The table meat_poultry_egg_inspect is being updated where column zip is being set to something wherever column st matches with PR, VR and length of zip is 3. I think its making the zip column into a five digit value: '00 + zip'.
UPDATE meat_poultry_egg_inspect
SET zip = '00' || zip
WHERE st IN('PR','VI') AND length(zip) = 3;
The || is the operator for string concatenation.
This is the SQL standard operator, although not all databases support it.
Related
I need to write a T-SQL procedure where the parameter is zip code. We've got the following parameter declared.
declare #postal_code varchar(10)
Sample data in table:
postal_codes
NULL
46383
074523632
B4H34
113601419
ZH/8600
A1G 9Z9
WN73R
Wd3 3he
89136
etc. We've got a variety of addresses some having no postal code for certain foreign countries to some having your standard 5 digit or 10 digit US postal codes.
I need to code the query in some way to say:
select *
from table_name
where postal_code = #postal_code
My initial code was this:
select *
from table_name
where (#postal_code is null or
left(ad.postal_code, 5) = #postal_code)
but this doesn't work for anything other then 5 digit ones, then I tried using 10 digit ones but the 5 digit ones didn't match. Do I need to strip spaces or other characters? I tried searching and there is a variety of solutions but I need something that works for all kinds of zip codes foreign and domestic.
Based on your last comment it sounds like you need a "starts with" query. Try this
SELECT *
FROM table_name
WHERE REPLACE(postal_code, ' ', '') LIKE REPLACE(#postal_code, ' ', '') + '%';
Was working on SQL-EX.ru exercises.
There is one question for DML that I could not do, but I cannot proceed to the next one, until this one is done.
the question itself: All the trailing spaces in the name column of the Battles table remove and add them at the beginning of the name.
My code:
Update Battles
set name=concat(' ',(LTRIM(RTRIM(name))))
The system does not let it go through, I understand that I am using ' ' for the concat, whereas I need to use the stuff that got trimmed. And I have no idea how...
Any help would be very much appreciated
Try Something Like:-
set name = lpad(trim(name), length(trim(name))+4, ' ')
Here use TRIM to remove space from both side. use LPAD to add something on left side with n (4) chars
I'm not familiar with SQL-EX.ru, but if it's Oracle compatible and you can use regular expressions (or you are at that point in the training) here's a way. Maybe it'll give you an idea at least. The first part is just setup and uses a WITH clause to create a table (like a temp table in memory, actually called a Common Table Expression or CTE) called battles containing a name column with 2 rows. Each name column datum has a different number of spaces at the end. Next select from that column using a regular expression that uses 2 "remembered" groups surrounded by parentheses, the first containing the string up to until but not including the first space, the second containing 0 or more space characters anchored to the end of the line. Replace that with the 2nd group (the spaces) first, followed by the first group (the first part of the string). This is surrounded by square brackets just to prove in the output the same spaces were moved to the front of the string.
SQL> with battles(name) as (
select 'test2 ' from dual union
select 'test1 ' from dual
)
select '[' || regexp_replace(name, '(.*?)([ ]*)$', '\2\1') || ']' fixed
from battles;
FIXED
----------------------------------------------------------------------------
[ test1]
[ test2]
SQL>
I hope this solution can be applied to your problem or at least give you some ideas.
Try this:
set name = case when len(name) > len(rtrim(name))
then replicate(' ', len(name) - len(rtrim(name))) + rtrim(name)
else name
end
update battles
set name = case when (len(name+'a')-1) > len(rtrim(name))
then
replicate(' ',
(len(name+'a')-1) - len(rtrim(name))) + rtrim(name)
else name
end
Len() doesn't count trailing spaces. So using (len(name+'a')-1).
Simplest answer:
UPDATE Battles
SET name = SPACE(DATALENGTH(name)-DATALENGTH(RTRIM(name))) + RTRIM(name)
But only works because name is VARCHAR.
More generic is to do:
UPDATE Battles
SET name = SPACE(len(name+'x')-1-len(RTRIM(name))) + RTRIM(name)
simple example below ... enjoy :)
update battles set name =
Space( DATALENGTH(name) - DATALENGTH(rtrim(name))) + rtrim(name)
where date in ( select date from battles)
I have three columns for a person's name (first middle last) and a column for a user ID.
The purpose of this code is to find persons with a UserID that does not match their name.
The UserID is created by taking the FIRST letter of the first name, the FIRST letter of the middle name and the FULL last name. Mary Jane Smith would have the UserID of MJSmith34. Random numbers are added to the end when there is more than one MJSmith, but this does not matter for what I need.
The code below compares the person's last name in two areas. If they do not match, it means that the person's name has been changed. What I need now is to check the UserID against the most current First Middle Last name to see if the UserID need to be changed (updated). The Pseudocode is what I need, but I am not sure if it can even be done. Please help!!
Select DISTINCT
NL.spriden_id as "STU_ID",
NL.SPRIDEN_LAST_NAME as "Last_Name" ,
NL.SPRIDEN_FIRST_NAME as "First_Name"
FROM SARADAP SA
JOIN SPRIDEN NM -- NM is Name
ON SA.SARADAP_PIDM = NM.SPRIDEN_PIDM
JOIN SPRIDEN NL -- NL is null
ON SA.SARADAP_PIDM = NL.SPRIDEN_PIDM
JOIN IDTABLE ID
ON ST.SOMETABLE_PIDM = ID.IDTABLE_PIDM =
WHERE
NM.SPRIDEN_CHANGE_IND LIKE '%N%'
AND
NL.SPRIDEN_CHANGE_IND IS NULL
AND
NL.SPRIDEN_ACTIVITY_DATE between sysdate - 10 and sysdate
AND
NL.spriden_id LIKE 'A00%'
AND
lower(NL.SPRIDEN_LAST_NAME) <> lower(NM.SPRIDEN_LAST_NAME)
AND
NL.SPRIDEN_ACTIVITY_DATE <> NM.SPRIDEN_ACTIVITY_DATE
Pseudocode -
I know I need something with the POSITION of the characters.
I need help making this pseudocode into real code, please! :)
AND ID.USERID LIKE '%(NL.SPRIDEN_LAST_NAME)%'
AND SUBSTRING (1st CHAR OF ID.USERID) LIKE
SUBSTRING FIRST CHARACTER OF (NL.SPRIDEN_FIRST_NAME)
AND SUBSTRING (2nd char of ID.USERID) LIKE
SUBSTRING FIRST CHAR OF (NL.SPRIDEN_MIDDLE_NAME)
AND ID.USERID LIKE SUBSTR(NL.SPRIDEN_FIRST_NAME, 1, 1)
|| SUBSTR(NL.SPRIDEN_MIDDLE_NAME, 1, 1)
|| NL.SPRIDEN_LAST_NAME || '%'
|| is a concatenation operator
This condition means: check if USERID starts with the first symbol SPRIDEN_FIRST_NAME + the first symbol of SPRIDEN_MIDDLE_NAME + SPRIDEN_LAST_NAME
A slight variation on Multisync's good answer:
AND REGEXP_LIKE(ID.USERID, SUBSTR(NL.SPRIDEN_FIRST_NAME, 1, 1)
|| SUBSTR(NL.SPRIDEN_MIDDLE_NAME, 1, 1)
|| NL.SPRIDEN_LAST_NAME || '[0-9]*$', 'i')
-- ^
-- case insensitive compare
That way you won't have false positive for cases such as James Tiberius Kirk => jtkirkwood and you get case insensitive compare "for free".
The drawback here is I assume you don't have regex special characters as part of the name of your users...
Think about normalizing case too!
Currently working with a Firebird 1.5 database and attempting to pull the data in the correct format natively with SQL.
Consider the following database:
ID | Full Name
1 Jon Doe
2 Sarah Lee
What I am trying to achieve is a simple split on the full name field (space) within a query.
ID | First Name | Last Name
1 Jon Doe
2 Sarah Lee
The issue faced is Firebird POSITION() was introduced in v2.0. Is there any known workaround to split on a space that anyone has come across?
Much appreciate your assistance!
For Firebird 1.5, a solution is to find a UDF that either combines both functions, or provides the position (I don't use UDFs, so I am not sure if one already exists). If none is available, you might have to write one.
The other solution is to write a stored procedure for this functionality, see for example: Position of substring function in SP
CREATE PROCEDURE Pos (SubStr VARCHAR(100), Str VARCHAR(100))
RETURNS (Pos INTEGER) AS
DECLARE VARIABLE SubStr2 VARCHAR(201); /* 1 + SubStr-lenght + Str-length */
DECLARE VARIABLE Tmp VARCHAR(100);
BEGIN
IF (SubStr IS NULL OR Str IS NULL)
THEN BEGIN Pos = NULL; EXIT; END
SubStr2 = SubStr || '%';
Tmp = '';
Pos = 1;
WHILE (Str NOT LIKE SubStr2 AND Str NOT LIKE Tmp) DO BEGIN
SubStr2 = '_' || SubStr2;
Tmp = Tmp || '_';
Pos = Pos + 1;
END
IF (Str LIKE Tmp) THEN Pos = 0;
END
This example (taken from the link) can be extended to then use SUBSTRING to split on the space.
For searching on a single character like a space, a simpler solution can probably be devised than above stored procedure. For your exact needs you might need to write a selectable stored procedure specifically for this purpose.
However, upgrading your database to Firebird 2.5 will give you much more powerful internal functions that simplify this query (and your life)!
I also wanted to split a full name string to first and last name and I used the following SQL statements in firebird 2.1 Database:
Patients is the table name.
The Name field holds the full name string e.g.: "Jon Doe". The FIRST_NAME field will store the first name and the LAST_NAME field the last name
First get the first name (string part before the first space) and execute a TRIM UPDATE statement to remove any spaces.
UPDATE "Patients" SET "Patients".FIRST_NAME = (SUBSTRING("Patients"."Name" FROM 1 FOR (POSITION(' ' IN "Patients"."Name"))))
UPDATE "Patients" SET "Patients".FIRST_NAME = TRIM(BOTH ' ' FROM "Patients".FIRST_NAME)
Then get the last name (the string after the first space) and execute a TRIM UPDATE statement to remove any spaces
UPDATE "Patients" SET "Patients"."LAST_NAME" = (SUBSTRING("Patients"."Name" FROM (POSITION(' ' IN "Patients"."Name")+1)))
UPDATE "Patients" SET "Patients".LAST_NAME = TRIM(BOTH ' ' FROM "Patients".LAST_NAME)
The result will be:
ID | NAME | FIRST_NAME | LAST_NAME
1 Jon Doe Jon Doe
2 Sarah Lee Sarah Lee
You could use a UDF, but that isn't strictly SQL
you could write a stored procedure to parse and split but thats not strictly SQL either
Does anyone know a SQL command to replace MS Office smart quotes with their ASCII cousins? I'm using an oracle database and the fields are of type varchar2
update table set column = replace(replace(column, chr(147),'"'), chr(148), '"')
REPLACE(REPLACE(str, '`', ''''), '´', '''')
Or am I missing your question?
I have had a similar problem. For me after the quotes were stored in the database they appeared thus "Â’".
SELECT abstract FROM foo WHERE version = '1.0' and newscode = 'au20309';
MaeÂ’r ffordd gynaliadwy y mae bwyd yn cael ei dyfu, ei brynu aÂ’i baratoi ...
This is how I replaced them. First find the ascii value for that unusual "Â" character.
SELECT ascii('Â') FROM DUAL; -- returns 50050
Then use the chr function to render the "Â".
The || function concatenate the two characters.
The q function is useful to 'quote' the smart quote string..
SELECT REPLACE(abstract,chr(50050) || q'#’#' , q'#'#')
FROM foo
WHERE version = '1.0' and newscode = 'au20309';
Mae'r ffordd gynaliadwy y mae bwyd yn cael ei dyfu, ei brynu a'i baratoi ...
This worked just fine for me on our Oracle 10 system.
TRANSLATE would be more appropriate than REPLACE.
TRANSLATE(str, '`´', '''''')
http://download.oracle.com/docs/cd/B28359_01/server.111/b28286/functions204.htm#sthref2477
update table set column = replace( column, string_to_replace, [ replacement_string ] )