zsh completion: Disable ssh username completion - ssh

I am using the completion scripts that ship with ZSH (5.7.1) and I would like to turn off the autocompletion for usernames, but keep the completion for hostnames.
How can I do this?
Currently, there's an erroneous user that I can't figure out why it's being included (not in ~/.ssh/config, any identities, /etc/ssh, or any other location) and I figure it's probably easier to just disable username completion.
Example output is below; I want to remove the entire "login name" section rather than try and hunt down where unwanted-username is coming from.
$ ssh <tab>
-- login name --
unwanted-username
-- host --
example-host-1 example-host-1
I expect there is a zstyle command which can disable it, but I'm not sure the correct incantation. I expect this is the relevant configuration that needs to be changed:
$ zstyle | grep completion | grep ssh
:completion:*:ssh:* users hosts-domain hosts-host users hosts-ipaddr
However, I can't seem to get the correct incantation to remove the login name section.

To disable completion of login names, in that context, try:
zstyle ':completion:*:ssh:argument-1:*' tag-order hosts
or to merely hide them, try:
zstyle ':completion:*:ssh:*:users' hidden true
Pressing Ctrl-X h instead of tab is a good way to determine the relevant tags and context strings.
Seems odd that you have an erroneous user being completed. Check for a users-hosts style being set, possibly without mention of ssh in the context. The ignored-patterns style could be another way to deal with an erroneous match in the general case, for example:
zstyle ':completion:*:ssh:*:users' ignored-patterns erroneous-username
As you might discern from the name of the style, the last argument here can be a shell pattern with *, ? etc.

Related

Paramiko, channel.recv(9999) causing confusion [duplicate]

I am using Python's Paramiko library to SSH a remote machine and fetch some output from command-line. I see a lot of junk printing along with the actual output. How to get rid of this?
chan1.send("ls\n")
output = chan1.recv(1024).decode("utf-8")
print(output)
[u'Last login: Wed Oct 21 18:08:53 2015 from 172.16.200.77\r', u'\x1b[2J\x1b[1;1H[local]cli#BENU>enable', u'[local]cli#BENU#Configure',
I want to eliminate, [2J\x1b[1;1H and u from the output. They are junk.
It's not a junk. These are ANSI escape codes that are normally interpreted by a terminal client to pretty print the output.
If the server is correctly configured, you get these only, when you use an interactive terminal, in other words, if you requested a pseudo terminal for the session (what you should not, if you are automating the session).
The Paramiko automatically requests the pseudo terminal, if you used the SSHClient.invoke_shell, as that is supposed to be used for implementing an interactive terminal. See also How do I start a shell without terminal emulation in Python Paramiko?
If you automate an execution of remote commands, you better use the SSHClient.exec_command, which does not allocate the pseudo terminal by default (unless you override by the get_pty=True argument).
stdin, stdout, stderr = client.exec_command('ls')
See also What is the difference between exec_command and send with invoke_shell() on Paramiko?
Or as a workaround, see How can I remove the ANSI escape sequences from a string in python.
Though that's rather a hack and might not be sufficient. You might have other problems with the interactive terminal, not only the escape sequences.
You particularly are probably not interested in the "Last login" message and command-prompt (cli#BENU>) either. You do not get these with the exec_command.
If you need to use the "shell" channel due to some specific requirements or limitations of the server, note that it is technically possible to use the "shell" channel without the pseudo terminal. But Paramiko SSHClient.invoke_shell does not allow that. Instead, you can create the "shell" channel manually. See Can I call Channel.invoke_shell() without calling Channel.get_pty() beforehand, when NOT using Channel.exec_command().
And finally the u is not a part of the actual string value (note that it's outside the quotes). It's an indication that the string value is in the Unicode encoding. You want that!
This is actually not junk. The u before the string indicates that this is a unicode string. The \x1b[2J\x1b[1;1H is an escape sequence. I don't know exactly what it is supposed to do, but it appears to clear the screen when I print it out.
To see what I mean, try this code:
for string in output:
print string

Renaming a Yakuake session from commandline

Yakuake provides a hotkey and a GUI way to rename commandline tabs/sessions.
I'd like to do the same via the command line, so I can script it and use it in an alias. (My goal is that if I use an alias which does an SSH to some server, then the tab is renamed according to this servers name...)
I tried the suggestions shown here Renaming a Konsole session from commandline after ssh so far no luck.
Since KDE4, one should use qdbus to control KDE apps (instead of deprecated and deleted DCOP).
For example, to change a title of the first session one may use:
qdbus org.kde.yakuake /Sessions/1 org.kde.konsole.Session.setTitle 1 "New title"
To explore available interfaces, methods and properties one may use qdbusviewer.
As a homework try to get a list of active sessions (before you going to change smth).
Like #fgysin pointed out, his command also works for me. BUT it needs the ` character and not " for the subcommand :
qdbus org.kde.yakuake /yakuake/sessions org.kde.yakuake.activeSessionId
It gives :
qdbus org.kde.yakuake /yakuake/tabs org.kde.yakuake.setTabTitle `qdbus org.kde.yakuake /yakuake/sessions org.kde.yakuake.activeSessionId` "NEW TAB TITLE";

How to interact with an external command in vimscript?

I have a script which interacts with user (prints some questions to stderr and gets input from stdin) and then prints some data to stdin. I want to put the output of the script to a variable in vimscript. It probably should look like this:
let a = system("./script")
The supposed behavior is that script runs, interacts with user, and after all a is assigned with its output to stdout. But instead a is assigned both with outputs to stdout and stderr, so user seed no prompts.
Could you help me fixing it?
Interactive commands are best avoided from within Vim; especially with GVIM (on Windows), a new console window pops up; you may not have a fully functional terminal, ...
Better query any needed arguments in Vimscript itself (with input(); or pass them on from a custom Vim :command), and just use the external script non-interactively, feeding it everything it needs.
What gets captured by system() (as well as :!) is controlled by the 'shellredir' option. Its usual value, >%s 2>&1 captures stdout as well as stderr. Your script needs to choose one (e.g. stdout) for its output, and the other for user interaction, and the Vimscript wrapper that invokes it must (temporarily) change the option.
:let save_shellredir = &shellredir
:set shellredir=>
:let a = system('./script') " The script should interact via stderr.
:let &shellredir = save_shellredir
Call the script within the other as,
. ./script.sh
I think this is what you meant.

Zsh trouble when using echo with color/formatting characters

I'm just switch to zsh and now adapting the alias in which was printing some text (in color) along with a command.
I have been trying to use the $fg array var, but there is a side effect, all the command is printed before being executed.
The same occur if i'm just testing a echo with a color code in the terminal:
echo $fg_bold[blue] "test"
]2;echo "test" test #the test is in the right color
Why the command print itself before to do what it's supposed to do ? (I precise this doesn't happen when just printing whithout any wariable command)
Have I to set a specific option to zsh, use echo with a special parameter to get ride of that?
Execute the command first (keep its output somewhere), and then issue echo. The easiest way I can think of doing that would be:
echo $fg[red] `ls`
Edit: Ok, so your trouble is some trash before the actual output of echo. You have some funny configuration that is causing you trouble.
What to do (other than inspecting your configuration):
start a shell with zsh -f (it will skip any configuration), and then re-try the echo command: autoload colors; colors; echo $fg_bold[red] foo (this should show you that the problem is in your configuration).
Most likely your configuration defines a precmd function that gets executed before every command (which is failing in some way). Try which precmd. If that is not defined, try echo $precmd_functions (precmd_functions is an array of functions that get executed before every command). Knowing which is the code being executed would help you search for it in your configuration (which I assume you just took from someone else).
If I had to guess, I'd say you are using oh-my-zsh without knowing exactly what you turned on (which is an endless source of troubles like this).
I don't replicate your issue, which I think indicates that it's either an option (that I've set), or it's a zsh version issue:
$ echo $fg_bold[red] test
test
Because I can't replicate it, I'm sure there's an option to stop it happening for you. I do not know what that option is (I'm using heavily modified oh-my-zsh, and still haven't finished learning what all the zsh options do or are).
My suggestions:
You could try using print:
$ print $fg_bold[red] test
test
The print builtin has many more options than echo (see man zshbuiltins).
You should also:
Check what version zsh you're using.
Check what options (setopt) are enabled.
Check your ~/.zshrc (and other loaded files) to see what, if any, options and functions are being run.
This question may suggest checking what TERM you're using, but reading your question it sounds like you're only seeing this behaviour (echoing of the command after entry) when you're using aliases...?

Git - how do I view the change history of a method/function?

So I found the question about how to view the change history of a file, but the change history of this particular file is huge and I'm really only interested in the changes of a particular method. So would it be possible to see the change history for just that particular method?
I know this would require git to analyze the code and that the analysis would be different for different languages, but method/function declarations look very similar in most languages, so I thought maybe someone has implemented this feature.
The language I'm currently working with is Objective-C and the SCM I'm currently using is git, but I would be interested to know if this feature exists for any SCM/language.
Recent versions of git log learned a special form of the -L parameter:
-L :<funcname>:<file>
Trace the evolution of the line range given by "<start>,<end>" (or the function name regex <funcname>) within the <file>. You may not give any pathspec limiters. This is currently limited to a walk starting from a single revision, i.e., you may only give zero or one positive revision arguments. You can specify this option more than once.
...
If “:<funcname>” is given in place of <start> and <end>, it is a regular expression that denotes the range from the first funcname line that matches <funcname>, up to the next funcname line. “:<funcname>” searches from the end of the previous -L range, if any, otherwise from the start of file. “^:<funcname>” searches from the start of file.
In other words: if you ask Git to git log -L :myfunction:path/to/myfile.c, it will now happily print the change history of that function.
Using git gui blame is hard to make use of in scripts, and whilst git log -G and git log --pickaxe can each show you when the method definition appeared or disappeared, I haven't found any way to make them list all changes made to the body of your method.
However, you can use gitattributes and the textconv property to piece together a solution that does just that. Although these features were originally intended to help you work with binary files, they work just as well here.
The key is to have Git remove from the file all lines except the ones you're interested in before doing any diff operations. Then git log, git diff, etc. will see only the area you're interested in.
Here's the outline of what I do in another language; you can tweak it for your own needs.
Write a short shell script (or other program) that takes one argument -- the name of a source file -- and outputs only the interesting part of that file (or nothing if none of it is interesting). For example, you might use sed as follows:
#!/bin/sh
sed -n -e '/^int my_func(/,/^}/ p' "$1"
Define a Git textconv filter for your new script. (See the gitattributes man page for more details.) The name of the filter and the location of the command can be anything you like.
$ git config diff.my_filter.textconv /path/to/my_script
Tell Git to use that filter before calculating diffs for the file in question.
$ echo "my_file diff=my_filter" >> .gitattributes
Now, if you use -G. (note the .) to list all the commits that produce visible changes when your filter is applied, you will have exactly those commits that you're interested in. Any other options that use Git's diff routines, such as --patch, will also get this restricted view.
$ git log -G. --patch my_file
Voilà!
One useful improvement you might want to make is to have your filter script take a method name as its first argument (and the file as its second). This lets you specify a new method of interest just by calling git config, rather than having to edit your script. For example, you might say:
$ git config diff.my_filter.textconv "/path/to/my_command other_func"
Of course, the filter script can do whatever you like, take more arguments, or whatever: there's a lot of flexibility beyond what I've shown here.
The closest thing you can do is to determine the position of your function in the file (e.g. say your function i_am_buggy is at lines 241-263 of foo/bar.c), then run something to the effect of:
git log -p -L 200,300:foo/bar.c
This will open less (or an equivalent pager). Now you can type in /i_am_buggy (or your pager equivalent) and start stepping through the changes.
This might even work, depending on your code style:
git log -p -L /int i_am_buggy\(/,+30:foo/bar.c
This limits the search from the first hit of that regex (ideally your function declaration) to thirty lines after that. The end argument can also be a regexp, although detecting that with regexp's is an iffier proposition.
git log has an option '-G' could be used to find all differences.
-G Look for differences whose added or removed line matches the
given <regex>.
Just give it a proper regex of the function name you care about. For example,
$ git log --oneline -G'^int commit_tree'
40d52ff make commit_tree a library function
81b50f3 Move 'builtin-*' into a 'builtin/' subdirectory
7b9c0a6 git-commit-tree: make it usable from other builtins
The correct way is to use git log -L :function:path/to/file as explained in eckes answer.
But in addition, if your function is very long, you may want to see only the changes that various commit had introduced, not the whole function lines, included unmodified, for each commit that maybe touch only one of these lines. Like a normal diff does.
Normally git log can view differences with -p, but this not work with -L.
So you have to grep git log -L to show only involved lines and commits/files header to contextualize them. The trick here is to match only terminal colored lines, adding --color switch, with a regex. Finally:
git log -L :function:path/to/file --color | grep --color=never -E -e "^(^[\[[0-9;]*[a-zA-Z])+" -3
Note that ^[ should be actual, literal ^[. You can type them by pressing ^V^[ in bash, that is Ctrl + V, Ctrl + [. Reference here.
Also last -3 switch, allows to print 3 lines of output context, before and after each matched line. You may want to adjust it to your needs.
Show function history with git log -L :<funcname>:<file> as showed in eckes's answer and git doc
If it shows nothing, refer to Defining a custom hunk-header to add something like *.java diff=java to the .gitattributes file to support your language.
Show function history between commits with git log commit1..commit2 -L :functionName:filePath
Show overloaded function history (there may be many function with same name, but with different parameters) with git log -L :sum\(double:filepath
git blame shows you who last changed each line of the file; you can specify the lines to examine so as to avoid getting the history of lines outside your function.