I don't know anything about SQL. I currently have a query that gives me this. Sales for some products by channel/etc (please note this is a very simplified version, there's more fields) by week/period/year:
Basically what I would need is to add a column that gives me the sales for prior year. Basically, transform the table as below. In Excel it would be a simple sumifs that would just sum the same exact criteria aside from the year which would be the previous year.
Is it possible to do this within SQL? The dataset is too large to do it within Excel.
I think you just want lag():
select t.*,
lag(sales) over (partition by channel, product, weekno order by yearno) as prev_sales
from t;
If I understand the data, then periodno is redundant with weekno.
Related
I'm hoping you guys can help with this problem.
I have a set of data which I have displayed via excel.
I'm trying to work out the rolling new cap allowance but need to deduct from previous weeks bookings. I don't want to use a cursor so can anyone help.
I'm going to group by the product id so it will need to start afresh for every product.
In the image, Columns A to D are fixed and I am trying to calculate the data in column E ('New Cap'). The 'New Cap' is the expected results.
Column F gives a detailed formula of what im trying to do.
Not sure what I've done for the post to be marked down.
Thanks
Update:
The formula looks like this.
You want the sum of the cap through this row minus the sum of booked through the previous row. This is easy to do with window functions:
select t.*,
(sum(cap + booked) over (partition by productid order by weekbeg) - booked
) as new_cap
from t;
You can get the new running total using lag and sum over window functions - calculate the cap-booked first, then use sum over() for the running total:
select weekbeg, ProductId, Cap, Booked,
Sum(n) over(partition by productid order by weekbeg) New_Cap
from (
select *, cap - Lag(booked,1,0) over(partition by productid order by weekbeg)n
from t
)t
I have a table in Oracle database whith projected sales per week and would like to sum the next 3 weeks for each week. Here is an example of the table for one product and what I would like to achieve in the last column.
I tried the Sum(Proj Sales) over (partition by Product order by Date), but I am not sure how to configure the Sum Over to get what I am looking for.
Any assistance will be much appreciated.
You can use analytic functions. Assuming that the next three weeks are the current row and the next two:
select t.*,
sum(proj_sales) over (partition by product
order by date
rows between current row and 2 following
) as next_three_weeks
from t;
Today i have below problem while perform an sql query. Please find below data.
I perform SQL query on my table and get the below resulted output. i perform Group by on ID, Name, Week, Year, Days now i want the Days column as average of All Days based on year column. means there is multiple value of year is exist so i need Avg of Days data in all rows of DAYS for particular row. expected result as per below.
Thanks in Advance!!!
Write in comment if you have any query.
You can use OVER:
SELECT
*,
AVG(Days) OVER (PARTITION BY LEFT(Year, 4)) AvgDays
FROM
Tbl
Note: Just grouped by year (2016)
I use queries in Ms ACCESS to create graphs (shown in forms) to represent monthly spend data on a supplier. I want the x axis to be the months in chronological order, and this is where I'm having issues.
The picture above shows that the x axis starts with april 2016, although the earliest date is august 2015.
The query code that creates the graph is the following:
SELECT (Format([DateStamp],"mmm"" '""yy")) AS Expr1, Sum([Item Master].SpendPerMaterial) AS Expr2
FROM [Item Master]
WHERE ((([Item Master].SupplierName)=[Forms]![Supplier History]![List0]))
GROUP BY (Format([DateStamp],"mmm"" '""yy")), (Year([DateStamp])*12+Month([DateStamp])-1);
[Item Master] is the table were all data is retrieved from. DateStamp refers to the column with months, SpendPerMaterial is the spend of a certain material in that month (which is aggregated since we look at the supplier level, not the material level), and List0 is a list where users can select a supplier from a list of suppliers.
You should never rely on the ordering of results from a query unless you include an explicit order by. In your case, the results are ordered by the columns alphabetically (because of the group by).
You can fix this by adding:
order by max([DateStamp])
to the query.
I would add the following to your query, after your GROUP BY clause:
ORDER BY [datestamp] ASC;
I tried the other suggesions on an aggregate totals by month report and no luck. the only way i could get the actual month labels was by putting labels directly beneath the chart, which means altering it every month!
I hope the title of this post makes sense.
The db in question has two columns that are related to my issue, a date column that follows the format xx/xx/xxxx and price a column. What I want to do is get a sum of the prices in the price column based on the month and year in which they occurred, but that data is in the other aforementioned column. Doing so will allow me to determine the total for a given month of a given year. The problem is I have no idea how to construct a query that would do what I need. I have done some reading on the web, but I'm not really sure how to go about this. Can anyone provide some advice/tips?
Thanks for your time!
Mike
I was able to find a solution using a LIKE clause:
SELECT sum(price) FROM purchases WHERE date LIKE '11%1234%'
The "11" could be any 2-digit month and the "1234" is any 4 digit year. The % sign acts as a wildcard. This query, for example, returns the sum of any prices that were from month 11 of year 1234 in the db.
Thanks for your input!
You cannot use the built-in date functions on these date values because you have stored them formatted for displaing instead of in one of the supported date formats.
If the month and day fields always have two digits, you can use substr:
SELECT substr(MyDate, 7, 4) AS Year,
substr(MyDate, 1, 2) AS Month,
sum(Price)
FROM Purchases
GROUP BY Year,
Month
So, the goal is to get an aggregate grouping by the month?
select strftime('%m', mydate), sum(price)
from mytable
group by strftime('%m', mydate)
Look into group by