I have these columns
Id Status
----------
1 pass
1 fail
2 pass
3 pass
How do I select all that only have a status of pass but if the Id has at least one fail it will not be selected as well.
If same id can have multiple passes
SELECT id
from table
WHERE status = 'pass'
and id NOT IN (SELECT id FROM table WHERE status = 'fail')
You need to use GROUP BY & HAVING clause
SELECT Id
FROM yourtable
GROUP BY Id
HAVING Sum(case when status ='pass' then 1 else 0 end) = count(status)
HAVING clause can be changed to
HAVING Count(case when status ='pass' then 1 end) = count(status)
I just hate chatty case statement, so
SELECT Id
FROM table1
GROUP BY Id
HAVING COUNT(DISTINCT [Status]) = 1 AND MIN([Status]) = 'pass'
or
SELECT Id
FROM table1
GROUP BY Id
HAVING COUNT(NULLIF([Status], 'fail')) = 1 AND COUNT(NULLIF([Status], 'pass')) = 0
The second query only works when status has two values 'pass' and 'fail'.
Related
I have data like this
Now I need a single query to get count of id where Info is 'Yes' and count of id which are in both 'yes' and 'no'
Single query for:
SELECT COUNT(id) FROM table WHERE info = 'yes'
and
SELECT COUNT(id) FROM table WHERE info = 'yes' AND info = 'No'
Since
Id having Yes are 7 (1,2,3,4,5,6,7)
and Id having and Yes and No both vaules are only 3 (1,4, 6)
it should give me id_as_yes = 7 and id_as_yes_no = 3
You can do it with aggregation and window functions:
SELECT DISTINCT
SUM(MAX(CASE WHEN info = 'yes' THEN 1 ELSE 0 END)) OVER () id_as_yes,
COUNT(CASE WHEN COUNT(DISTINCT info) = 2 THEN 1 END) OVER () id_as_yes_no
FROM tablename
GROUP BY id
See the demo.
Results:
> id_as_yes | id_as_yes_no
> --------: | -----------:
> 7 | 3
You need conditional aggregation.
Select id,
Count(case when info = 'y' then 1 end) as y_count,
Count(case when info = 'y' and has_n = 1 then 1 end) as yn_count
From (SELECT id, info,
Max(case when info = 'no' then 1 end) over (partirion by id) as has_n
From your_table) t
You can do this without a subquery. This relies on the observation that the number of ids that are "no" only is:
count(distinct id) - count(distinct case when info = 'yes' then id end)
And similarly for the number of yeses. So, the number that have both is the number of ids minus the number of no only minus the number of yes only:
select count(distinct case when info = 'yes' then id end) as num_yeses,
(count(distinct id) -
(count(distinct id) - count(distinct case when info = 'yes' then id end)) -
(count(distinct id) - count(distinct case when info = 'no' then id end))
)
from t;
This should do the trick...it's definitely not efficient or elegant, but no null value aggregate warnings
dbFiddle link
Select
(select count(distinct id) from mytest where info = 'yes') as yeses
,(select count(distinct id) from mytest where info = 'no' and id in (select distinct id from mytest where info = 'yes' )) as [yes and no]
My requirement is to get id for missing status from SQL table. I will get a list of status for each id, say A,B,C,D. In a scenario, I have to check status B exists or not. Table gets updated everyday and each time new Id will be created
Conditions,
If status A exists and other statuses such as C and D does not
exists, then don't need to get id.
If status A and B exists and other statuses such as C or D does not exists, then don't need to get id .
If status A exists and B not exists, other
statuses such as C or D exists, then I should get the id of that
record
If status A and B exists, other
statuses such as C or D exists (all status exists), then I don't need to get the id of that
record
Table1:
Id StatusCode
1 A
1 C
2 A
2 B
2 C
3 A
3 C
3 D
How do I get Id 1 and 3 using SQL query?, Seems simple but as I am new to SQL I could not able to get it in SQL.
select statement in this screenshot works fine when there is only one id, it fails on multiple id. I tried many other way, but no use
Try this
SELECT DISTINCT ID
FROM T1
WHERE Statuscode = 'A' AND ID NOT IN (SELECT ID FROM T1 WHERE Statuscode = 'B' )
AND (ID IN (SELECT ID FROM T1 WHERE Statuscode = 'C' ) OR ID IN (SELECT ID FROM T1 WHERE Statuscode = 'D' ))
FIDDLE DEMO
Also, To correct Gordon Linoff's answer, we need to add one more where criteria there
SELECT Id
FROM T1
GROUP BY Id
HAVING SUM(CASE WHEN Statuscode = 'A' THEN 1 ELSE 0 END) > 0 AND
SUM(CASE WHEN Statuscode = 'B' THEN 1 ELSE 0 END) = 0 AND
SUM(CASE WHEN Statuscode IN ('C', 'D') THEN 1 ELSE 0 END) > 0;
FIDDLE DEMO
This answers the original version of the question.
I think you can use aggregation:
select id
from t
group by id
having sum(case when status = 'A' then 1 else 0 end) > 0 and
sum(case when status in ('C', 'D') then 1 else 0 end) > 0;
SELECT id
FROM t
GROUP BY
Id
HAVING MAX(status) = CHAR(64 + COUNT(*))
--char(64+1) = A, char(64+2) = B etc
The logic behind this is that it will take all count the same types of id. So if you have 3 rows you will need abc. If you have an id with 4 rows you will have ABCD. Generally the max status should always be the same as the number of rows.
This is true of course if you have no duplicate between id and status code.
select distinct id from t where t.statuscode = 'C' or t.statuscode = 'D' group by t.id
I have a SQL query which returns :
id | value
1 a
1 a
1 b
2 a
2 a
I want to get only id who have only the value a. So the id 2
How to do this ?
You can use aggregation and having clause to check if all the rows have value 'a' for a given id:
Using Count:
select id
from t
group by id
having count(*) = count(case when value = 'a' then 1 end);
Or using Sum
select id
from t
group by id
having SUM(case when value = 'a' then 0 else 1 end) = 0;
Use the next code:-
Select id
from #test
group by id
having sum (case when value = 'a' then 0 else 1 end) = 0
The clue is passing 0 for 'a' and pass 1 for other, then having sum equals 0
This is slightly slower than #Gurwinder Singh's answer but can be more readable if performance is not your top priority.
CREATE TABLE tmp (id int, [value] char(1))
INSERT INTO tmp values (1,'a'),(1,'a'),(1,'b'),(2,'a'),(2,'a')
SELECT DISTINCT id
FROM tmp a
WHERE [value] = 'a'
AND id NOT IN (
SELECT id FROM tmp
WHERE [value] <> 'a')
How to retrieve all rows having value in a status column (not null) group by ID column.
Id Name Status
1394 Test 1 Y
1394 Test 2 null
1394 Test 3 null
1395 Test 4 Y
1395 Test 5 Y
I wrote like select * from table where status = 'Y'. It brings me 3 records, how to add condition to bring in only last 2? the 1394 ID have other 2 records, which status is null.
If you want to select groups where the status is only y, you can do:
select t.*
from t
where not exists (select 1
from t t2
where t2.id = t.id and
(t2.Status <> 'Y' or t2.status is null)
);
If you only want the ids, I would use group by and having:
select id
from t
group by id
having min(status) = 'Y' and max(status) = 'Y' and count(*) = count(status);
The last condition checks for no NULL values.
You could also write:
having min(status = 'Y' then 1 else 0 end) = 1
A simple way is:
select * from mytable
where status = 'Y'
and id not in (select id from mytable where status is null)
The existing query "where status = 'Y'" will bring you not null by definition.
If you are trying to get grouped results, a "GROUP BY id" clause will achieve this, which will also require putting id in the select explicitly instead of "*".
Example: SELECT id, COUNT(id) from table where status = 'Y'
If I am reading this correctly you want to bring in the ID for a grouping that never has a NULL status value:
I would use a subquery with a not-exist:
SELECT DISTINCT ID FROM mytable WHERE status IS NULL;
Then filter IDs that do not exist in that list:
SELECT * FROM mytable WHERE id NOT IN (SELECT DISTINCT ID FROM mytable WHERE status IS NULL);
Here are some possible solutions, because I am unclear on exactly what you want as output:
Select Id, Name, Status from table where status is not null;
results in 3 rows:
Id Name Status
1394 Test 1 Y
1395 Test 4 Y
1395 Test 5 Y
Select Id, count(*) as anAmt from table where status is not null group by Id;
/* only retrieves counts per Id */
results in 1 row for each Id:
Id anAmt
1394 1
1395 2
I would like to SUM() while also using a WHERE but when there are no records found for a certain ID I would like it to return NULL instead of just not returning anything.
Initial Code:
SELECT
ID,
SUM(CASE WHEN EVENTS = 3 THEN 1 ELSE 0 END)
FROM Events_ID
WHERE
YEAR = 2012
GROUP BY ID
This would not return an ID if there were no events for it in 2012.
I then changed it to the following that appears to work but is around 100x slower!
SELECT
ID,
(SELECT
SUM(CASE WHEN EVENTS = 3 THEN 1 ELSE 0 END)
FROM EVENTS_ID r WHERE r.ID = t.ID AND r.YEAR = 2012)
FROM (SELECT * FROM Events_ID GROUP BY ID) as t;
Is there anyway to get the output of the second query nearer to the speed of the first?
Is this what you want?
SELECT ID,
SUM(CASE WHEN EVENTS = 3 AND YEAR = 2012 THEN 1 END)
FROM Events_ID
GROUP BY ID;
This will return all ids, with a NULL as a second value if no events match both conditions.