I'm trying to return a couple of 'average if' columns using the following:
select
date,
avg(case when hour >= 23 or hour <= 6) then (select price) else null end) as price1,
avg(case when (hour >= 16 and hour <= 18) then (select price) else null end) as price2
from
xxxxxxxxx
where
date <= '2019-12-31' and
date >= '2018-12-01'
group by
date
order by
date
it works when I use each avg(case when) individually but when I use them both I get the error
Invalid operation: This type of correlated subquery pattern is not supported due to internal error
Why the select in the select?
select date,
avg(case when hour >= 23 or hour <= 6 then price end) as price1,
avg(case when hour >= 16 and hour <= 18 then price end) as price2
from xxxxxxxxx
where date <= '2019-12-31' and
date >= '2018-12-01'
group by date
order by date;
The else null is also redundant.
Related
I currently have this code that I want to sum every quantity based on the year. I have written a code that I thought would sum all the charges in 2016 and 2017, but it isn't running correctly.
I added the two different types of partition by statements to test and see if either would work and they don't. When I take them out, the Annual column just shows me the quantity for that specific receipt.
Here is my current code:
SELECT
ReceiptNumber
,Quantity
,Date
,sum(CASE WHEN (Date >= '2016-01-01' and Date < '2017-01-01') THEN
Quantity
ELSE 0 END)
OVER (PARTITION BY Date)
as Annual2016
,sum(CASE WHEN (Date >= '2017-01-01' and Date < '2018-01-01') THEN
Quantity
ELSE 0 END)
OVER (PARTITION BY ReceiptNumber)
as Annual2017
FROM Table1
GROUP BY ReceiptNumber, Quantity, Date
I would like my data to look like this
ReceiptNumber Quantity Date Annual2016 Annual2017
1 5 2016-01-05 17 13
2 11 2017-04-03 17 13
3 12 2016-11-11 17 13
4 2 2017-09-09 17 13
Here is a sample of some of the data I am pulling from:
ReceiptNumber Quantity Date
1 5 2016-01-05
2 11 2017-04-03
3 12 2016-11-11
4 2 2017-09-09
5 96 2015-07-08
6 15 2016-12-12
7 24 2016-04-19
8 31 2017-01-02
9 10 2017-0404
10 18 2015-10-10
11 56 2017-06-02
Try something like this
Select
..
sum(CASE WHEN (Date >= '2016-01-01' and Date < '2017-01-01') THEN
Quantity
ELSE 0 END)
OVER () as Annual2016
sum(CASE WHEN (Date >= '2017-01-01' and Date < '2018-01-01') THEN
Quantity
ELSE 0 END)
OVER ()as Annual2017
..
Where Date >= '2016-01-01' and Date < '2018-01-01'
If you want it printed only once at the top then you should run it in a separate query like:
SELECT YEAR(Date) y, sum(Quantity) s FROM Table1 GROUP BY YEAR(Date)
and then do the main query like this:
SELECT * FROM table1
Easy, peasey ... ;-)
Your original question could also be answered with:
SELECT *,
(SELECT SUM(Quantity) FROM Table1 WHERE YEAR(Date)=2016 ) Annual2016,
(SELECT SUM(Quantity) FROM Table1 WHERE YEAR(Date)=2017 ) Annual2017
FROM table1
You need some conditional aggreation over a Window Aggregate. Simply remove both PARTITION BY as you're already filtering the year in the CASE:
SELECT
ReceiptNumber
,Quantity
,Date
,sum(CASE WHEN (Date >= '2016-01-01' and Date < '2017-01-01') THEN
Quantity
ELSE 0 END)
OVER () as Annual2016
,sum(CASE WHEN (Date >= '2017-01-01' and Date < '2018-01-01') THEN
Quantity
ELSE 0 END)
OVER () as Annual2017
FROM Table1
You probably don't need the final GROUP BY ReceiptNumber, Quantity, Date
I need count in range two date，this sql is work，bug not better,can you help me?
select dmc.doctor_id,
(
select count(*)
from hele_dct_member_config dmc
WHERE (EXTRACT(YEAR FROM dmc.start_time) = 2016 OR EXTRACT(YEAR FROM dmc.end_time) = 2016) AND dmc.status=1
AND TO_DATE('2016-01-31', 'yyyy-mm-dd') BETWEEN start_time AND end_time
) Jan,
(
select count(*)
from hele_dct_member_config dmc
WHERE (EXTRACT(YEAR FROM dmc.start_time) = 2016 OR EXTRACT(YEAR FROM dmc.end_time) = 2016) AND dmc.status=1
AND TO_DATE('2016-02-28', 'yyyy-mm-dd') BETWEEN start_time AND end_time
) Feb,
.
.
.
from hele_dct_member_config dmc
enter code here
WHERE (EXTRACT(YEAR FROM dmc.start_time) = 2016 OR EXTRACT(YEAR FROM dmc.end_time) = 2016) AND dmc.status=1
grouy by dmc.doctor_id
I need count in range two date，this sql is work，bug not better,can you help me?
Use conditional aggregation:
select dmc.doctor_id,
sum(case when date '2016-01-31' BETWEEN start_time AND end_time then 1 else 0
end) as Jan,
sum(case when date '2016-02-31' BETWEEN start_time AND end_time then 1 else 0
end) as Feb,
.
.
.
from hele_dct_member_config dmc
where (extract(year from dmc.start_time) = 2016 or
extract(year from dmc.end_time) = 2016) AND
dmc.status = 1
group by dmc.doctor_id;
if i want get quarter count ? this is one way
SUM(case when date '2016-01-31' BETWEEN start_time AND end_time then 1 else 0 end) +
SUM(case when date '2016-02-28' BETWEEN start_time AND end_time then 1 else 0 end) +
SUM(case when date '2016-03-31' BETWEEN start_time AND end_time then 1 else 0 end) one
i have the following situation. every row has a timestamp when it was written on table. now i want to evaluate per day how many rows have been inserted before 5 am and how many after. how can that be done??
You can use the HH24 format to get the hour in 24-hour time:
select trunc(created_Date) as the_day
,sum(case when to_number(to_char(created_Date,'HH24')) < 5 then 1 else 0 end) as before_five
,sum(case when to_number(to_char(created_Date,'HH24')) >= 5 then 1 else 0 end) as after_five
from yourtable
group by trunc(created_Date)
Per USER's comment on 5:10, to show timestamps just before and after 5:
select trunc(created_Date) as the_day
,sum(case when to_number(to_char(created_Date,'HH24')) < 5 then 1 else 0 end) as before_five
,sum(case when to_number(to_char(created_Date,'HH24')) >= 5 then 1 else 0 end) as after_five
from (
-- one row januar 1 just after 5:00 a.m.
select to_Date('01/01/2015 05:10:12','dd/mm/yyyy hh24:mi:ss') as created_date from dual
union all
-- one row Januar 2 just before 5:00 a.m.
select to_Date('02/01/2015 04:59:12','dd/mm/yyyy hh24:mi:ss') as created_date from dual
)
group by trunc(created_Date);
THE_DAY, BEFORE_FIVE, AFTER_FIVE
02/01/2015, 1, 0
01/01/2015, 0, 1
Assuming your timestamp is a DATE column:
select trunc(date_written) as day
, count (case when (date_written-trunc(date_written))*24 < 5 then 1 end) before_5_count
, count (case when (date_written-trunc(date_written))*24 >= 5 then 1 end) after_5_count
from mytable
group by trunc(date_written)
select to_char(time_column, 'dd/mm/yyyy'),
sum( decode ( greatest(extract(hour from time_column), 5), extract(hour from time_column), 1, 0)) post_5,
sum( decode ( greatest(extract(hour from time_column), 5), extract(hour from time_column), 0, 1)) pre_5
from test_time
group by to_char(time_column, 'dd/mm/yyyy')
I have a table like:
ID TIMEVALUE
----- -------------
1 06.07.15 06:43:01,000000000
2 06.07.15 12:17:01,000000000
3 06.07.15 18:21:01,000000000
4 06.07.15 23:56:01,000000000
5 07.07.15 04:11:01,000000000
6 07.07.15 10:47:01,000000000
7 07.07.15 12:32:01,000000000
8 07.07.15 14:47:01,000000000
and I want to group this data by special times.
My current query looks like this:
SELECT TO_CHAR(TIMEVALUE, 'YYYY\MM\DD'), COUNT(ID),
SUM(CASE WHEN TO_CHAR(TIMEVALUE, 'HH24MI') <=700 THEN 1 ELSE 0 END) as morning,
SUM(CASE WHEN TO_CHAR(TIMEVALUE, 'HH24MI') >700 AND TO_CHAR(TIMEVALUE, 'HH24MI') <1400 THEN 1 ELSE 0 END) as daytime,
SUM(CASE WHEN TO_CHAR(TIMEVALUE, 'HH24MI') >=1400 THEN 1 ELSE 0 END) as evening FROM Table
WHERE TIMEVALUE >= to_timestamp('05.07.2015','DD.MM.YYYY')
GROUP BY TO_CHAR(TIMEVALUE, 'YYYY\MM\DD')
and I am getting this output
day overall morning daytime evening
----- ---------
2015\07\05 454 0 0 454
2015\07\06 599 113 250 236
2015\07\07 404 139 265 0
so that is fine grouping on the same day (0-7 o'clock, 7-14 o'clock and 14-24 o'clock)
But my question now is:
How can I group over midnight?
For example count from 6-14 , 14-23 and 23-6 o'clock on next day.
I hope you understand my question. You are welcome to even improve my upper query if there is a better solution.
EDIT: It is tested now: SQL Fiddle
The key is simply to adjust the group by so that anything before 6am gets grouped with the previous day. After that, the counts are pretty straight-forward.
SELECT TO_CHAR(CASE WHEN EXTRACT(HOUR FROM timevalue) < 6
THEN timevalue - 1
ELSE timevalue
END, 'YYYY\MM\DD') AS day,
COUNT(*) AS overall,
SUM(CASE WHEN EXTRACT(HOUR FROM timevalue) >= 6 AND EXTRACT(HOUR FROM timevalue) < 14
THEN 1 ELSE 0 END) AS morning,
SUM(CASE WHEN EXTRACT(HOUR FROM timevalue) >= 14 AND EXTRACT(HOUR FROM timevalue) < 23
THEN 1 ELSE 0 END) AS daytime,
SUM(CASE WHEN EXTRACT(HOUR FROM timevalue) < 6 OR EXTRACT(HOUR FROM timevalue) >= 23
THEN 1 ELSE 0 END) AS evening
FROM my_table
WHERE timevalue >= TO_TIMESTAMP('05.07.2015','DD.MM.YYYY')
GROUP BY TO_CHAR(CASE WHEN EXTRACT(HOUR FROM timevalue) < 6
THEN timevalue - 1
ELSE timevalue
END, 'YYYY\MM\DD');
Substract 1 day from timevalue for times lower than '06:00' at first and then:
SQLFiddle demo
select TO_CHAR(day, 'YYYY\MM\DD') day, COUNT(ID) cnt,
SUM(case when '23' < tvh or tvh <= '06' THEN 1 ELSE 0 END) as midnight,
SUM(case when '06' < tvh and tvh <= '14' THEN 1 ELSE 0 END) as daytime,
SUM(case when '14' < tvh and tvh <= '23' THEN 1 ELSE 0 END) as evening
FROM (
select id, to_char(TIMEVALUE, 'HH24') tvh,
trunc(case when (to_char(timevalue, 'hh24') <= '06')
then timevalue - interval '1' day
else timevalue end) day
from t1
)
GROUP BY day
Maybe you can do it like this (with some reformatting or PIVOT):
WITH spans AS
(SELECT TIMESTAMP '2015-01-01 00:00:00' + LEVEL * INTERVAL '1' HOUR AS start_time
FROM dual
CONNECT BY TIMESTAMP '2015-01-01 00:00:00' + LEVEL * INTERVAL '1' HOUR < LOCALTIMESTAMP),
t AS
(SELECT start_time, lead(start_time, 1) OVER (ORDER BY start_time) AS end_time, ROWNUM AS N
FROM spans
WHERE EXTRACT(HOUR FROM start_time) IN (6,14,23))
SELECT N, start_time, end_time, COUNT(*) AS ID_COUNT,
DECODE(EXTRACT(HOUR FROM start_time), 6,'morning', 14,'daytime', 23,'evening') AS daytime
FROM t
JOIN YOUR_TABLE WHERE TIMEVALUE BETWEEN start_time AND end_time
GROUP BY N;
Of course, the initial time value ('2015-01-01 00:00:00' in my example) has to be lower than the least date in your table.
I'm trying to return some results spread over a rolling 12 month period eg:
MONTH IN OUT
January 210 191
February 200 111
March 132 141
April 112 141
May 191 188
etc...
How do I spread the results over a date range, populating the first column with the month name?
IN MSSQL it would be something like:
SELECT COUNT(problem.problem_type = 'IN') AS IN,
COUNT(problem.problem_type = 'OUT') AS OUT,
DATEPART(year, DateTime) as Year,
DATEPART(month, DateTime) as Month
FROM problem
WHERE (DateTime >= dbo.FormatDateTime('2010-01-01'))
AND
(DateTime < dbo.FormatDateTime('2010-01-31'))
GROUP BY DATEPART(year, DateTime),
DATEPART(month, DateTime);
But this is against an Oracle database so DATEPART and DateTime are not available.
My Problem table is roughly:
problem_ID Problem_type IN_Date OUT_Date
1 IN 2010-01-23 16:34:29.0 2010-02-29 13:06:28.0
2 IN 2010-01-27 12:34:29.0 2010-01-29 12:01:28.0
3 OUT 2010-02-13 13:24:29.0 2010-09-29 15:04:28.0
4 OUT 2010-02-15 16:31:29.0 2010-07-29 11:03:28.0
Use:
SELECT SUM(CASE WHEN p.problem_type = 'IN' THEN 1 ELSE 0 END) AS IN,
SUM(CASE WHEN p.problem_type = 'OUT' THEN 1 ELSE 0 END) AS OUT,
TO_CHAR(datetime, 'YYYY') AS year,
TO_CHAR(datetime, 'MM') AS month
FROM PROBLEM p
WHERE p.DateTime >= TO_DATE('2010-01-01', 'YYYY-MM-DD')
AND p.DateTime < TO_DATE('2010-01-31', 'YYYY-MM-DD')
GROUP BY TO_CHAR(datetime, 'YYYY'), TO_CHAR(datetime, 'MM')
You could also use:
SELECT SUM(CASE WHEN p.problem_type = 'IN' THEN 1 ELSE 0 END) AS IN,
SUM(CASE WHEN p.problem_type = 'OUT' THEN 1 ELSE 0 END) AS OUT,
TO_CHAR(datetime, 'MM-YYYY') AS mon_year
FROM PROBLEM p
WHERE p.DateTime >= TO_DATE('2010-01-01', 'YYYY-MM-DD')
AND p.DateTime < TO_DATE('2010-01-31', 'YYYY-MM-DD')
GROUP BY TO_CHAR(datetime, 'MM-YYYY')
Reference:
TO_CHAR
TO_DATE
You probably want something like
SELECT SUM( (CASE WHEN problem_type = 'IN' THEN 1 ELSE 0 END) ) in,
SUM( (CASE WHEN problem_type = 'OUT' THEN 1 ELSE 0 END) ) out,
EXTRACT( year FROM DateTime ) year,
EXTRACT( month FROM DateTime ) month
FROM problem
WHERE DateTime >= date '2010-01-01'
AND DateTime < date '2010-01-31'
GROUP BY EXTRACT( year FROM DateTime ),
EXTRACT( month FROM DateTime )