I have a table having some records.(refer below Image)
In This, I want variant_id based on some condition. Here I tried this query which was not worked for me in the above table.
SELECT distinct variant_id FROM variant_parameter
WHERE (parameter_id = '2' AND parameter_value IN ( 'M' ))
AND (parameter_id = '1' AND parameter_value IN ( 'Black' ))
AND variant_id IN ('1','2','3','4','5')
Expected Output: 4 but no record coming.
Could anyone help me with this?
You can use aggregation and flter with a having clause:
select variant_id
from variant_parameter
where variant_id between 1 and 5 and parameter_id in (1, 2)
group by variant_id
having
max(case when parameter_id = 2 and parameter_value = 'M' then 1 end) = 1
and max(case when parameter_id = 1 and parameter_value = 'Black' then 1 end) = 1
You haven't provided an MCRE, so this just a guess...
SELECT variant_id
FROM variant_parameter
WHERE (parameter_id = 2 AND parameter_value IN ( 'M' ) )
OR (parameter_id = 1 AND parameter_value IN ( 'Black' ))
GROUP BY variant_id
HAVING COUNT(*) = 2
-- AND optional other condition
Related
I am extracting 3 values from a table, I can extract these values from 3 statements. But I need to put these values in one table so I plan to do it in one statement.
select count(*) from fruit;
select count(*) from fruit where color = 'red';
select count(*) from fruit
where color = 'red' and substring(city, 1, 8) = 'New York';
What I am trying to do is similar like this:
select
count(*) total_items,
(count(*) where color = 'red') red_items,
(count(*) where color = 'red' and substring(city, 1, 8) = 'New York') fruit_in_newyork
from
fruit
New Table will have total_items, red_items, fruit_in_newyork as columns.
You could do a conditionally SUM
SELECT count(*) total_items
,sum(CASE WHEN color = 'red'
THEN 1
ELSE 0
END) AS red_items
,sum(CASE WHEN color = 'red' AND SUBSTRING(city, 1, 8) = 'New York'
THEN 1
ELSE 0
END) AS fruit_in_newyork
FROM fruit
I have a SQL query which returns :
id | value
1 a
1 a
1 b
2 a
2 a
I want to get only id who have only the value a. So the id 2
How to do this ?
You can use aggregation and having clause to check if all the rows have value 'a' for a given id:
Using Count:
select id
from t
group by id
having count(*) = count(case when value = 'a' then 1 end);
Or using Sum
select id
from t
group by id
having SUM(case when value = 'a' then 0 else 1 end) = 0;
Use the next code:-
Select id
from #test
group by id
having sum (case when value = 'a' then 0 else 1 end) = 0
The clue is passing 0 for 'a' and pass 1 for other, then having sum equals 0
This is slightly slower than #Gurwinder Singh's answer but can be more readable if performance is not your top priority.
CREATE TABLE tmp (id int, [value] char(1))
INSERT INTO tmp values (1,'a'),(1,'a'),(1,'b'),(2,'a'),(2,'a')
SELECT DISTINCT id
FROM tmp a
WHERE [value] = 'a'
AND id NOT IN (
SELECT id FROM tmp
WHERE [value] <> 'a')
I have these columns
Id Status
----------
1 pass
1 fail
2 pass
3 pass
How do I select all that only have a status of pass but if the Id has at least one fail it will not be selected as well.
If same id can have multiple passes
SELECT id
from table
WHERE status = 'pass'
and id NOT IN (SELECT id FROM table WHERE status = 'fail')
You need to use GROUP BY & HAVING clause
SELECT Id
FROM yourtable
GROUP BY Id
HAVING Sum(case when status ='pass' then 1 else 0 end) = count(status)
HAVING clause can be changed to
HAVING Count(case when status ='pass' then 1 end) = count(status)
I just hate chatty case statement, so
SELECT Id
FROM table1
GROUP BY Id
HAVING COUNT(DISTINCT [Status]) = 1 AND MIN([Status]) = 'pass'
or
SELECT Id
FROM table1
GROUP BY Id
HAVING COUNT(NULLIF([Status], 'fail')) = 1 AND COUNT(NULLIF([Status], 'pass')) = 0
The second query only works when status has two values 'pass' and 'fail'.
I'm after a CTE which I want to return two columns, one with the total number of 1's and one with the total number of 0's. Currently I can get it to return one column with the total number of 1's using:
WITH getOnesAndZerosCTE
AS (
SELECT COUNT([message]) AS TotalNo1s
FROM dbo.post
WHERE dbo.checkletters([message]) = 1
--SELECT COUNT([message]) AS TotalNo0s
--FROM dbo.post
--WHERE dbo.checkletters([message]) = 0
)
SELECT * FROM getOnesAndZerosCTE;
How do I have a second column called TotalNo0s in the same CTE which I have commented in there to show what I mean.
Using conditional aggregation:
WITH getOnesAndZerosCTE AS(
SELECT
TotalNo1s = SUM(CASE WHEN dbo.checkletters([message]) = 1 THEN 1 ELSE 0 END),
TotalNo0s = SUM(CASE WHEN dbo.checkletters([message]) = 0 THEN 1 ELSE 0 END)
FROM post
)
SELECT * FROM getOnesAndZerosCTE;
For using COUNT() directly just be aware that it counts any NON-NULL values. You can omit the ELSE condition which implicitly returns NULL if not stated
SELECT
COUNT(CASE WHEN dbo.checkletters([message]) = 1 THEN 1 END) TotalNo1s
, COUNT(CASE WHEN dbo.checkletters([message]) = 0 THEN 1 END) TotalNo0s
FROM post
or, explicitly state NULL
SELECT
COUNT(CASE WHEN dbo.checkletters([message]) = 1 THEN 1 ELSE NULL END) TotalNo1s
, COUNT(CASE WHEN dbo.checkletters([message]) = 0 THEN 1 ELSE NULL END) TotalNo0s
FROM post
You can do it without CTE
select count(message) total,
dbo.checkletters(message) strLength
from post
group by dbo.checkletters(message)
having dbo.checkletters(message) in (1, 2) //All the messages with length 1 or 2
I need to fetch result from one tables and one view joined on 2 columns.
View: 8million records
Table: 5K Records
I went through query plan and observe that query will take very long to run and infact try to run this query but not getting any result.
Please help me in optimize the query.I am not using any hint.
SELECT coupon_upc
, sum ( loyalty_a ) a
, sum ( loyalty_b ) b
, sum ( loyalty_c ) c
, sum ( loyalty_x )
FROM ( SELECT ccd.coupon_upc AS coupon_upc
, ( CASE WHEN a.loyalty_cell = 'A' then 1 else 0 end ) AS loyalty_a
, ( CASE WHEN a.loyalty_cell = 'B' then 1 else 0 end ) AS loyalty_b
, ( CASE WHEN a.loyalty_cell = 'C1' then 1 else 0 end ) AS loyalty_c
, ( CASE WHEN a.loyalty_cell = 'X' then 1 else 0 end ) AS loyalty_x
FROM view1 a
, ( select distinct coupon_upc
, coupon_id
, division
from table2
where schedule_key = 'XXX' ) ccd
WHERE a.campaign_code = 'XXX'
AND a.coupon_id = ccd.coupon_id
AND a.division = ccd.division ) a
GROUP BY coupon_upc
Without the explain plan, or the schema/DDL, there is a limitted amount of optimisation that can be done.
Here is an alternative, but you'd need to test it to see if it makes any difference. (Replace a join with a correlated sub-query.)
SELECT
coupon_upc, sum(loyalty_a) a, sum(loyalty_b) b, sum(loyalty_c) c, sum(loyalty_x) x
FROM
(
SELECT
(
SELECT
coupon_upc
FROM
table2
WHERE
schedule_key = 'XXX'
AND coupon_id = a.coupon_id
AND division = a.division
GROUP BY
coupon_upc
) as coupon_upc,
(case when a.loyalty_cell = 'A' then 1 else 0 end) as loyalty_a,
(case when a.loyalty_cell = 'B' then 1 else 0 end) as loyalty_b,
(case when a.loyalty_cell = 'C1' then 1 else 0 end) as loyalty_c,
(case when a.loyalty_cell = 'X' then 1 else 0 end) as loyalty_x
FROM
view1 a
WHERE
a.campaign_code = 'XXX'
) a
GROUP BY
coupon_upc
Other than that, the kind of optimisations are:
- persisting the view
- indexes
- refactoring data structures
EDIT
Another possible refactor of the query... I don't know how well Oracle would optimise the 4 instances of correlated sub-queries.
SELECT
coupon_upc,
SUM((SELECT COUNT(*) FROM view1 WHERE campaign_code = 'XXX' AND loyalty_cell = 'A' AND coupon_id = map.coupon_id AND division = map.division)) AS loyalty_a,
SUM((SELECT COUNT(*) FROM view1 WHERE campaign_code = 'XXX' AND loyalty_cell = 'B' AND coupon_id = map.coupon_id AND division = map.division)) AS loyalty_b,
SUM((SELECT COUNT(*) FROM view1 WHERE campaign_code = 'XXX' AND loyalty_cell = 'C1' AND coupon_id = map.coupon_id AND division = map.division)) AS loyalty_c,
SUM((SELECT COUNT(*) FROM view1 WHERE campaign_code = 'XXX' AND loyalty_cell = 'X' AND coupon_id = map.coupon_id AND division = map.division)) AS loyalty_x
FROM
(
SELECT coupon_upc, coupon_id, division
FROM table2 WHERE schedule_key = 'xxx'
GROUP BY coupon_upc, coupon_id, division
)
AS map
GROUP BY
coupon_upc
Or maybe...
SELECT
map.coupon_upc, SUM(data.loyalty_a) AS a, SUM(data.loyalty_b) AS b, SUM(data.loyalty_c) AS c, SUM(data.loyalty_x) AS X
FROM
(
SELECT coupon_upc, coupon_id, division
FROM table2 WHERE schedule_key = 'xxx'
GROUP BY coupon_upc, coupon_id, division
)
AS map
INNER JOIN
(
SELECT
coupon_id,
division,
SUM(CASE WHEN loyalty_cell = 'A' THEN 1 ELSE 0 END) AS loyalty_a,
SUM(CASE WHEN loyalty_cell = 'B' THEN 1 ELSE 0 END) AS loyalty_b,
SUM(CASE WHEN loyalty_cell = 'C1' THEN 1 ELSE 0 END) AS loyalty_c,
SUM(CASE WHEN loyalty_cell = 'X' THEN 1 ELSE 0 END) AS loyalty_x
FROM
view1
WHERE
campaign_code = 'XXX'
)
AS data
ON data.coupon_id = map.coupon_id
AND data.division = map.division
GROUP BY
map.coupon_upc
Another possible rewrite would be:
SELECT
map.coupon_upc
, COUNT(CASE WHEN a.loyalty_cell = 'A' THEN 1 ELSE NULL END) AS loyalty_a
, COUNT(CASE WHEN a.loyalty_cell = 'B' THEN 1 ELSE NULL END) AS loyalty_b
, COUNT(CASE WHEN a.loyalty_cell = 'C1' THEN 1 ELSE NULL END) AS loyalty_c
, COUNT(CASE WHEN a.loyalty_cell = 'X' THEN 1 ELSE NULL END) AS loyalty_x
FROM
( SELECT coupon_upc, coupon_id, division
FROM table2 WHERE schedule_key = 'xxx'
GROUP BY coupon_upc, coupon_id, division
) AS map
JOIN view1 a
ON a.coupon_id = map.coupon_id
AND a.division = map.division
WHERE
a.campaign_code = 'xxx'
GROUP BY
map.coupon_upc
Do you have indexes on the fields that are used in the JOIN, WHERE and the GROUP BY clauses?