Microsoft Office Access - Median function - Too few parameters - sql

Question

I am trying to use this code to calculate median from my query which has these criteria:
<[Form]![testForm2]![crit1] And >[Form]![testForm2]![crit2] and <[Form]![testForm2]![Age1] And >[Form]![testForm2]![Age2]
without these criteria function works well and gives for every task median based on "MP", however when I put in there my criteria I receive error:
error - Too few parameters. Expected 4 and then it says 'Object Variable or With block not set'
my input: DMedian("MP";"testForm2";"[TASK]= '" & [TASK] & "'")
*even when the Form is open it end up with the error.
*I probably need to find a different way to filter this query from the form, but I don't know how
Public Function DMedian(FieldName As String, _
TableName As String, _
Optional Criteria As Variant) As Variant
' Created by Roger J. Carlson
' http://www.rogersaccesslibrary.com
' Terms of use: You may use this function in any application, but
' it must include this notice.
'Returns the median of a given field in a given table.
'Returns -1 if no recordset is created
' You use this function much like the built-in Domain functions
' (DLookUp, DMax, and so on). That is, you must provide the
' 1) field name, 2) table name, and 3) a 'Where' Criteria.
' When used in an aggregate query, you MUST add each field
' in the GROUP BY clause into the into the Where Criteria
' of this function.
' See Help for more on Domain Aggregate functions.
On Error GoTo Err_Median
Dim db As DAO.Database
Dim rs As DAO.Recordset
Dim strSQL As String
Dim RowCount As Long
Dim LowMedian As Double, HighMedian As Double
'Open a recordset on the table.
Set db = CurrentDb
strSQL = "SELECT " & FieldName & " FROM " & TableName
If Not IsMissing(Criteria) Then
strSQL = strSQL & " WHERE " & Criteria & " ORDER BY " & FieldName
Else
strSQL = strSQL & " ORDER BY " & FieldName
End If
Set rs = db.OpenRecordset(strSQL, dbOpenDynaset)
'Find the number of rows in the table.
rs.MoveLast
RowCount = rs.RecordCount
rs.MoveFirst
'Determine Even or Odd
If RowCount Mod 2 = 0 Then
'There is an even number of records. Determine the low and high
'values in the middle and average them.
rs.Move Int(RowCount / 2) - 1
LowMedian = rs(FieldName)
rs.Move 1
HighMedian = rs(FieldName)
'Return Median
DMedian = (LowMedian + HighMedian) / 2
Else
'There is an odd number of records. Return the value exactly in
'the middle.
rs.Move Int(RowCount / 2)
'Return Median
DMedian = rs(FieldName)
End If
Exit_Median:
'close recordset
rs.Close
Exit Function
Err_Median:
If Err.number = 3075 Then
DMedian = 0
Resume Exit_Median
ElseIf Err.number = 3021 Then
'EOF or BOF ie no recordset created
DMedian = -1
Resume Exit_Median
Else
MsgBox Err.Description
Resume Exit_Median
End If
End Function

Answer 1

The parameter separation character is comma and you are using a semi-colon
CHANGE:
DMedian("MP";"testForm2";"[TASK]= '" & [TASK] & "'")
TO:
DMedian("MP", "testForm2", "[TASK]= '" & [TASK] & "'")

Answer 2

Solution was to refer the text boxes in SQL declaration, Thank you guys
like this:
HAVING (((Data.[REV]< " & Me.crit1 & ") And (Data.[REV])>" & Me.crit2 & ") AND ((Reg.Age)<" & Me.Age1 & " And (Reg.Age)>" & Me.Age2 & " " & SQLcritComplete & "));"
NOT like this:
"HAVING (((Data.[REV]<[Form]![testForm2]![crit1]) And (Data.[REV])>[testForm2]![crit2]) AND ((Reg.Age)<[Form]![testForm2]![Age1] And (Reg.Age)>[Form]![testForm2]![Age2] & SQLcritComplete & "));"