_NAME LIKE ''%English 1%'')
group by B.STUDENT_NUMBER , A.COURSE_NAME, a.STORECODE, A.GRADE, A.PERCENT, A.GRADE_LEVEL, A.SCHOOLNAME
ORDER BY STUDENT_NUMBER, STORECODE DESC
'
)
) as Coursework on Coursework.STUDENT_NUMBER = U.StudentNumber
join [OnlineApplications].[dbo].ScholarsApps Sapps on Sapps.ScholarsAppId = u.UserId
where AppYear = 2019 and StudentNumber <> '' and StudentNumber = '17476'
) T
PIVOT (
COUNT (COURSE_NAME)
FOR course_name IN (
[Algebra 1],
[Geometry Honors],
[English 1])
)
as Pivot_table
Again, very complicated query before and I'm not clear if I'm using the pivot function correctly.
I'd love to have this pivot with the counts of the courses.

Related

How to check more than one unrelated conditions in SQL?

I have following query:
SQL> SELECT DISTINCT INSTRUCTORADDRESSMODPER.instructor_id, Instructor.instructor_name, InstructorRank.salary, Student.specification_id
2 FROM INSTRUCTORADDRESSMODPER
3 JOIN Student ON INSTRUCTORADDRESSMODPER.student_id = Student.student_id
4 JOIN Instructor ON INSTRUCTORADDRESSMODPER.instructor_id = Instructor.instructor_id
5 JOIN InstructorRank ON Instructor.instructor_rank = InstructorRank.instructor_rank
6 ORDER BY specification_id;
which has yielded following result:
I was trying to get result which shows same column values for instructors with same salary and same specification as highlighted in the figure. Now these two conditions require completely different checks and I don't even know how to get started.
You need something like this ?
SELECT instructor_id, instructor_name, instructor_name, specification_id
FROM (
SELECT DISTINCT INSTRUCTORADDRESSMODPER.instructor_id, Instructor.instructor_name, InstructorRank.instructor_name, Student.specification_id
, COUNT(distinct INSTRUCTORADDRESSMODPER.instructor_id)over(partition by InstructorRank.salary, Student.specification_id) cnt
FROM INSTRUCTORADDRESSMODPER
JOIN Student ON INSTRUCTORADDRESSMODPER.student_id = Student.student_id
JOIN Instructor ON INSTRUCTORADDRESSMODPER.instructor_id = Instructor.instructor_id
JOIN InstructorRank ON Instructor.instructor_rank = InstructorRank.instructor_rank
ORDER BY specification_id
)
WHERE cnt > 1
;
You can use the window function count as follows:
Select * from
(SELECT DISTINCT INSTRUCTORADDRESSMODPER.instructor_id, Instructor.instructor_name, InstructorRank.salary, Student.specification_id,
Count(1) over (partition by InstructorRank.salary, Student.specification_id) as cnt
FROM INSTRUCTORADDRESSMODPER
JOIN Student ON INSTRUCTORADDRESSMODPER.student_id = Student.student_id
JOIN Instructor ON INSTRUCTORADDRESSMODPER.instructor_id = Instructor.instructor_id
JOIN InstructorRank ON Instructor.instructor_rank = InstructorRank.instructor_rank)
Where cnt > 1
ORDER BY specification_id;
SQL> SELECT DISTINCT INSTRUCTORADDRESSMODPER.instructor_id,
Instructor.instructor_name,InstructorRank.salary, Student.specification_id
FROM INSTRUCTORADDRESSMODPER
WHERE 1=1
AND INSTRUCTORADDRESSMODPER.student_id = Student.student_id
AND INSTRUCTORADDRESSMODPER.instructor_id = Instructor.instructor_id
AND Instructor.instructor_rank = InstructorRank.instructor_rank
AND ORDER BY specification_id
AND ...;
With the above use, desired conditions can be added.

PIVOT on multiple columns SQL server (Aspen Relay Database)

I'm using a vendor supplied Relay Database (Aspen), which is running on MS SQL server). I'm attempting to write a pivot query that needs to pivot on 2 columns.
I created a temp table since the data is across multiple tables.
WITH TEMP_TABLE AS (
SELECT
R.LOCATIONID LLOCATIONID, R.ID RID, s.groupname SGROUPNAME,t.settingname TSETTINGNAME, s.setting SSETTING
from tsetting1 s
inner join tsettype1 t on t.relaytype=s.relaytype and t.groupname = s.groupname and t.rownumber = s.rownumber
INNER JOIN TREQUEST Q ON S.REQUESTID = Q.ID
INNER JOIN TRELAY R ON R.ID = Q.RELAYID
INNER JOIN TLOCATION L ON L.ID = R.LOCATIONID
where s.requestid=29117
)
select * from TEMP_TABLE
That select all from Temp returns 38 rows of data, a subset is shown here:
RID -----SGROUPNAME------TSETTINGNAME-------SSETTING
31297 LOAD1 ENABLE TRUE
31297 LOAD1 ANGLE 60
31297 LOAD2 CALCULATED_LOAD 12269
ETC....
I added this pivot, which gets me close:
PIVOT (MAX(SSETTING) FOR TSETTINGNAME IN (ENABLE, REACH, ANGLE, CALCULATED_LOADABILITY, ZLE, CTR, PTR, KVNOM, PICKUP, PERCENTAGE)) P
Returned result from Pivot:
RID-----SGROUPNAME-----ENABLE----REACH----ANGLE----CALCULATED_LOADABILITY
31297 LOAD1 TRUE 15 60 9444
31297 LOAD2 TRUE 10 30 12269
31297 LOAD3 TRUE 20 60 14167
ETC...
I would like to have the data as 1 record for RID 31297, where LOAD1-ENABLE, LOAD2-ENABLE, LOAD3-ENABLE, LOAD1-REACH, ETC. are all headers.
I've tried multiple pivots and cross apply, but I can't seem to get the data to display correctly.
Let me know if anything is unclear or if you need more information. Any help will be greatly appreciated.
Thanks,
Joe C.
It may be easier with a bunch of case statements and a group by RID. By the way this is the "original" method of pivoting before PIVOT was implemented.
select RID
, Load1_Enable = MAX(case when SGROUPNAME = 'Load1' then enable else null end)
, Load2_Enable = MAX(case when SGROUPNAME = 'Load2' then enable else null end)
from [YourTable]
group by RID
I would go all the way to the first cte though:
WITH TEMP_TABLE AS (
SELECT
R.LOCATIONID LLOCATIONID, R.ID RID, s.groupname SGROUPNAME,t.settingname TSETTINGNAME, s.setting SSETTING
from tsetting1 s
inner join tsettype1 t on t.relaytype=s.relaytype and t.groupname = s.groupname and t.rownumber = s.rownumber
INNER JOIN TREQUEST Q ON S.REQUESTID = Q.ID
INNER JOIN TRELAY R ON R.ID = Q.RELAYID
INNER JOIN TLOCATION L ON L.ID = R.LOCATIONID
where s.requestid=29117
)
select RID
,Load1_Enable = MAX(case when SGROUPNAME = 'Load1' and TSETTINGNAME = 'Enable' then SSETTING else null end)
from TEMP_TABLE
group by RID
Note MAX is only there for an aggregate -- you should be aggregating only one record.

How to use alias of a subquery to get the running total?

I have a UNION of 3 tables for calculating some balance and I need to get the running SUM of that balance but I can't use PARTITION OVER, because I must do it with a sql query that can work in Access.
My problem is that I cannot use JOIN on an alias subquery, it won't work.
How can I use alias in a JOIN to get the running total?
Or any other way to get the SUM that is not with PARTITION OVER, because it does not exist in Access.
This is my code so far:
SELECT korisnik_id, imePrezime, datum, Dug, Pot, (Dug - Pot) AS Balance
FROM (
SELECT korisnik_id, k.imePrezime, r.datum, SUM(IIF(u.jedinstven = 1, r.cena, k.kvadratura * r.cena)) AS Dug, '0' AS Pot
FROM Racun r
INNER JOIN Usluge u ON r.usluga_id = u.ID
INNER JOIN Korisnik k ON r.korisnik_id = k.ID
WHERE korisnik_id = 1
AND r.zgrada_id = 1
AND r.mesec = 1
AND r.godina = 2017
GROUP BY korisnik_id, k.imePrezime, r.datum
UNION ALL
SELECT korisnik_id, k.imePrezime, rp.datum, SUM(IIF(u.jedinstven = 1, rp.cena, k.kvadratura * rp.cena)) AS Dug, '0' AS Pot
FROM RacunP rp
INNER JOIN Usluge u ON rp.usluga_id = u.ID
INNER JOIN Korisnik k ON rp.korisnik_id = k.ID
WHERE korisnik_id = 1
AND rp.zgrada_id = 1
AND rp.mesec = 1
AND rp.godina = 2017
GROUP BY korisnik_id, k.imePrezime, rp.datum
UNION ALL
SELECT uu.korisnik_id, k.imePrezime, uu.datum, '0' AS Dug, SUM(uu.iznos) AS Pot
FROM UnosUplata uu
INNER JOIN Korisnik k ON uu.korisnik_id = k.ID
WHERE korisnik_id = 1
GROUP BY uu.korisnik_id, k.imePrezime, uu.datum
) AS a
ORDER BY korisnik_id
You can save a query (let's name it Query1) for the UNION of the 3 tables and then create another query that returns each row in the first query and calculates the sum of the rows that are before it (optionally checking that they are in the same group).
It should be something like this:
SELECT *, (
SELECT SUM(Value) FROM Query1 AS b
WHERE b.GroupNumber=a.GroupNumber
AND b.Position<=a.Position
) AS RunningSum
FROM Query1 AS a
However, it's more efficient to do that in the report.

Return a Count of 0 When No Rows

OK, I've looked this up and tried a number of solutions, but can't get it to work. I'm a bit of a novice. Here's my original query - how can I get it to return 0 for an account when there are no results in the student table?
SELECT a.NAME
,count(s.student_sid)
FROM account a
JOIN inst i ON a.inst_sid = i.root_inst_sid
JOIN inst_year iy ON i.inst_sid = iy.inst_sid
JOIN student s ON iy.inst_year_sid = s.inst_year_sid
WHERE s.demo = 0
AND s.STATE = 1
AND i.STATE = 1
AND iy.year_sid = 16
AND a.account_sid IN (
20187987
,20188576
,20188755
,52317128
,20189249
)
GROUP BY a.NAME;
Use an outer join, moving the condition on that table into the join:
select a.name, count(s.student_sid)
from account a
join inst i on a.inst_sid = i.root_inst_sid
join inst_year iy on i.inst_sid = iy.inst_sid
left join student s on iy.inst_year_sid = s.inst_year_sid
and s.demo = 0
and s.state = 1
where i.state = 1
and iy.year_sid = 16
and a.account_sid in (20187987, 20188576, 20188755, 52317128, 20189249)
group by a.name;
count() does not count null values, which s.student_sid will be if no rows join from student.
You need to LEFT JOIN and then SUM() over the group where s.student_sid is not null:
select
a.name,
sum(case when s.student_sid is null then 0 else 1 end) as student_count
from account a
join inst i on a.inst_sid = i.root_inst_sid
join inst_year iy on i.inst_sid = iy.inst_sid
left join student s
on iy.inst_year_sid = s.inst_year_sid
and s.demo = 0
and s.state = 1
where i.state = 1
and iy.year_sid = 16
and a.account_sid in (20187987, 20188576, 20188755, 52317128, 20189249)
group by a.name;
This is assuming that all of the fields in the student table that you are filtering on are optional. If you don't want to enforce removal of records where, say, s.state does not equal 1, then you need to move the s.state=1 predicate into the WHERE clauses.
If, for some reason, you are getting duplicate student IDs and students are being counted twice, then you can change the aggregate function to this:
count(distinct s.student_id) as student_count
...which is safe to do as count(distinct ...) ignores null values.

SQL Union Query

SELECT pv.PropertyID, COUNT(pv.VisitID) AS InitialVisit
FROM tblPAppointments pa INNER JOIN tblPropertyVisit pv ON pv.AppID = pa.AppID
WHERE pv.Status = 0
GROUP BY pv.PropertyID
UNION ALL
SELECT jv.PropertyID, COUNT(jv.JobVistID) AS JobVisit
FROM tblPAppointments pa INNER JOIN tblJobVisits jv ON jv.AppID = pa.AppID
WHERE jv.VisitStatus = 1
GROUP BY jv.PropertyID
I need to get InitialVisit count and JobVisit count in two separate columns.above query returns just two columns (PropertyID,InitialVisit).
Use a NULL as a placeholder for the column that there won't be any output for:
SELECT pv.PropertyID,
COUNT(pv.VisitID) AS InitialVisit,
NULL AS jobvisit
FROM tblPAppointments pa
JOIN tblPropertyVisit pv ON pv.AppID = pa.AppID
WHERE pv.Status = 0
GROUP BY pv.PropertyID
UNION ALL
SELECT jv.PropertyID,
NULL AS initialvisit,
COUNT(jv.JobVistID) AS JobVisit
FROM tblPAppointments pa
JOIN tblJobVisits jv ON jv.AppID = pa.AppID
WHERE jv.VisitStatus = 1
GROUP BY jv.PropertyID
This will return three columns. The column alias is necessary in the first query, but not in the second -- I aliased both to make it clear what is happening.
Be aware that using NULL like this in SQL Server will require you to use CAST/CONVERT on the NULL for data types other than INT because SQL Server defaults the NULL to an INT data type (as odd as that is).
An alternate query that doesn't use UNION:
SELECT x.propertyid,
COUNT(y.visitid) AS initialvisit,
COUNT(z.jobvisitid) AS jobvisit
FROM (SELECT pv.propertyid
FROM TBLPROPERTYVISIT pv
WHERE EXISTS (SELECT NULL
FROM TBLAPPOINTMENTS a
WHERE a.appid = pv.appid)
UNION
SELECT jv.propertyid
FROM TBLJOBVISIT jv
WHERE EXISTS (SELECT NULL
FROM TBLAPPOINTMENTS a
WHERE a.appid = jv.appid)) x
LEFT JOIN TBLPROPERTYVISIT y ON y.propertyid = x.propertyid
LEFT JOIN TBLJOBVISIT z ON z.propertyid = x.propertyid
GROUP BY x.propertyid
No need for a UNION at all. And you don't use tblPAppointments either
Edited to allow for no rows in one of the tables. Still one row output though
SELECT
ISNULL(pv2.PropertyID, jv2.PropertyID),
ISNULL(pv2.InitialVisit, 0),
ISNULL(jv2.JobVisit, 0)
FROM
(
SELECT pv.PropertyID, COUNT(pv.VisitID) AS InitialVisit
FROM tblPropertyVisit pv
WHERE pv.Status = 0
GROUP BY pv.PropertyID
) pv2
FULL OUTER JOIN
(
SELECT jv.PropertyID, COUNT(jv.JobVistID) AS JobVisit
FROM tblJobVisits jv
WHERE jv.VisitStatus = 1
GROUP BY jv.PropertyID
) jv2 ON pv2.PropertyID = jv2.PropertyID