How To Convert To String Search In SPARQL - sparql

I want to use a string instead of the Wikidata ID#.
The code below works perfectly using wd:Q2263 (Tom Hanks) to show what films (Q11424) he was cast (P161) in.
SELECT DISTINCT ?item ?itemLabel ?itemDescription
WHERE {
?item wdt:P31 wd:Q11424; wdt:P161 wd:Q2263.
?article schema:about ?item;
schema:name ?title;
schema:inLanguage "en";
schema:isPartOf <https://en.wikipedia.org/>.
SERVICE wikibase:label { bd:serviceParam wikibase:language "en". }
}
LIMIT 10
The problem is that I want to change wd:Q2263 (Tom Hanks) to be a string like: item ?label "Tom Hanks"#en.
On my website, I am using a search box, so in the code I need the name of the person to be a string. I don't want to have to look it up in Wikipedia to get the Wikidata ID.

Related

Wikidata SPARQL query that returns date a particular property was last edited on queried items

Let's say I'm looking for Wikidata cats who have their place of birth (P19) listed, using this query (also at https://w.wiki/5mdp):
SELECT ?item ?itemLabel ?placeofbirthLabel ?date
WHERE
{
?item wdt:P31 wd:Q146;
wdt:P19 ?placeofbirth;
schema:dateModified ?date.
SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE],en". }
}
This retrieves: item id, item label, (the label of) the place of birth, and the date that any part of the item was last updated.
What if I also want to retrieve the date that the place of birth (P19) was last edited?
Thanks in advance!
Place items can also have a schema:dateModified property:
SELECT ?item ?itemLabel ?item_modified ?placeofbirthLabel ?placeofbirth_modified
WHERE
{
?item wdt:P31 wd:Q146 ;
wdt:P19 ?placeofbirth ;
schema:dateModified ?item_modified .
?placeofbirth schema:dateModified ?placeofbirth_modified .
SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE],en" . }
} LIMIT 10

Wikidata do not return me itemLabel sometimes

I am looking for people of french nationality born in 1900 (and still living). I do not well understand the behaviour of wikidata in response to my following request:
SELECT ?item ?itemLabel ?itemDescription
WHERE {
?item wdt:P31 wd:Q5.
?item wdt:P569 ?dateOfBirth.
?item wdt:P27 wd:Q142.
FILTER NOT EXISTS {?item wdt:P570|wdt:P509|wdt:P20 ?o}
FILTER("1900-00-00"^^xsd:dateTime <= ?dateOfBirth && ?dateOfBirth < "1901-00-00"^^xsd:dateTime)
SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE],fr". }
}
I do not understand why the folowing request do not return itemLabel for some rows; for example the itemlabel returned for https://www.wikidata.org/wiki/Q47508624 is its "id": Q47508624
By using the wikibase:language option, you're asking for Wikidata to provide you with the labels for each ?item in the ?itemLabel variable. You've requested that it provide you labels in either the language preferred by your browser ([AUTO_LANGUAGE]) or French (fr). I would guess that your browser's default language is French also. With a browser set with English as the default, I get "Hugues Esquerre" as the ?itemLabel value for wd:Q47508624 (this record has labels defined in English and Spanish).
You can add additional acceptable languages in the comma-separated list in the query to increase the liklihood of getting label values back:
SELECT ?item ?itemLabel ?itemDescription
WHERE {
?item wdt:P31 wd:Q5.
?item wdt:P569 ?dateOfBirth.
?item wdt:P27 wd:Q142.
FILTER NOT EXISTS {?item wdt:P570|wdt:P509|wdt:P20 ?o}
FILTER("1900-00-00"^^xsd:dateTime <= ?dateOfBirth && ?dateOfBirth < "1901-00-00"^^xsd:dateTime)
SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE],fr,en,es". }
}

SPARQL query that returns Wikidpedia labels from Wikidata itemLabel

I am new to SPARQL,
Is it possible to write a query that returns Wikipedia box information for a corresponding item label from the Wikipedia box for the Arabic Language that appears at the bottom of the Wikidata item page?
see the picture:
Instead of the Wikipedia URL in the following Query, I need to return the Wikipedia Label, in our case (الرامة (جنين))
Try Query on Wikidata Query Service
SELECT DISTINCT ?article ?item ?itemLabel ?itemDescription ?entity_type ?main_category (GROUP_CONCAT(DISTINCT(?altLabel); separator = ", ") AS ?altLabel_list) WHERE {
?item ?label "الرامة"#ar.
?item wdt:P31 ?entity_type .
MINUS { ?item wdt:P31 wd:Q4167410}
OPTIONAL{ ?item wdt:P910 ?main_category}
?article schema:about ?item;
schema:isPartOf <https://ar.wikipedia.org/>;
OPTIONAL { ?item skos:altLabel ?altLabel . FILTER (lang(?altLabel) = "ar") }
SERVICE wikibase:label { bd:serviceParam wikibase:language "ar" .}
}
GROUP BY ?article ?item ?itemLabel ?itemDescription ?entity_type ?main_category
This is the answer by the UninformedUser
> SELECT ?article ?wikipediaLabel WHERE
> { ?article schema:about wd:Q12187640 . ?article schema:isPartOf <https://ar.wikipedia.org/>; schema:name
> ?wikipediaLabel }

How to make a sparql query inside another sparql query?

I am trying to make a sparql query inside another sparql query. In sql, we can do it like this:
SELECT column_name(s)
FROM table_name
WHERE column_name IN (SELECT STATEMENT);
I want to do the same thing in SPARQL query. Specifically I have two sparql queries and I want to combine them together. My end goal is to find 'Siemens PLM Software Company's subsidiaries. In order to do this, first i need to find the company's id and then look for its subsidiaries.
Q1: Finds the unique identity of 'Siemens PLM Software Company'
SELECT DISTINCT ?item ?label ?articleLabel WHERE {
?item ?label "Siemens PLM Software"#en;
wdt:P31 wd:Q4830453.
?article schema:about ?item;
schema:inLanguage "en".
SERVICE wikibase:label { bd:serviceParam wikibase:language "en". }
}
Returns Q15898201
Q2: Find the subsidiary of 'Siemens PLM Software Company'
SELECT ?Subsidiary ?SubsidiaryLabel ?parent_organization ?parent_organizationLabel WHERE {
SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE],en". }
?Subsidiary wdt:P749 wd:Q15898201.
OPTIONAL { ?Subsidiary wdt:P749 ?parent_organization. }
Returns Siemens
I would like to combine them together to something like this:
SELECT ?Subsidiary ?SubsidiaryLabel ?parent_organization ?parent_organizationLabel WHERE {
SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE],en". }
?Subsidiary wdt:P749 wd:
{SELECT DISTINCT ?item ?label ?articleLabel WHERE {
?item ?label "Siemens PLM Software"#en;
wdt:P31 wd:Q4830453.
?article schema:about ?item;
schema:inLanguage "en".
SERVICE wikibase:label { bd:serviceParam wikibase:language "en". }
}
}.
OPTIONAL { ?Subsidiary wdt:P749 ?parent_organization. }
Do you have any idea how can i do this? Thank you!
There were several things not quite clear:
Did you really mean to return the rdfs:label property as ?label? I don't understand why you'd want to do that, so I assume you mean to just directly match on the rdfs:label property without returning it
Why return ?articleLabel? It's not a real label anyway but just the value of ?label as a literal. I assume you mean to just return ?article.
It seems you have the parent organization relationship backwards? Your Q2 asks for subsidiaries of Siemens PLM Software. None exist. To ask for Siemens, you need to ask for
wd:Q15898201 wdt:P749 ?parent_organization
and not
?Subsidiary wdt:P749 wd:Q15898201
With that out of the way: There is no need for a subquery here. The query can be achieved simply by writing out the graph pattern for the desired graph structure, using OPTIONAL for parts that may not exist, and making sure that the variable names match up correctly throughout the query:
SELECT ?item ?itemLabel ?parent_organization ?parent_organizationLabel WHERE {
# Find business by label
?item rdfs:label "Siemens PLM Software"#en;
wdt:P31 wd:Q4830453.
# Find English-language articles about the business
?article schema:about ?item;
schema:inLanguage "en".
# Find the business' parent organization, if one exists
OPTIONAL { ?item wdt:P749 ?parent_organization. }
# For any variable ?xxx, add variable ?xxxLabel with the label
SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE],en". }
}
That being said, you can use a subquery if you really want to:
SELECT ?item ?itemLabel ?parent_organization ?parent_organizationLabel WHERE {
{
SELECT ?item {
?item rdfs:label "Siemens PLM Software"#en;
wdt:P31 wd:Q4830453.
}
}
?article schema:about ?item;
schema:inLanguage "en".
OPTIONAL { ?item wdt:P749 ?parent_organization. }
SERVICE wikibase:label { bd:serviceParam wikibase:language "[AUTO_LANGUAGE],en". }
}
This is equivalent to the first query, but runs much slower because the query optimiser is not as good at handling subqueries.

Filter by type in Wikidata

This SPARQL request looks for all cities called "Berlin" in Wikidata:
SELECT DISTINCT ?item ?itemLabel ?itemDescription WHERE {
?type (a | wdt:P279) wd:Q515. # Sub-type of city
?item wdt:P31 ?type.
?item rdfs:label "Berlin"#en.
SERVICE wikibase:label { bd:serviceParam wikibase:language "en". }
}
PROBLEM: It returns zero result.
Meanwhile, the request below correctly finds Q64 (capital and city-state of Germany), but it also returns a lot of other things called Berlin, so I want to filter on cities (then in a future phase I will order these cities by population, but that is outside the scope of this question):
SELECT DISTINCT ?item ?itemLabel ?itemDescription WHERE {
?item rdfs:label "Berlin"#en.
SERVICE wikibase:label { bd:serviceParam wikibase:language "en". }
}
Note: My code for getting instances of subclasses of city (Berlin is a big city which is subclass of city) seems to work correctly, as illustrated by the results of this query.
It was a Wikidata bug.
According to Wikidata's Jura1, it was a bug in Wikidata caused by someone's experiments with "preferred rank".
Discussion at https://www.wikidata.org/wiki/Wikidata:Project_chat/Archive/2016/09#P31_inconsistency
The bug has been fixed just now.
You can only query for data that is contained in the dataset.
If you try an alternative of your query
SELECT DISTINCT ?item ?itemLabel ?itemDescription ?type1 ?type2 WHERE {
?item rdfs:label "Berlin"#en.
optional{?item rdf:type ?type1 }
optional{?item wdt:P279 ?type2 }
SERVICE wikibase:label { bd:serviceParam wikibase:language "en". }
}
it returns no types, neither connected by rdf:type nor wdt:P279.
If you have a look at the entity of the capital and city state Berlin, you can see that there is information about "instance of", but this property is supposed to be https://www.wikidata.org/wiki/Property:P31. And none of them links to wd:Q515, I'm wondering from where you got this idea.
But to be honest, I don't know that much about Wikidata and to me, it's not clear why no rdf:type is used, but a common pattern for RDF datasets is to use
?s rdf:type/rdfs:subClassOf* SUPER_CLASS .
if we assume that there is rdf:type information available.
If you check the types wd:Q64 is an instance of
SELECT DISTINCT ?type ?typeLabel WHERE {
wd:Q64 (a | wdt:P31) ?type.
SERVICE wikibase:label { bd:serviceParam wikibase:language "en". }
}
ORDER BY ?item
None of them are City (wd:Q515) or a sub-class of it.
Looks like a data issue. Perhaps you should contact Wikidata.