I've got a table
CREATE TABLE Table1(
Id INT NOT NULL IDENTITY(1,1),
EvType INT NOT NULL,
CreatedByUserId INT NOT NULL
)
Initial data:
And i wonna get only rows which meet the next condition: We select row until Id of the row will be less than first row with EvType == 200 per createdByUserId. So we need to select firsly all first rows for each user with evType == 200, which i've done in this way:
WITH EVS1 AS (
SELECT evs.Id, evs.EvType, evs.CreatedByUserId
ROW_NUMBER() OVER (PARTITION BY evs.CreatedByUserId ORDER BY evs.CreatedDate DESC) as rk
FROM [dbo].Table1 evs)
select *
From EVS1
WHERE EVS1.rk=1
Which produces the following result:
And then somehow i need to select rows for each user until Id is greater then row from CTE for that user, Is that possible to do that?
So we need to retrieve from that table rows until 4th included. Skip the 5th row cause it goes after the first user row with evType 200
Expected Result:
Find min(id) first and then the row having lower or equal id
SELECT *
FROM EVS1
WHERE id <= (SELECT MIN(id) FROM EVS1 WHERE evType = 200)
I assume that you define the ordering according to the id attribute.
If it is necessary to do it for each CreatedByUserId then use a dependent subquery for the minimal id computation
SELECT *
FROM EVS1 e1
WHERE id <= (
SELECT MIN(id)
FROM EVS1 e2
WHERE e2.evType = 200
and e1.CreatedByUserId = e2.CreatedByUserId
)
DBFIDDLE DEMO
I believe that this solution will be faster then a window function for a large data if you will have an index
CREATE INDEX ix_evs1_evType_CreatedByUserId ON evs1(evType, CreatedByUserId) INCLUDE(id)
You can do a window max:
select Id, EvType, CreatedByUserId
from (
select
t.*,
max(case when EvType = 200 then 1 else 0 end)
over(partition by CreatedByUserId order by Id) flagEvType
from [dbo].Table1
)
where flagEvType = 0
You want to select all rows created by a user except for those where an event type 200 occurred before:
select *
from mytable t1
where not exists
(
select null
from mytable t2
where t2.evtype = 200
and t2.createdbyuserid = t1.createdbyuserid
and t2.id < t1.id
);
Related
I want to count number fullvisitorID where rank in /page_y is higher then rank in page_x. So in this case result would be 1, only 111
fullvisitorID
rank
page
111
1
/page_x
111
2
/page_y
222
1
/page_x
222
2
/page_x
333
2
/page_x
333
1
/page_y
Consider below approach
select count(*) from (
select distinct fullvisitorID
from your_table
qualify max(if(page='/page_y',rank,null)) over win > max(if(page='/page_x',rank,null)) over win
window win as (partition by fullvisitorID)
)
SELECT COUNTIF(page = '/page_y') cnt FROM (
SELECT * FROM sample_table WHERE page IN ('/page_x', '/page_y')
QUALIFY ROW_NUMBER() OVER (PARTITION BY fullvisitorID ORDER BY rank DESC) = 1
);
for count you can use COUNT and GROUP BY
SELECT fullvisitorID, COUNT(fullvisitorID), Page FROM table t1
WHERE rank = (SELECT MAX(t2.rank) FROM table t2 WHERE t2.fullvisitorID = t1.fullvisitorID)
Group By fullvisitorID, Page
You can apply a SELF JOIN between the two tables, by matching on the "fullvisitorID" field, then force
the first table to have "page_y" values
the second table to have "page_x" values
rank of the first table to have higher rank of the second table
SELECT *
FROM tab t1
INNER JOIN tab t2
ON t1.fullvisitorID = t2.fullvisitorID
AND t1.page = '/page_y'
AND t2.page = '/page_x'
AND t1.rank > t2.rank
Table separation approach:
DECLARE #t1 TABLE ( fullvisitorID INT, [rank] INTEGER,[page] VARCHAR (max)) --here where page = x
DECLARE #t2 TABLE ( fullvisitorID INT, [rank] INTEGER,[page] VARCHAR (max)) --here where page = y
INSERT INTO #t1 SELECT * FROM #test t WHERE t.[page] LIKE '/page_x'
INSERT INTO #t2 SELECT * FROM #test t WHERE t.[page] LIKE '/page_y'
SELECT COUNT(*) FROM #t1 INNER JOIN #t2 ON [#t1].fullvisitorID = [#t2].fullvisitorID WHERE [#t1].rank < [#t2].rank
I have a table with data similar to below. I am trying to get a list of results that will display all rows where only one unique SourceID exists in status 10. If I were querying this table, I would expect ID's 3 and 4 to be returned.
Table Example
Select *
From table
Where Status = 10 and Source ID in
(
Select SourceID
From Table
Group by SourceID
Having Count(*) = 1
)
You can use NOT EXISTS :
SELECT t.*
FROM table t
WHERE NOT EXISTS (SELECT 1 FROM table t1 WHERE t1.SourceID = t.SourceID AND t1.Status <> t.Status);
Maybe that would work?
SELECT ID FROM Mytable
WHERE [Status] = 10
GROUP BY ID
HAVING COUNT(SourceID) = 1
First, find out all the unique SourceIDs
SELECT
SourceID
FROM
Data
GROUP BY
SourceID
HAVING
COUNT(SourceID) = 1
And then use this query as a sub query to get all the rows that has unique SourceID;
SELECT
*
FROM
Data
WHERE
SourceID IN (
SELECT
SourceID
FROM
Data
GROUP BY
SourceID
HAVING
COUNT(SourceID) = 1
)
Use a sub-query to check if t there is an exact count of 1 of those source id's
SELECT t.* FROM YourTable t WHERE t.status = 10
AND
(SELECT COUNT(0) x From YourTable t2
where t2.sourceid = t.sourceid) = 1
EDITED THE WHOLE TOPIC.
I need to create a view that sort article per type.
If I only have the type : *VALUE -> I need to show this line only.
If I have the type : *VALUE & 2 -> Still showing row accordingly to *VALUE type only.
If I only have the type : 2 -> Showing this one.
I already did somethink like this :
VALUE* is a value that should come from an another table with a Join.
SELECT Id_item ,Name_item , Type_item , Id_type_item FROM ITEM
WHERE Name_item = 'Gillette' AND (Id_Type_item = VALUE* OR Id_Type_item ='10')
ORDER BY CASE
WHEN row_number() OVER(ORDER BY Id_item DESC , Id_Type_Item DESC) <= 1 THEN 0
ELSE 1
END;
But it does that in the case where we've got both row for the types(*VALUE & 10):
Id_item / Name_item / Type_item / Id_Type_Item
1 Gillette 45 30 (*VALUE)
1 Gillette 2 10
So I think that the order by on the Over() could be useful to always sort by *VALUE (which are in reality another column from another table)
I always want to select 1 row of data only ! :)
I'm guessing, that what you want is the "first" row returned from each SELECT? There's no need to use a separate SELECT statement for each variable on the same table, you can use a window function to do so. I believe this is what you might be after.
WITH CTE AS(
--The following assumes table A and B have the same DDL (which begs the question, why are they different tables?)
SELECT *,
ROW_NUMBER() OVER (PARTITION BY var
ORDER BY (SELECT NULL)) AS RN --Replace SELECT(NULL) with your actual ordering criteria
FROM A
WHERE var IN (1,2)
UNION --ALL(?)
SELECT *
ROW_NUMBER() OVER (PARTITION BY var
ORDER BY (SELECT NULL)) AS RN --Replace SELECT(NULL) with your actual ordering criteria
FROM B
WHERE var IN (3))
SELECT *
FROM CTE
WHERE RN = 1;
Here is a possible solution. In this case ROW_NUMBER, RANK and DENSE_RANK would all work. However, ROW_COUNT is not a valid window function in sql server.
DECLARE #A TABLE(ID INT, Value INT)
DECLARE #B TABLE(ID INT,Value INT)
INSERT INTO #A VALUES (1,1),(2,1),(3,2),(4,3),(5,2),(6,1),(7,3)
INSERT INTO #B VALUES (1,1),(2,1),(3,1),(4,2),(5,3),(6,2),(7,1),(8,3)
;WITH D AS
(
SELECT ID,Value FROM #A WHERE Value IN(1,2)
UNION ALL
SELECT ID,Value FROM #B WHERE Value IN (3)
)
SELECT * FROM
(
SELECT
ID, Value,
ValueRankInSet = DENSE_RANK() OVER(PARTITION BY VALUE ORDER BY ID) -- <-- If you do not have an ID field you can subst ID with NEWID() as order is not important
FROM D
)AS X
WHERE ValueRankInSet = 1
Assign the priority within your Select(s) and then order by it in the row_number:
with cte as
(
SELECT *,
row_number()
over (-- partition by ???
order by prio) as Position
FROM
(
SELECT 1 as prio, * FROM A WHERE var = 1
UNION -- probably a more efficient UNION ALL
SELECT 2 as prio, * FROM A WHERE var = 2
UNION -- probably a more efficient UNION ALL
SELECT 3 as prio, * FROM B WHERE var = 3
)
)
select *
from cte
WHERE Position = 1
I have a little sql query, like so
SELECT * FROM table
This returns a bunch of results, i output the following fields:
ID
UserID
Amount
Date
What i want to do is get the most recent entry from each UserID ( based on ID ), then if the amount is 0 do not return ANY results from that UserID.
select t1.*
from your_table t1
join
(
select userid, max(date) as mdate
from your_table
group by userid
having sum(case when amount = 0 then 1 else 0 end) = 0
) t2 on t1.userid = t2.userid and t1.date = t2.mdate
In the subquery you group by the user and select only those having no amount of zero. In that select you use max(date) as mdate to get the latest date for each user.
That subquery can be joined to the original table to get the complete record and not just the userid.
try this
WITH cte AS
(
SELECT
MAX(ID) OVER (PARTITION BY UserID) MaxIDForUserID,
ROW_NUMBER() OVER (PARTITION BY UserID ORDER BY ID DESC) rn,
UserID,
Amount,
Date
FROM TableName
)
SELECT * FROM cte WHERE rn = 1 AND Amount != 0
I have the following table structure:
Id, Message
1, John Doe
2, Jane Smith
3, Error
4, Jane Smith
Is there a way to get the error record and the surrounding records? i.e. find all Errors and the record before and after them.
;WITH numberedlogtable AS
(
SELECT Id,Message,
ROW_NUMBER() OVER (ORDER BY ID) AS RN
FROM logtable
)
SELECT Id,Message
FROM numberedlogtable
WHERE RN IN (SELECT RN+i
FROM numberedlogtable
CROSS JOIN (SELECT -1 AS i UNION ALL SELECT 0 UNION ALL SELECT 1) n
WHERE Message='Error')
WITH err AS
(
SELECT TOP 1 *
FROM log
WHERE message = 'Error'
ORDER BY
id
),
p AS
(
SELECT TOP 1 l.*
FROM log
WHERE id <
(
SELECT id
FROM err
)
ORDER BY
id DESC
)
SELECT TOP 3 *
FROM log
WHERE id >
(
SELECT id
FROM p
)
ORDER BY
id
Adapt this routine to pick out your target.
DECLARE #TargetId int
SET #TargetId = 3
select *
from LogTable
where Id in (-- "before"
select max(Id)
from LogTable
where Id < #TargetId
-- target
union all select #TargetId
-- "after"
union all select min(Id)
from LogTable
where Id > #TargetId)
select id,messag from
(Select (Row_Number() over (order by ID)) as RNO, * from #Temp) as A,
(select SubRNO-1 as A,
SubRNO as B,
SubRNO+1 as C
from (Select (Row_Number() over (order by ID)) as SubRNO, * from #Temp) as C
where messag = 'Error') as B
where A.RNO = B.A or A.RNO = B.B or A.RNO = B.C
;WITH Logs AS
(
SELECT ROW_NUMBER() OVER (ORDER BY id), id, message as rownum FROM LogTable lt
)
SELECT curr.id, prev.id, next.id
FROM Logs curr
LEFT OUTER JOIN Logs prev ON curr.rownum+1=prev.rownum
RIGHT OUTER JOIN Logs next ON curr.rownum-1=next.rownum
WHERE curr.message = 'Error'
select id, message from tbl where id in (
select id from tbl where message = "error"
union
select id-1 from tbl where message = "error"
union
select id+1 from tbl where message = "error"
)
Get fixed number of rows before & after target
Using UNION for a simple, high performance query (I found selected answer WITH query above to be extremely slow)
Here is a high performance alternative to the WITH top selected answer, when you know an ID or specific identifier for a given record, and you want to select a fixed number of records BEFORE and AFTER that record. Requires a number field for ID, or something like date that can be sorted ascending / descending.
Example: You want to select the 10 records before and after a specific error was recorded, you know the error ID, and can sort by date or ID.
The following query gets (inclusive) the 1 result above, the identified record itself, and the 1 record below. After the UNION, the results are sorted again in descending order.
SELECT q.*
FROM(
SELECT TOP 2
id, content
FROM
the_table
WHERE
id >= [ID]
ORDER BY id ASC
UNION
SELECT TOP 1
id, content
FROM
the_table
WHERE
id < [ID]
ORDER BY id DESC
) q
ORDER BY q.id DESC