I am trying to get the following result in SQL server:
From the purchase order rows, last purchase quantity + date from all item codes in the order rows table and from the warehouse table amount in stock for the item codes I get from the rows table.
Order rows:
ORDER_DATE ITEM_CODE QTY
2019-03-01 A 5
2019-03-02 A 3
2019-03-05 A 4
2019-03-03 B 3
2019-03-04 B 10
Warehouse:
ITEM_CODE INSTOCK STOCKPLACE
A 10 VV
A 3 LP
A 8 XV
B 5 VV
B 15 LP
Wanted result (Latest order date, latest order qty and total in stock):
ORDER_DATE ITEM_CODE QTY INSTOCK
2019-03-05 A 4 21
2019-03-04 B 10 20
I have tried some queries but only failed. I have a steep learning curve ahead of me :) Thanks in advance for all the help!
Here is one method:
select o.*, wh.*
from (select wh.item_code, sum(wh.instock) as instock
from warehouse wh
group by wh.item_code
) wh outer apply
(select top (1) o.*
from orders o
where o.item_code = wh.item_code
order by o.order_date desc
) o;
You can use row_number() with apply :
select t.*, wh.instock
from (select o.*, row_number () over (partition by item_code order by o.order_date desc) as seq
from Order o
) t cross apply
( select sum(wh.instock) as instock
from warehouse wh
where wh.item_code = t.item_code
) wh
where t.seq = 1;
Your Orders aren't identified with a unique ID, and therefore if multiple Orders were to coincide on the same date, you have no way of telling which is the most recent order on that day.
Anyway, assuming that the database you posted is correct and an Order date + Item Code combines to form a unique key, you could use grouping and some CTE to get the desired output as follows.
;WITH MostRecentOrders (ITEM_CODE, ORDER_DATE)
AS (
SELECT
O.ITEM_CODE
, MAX(O.ORDER_DATE) AS ORDER_DATE
FROM
#Order O
GROUP BY ITEM_CODE
)
SELECT
O.ORDER_DATE
, O.ITEM_CODE
, O.QTY
, SUM(WH.INSTOCK) AS INSTOCK
FROM
#Warehouse WH
INNER JOIN #Order O ON O.ITEM_CODE = WH.ITEM_CODE
INNER JOIN MostRecentOrders MRO ON MRO.ITEM_CODE = O.ITEM_CODE
AND MRO.ORDER_DATE = O.ORDER_DATE
GROUP BY
O.ORDER_DATE
, O.ITEM_CODE
, O.QTY
ORDER BY O.ITEM_CODE
Related
I have a sales table in SQLite:
purchase_date
units_sold
customer_id
15
1
1
17
1
1
30
3
1
I want to get the total unit_solds for each customer on the first date and last date of their purchases. My query is:
select customer_id,
sum(units_sold) total_units_sold
from sales
group by customer_id
having purchase_date = min(purchase_date)
or purchase_date = max(purchase_date)
I was expecting results like:
customer_id
total_units_sold
1
4
but I got:
customer_id
total_units_sold
1
5
I would like to know why this solution doesn't work.
The order of the phrase is incorrect
Note: The having statement is executed after compilation.
You need to get the results as partial queries
For example, I arranged to know the first line of the date according to each customer
as well as the last line of the date (by getting the first line after descending order)
and then execute the group statement
The example is complete
select customer_id,sum(units_sold) from (
select customer_id, units_sold,purchase_date,
ROW_NUMBER() over(partition by customer_id order by purchase_date) As RowDatefirst,
ROW_NUMBER() over(partition by customer_id order by purchase_date desc)As RowDatelast
from sales
) t where t.RowDatefirst = 1 or t.RowDatelast=1
group by customer_id
Try this:
SELECT a.customer_id, SUM(a.units_sold) as total_units_sold
FROM sales a
INNER JOIN (
SELECT customer_id, MIN(purchase_date) as _first ,MAX(purchase_date) as _last
FROM sales
GROUP BY customer_id
) b ON a.customer_id = b.customer_id AND
(a.purchase_date = b._first OR a.purchase_date = b._last)
GROUP BY a.customer_id
http://sqlfiddle.com/#!7/0a4a4/7
I'm new in SQL. Need some help to improve my query to ovoid duplicate code.
SELECT customers.name, orders.price
FROM customers
JOIN orders ON orders.id = customers.order_id
WHERE customers.order_id IN (
SELECT orders.id
FROM orders
WHERE orders.price = (
SELECT orders.price
FROM orders
WHERE orders.order_date BETWEEN
(SELECT MIN(orders.order_date) FROM orders)
AND
(SELECT DATE_ADD(MIN(orders.order_date), INTERVAL 10 year)FROM orders)
ORDER BY orders.price DESC LIMIT 1
)
AND orders.order_date BETWEEN
(SELECT MIN(orders.order_date) FROM orders)
AND
(SELECT DATE_ADD(MIN(orders.order_date), INTERVAL 10 year)FROM orders)
)
I would like ovoid duplicate code here
SELECT MIN(orders.order_date) FROM orders
and
SELECT DATE_ADD(MIN(orders.order_date), INTERVAL 10 year)FROM orders
You can use WITH to get first 10 years orders. By defitinion there exists no orders with the date < min(date), so you needn't between, just <= .
firstOrders as (
SELECT *
FROM orders
WHERE order_date <=
(SELECT DATE_ADD(MIN(o.order_date), INTERVAL 10 year)
FROM orders o)
)
SELECT customers.name, orders.price
FROM customers
JOIN FirsrOrders orders ON orders.id = customers.order_id
AND orders.price = (
select price
from firstOrders
order py price desc
limit 1
)
You want orders from the first ten years where the price was equal to the maximum price among those orders. So rank by price and grab those holding the #1 spot.
with data as (
select *,
date_add(min(order_date) over (), interval 10 year) as max_date,
rank() over (order by price desc) as price_rank
from orders
)
select *
from data
where order_date <= max_date and price_rank = 1;
I have 2 tables, the first one is contain customer information such as id,age, and name . the second table is contain their id, information of product they purchase, and the purchase_date (the date is from 2016 to 2018)
Table 1
-------
customer_id
customer_age
customer_name
Table2
------
customer_id
product
purchase_date
my desired result is to generate the table that contain customer_name and product who made purchase in 2017 and older than 75% of customer that make purchase in 2016.
Depending on your flavor of SQL, you can get quartiles using the more general ntile analytical function. This basically adds a new column to your query.
SELECT MIN(customer_age) as min_age FROM (
SELECT customer_id, customer_age, ntile(4) OVER(ORDER BY customer_age) AS q4 FROM table1
WHERE customer_id IN (
SELECT customer_id FROM table2 WHERE purchase_date = 2016)
) q
WHERE q4=4
This returns the lowest age of the 4th-quartile customers, which can be used in a subquery against the customers who made purchases in 2017.
The argument to ntile is how many buckets you want to divide into. In this case 75%+ equals 4th quartile, so 4 buckets is OK. The OVER() clause specifies what you want to sort by (customer_age in our case), and also lets us partition (group) the data if we want to, say, create multiple rankings for different years or countries.
Age is a horrible field to include in a database. Every day it changes. You should have date-of-birth or something similar.
To get the 75% oldest value in 2016, there are several possibilities. I usually go for row_number() and count(*):
select min(customer_age)
from (select c.*,
row_number() over (order by customer_age) as seqnum,
count(*) over () as cnt
from customers c join
where exists (select 1
from customer_products cp
where cp.customer_id = c.customer_id and
cp.purchase_date >= '2016-01-01' and
cp.purchase_date < '2017-01-01'
)
)
where seqnum >= 0.75 * cnt;
Then, to use this for a query for 2017:
with a2016 as (
select min(customer_age) as customer_age
from (select c.*,
row_number() over (order by customer_age) as seqnum,
count(*) over () as cnt
from customers c
where exists (select 1
from customer_products cp
where cp.customer_id = c.customer_id and
cp.purchase_date >= '2016-01-01' and
cp.purchase_date < '2017-01-01'
)
) c
where seqnum >= 0.75 * cnt
)
select c.*, cp.product_id
from customers c join
customer_products cp
on cp.customer_id = c.customer_id and
cp.purchase_date >= '2017-01-01' and
cp.purchase_date < '2018-01-01' join
a2016 a
on c.customer_age >= a.customer_age;
I am trying to return the most ordered product per month, of the year 2007. I would like to see the name of the product, how many of them where ordered that month, and the month. I am using the AdventureWorks2012 database. I have tried a few different ways but each time multiple product orders are returned for the same month, instead of the one product that had the most order quantity that month. Sorry if this is not clear. I am trying to test myself so I make up my own questions and try to answer them. If anyone knows a site that have questions and answers like this so I can verify that would be super helpful! Thanks for any help. Here is the farthest I have been able to get with the query.
WITH Ord2007Sum
AS (SELECT sum(od.orderqty) AS sorder,
od.productid,
oh.orderdate,
od.SalesOrderID
FROM Sales.SalesOrderDetail AS od
INNER JOIN
sales.SalesOrderHeader AS oh
ON od.SalesOrderID = oh.SalesOrderID
WHERE year(oh.OrderDate) = 2007
GROUP BY ProductID, oh.OrderDate, od.SalesOrderID)
SELECT max(sorder),
s.productid,
month(h.orderdate) AS morder --, s.salesorderid
FROM Ord2007Sum AS s
INNER JOIN
sales.SalesOrderheader AS h
ON s.OrderDate = h.OrderDate
GROUP BY s.ProductID, month(h.orderdate)
ORDER BY morder;
Make a CTE that groups our products by month and creates a sum
;WITH OrderRows AS
(
SELECT
od.ProductId,
MONTH(oh.OrderDate) SalesMonth,
SUM(od.orderqty) OVER (PARTITION BY od.ProductId, MONTH(oh.OrderDate) ORDER BY oh.OrderDate) ProdMonthSum
FROM SalesOrderDetail AS od
INNER JOIN SalesOrderHeader AS oh
ON od.SalesOrderID = oh.SalesOrderID
WHERE year(oh.OrderDate) = 2007
),
Make a simple numbers table to break out each month of the year
Months AS
(
SELECT 1 AS MonthNum UNION SELECT 2 UNION SELECT 3 UNION SELECT 4
UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8
UNION SELECT 9 UNION SELECT 10 UNION SELECT 11 UNION SELECT 12
)
We query our months table against the data and select the top product for each month based on the sum
SELECT
m.MonthNum,
d.ProductID,
d.ProdMonthSum
FROM Months m
OUTER APPLY
(
SELECT TOP 1 r.ProductID, r.ProdMonthSum
FROM OrderRows r
WHERE r.SalesMonth = m.MonthNum
ORDER BY ProdMonthSum DESC
) d
Your group by statement should not include oh.OrderDate, od.SalesOrderID because this will aggregate your data to the incorrect level. You want the ProductID that was most commonly sold per month so the group by conditions become ProductID, datepart(mm,oh.OrderDate). As Andrew suggested the Row_Number function is useful in this case as it lets you create a key that is ordered by month and sorder and which resets each month. Finally in the outer query limits the results to the first instance (which is the highest quantity)for each month.
WITH Ord2007Sum
AS(
SELECT sum(od.orderqty) AS sorder,
od.productid,
datepart(mm,oh.OrderDate) AS 'Month'
row_number() over (partition by datepart(mm,oh.OrderDate)
Order by datepart(mm,oh.OrderDate)desc, sorder desc) row
FROM Sales.SalesOrderDetail AS od
INNER JOIN
sales.SalesOrderHeader AS oh
ON od.SalesOrderID = oh.SalesOrderID
WHERE datepart(yyyy,oh.OrderDate) = 2007
GROUP BY ProductID, datepart(mm,oh.OrderDate)
)
SELECT productid,
sorder,
[month]
FROM Ord2007Sum
WHERE row =1
SELECT TOP 100 PERCENT soheader.custid,SOHeader.OrdNbr, SOLine.InvtID, SOLine.Descr,SOLine.QtyOrd
FROM SOHeader INNER JOIN
SOLine ON SOHeader.OrdNbr = SOLine.OrdNbr
WHERE (SOHeader.OrdDate >= CONVERT(DATETIME, '2013-06-01 00:00:00', 102)) AND (SOHeader.OrdDate <= GETDATE()) AND (SOHeader.CustID = '69065')
ORDER BY SOLine.InvtID, SOHeader.OrdNbr
here is my sample data
69065 WO0175279 69407 Jazzy Laces White 3
69065 WO0175393 69407 Jazzy Laces White 6
69065 WO0175393 69407 Jazzy Laces White 9
Now I want to know how to get the total qty of this item ordered after the first order. I do not want to include the qty of 3 in the first record above. I just want to include the qty of 6 in the first reorder and the qty 9 of the second reorder which equals the qty of 15.
69065 is the customer ID
WO##### is the order ID
69407 is the inventory ID
SELECT invtId, SUM(QtyOrd)
FROM (
SELECT invtId,
qtyOrd,
ROW_NUMBER() OVER (PARTITION BY invtId ORDER BY h.ordDate, h.ordNbr) rn
FROM soLine l
JOIN soHeader h
ON h.ordNbr = l.ordNbr
WHERE l.custId = 69065
) q
WHERE rn > 1
GROUP BY
invtId
WITH cl
as
(select *, ROW_NUMBER() OVER (PARTITION BY InvtID ORDER BY QtyOrd) rn
from t)
select InvtID, QtyOrd,
(select SUM(QtyOrd) from cl oo
where o.InvtID = oo.InvtID and o.rn -1 > 0
and rn between o.rn -1 and o.rn) as 'sm'
from cl o
Here's a Demo on SqlFiddle.