I have column with this strings:
['autre__renvoi_vers_un_mail', 'contact_type__email']
['contact_type__email', 'internal__shop', 'uk']
I need to get from the string ONLY the contact_type__* part (appears only once in each row)
contact_type__email
contact_type__email
Any suggestions?
You could use regexp function regexp_extract(), like:
regexp_extract(mycol, 'contact_type__[a-zA-Z0-9_]*')
This will match on string 'contact_type__ followed by a sequence of letters, numbers, or underscore (which are commonly defined as word characters).
Given this example:
create table t (col varchar(100));
insert into t values
('[''autre__renvoi_vers_un_mail'', ''contact_type__email'']'),
('[''contact_type__email'', ''internal__shop'', ''uk'']');
You can use:
select
substring
(
col,
charindex('contact_type', col) + 14,
charindex('''', col, charindex('contact_type', col)) - charindex('contact_type', col) - 14
)
from
t;
db<>fiddle here
Related
I have a query that in SQL Server that returns data like this:
1234-A
2345-BB
3456-C
5678-CC
4567-AA
6789-B
01234-A
26857-ZZ
This is what I need it display:
A
B
C
C
A
B
A
Z
I need to get the first letter behind the '-'. How do I get this to display?
Try this:
DECLARE #MyTable TABLE (MyCol VARCHAR(255));
INSERT #MyTable (MyCol)
VALUES ('1234-A'),('2345-BB'),('3456-C'),('5678-CC'),
('4567-AA'),('6789-B'),('01234-A'),('26857-ZZ');
SELECT SUBSTRING(MyCol, CHARINDEX('-', MyCol, 1) + 1, 1)
FROM #MyTable;
CHARINDEX finds where the '-' in the column value is.
SUBSTRING starts at that index + 1 and returns, in this case, 1 character.
You can use substr In conjunction with instr to get the output
how to select a cells with contents (varchar) starting and ending with equals letter in SQL??
You can use string functions. Assuming a table called mytable with a column called col:
select *
from mytable
where left(col, 1) = right(col, 1)
Note that this also allows values that are made of just one character - you did not tell which behavior you want in that case. You can easily avoid that, if that's what you want, with another condition on the length of the string:
select *
from mytable
where left(col, 1) = right(col, 1) and len(col) > 1
Hi I have one doubt in sql server .
how to get first position to right side specific character position.
table : empfiles
filename:
ab_re_uk_u_20101001
ax_by_us_19991001
abc_20181002
I want output like below:
filename
ab_re_uk_u
ax_by_us
abc
I tried like below :
select SUBSTRING(filename,1,CHARINDEX('2',filename) - 1) as filename from empfiles
above query is not given expected result please tell me how to write query to achive this task in sql server .
If last position has always numeric values then you can use patindex():
select *, substring(filename, 1, patindex('%[0-9]%', filename)-2) as NewFile
from empfiles e;
If you want to get characters after than _ to right sight of string then you can use combo to reverse() and substring()
select *,
reverse(substring(reverse(filename),charindex('_', reverse(filename))+1, len(filename)))
from empfiles e;
Another way is to use reverse in combination with STUFF.
create table f(filename nvarchar(100));
insert into f values
('ab_re_uk_u_20101001')
,('ax_by_us_19991001')
,('abc_20181002');
select
filename=reverse(stuff(reverse(filename),1,charindex('_',reverse(filename)),''))
from f
Try This
CREATE TABLE #DATA([FILENAME] NVARCHAR(100));
INSERT INTO #DATA VALUES
('ab_re_uk_u_20101001')
,('ax_by_us_19991001')
,('abc_20181002');
SELECT [filename],
SUBSTRING([filename],0,PATINDEX('%[0-9]%',[filename])-1) AS ExpectedResult
FROM #Data
Result
filename ExpectedResult
--------------------------------------
ab_re_uk_u_20101001 ab_re_uk_u
ax_by_us_19991001 ax_by_us
abc_20181002 abc
Well, obviously the last position value is a date, and the format is YYYYMMDD so its 8 characters, plus, added by underscore character, so that makes its 9 character.
Assumed by the above statement applied, the following logic of the query should work
SELECT SUBSTRING(ColumnText, 1, LEN(ColumnText) - 9)
Which means, only display characters from character position 1, to character position LEN - 9, which LEN is the length of characters, and 9 is the last 9 digit of number to be removed
Try with this ..
select [filename],SUBSTRING([filename],1,PATINDEX('%_[0-9]%',[filename])-1) from empfiles
Individual Select records
SELECT SUBSTRING('ab_re_uk_u_20101001',1,PATINDEX('%_[0-9]%','ab_re_uk_u_20101001')-1)
SELECT SUBSTRING('ax_by_us_19991001',1,PATINDEX('%_[0-9]%','ax_by_us_19991001')-1)
SELECT SUBSTRING('abc_20181002',1,PATINDEX('%_[0-9]%','abc_20181002')-1)
I am trying to formulate a query that will allow me to find all records from a single column with 3 hyphens. An example of a record would be like XXXX-RP-XXXAS1-P.
I need to be able to sort through 1000s of records with either 2 or 3 hyphens.
You can REPLACE the hyphens in the string with an empty string and compute the difference of the length of original string and the replaced string to check for the number of hyphens.
select *
from yourtable
where len(column_name)-len(replace(column_name,'-',''))=3
and substring(column_name,9,1) not like '%[0-9]%'
If your records have 2 or 3 hyphens, then just do:
where col like '%-%-%-%'
This will get 3 or more hyphens. For exactly 3:
where col like '%-%-%-%' and col not like '%-%-%-%-%'
try this,
declare #t table(col1 varchar(50))
insert into #t values ('A-B'),('A-B-C-D-E'),('A-B-C-D')
select * from
(SELECT *
,(len(col1) - len(replace(col1, '-', ''))
/ len('-')) col2
FROM #T)t4
where col2=3
Problem Statement
Example is shown in below image :
The last 2 rows have the patterns like "1.283 2 3" in a single cell. The numbers are seperated by space in the column. We need to add those nos and represent in the format given in Output.
So, the cell having "1.283 2 3" must be converted to 6.283
Challenges facing :
The column values are in string format.
Add nos after casting them into integer
Donot want to take data in UNIX box and manipulate the same.
In TD14 there would be a built-in table UDF named STRTOK_SPLIT_TO_TABLE, before you need to implement your own UDF or use a recursive query.
I modified an existing string splitting script to use blanks as delimiter:
CREATE VOLATILE TABLE Strings
(
groupcol INT NOT NULL,
string VARCHAR(991) NOT NULL
) ON COMMIT PRESERVE ROWS;
INSERT INTO Strings VALUES (1,'71.792');
INSERT INTO Strings VALUES (2,'71.792 1 2');
INSERT INTO Strings VALUES (3,'1.283 2 3');
WITH RECURSIVE cte
(groupcol,
--string,
len,
remaining,
word,
pos
) AS (
SELECT
GroupCol,
--String,
POSITION(' ' IN String || ' ') - 1 AS len,
TRIM(LEADING FROM SUBSTRING(String || ' ' FROM len + 2)) AS remaining,
TRIM(SUBSTRING(String FROM 1 FOR len)) AS word,
1
FROM strings
UNION ALL
SELECT
GroupCol,
--String,
POSITION(' ' IN remaining)- 1 AS len_new,
TRIM(LEADING FROM SUBSTRING(remaining FROM len_new + 2)),
TRIM(SUBSTRING(remaining FROM 1 FOR len_new)),
pos + 1
FROM cte
WHERE remaining <> ''
)
SELECT
groupcol,
-- remove the NULLIF to get 0 for blank strings
SUM(CAST(NULLIF(word, '') AS DECIMAL(18,3)))
FROM cte
GROUP BY 1
This might use a lot of spool, hopefully you're not running that on a large table.