Error parse JSON missing comma pos <number> - sql

Question

I have a column with a varchar and want to convert it to a JSON by parse_Json.
({u'meta': {u'removedAt': None, u'validation': {u'createdTime': 157....)
When I use :
select get_path(PARSE_JSON(OFFER), 'field') from
this error occours: SQL-Fehler [100069] [22P02]: Error parsing JSON: missing colon, pos 3.
So I try to add a Colon at position 3
select get_path(PARSE_JSON(REPLACE (offer,'u','u:')), 'field') from
So this error occurred SQL-Fehler [100069] [22P02]: Error parsing JSON: misplaced colon, pos 10
By now I don't know how do handle this and the information by snowflake doesnt really help.
https://support.snowflake.net/s/article/error-error-parsing-json-missing-comma-pos-number
Thanks for your help

Answer 1

Your 'JSON input' is actually a Python representation string of its dictionary data structure, and is not a valid JSON format. While dictionaries in Python may appear similar to JSON when printed in an interactive shell, they are not the same.
To produce valid JSON from your Python objects, use the json module's dump or dumps functions, and then use the proper string serialized JSON form in your parse_json function.