I have 3 columns
ProjektNummer, DokumentNummer, DokumentType
In DokumentType there are 3 possible values: Angebot, Rechnung, Lieferschein).
I want to select only those which have only Angebot and no other values.
Like you see in the picture, I only want the ProjektNummer (17011) where the DokumentType = Angebot and there no other entries for other values of DokumentType.
So it should NOT select ProjektNummmer = 17016 because there are other entries with different values.
I hope you know what I mean.
I already tried if conditions and other stuff but I can't get it done.
Thanks for your help
You can use NOT EXISTS :
SELECT t.*
FROM table t
WHERE NOT EXISTS (SELECT 1
FROM table t1
WHERE t1.ProjektNummer = t.ProjektNummer AND
t1.DokumentType <> t.DokumentType
)
AND t.DokumentType = 'Angebot';
As I read the question, you only want ProjektNummers that meet the criteria -- not the individual rows. If so, then aggregation is a simple solution:
select ProjektNummer
from t
group by ProjektNummer
having min(DokumentType) = max(DokumentType) and
min(DokumentType) = 'Angebot'
Related
I have two columns in a hive table that look something like this:
code codeset
AB AB123,MU124
LM LM123,LM234
I need to verify that all elements in codeset column contain the value in code column so in the above example the first row would be false and the second row would be true.
Is there a simple way to do this that I am missing? I already read about array_contains but that returns true if just one element matches, I need all elements to contain what's in the code column.
Thanks in advance.
split the string, explode and use lateral view to unpivot the data. Then check using locate if the split codeset contains each code (which is done with group by and having).
select code,codeset
from tbl
lateral view explode(split(codeset,',')) t as split_codeset
group by code,codeset
having sum(cast(locate(code,split_codeset)>0 as int))=count(*)
select a.pattern,b.listOfInputs from ( select * from (select a.pattern, case when inputCount = sumPatternMatchResult then true else false end finalResult from (select pattern , sum(patternMatchResult) as sumPatternMatchResult from (select pattern,case when locate(pattern,input) !=0 then 1 else 0 end patternMatchResult from (select pattern,explode(split(listOfInputs,',')) as input from tbl)a ) b group by pattern) a join (select pattern , count(input) inputCount from (select pattern,explode(split(listOfInputs,',')) as input from tbl)a group by pattern) b on a.pattern=b.pattern )c where finalResult=true)a join (select * from tbl) b on a.pattern=b.pattern
This works too.
column mapping details for your table:
code -> pattern
codeset -> listOfInputs
In the sql, i wanted all the record but for value RM in column MCCU occurs twice..but i'm in a situation that cannot distinct it because the value of misc of both value are not same..
How can i make if MCCU have more than one RM and then only select the one that have higher position in column POSI and in the misc column, add up their two value together. Hope idea to solve it. Thank you very much!
This is my sql statement
select * from Oclaimc Where cono='NP' and CLNO='7150000032'
There is no column names misc in your image. I am assuming you need to sum gamntMisc and gttlMisc.
So try this. Add other columns when needed.
select max(CONO) as CONO,max(CLNO) as CLNO,max(posi) as posi,MCCU,
sum(gamntMisc) as totalgamntMisc,sum(gttlMisc) as totalgttlMisc from Oclaimc
where cono='NP' and CLNO='7150000032'
group by mccu
Note: Query will fail if you remove the where clause. If you need this result for each combination of cono and clno then change the group by clause to
group by cono,clno,mccu
This may help:
select *
from oclaimc
where cono = 'NP'
and clno = '7150000032'
and mccu <> 'RM'
union
select *
from (select *
from oclaimc
where cono = 'NP'
and clno = '7150000032'
and mccu = 'RM'
order by posi)
where rownum = 1
I have this query:
SELECT *
FROM GUITARS.FENDER
WHERE FENDER.GUITARTYPE IN (
SELECT GUITARTYPE,Count(*)
FROM GUITARS.GUITAR_TYPE
WHERE GuitarColor = 'RED'
Group By GUITARTYPE
Having Count(*) = 1)
Basically I want to make sure I am only checking the Guitartypes that don't have duplicates with a count. The issue is the IN is only checking for 1 column, but i need the count(*)in there for instances of more than one guitar type. Is there a way to make this query work, or possible another way around doing the count.
You don't need to have the count() returned in the select statement, having the group by and the count() is sufficient.
SELECT *
FROM GUITARS.FENDER
WHERE FENDER.GUITARTYPE IN (
SELECT GUITARTYPE
FROM GUITARS.GUITAR_TYPE
WHERE GuitarColor = 'RED'
Group By GUITARTYPE
Having Count(*) = 1)
Adding the code so it looks right.
I'm writing a query to retrieve translated content. I want it so that if there isn't a translation for the given language id, it automatically returns the translation for the default language, with Id 1.
select Translation.Title
,Translation.Summary
from Translation
where Translation.FkLanguageId = 3
-- If there is no LanguageId of 3, select the record with LanguageId of 1.
I'm working in MS SQL but I think the theory is not DBMS-specific.
Thanks in advance.
This assumes one row per Translation only, based on how you phrased the question. If you have multiple rows per FkLanguageId and I've misunderstood, please let us know and the query becomes more complex of course
select TOP 1
Translation.Title
,Translation.Summary
from
Translation
where
Translation.FkLanguageId IN (1, 3)
ORDER BY
FkLanguageId DESC
You'd use LIMIT in another RDBMS
Assuming the table contains different phrases grouped by PhraseId
WITH Trans As
(
select Translation.Title
,Translation.Summary
,ROW_NUMBER() OVER (PARTITION BY PhraseId ORDER BY FkLanguageId DESC) RN
from Translation
where Translation.FkLanguageId IN (1,3)
)
SELECT *
FROM Trans WHERE RN=1
This assumes the existance of a TranslationKey that associates one "topic" with several different translation languages:
SELECT
isnull(tX.Title, t1.Title) Title
,isnull(tX.Summary, t1.Summary) Summary
from Translation t1
left outer join Translation tX
on tx.TranslationKey = t1.Translationkey
and tx.FkLanguageId = #TargetLanguageId
where t1.FkLanguageId = 1 -- "Default
Maybe this is a dirty solution, but it can help you
if not exists(select t.Title ,t.Summary from Translation t where t.FkLanguageId = 3)
select t.Title ,t.Summary from Translation t where t.FkLanguageId = 1
else
select t.Title ,t.Summary from Translation t where t.FkLanguageId = 3
Since your reference to pastie.org shows that you're looking up phrases or specific menu item names in a table I'm going to assume that there is a phrase ID to identify the phrases in question.
SELECT ISNULL(forn_lang.Title, default_lang.Title) Title,
ISNULL(forn_lang.Summary, default_lang.Summary) Summary
FROM Translation default_lang
LEFT OUTER JOIN Translation forn_lang ON default_lang.PhraseID = forn_lang.PhraseID AND forn_lang.FkLanguageId = 3
WHERE default_lang.FkLanguageId = 1
Please see attached image.
alt text http://img241.imageshack.us/img241/3585/customcost.png
Can you please tell me what query will work. Please ignore isdefinite and productpriceid columns.
Thanks
If you want a single query, this should do it if I've interpreted your question properly:
SELECT DISTINCT t1.SupplierVenueProductID, [...]
FROM table t1
LEFT JOIN
table t2
ON t1.SupplierVenueProductID = t2.SupplierVenueProductID
AND t2.iscustomcost = 1
WHERE t2.SupplierVenueProductID IS NULL
OR t1.iscustomcost = 1
I don't know your table name, but you join it to itself.
I'm a bit lost on what you want to accomplish here,
going by your requirement if isCustomCost = 1 then return record #3 from SupplierVenueProductId 1 and both records from SupplierVenueProductId 2
Trying to generalize this, I think what you need is :
return all rows from the table, unless when there is a record for a SupplierVenueProductId that has isCustomCost = 1, then only return that record for this SupplierVenueProductId
Which then becomes something along the lines of :
SELECT t1.*
FROM myTable t1
WHERE t1.isCustomCost = 1
OR NOT EXISTs (SELECT *
FROM t2
WHERE t2.SupplierVenueProductId = t1.SupplierVenueProductId
AND t2.isCustomCost = 1)
Hope this helps.