I'm using the following SQL request to Informix DB:
select fromQ, toQ, count(callid) as cont_num, type
from some_table
group by fromQ, toQ, type
order by fromQ, toQ;
It produces the result:
fromq toq cont_num type
-----------------------------------
Sales 12 1
English 1 1
MB 59 1
Reception 3 2
Reception 53 1
Service 1 1
MB Sales 1 1
MB English 1 1
This is OK, as expected. Please note there are 2 rows for toq=Reception.
Field WRTYPE can have values only from 1 to 3.
So idea is to make an output like this:
fromq toq cont_num type1 type2 type3
------------------------------------------------
Sales 12 12 0 0
English 1 1 0 0
MB 59 59 0 0
Reception 56 53 3 0
Service 1 1 0 0
MB Sales 1 1 0 0
MB English 1 1 0 0
Is there a simple way to do this?
Use conditional aggregation:
select fromQ, toQ, count(callid) as cont_num,
sum(case when type = 1 then 1 else 0 end) as type_1,
sum(case when type = 2 then 1 else 0 end) as type_2,
sum(case when type = 3 then 1 else 0 end) as type_3
from some_table
group by fromQ, toQ
order by fromQ, toQ;
Related
I m having data in columns as:
item_id
month_in
amount
1
1
1500
1
1
1000
2
1
2500
3
1
2600
3
1
1000
4
1
2700
4
1
1000
1
2
1500
1
2
2000
2
2
1000
3
3
2500
3
3
2500
4
3
1000
4
3
2500
I want to have like this result
item_id
januari
februari
maret
1
2500
3500
0
2
2500
1000
0
3
3600
0
0
4
3700
0
3500
in oracle sql query how to solve this.
please help me
I have try this
select
item_id,
(case month_in=1 then sum(amout) end) AS januari
from table
group by item_id, month_in
order by item_id asc
but not working as I expected
We can try a pivot query here:
SELECT
item_id,
SUM(CASE WHEN month_in = 1 THEN amount ELSE 0 END) AS januari,
SUM(CASE WHEN month_in = 2 THEN amount ELSE 0 END) AS februari,
SUM(CASE WHEN month_in = 3 THEN amount ELSE 0 END) AS maret
FROM yourTable
GROUP BY
item_id
ORDER BY
item_id;
You almost got it. This is the simplest solution, without extra hassle:
SELECT
item_id,
SUM(CASE WHEN month_in = 1 THEN amount ELSE 0 END) AS januari,
SUM(CASE WHEN month_in = 2 THEN amount ELSE 0 END) AS februari,
SUM(CASE WHEN month_in = 3 THEN amount ELSE 0 END) AS maret
from table
group by item_id
order by item_id asc
You don't need to define the months as a separate rowset, because the months are defined as values 1, 2, 3, ... as columns. Similarly, the items are defined by the group by function.
Here's my sample input of match results from a tournament and the result column indicates whether team 1 or team 2 won the game (0 stands for a draw).
score table -
-----------------
t1 t2 result
-----------------
us aus 1
aus sa 2
sa us 0
us nz 1
Desired output -
---------------------------------
team played won lost draw
---------------------------------
aus 2 0 2 0
us 3 2 0 1
nz 1 0 1 0
sa 2 1 0 1
Here's my solution that I came up with, but Is it possible to solve it without using a UNION operator?
select
t1 as team,
count(1) as played,
sum(case when result=1 then 1 else 0 end) as won,
sum(case when result=2 then 1 else 0 end) as lost,
sum(case when result=0 then 1 else 0 end) as draw
from
(select
t1,
t2,
result
from score
union
select
t2,
t1,
case when result=1 then 2
when result=2 then 1
else 0 end as result
from score
) t
group by t.t1
You could UNPIVOT your data via a CROSS APPLY and then perform the aggregation on the results
Example
Select Team
,played = count(1)
,won = sum(case when Val=1 then 1 else 0 end)
,lost = sum(case when Val=2 then 1 else 0 end)
,draw = sum(case when Val=0 then 1 else 0 end)
From score A
Cross Apply ( values (T1,Result )
,(T2,case when result=1 then 2 when result=2 then 1 else 0 end)
) B(Team,Val)
Group By Team
Results
team played won lost draw
aus 2 0 2 0
nz 1 0 1 0
sa 2 1 0 1
us 3 2 0 1
I have the following table:
IdSce Year NoIte Value
1 0 1 1
1 0 2 5
1 0 3 1
1 1 1 2
1 1 2 3
1 1 3 2
2 0 1 4
2 0 2 4
2 0 3 1
2 1 1 2
2 1 2 4
2 1 3 3
I want to group by IdSce and Year, and show each possible value and count how many time each value appears like this:
IdSce Year Value1 Value2 Value3 Value4 Value5
1 0 2 0 0 0 1
1 1 0 2 1 0 0
2 0 1 0 0 2 0
2 1 0 1 1 1 0
Thanks !
EDIT
shawnt00 is really close to what I want, but I'm looking to do it as dynamic as possible, meaning if I have 10 different values for the column value, I will be missing information in my table. Therefore, if I have 10 different values, I want 10 new columns (value1, value2, ... , value10)
This is what I've tried so far:
SELECT IdSce
,Year
,SUM(CASE WHEN Value >= 0 and Value < 1 THEN 1 else 0 end) Zero
,SUM(CASE WHEN Value >= 1 and Value < 2 THEN 1 else 0 end) One
,SUM(CASE WHEN Value >= 2 and Value < 3 THEN 1 else 0 end) Two
,SUM(CASE WHEN Value >= 3 and Value < 4 THEN 1 else 0 end) Three
,SUM(CASE WHEN Value >= 4 and Value < 5 THEN 1 else 0 end) Four
,SUM(CASE WHEN Value >= 5 THEN 1 else 0 end) FiveMore
,SUM(CASE WHEN Value >= 0 THEN 1 else 0 end) Total
FROM Table
GROUP BY IdSce
,Year
Thanks for the help again!
Ok, I'll do it!
select IdSce, "Year"
count(case when Value = 1 then 1 end) as "1",
count(case when Value = 2 then 1 end) as "2",
count(case when Value = 3 then 1 end) as "3",
count(case when Value = 4 then 1 end) as "4",
count(case when Value = 5 then 1 end) as "5"
from T
group by IdSce, "Year"
I think you'll often find this filed under "conditional aggregation". SQL Server has a proprietary syntax that uses pivot if you want to look into that also.
I have table like this
ID Specified TIN
-----------------
1 0 tin1
2 0 tin1
3 1 tin1
4 0 tin2
5 0 tin3
6 1 tin3
7 1 tin3
I need to count rows groupped by TIN, Specified columns - but result should one row for each TIN:
TIN ZEROSpecified NOTZEROSpecified
tin1 2 1
tin2 0 1
tin3 1 2
Important notice - i have only 2 values for Specified column - 0 and 1
SELECT TIN,
SUM(case when Specified=0 then 1 else 0 end) as ZeroSpecified,
SUM(case when Specified<>0 then 1 else 0 end) as NOTZEROSpecified
FROM table
GROUP BY TIN
Pretty Simple;
SELECT
TIN
,SUM(CASE WHEN Specified = 0 THEN 1 ELSE 0 END) ZEROSpecified
,SUM(CASE WHEN Specified <> 0 THEN 1 ELSE 0 END) NotZEROSpecified
FROM TableName
GROUP BY TIN
I need to create query that has below result.
I add my table for example for better understanding.
QTable:
QID Name
-------
1 x
1 y
2 z
FTable:
QID FID
-------
1 1
1 2
2 3
Inner join with :
FID Type
-------
1 1
1 2
1 3
1 4
2 2
2 3
2 3
3 1
3 3
3 3
I need to result like this:
result:
QID FID-Count Type(1)-count Type(2)-count Type(3)-count Type(4)-count
-----------------------------------------------------------------
1 2 1 2 3 1
2 1 1 0 2 0
Thank u for help.
Ususally you can emulate a pivot with GROUP BY and SUM+CASE:
SELECT
T1.QID,
COUNT(DISTINCT T1.FID) as FIDCOUNT,
SUM(CASE WHEN Type=1 THEN 1 ELSE 0 END) as Type1Cnt,
SUM(CASE WHEN Type=2 THEN 1 ELSE 0 END) as Type2Cnt,
SUM(CASE WHEN Type=3 THEN 1 ELSE 0 END) as Type3Cnt,
SUM(CASE WHEN Type=4 THEN 1 ELSE 0 END) as Type4Cnt
FROM QFTable as T1
JOIN T2 ON
T1.FID=T2.FID
GROUP BY T1.QID
ORDER BY QID
SQLFiddle demo