I would like to have a list of all mountains names of the "dbo:firstAscentPerson" property of Lionel Terray (dbpedia: http://dbpedia.org/page/Lionel_Terray).
This below is what I have so far
select ?person ?firstAscentPerson where {
?person foaf:name "Lionel Terray"#en.
dbo:firstAscentPerson rdfs:label ?firstAscentPerson.
} LIMIT 100
The following query does what you need:
SELECT ?mountain ?mountainName ?person2 ?person2Name {
VALUES ?person1Name {"Lionel Terray"#en}
?mountain dbo:firstAscentPerson ?person1, ?person2 .
?mountain rdfs:label ?mountainName .
?person1 foaf:name ?person1Name .
FILTER (lang(?mountainName) = "en")
OPTIONAL {?person2 foaf:name ?person2Name . FILTER (lang(?person2Name) = 'en')}
}
Related
Why can get results with this query:
SELECT *
WHERE {
?person rdfs:label "Kirk Douglas"#en;
dbo:birthPlace ?place. # With dbp: too
}
but not with another one:
SELECT *
WHERE {
?person rdfs:label "Kirk Douglas"#en;
dbo:starring ?film.
}
I'm following tags in https://dbpedia.org/page/Kirk_Douglas
Some tip to understand it.
Thx!
In dbr:Kirk_Douglas you can read:
dbo:birthPlace dbr:Amsterdam_(city),_New_York
...
is dbo:starring of dbr:The_Light_at_the_Edge_of_the_World
dbr:Cast_a_Giant_Shadow
dbr:Two-Fisted_Tales_(film)
...
where is dbo:starring of is a way of simulating an inverse property for dbo:starring.
Indeed, in dbo:starring you can read:
rdfs:domain dbo:Work
...
rdfs:range dbo:Actor
This means that you shouldn't build triples like ?actor dbo:starring ?work, while ?work dbo:starring ?actor is a valid triple.
So your query should be something like:
SELECT *
WHERE {
?person rdfs:label "Kirk Douglas"#en .
?film dbo:starring ?person .
}
I wrote the following SPARQL query to find the wikidata item with the label "San Leucio" in Italy.
SELECT DISTINCT * WHERE {
?location ?label 'San Leucio'#en .
?location wdt:P17 wd:Q38 .
?location rdfs:label ?locationName .
OPTIONAL {
?article schema:about ?location .
?article schema:isPartOf <https://en.wikivoyage.org/> .
}
?location wdt:P18 ?image .
FILTER(lang(?locationName) = "en")
}
The query returns these 3 results:
wd:Q55179410
wd:Q20009063
wd:Q846499
The result I want is wd:Q846499, which is outside of Naples, Italy. Is there any way I could further filter this query to return the result that is nearest to Naples? I know that I can get the geoCoordinates for each of these with ?location wdt:P625 ?coordinates, but I'm not sure how I could use that to compare to the geo-coordinates of Naples to get what I want.
SELECT DISTINCT * {
VALUES ?naples {wd:Q2634}
?Napfes wdt:P625 ?naples_coordinates.
?location rdfs:label 'San Leucio'#en .
?location wdt:P17 wd:Q38 .
?location wdt:P18 ?image .
?location wdt:P625 ?location_coordinates.
OPTIONAL {
?article schema:about ?location .
?article schema:isPartOf <https://en.wikivoyage.org/> .
}
BIND (geof:distance(?location_coordinates, ?naples_coordinates) AS ?distance)
} ORDER BY ?distance LIMIT 1
I'm developing my own Fuseki endpoint from some DBpedia data.
I'm in doubt on how to aggregate properties related to a single resource.
SELECT ?name ?website ?abstract ?genre ?image
WHERE{
VALUES ?s {<http://dbpedia.org/resource/Attack_Attack!>}
?s foaf:name ?name ;
dbo:abstract ?abstract .
OPTIONAL { ?s dbo:genre ?genre } .
OPTIONAL { ?s dbp:website ?website } .
OPTIONAL { ?s dbo:image ?image } .
FILTER LANGMATCHES(LANG(?abstract ), "en")
}
SPARQL endpoint: http://dbpedia.org/sparql/
This query returns 2 matching results. They are different just for the dbo:genre value. There is a way I can query the knowledge base and retrieving a single result with a list of genres?
#chrisis's query works well on the DBpedia SPARQL Endpoint, which is based on Virtuoso.
However, if you are using Jena Fuseki, you should use more conformant syntax:
PREFIX dbo: <http://dbpedia.org/ontology/>
PREFIX dbp: <http://dbpedia.org/property/>
SELECT
?name
(SAMPLE(?website) AS ?sample_website)
(SAMPLE(?abstract) AS ?sample_abstract)
(SAMPLE(?image) AS ?sample_image)
(GROUP_CONCAT(?genre; separator=', ') AS ?genres)
WHERE {
VALUES (?s) {(<http://dbpedia.org/resource/Attack_Attack!>)}
?s foaf:name ?name ;
dbo:abstract ?abstract .
OPTIONAL { ?s dbo:genre ?genre } .
OPTIONAL { ?s dbp:website ?website } .
OPTIONAL { ?s dbo:image ?image} .
FILTER LANGMATCHES(LANG(?abstract ), "en")
} GROUP BY ?name
The differences from the #chrisis's query are:
Since GROUP_CONCAT is an aggregation function, it might be used with GROUP BY only;
Since GROUP BY is used, all non-grouping variables should be aggregated (e.g. via SAMPLE);
GROUP_CONCAT syntax is slightly different.
In Fuseki, these AS in the projection are in fact superfluous: see this question and comments.
Yes, the GROUP_CONCAT() function is what you want.
SELECT ?name ?website ?abstract (GROUP_CONCAT(?genre,',') AS ?genres) ?image
WHERE{
<http://dbpedia.org/resource/Attack_Attack!> a dbo:Band ;
foaf:name ?name;
dbo:abstract ?abstract .
OPTIONAL{ <http://dbpedia.org/resource/Attack_Attack!> dbo:genre ?genre } .
OPTIONAL{ <http://dbpedia.org/resource/Attack_Attack!> dbp:website ?website} .
OPTIONAL{ <http://dbpedia.org/resource/Attack_Attack!> dbo:image ?image} .
FILTER LANGMATCHES(LANG(?abstract ), "en")
}
I'm trying to grab some definition in dbpedia inside my thesaurus.
Although can find country that have a label that match my country, i don't get all of them. So i try to match similar label with contains but it does not work.
Any idea why.
SELECT distinct ?idbcountry ?label ?labelDb ?def
WHERE {
?idbcountry a skos:Concept .
?idbcountry rdfs:label ?label .
?idbcountry skos:inScheme iadb:IdBCountries .
FILTER(lang(?label) = "en")
Service <http://dbpedia.org/sparql> {
?s a <http://dbpedia.org/ontology/Country> .
?s rdfs:label ?labelDb .
FILTER(CONTAINS (?labelDb, ?label)).
?s rdfs:comment ?def .
FILTER(lang(?def) = "en") .
FILTER(lang(?labelDb) = "en") .
}}
The exact matching query that works is as follows:
SELECT distinct ?idbcountry ?label ?def
WHERE {
?idbcountry a skos:Concept .
?idbcountry rdfs:label ?label .
?idbcountry skos:inScheme iadb:IdBCountries .
FILTER(lang(?label) = "en")
Service <http://dbpedia.org/sparql> {
?s a <http://dbpedia.org/ontology/Country> .
?s rdfs:label ?label .
?s rdfs:comment ?def
FILTER(lang(?def) = "en")
}
}
EDIT1
Data Samples:
<http://thesaurus.iadb.org/publicthesauri/10157002136735779158437>
rdf:type skos:Concept ;
dct:created "2015-03-27T16:43:48.052-04:00"^^xsd:dateTime ;
rdfs:label "BO"#en ;
rdfs:label "Bolivia"#en ;
rdfs:label "Bolivia"#es ;
rdfs:label "Bolivie"#fr ;
rdfs:label "Bolívia"#pt ;
skos:altLabel "BO"#en ;
skos:definition "Bolivia (/bəˈlɪviə/, Spanish: [boˈliβja], Quechua: Buliwya, Aymara: Wuliwya), officially known as the Plurinational State of Bolivia (Spanish: Estado Plurinacional de Bolivia locally: [esˈtaðo pluɾinasjoˈnal de βoˈliβja]), is a landlocked country located in western-central South America."#en ;
skos:inScheme :IdBCountries ;
skos:prefLabel "Bolivia"#en ;
skos:prefLabel "Bolivia"#es ;
skos:prefLabel "Bolivie"#fr ;
skos:prefLabel "Bolívia"#pt ;
skos:topConceptOf :IdBCountries ;
<http://xmlns.com/foaf/0.1/focus> <http://dbpedia.org/resource/Bolivia> ;
Without seeing your data, we can't know why your query isn't working. However, using contains is pretty straightforward. It's just a matter of contains(string,substring). As Jeen said, we can't reproduce your problem without knowing what your data looks like, but here's an example of contains in action:
select distinct ?country ?label {
?country a dbpedia-owl:Country ; #-- select countries
rdfs:label ?label . #-- and get labels
filter langMatches(lang(?label),"en") #-- but only English labels
filter contains(?label,"land") #-- containing "land"
}
SPARQL results
To get movie detail from linkedmdb, I used sparql query :
PREFIX mdb: <http://data.linkedmdb.org/resource/movie/film>
SELECT DISTINCT ?Title ?Genre ?Actor ?Country ?Director ?Year WHERE {
?film mdb:id ?uri .
?film dc:title ?Title .
?film movie:genre ?filmgenre.
?filmgenre movie:film_genre_name ?Genre .
?film movie:actor ?cast .
?cast movie:actor_name ?Actor .
?film movie:country ?Ctr .
?Ctr movie:country_name ?Country .
?film dc:date ?Year .
?film movie:director ?Drc .
?Drc movie:director_name ?Director
FILTER regex(?Title, "Kingdom of Heaven")
}
But SPARQL results shown Title same as counted Actor . How to combine the query so that Title is not repeated?
I've try using GROUP_CONCAT but not working in LinkedMDB Endpoint?
Could someone guide me?