I need count in range two date，this sql is work，bug not better,can you help me?
select dmc.doctor_id,
(
select count(*)
from hele_dct_member_config dmc
WHERE (EXTRACT(YEAR FROM dmc.start_time) = 2016 OR EXTRACT(YEAR FROM dmc.end_time) = 2016) AND dmc.status=1
AND TO_DATE('2016-01-31', 'yyyy-mm-dd') BETWEEN start_time AND end_time
) Jan,
(
select count(*)
from hele_dct_member_config dmc
WHERE (EXTRACT(YEAR FROM dmc.start_time) = 2016 OR EXTRACT(YEAR FROM dmc.end_time) = 2016) AND dmc.status=1
AND TO_DATE('2016-02-28', 'yyyy-mm-dd') BETWEEN start_time AND end_time
) Feb,
.
.
.
from hele_dct_member_config dmc
enter code here
WHERE (EXTRACT(YEAR FROM dmc.start_time) = 2016 OR EXTRACT(YEAR FROM dmc.end_time) = 2016) AND dmc.status=1
grouy by dmc.doctor_id
I need count in range two date，this sql is work，bug not better,can you help me?
Use conditional aggregation:
select dmc.doctor_id,
sum(case when date '2016-01-31' BETWEEN start_time AND end_time then 1 else 0
end) as Jan,
sum(case when date '2016-02-31' BETWEEN start_time AND end_time then 1 else 0
end) as Feb,
.
.
.
from hele_dct_member_config dmc
where (extract(year from dmc.start_time) = 2016 or
extract(year from dmc.end_time) = 2016) AND
dmc.status = 1
group by dmc.doctor_id;
if i want get quarter count ? this is one way
SUM(case when date '2016-01-31' BETWEEN start_time AND end_time then 1 else 0 end) +
SUM(case when date '2016-02-28' BETWEEN start_time AND end_time then 1 else 0 end) +
SUM(case when date '2016-03-31' BETWEEN start_time AND end_time then 1 else 0 end) one
Related
I'm trying to return a couple of 'average if' columns using the following:
select
date,
avg(case when hour >= 23 or hour <= 6) then (select price) else null end) as price1,
avg(case when (hour >= 16 and hour <= 18) then (select price) else null end) as price2
from
xxxxxxxxx
where
date <= '2019-12-31' and
date >= '2018-12-01'
group by
date
order by
date
it works when I use each avg(case when) individually but when I use them both I get the error
Invalid operation: This type of correlated subquery pattern is not supported due to internal error
Why the select in the select?
select date,
avg(case when hour >= 23 or hour <= 6 then price end) as price1,
avg(case when hour >= 16 and hour <= 18 then price end) as price2
from xxxxxxxxx
where date <= '2019-12-31' and
date >= '2018-12-01'
group by date
order by date;
The else null is also redundant.
I want to get statistics with sql query. My table is like this:
ID MATERIAL CREATEDATE DEPARTMENT
1 M1 10.10.1980 D1
2 M2 11.02.1970 D2
2 M3 18.04.1971 D3
.....................
.....................
.....................
How can I get a range of data count like this
DEPARTMENT AGE<10 10<AGE<20 20<AGE
D1 24 123 324
D2 24 123 324
Assuming that CREATEDATE is a date column, in PostgreSQL you can use the AGE function:
select DEPARTMENT, age(CREATEDATE) as AGE
from Materials
and with date_part you can get the age in years. To show the data in the format that you want, you could use this GROUP BY query:
select
DEPARTMENT,
sum(case when date_part('year', age(CREATEDATE))<10 then 1 end) as "age<10",
sum(case when date_part('year', age(CREATEDATE))>=10 and date_part('year', age(CREATEDATE))<20 then 1 end) as "10<age<20",
sum(case when date_part('year', age(CREATEDATE))>=20 then 1 end) as "20<age"
from
Materials
group by
DEPARTMENT
which can be simplified as:
with mat_age as (
select DEPARTMENT, date_part('year', age(CREATEDATE)) as mage
from Materials
)
select
DEPARTMENT,
sum(case when mage<10 then 1 end) as "age<10",
sum(case when mage>=10 and mage<20 then 1 end) as "10<age<20",
sum(case when mage>=20 then 1 end) as "20<age"
from
mat_age
group by
DEPARTMENT;
if you are using PostgreSQL 9.4 you can use FILTER:
with mat_age as (
select DEPARTMENT, date_part('year', age(CREATEDATE)) as mage
from Materials
)
select
DEPARTMENT,
count(*) filter (where mage<10) as "age<10",
count(*) filter (where mage>=10 and mage<20) as "10<age<20",
count(*) filter (where mage>=20) as "20<age"
from
mat_age
group by
DEPARTMENT;
The following solution assumes that your CREATEDATE column exists as some sort of valid Postgres date type. If this be not the case, and it is being stored as text, you will first have to convert it to date in order for the query to work.
SELECT DEPARTMENT,
SUM(CASE WHEN DATEDIFF(year, CREATEDATE, now()::date) < 10 THEN 1 ELSE 0 END) AS "AGE<10",
SUM(CASE WHEN DATEDIFF(year, CREATEDATE, now()::date) >= 10 AND
DATEDIFF(year, CREATEDATE, now()::date) < 20 THEN 1 ELSE 0 END) AS "10<AGE<20",
SUM(CASE WHEN DATEDIFF(year, CREATEDATE, now()::date) >= 20 THEN 1 ELSE 0 END) AS "20<AGE"
FROM Materials
GROUP BY DEPARTMENT
You can use extract(year FROM age(createdate)) to get the exact age
i.e
select extract(year FROM age(timestamp '01-01-1989')) age
will give you
Result:
age
---
27
so you can use following select statement to get your desired output:
SELECT dept
,sum(CASE WHEN age < 10THEN 1 END) "age<10"
,sum(CASE WHEN age >= 10 AND age < 20 THEN 1 END) "10<age<20"
,sum(CASE WHEN age >= 20 THEN 1 END) "20<age"
FROM (
SELECT dept,extract(year FROM age(crdate)) age
FROM dt
) t
GROUP BY dept
If you don't want to use a sub select use this.
SELECT dept
,sum(CASE WHEN extract(year FROM age(crdate)) < 10THEN 1 END) "age<10"
,sum(CASE WHEN extract(year FROM age(crdate)) >= 10 AND extract(year FROM age(crdate)) < 20 THEN 1 END) "10<age<20"
,sum(CASE WHEN extract(year FROM age(crdate)) >= 20 THEN 1 END) "20<age"
FROM dt
GROUP BY dept
i have the following situation. every row has a timestamp when it was written on table. now i want to evaluate per day how many rows have been inserted before 5 am and how many after. how can that be done??
You can use the HH24 format to get the hour in 24-hour time:
select trunc(created_Date) as the_day
,sum(case when to_number(to_char(created_Date,'HH24')) < 5 then 1 else 0 end) as before_five
,sum(case when to_number(to_char(created_Date,'HH24')) >= 5 then 1 else 0 end) as after_five
from yourtable
group by trunc(created_Date)
Per USER's comment on 5:10, to show timestamps just before and after 5:
select trunc(created_Date) as the_day
,sum(case when to_number(to_char(created_Date,'HH24')) < 5 then 1 else 0 end) as before_five
,sum(case when to_number(to_char(created_Date,'HH24')) >= 5 then 1 else 0 end) as after_five
from (
-- one row januar 1 just after 5:00 a.m.
select to_Date('01/01/2015 05:10:12','dd/mm/yyyy hh24:mi:ss') as created_date from dual
union all
-- one row Januar 2 just before 5:00 a.m.
select to_Date('02/01/2015 04:59:12','dd/mm/yyyy hh24:mi:ss') as created_date from dual
)
group by trunc(created_Date);
THE_DAY, BEFORE_FIVE, AFTER_FIVE
02/01/2015, 1, 0
01/01/2015, 0, 1
Assuming your timestamp is a DATE column:
select trunc(date_written) as day
, count (case when (date_written-trunc(date_written))*24 < 5 then 1 end) before_5_count
, count (case when (date_written-trunc(date_written))*24 >= 5 then 1 end) after_5_count
from mytable
group by trunc(date_written)
select to_char(time_column, 'dd/mm/yyyy'),
sum( decode ( greatest(extract(hour from time_column), 5), extract(hour from time_column), 1, 0)) post_5,
sum( decode ( greatest(extract(hour from time_column), 5), extract(hour from time_column), 0, 1)) pre_5
from test_time
group by to_char(time_column, 'dd/mm/yyyy')
I have a table like:
ID TIMEVALUE
----- -------------
1 06.07.15 06:43:01,000000000
2 06.07.15 12:17:01,000000000
3 06.07.15 18:21:01,000000000
4 06.07.15 23:56:01,000000000
5 07.07.15 04:11:01,000000000
6 07.07.15 10:47:01,000000000
7 07.07.15 12:32:01,000000000
8 07.07.15 14:47:01,000000000
and I want to group this data by special times.
My current query looks like this:
SELECT TO_CHAR(TIMEVALUE, 'YYYY\MM\DD'), COUNT(ID),
SUM(CASE WHEN TO_CHAR(TIMEVALUE, 'HH24MI') <=700 THEN 1 ELSE 0 END) as morning,
SUM(CASE WHEN TO_CHAR(TIMEVALUE, 'HH24MI') >700 AND TO_CHAR(TIMEVALUE, 'HH24MI') <1400 THEN 1 ELSE 0 END) as daytime,
SUM(CASE WHEN TO_CHAR(TIMEVALUE, 'HH24MI') >=1400 THEN 1 ELSE 0 END) as evening FROM Table
WHERE TIMEVALUE >= to_timestamp('05.07.2015','DD.MM.YYYY')
GROUP BY TO_CHAR(TIMEVALUE, 'YYYY\MM\DD')
and I am getting this output
day overall morning daytime evening
----- ---------
2015\07\05 454 0 0 454
2015\07\06 599 113 250 236
2015\07\07 404 139 265 0
so that is fine grouping on the same day (0-7 o'clock, 7-14 o'clock and 14-24 o'clock)
But my question now is:
How can I group over midnight?
For example count from 6-14 , 14-23 and 23-6 o'clock on next day.
I hope you understand my question. You are welcome to even improve my upper query if there is a better solution.
EDIT: It is tested now: SQL Fiddle
The key is simply to adjust the group by so that anything before 6am gets grouped with the previous day. After that, the counts are pretty straight-forward.
SELECT TO_CHAR(CASE WHEN EXTRACT(HOUR FROM timevalue) < 6
THEN timevalue - 1
ELSE timevalue
END, 'YYYY\MM\DD') AS day,
COUNT(*) AS overall,
SUM(CASE WHEN EXTRACT(HOUR FROM timevalue) >= 6 AND EXTRACT(HOUR FROM timevalue) < 14
THEN 1 ELSE 0 END) AS morning,
SUM(CASE WHEN EXTRACT(HOUR FROM timevalue) >= 14 AND EXTRACT(HOUR FROM timevalue) < 23
THEN 1 ELSE 0 END) AS daytime,
SUM(CASE WHEN EXTRACT(HOUR FROM timevalue) < 6 OR EXTRACT(HOUR FROM timevalue) >= 23
THEN 1 ELSE 0 END) AS evening
FROM my_table
WHERE timevalue >= TO_TIMESTAMP('05.07.2015','DD.MM.YYYY')
GROUP BY TO_CHAR(CASE WHEN EXTRACT(HOUR FROM timevalue) < 6
THEN timevalue - 1
ELSE timevalue
END, 'YYYY\MM\DD');
Substract 1 day from timevalue for times lower than '06:00' at first and then:
SQLFiddle demo
select TO_CHAR(day, 'YYYY\MM\DD') day, COUNT(ID) cnt,
SUM(case when '23' < tvh or tvh <= '06' THEN 1 ELSE 0 END) as midnight,
SUM(case when '06' < tvh and tvh <= '14' THEN 1 ELSE 0 END) as daytime,
SUM(case when '14' < tvh and tvh <= '23' THEN 1 ELSE 0 END) as evening
FROM (
select id, to_char(TIMEVALUE, 'HH24') tvh,
trunc(case when (to_char(timevalue, 'hh24') <= '06')
then timevalue - interval '1' day
else timevalue end) day
from t1
)
GROUP BY day
Maybe you can do it like this (with some reformatting or PIVOT):
WITH spans AS
(SELECT TIMESTAMP '2015-01-01 00:00:00' + LEVEL * INTERVAL '1' HOUR AS start_time
FROM dual
CONNECT BY TIMESTAMP '2015-01-01 00:00:00' + LEVEL * INTERVAL '1' HOUR < LOCALTIMESTAMP),
t AS
(SELECT start_time, lead(start_time, 1) OVER (ORDER BY start_time) AS end_time, ROWNUM AS N
FROM spans
WHERE EXTRACT(HOUR FROM start_time) IN (6,14,23))
SELECT N, start_time, end_time, COUNT(*) AS ID_COUNT,
DECODE(EXTRACT(HOUR FROM start_time), 6,'morning', 14,'daytime', 23,'evening') AS daytime
FROM t
JOIN YOUR_TABLE WHERE TIMEVALUE BETWEEN start_time AND end_time
GROUP BY N;
Of course, the initial time value ('2015-01-01 00:00:00' in my example) has to be lower than the least date in your table.
I'm trying to return some results spread over a rolling 12 month period eg:
MONTH IN OUT
January 210 191
February 200 111
March 132 141
April 112 141
May 191 188
etc...
How do I spread the results over a date range, populating the first column with the month name?
IN MSSQL it would be something like:
SELECT COUNT(problem.problem_type = 'IN') AS IN,
COUNT(problem.problem_type = 'OUT') AS OUT,
DATEPART(year, DateTime) as Year,
DATEPART(month, DateTime) as Month
FROM problem
WHERE (DateTime >= dbo.FormatDateTime('2010-01-01'))
AND
(DateTime < dbo.FormatDateTime('2010-01-31'))
GROUP BY DATEPART(year, DateTime),
DATEPART(month, DateTime);
But this is against an Oracle database so DATEPART and DateTime are not available.
My Problem table is roughly:
problem_ID Problem_type IN_Date OUT_Date
1 IN 2010-01-23 16:34:29.0 2010-02-29 13:06:28.0
2 IN 2010-01-27 12:34:29.0 2010-01-29 12:01:28.0
3 OUT 2010-02-13 13:24:29.0 2010-09-29 15:04:28.0
4 OUT 2010-02-15 16:31:29.0 2010-07-29 11:03:28.0
Use:
SELECT SUM(CASE WHEN p.problem_type = 'IN' THEN 1 ELSE 0 END) AS IN,
SUM(CASE WHEN p.problem_type = 'OUT' THEN 1 ELSE 0 END) AS OUT,
TO_CHAR(datetime, 'YYYY') AS year,
TO_CHAR(datetime, 'MM') AS month
FROM PROBLEM p
WHERE p.DateTime >= TO_DATE('2010-01-01', 'YYYY-MM-DD')
AND p.DateTime < TO_DATE('2010-01-31', 'YYYY-MM-DD')
GROUP BY TO_CHAR(datetime, 'YYYY'), TO_CHAR(datetime, 'MM')
You could also use:
SELECT SUM(CASE WHEN p.problem_type = 'IN' THEN 1 ELSE 0 END) AS IN,
SUM(CASE WHEN p.problem_type = 'OUT' THEN 1 ELSE 0 END) AS OUT,
TO_CHAR(datetime, 'MM-YYYY') AS mon_year
FROM PROBLEM p
WHERE p.DateTime >= TO_DATE('2010-01-01', 'YYYY-MM-DD')
AND p.DateTime < TO_DATE('2010-01-31', 'YYYY-MM-DD')
GROUP BY TO_CHAR(datetime, 'MM-YYYY')
Reference:
TO_CHAR
TO_DATE
You probably want something like
SELECT SUM( (CASE WHEN problem_type = 'IN' THEN 1 ELSE 0 END) ) in,
SUM( (CASE WHEN problem_type = 'OUT' THEN 1 ELSE 0 END) ) out,
EXTRACT( year FROM DateTime ) year,
EXTRACT( month FROM DateTime ) month
FROM problem
WHERE DateTime >= date '2010-01-01'
AND DateTime < date '2010-01-31'
GROUP BY EXTRACT( year FROM DateTime ),
EXTRACT( month FROM DateTime )