How do I write a cursor to return only one column that contains digit values - sql

Question

For example I had a table named car with two column(col1,col2)
For now I would like insert some values inside the column like:
('Super car','Yellow car')
('BMW5','XL')
('Benz','AGM')
so I would like write a cursor to return ('BMW5','XL') in one single column, how do I do that?(I'm using sql developer)
I would appreciate any suggestion! Thank you!
declare
cursor mycursor is select concat(col1,col2) from car where REGEXP_LIKE(left, '^[[:digit:]]+$')
begin
for counter in mycursor
loop
dbms_output.put_line(counter.concat);
endloop;
end

Answer 1

You can use Concat() function in your query inside the cursor i.e.
CONCAT returns Col1 concatenated with Col2
select concat(col1,col2)
from car where <<conditions if any>>
You can write above query in Cursor like
DECLARE
CURSOR car_cursor IS select concat(col1,col2)
from car WHERE REGEXP_LIKE(col1, '[[:digit:]]');
cv_col1_col2 VARCHAR2 ;
BEGIN
OPEN car_cursor;
LOOP
FETCH car_cursor INTO cv_col1_col2;
Dbms_output.put_line('Concated Name' || cv_col1_col2)
END LOOP
CLOSE car_cursor;
END;

Answer 2

This is how I understood the question (though, more through by description than the title as they aren't related much).
Sample data:
SQL> create table car (col1 varchar2(10), col2 varchar2(10));
Table created.
SQL> insert into car
2 select 'Super car', 'Yellow car' from dual union all
3 select 'BMW5', 'XL' from dual union all
4 select 'Benz', 'AGM' from dual;
3 rows created.
PL/SQL code that uses a cursor FOR loop, returning concatenated col1 and col2 values for rows in which either of those columns contains a digit:
SQL> set serveroutput on;
SQL> begin
2 for cur_r in (select col1 ||' '|| col2 result
3 from car
4 where regexp_like(col1 || col2, '\d') -- any column contains
5 ) -- a digit
6 loop
7 dbms_output.put_line(cur_r.result);
8 end loop;
9 end;
10 /
BMW5 XL
PL/SQL procedure successfully completed.
SQL>