I wanted to know how to properly convert FLOAT value into a DATE?
The data we receive has a value oriented as such: YYYYMM ex. 201911 (today's Year + Month). However, all the values passing under the YYYYMM column signifies the first of the month ex. 201911 = 11/01/2019.
RIGHT([DATE],2) + '/01/' + LEFT([DATE],4) AS [DATE]
When I try converting it, it doesn't put it in a date format because I tried using it in a DATEADD function and it errored on the field I converted.
If your value is YYYYMM, then one simple method is to convert to a string and then a date:
select convert(date, convert(varchar(255), yyyymm) + '01')
Or, use datefromparts():
select datefromparts(floor(yyyymm / 100), yyyymm % 100, 1)
Please check this :
DECLARE #Date AS FLOAT;
SET #Date = 201911;
SELECT CONVERT(VARCHAR, CAST(CAST(LEFT(#Date,4) AS VARCHAR(4)) + '/01' + '/' + CAST(RIGHT(#Date,2) AS VARCHAR(2)) AS DATE) , 103) As CREATEDDATE
Will output 11/01/2019
Related
am working in SQL Server 2008, while merging I got error like
conversion failed when converting datetime from character string
select *
from table_name
where cast(f_datetime as date) <=
cast(cast(datepart(year,cast(convert(varchar(250),#Year,103) as date) )as varchar(250))+ '-'+ cast(datepart(MM,cast(convert(varchar(10),#month,103) as varchar(50))+'-01' as date)
I cannot speak to the cast() on f_datetime. But for the rest, you can do:
where cast(f_datetime as date) <= convert(date, convert(varchar(250), #year * 10000 + #month * 100 + 1))
This simplifies the calculation, and prevents things like #year from being treated as a date due to the convert() function.
I assume your f_datetime field format is "dd/mm/yyyy". If yes you can easily convert this field instead of trying to merge and convert #year and #month fields. check this query :
SELECT *
FROM table_name
WHERE CONVERT(DATE,f_datetime,103)<= CAST(CONVERT(VARCHAR, #year) + '-' + CONVERT(VARCHAR, #month) + '-' + '01' AS DATE)
I need merge two column to date format
input
month year
---- ----
7 2013
The result should be come date format like this (DD/MM/YYYY) :
New_Date
--------
01/07/2013
You can use for example this:
select convert(date, '01/' + convert(varchar(2), month) + '/' + convert(varchar(4), year), 101)
The output of your data is depended on the collation, not how you store it.
To get the date, try this:
SELECT DATEFROMPARTS(year, month, 1);
Check This: Suppose you have variable declaration as below and you can get the desired output in desired form by using CONVERT
DECLARE #year INT = '2017', #month INT = '7'
SELECT CONVERT(VARCHAR(10),DATEFROMPARTS(#year, #month, 1), 103) AS [DD/MM/YYYY]
OUTPUT:
DD/MM/YYYY
01/07/2017
You have so many date format which you can use to get output in various format please check this http://www.sql-server-helper.com/sql-server-2008/sql-server-2008-date-format.aspx
Try below code :
SELECT RIGHT('00'+CAST('1' AS VARCHAR(2)),2) + '/' + RIGHT('00'+CAST('7' AS
VARCHAR(2)),2) + '/' + CAST('2013' AS VARCHAR(4))
I've received a flat file and after parsing and inserting it in a table. I've a column which has dates in a format yyyyMMddhhmmss
Here, yyyy is year, MM is month, dd is day, hh is hours, mm is minute and ss is seconds part
I'm trying to convert this to DateTime type as mentioned below but not working for me
SELECT CAST(StrDate as DateTime) FROM [dbo].[Mytable]
For example:
Column has a value 20150121190941 in Varchar format and it should be converted to DateTime as 2015-01-21 19:09:41.000
I apologize if it's a duplicate one.
You can use select DATETIMEFROMPARTS ( year, month, day, hour, minute, seconds, milliseconds )
declare #dt nvarchar(25) = '20150121190941'
select datetimefromparts(left(#dt,4), substring(#dt,5,2), substring(#dt,7,2),substring(#dt,9,2), substring(#dt,11,2), substring(#dt,13,2), '000')
SQL Server readily recognizes YYYYMMDD as a date. So, converting the first 8 characters to a date is easy. Alas, I don't think there is a time representation without colons.
So, here is one rather brutal method:
select (convert(datetime, left(StrDate, 8)) +
convert(time, substring(StrDate, 9, 2 ) + ':' + substring(StrDate, 11, 2 ) + ':' + substring(StrDate, 13, 2 )
)
)
Declare #dt varchar(50)
set #dt=20150121190941
create table tblDateTbl
(
col1 datetime
)
insert into dt (col1)
select SUBSTRING(#dt,1,4) + '-' + SUBSTRING(#dt,5,2) + '-' + SUBSTRING(#dt,7,2)+ ' ' + SUBSTRING(#dt,9,2)+ ':' + SUBSTRING(#dt,11,2)+ ':' + SUBSTRING(#dt,13,2)+ '.000'
DECLARE #day CHAR(2)
SET #day = DATEPART(DAY, GETDATE())
PRINT #day
If today was the 9th of December, the above would print "9".
I want to print "09". How do I go about doing this?
Pad it with 00 and take the right 2:
DECLARE #day CHAR(2)
SET #day = RIGHT('00' + CONVERT(NVARCHAR(2), DATEPART(DAY, GETDATE())), 2)
print #day
For SQL Server 2012 and up , with leading zeroes:
SELECT FORMAT(GETDATE(),'MM')
without:
SELECT MONTH(GETDATE())
Use SQL Server's date styles to pre-format your date values.
SELECT
CONVERT(varchar(2), GETDATE(), 101) AS monthLeadingZero -- Date Style 101 = mm/dd/yyyy
,CONVERT(varchar(2), GETDATE(), 103) AS dayLeadingZero -- Date Style 103 = dd/mm/yyyy
Try this :
SELECT CONVERT(varchar(2), GETDATE(), 101)
Leading 0 day
SELECT FORMAT(GetDate(), 'dd')
SQL Server 2012+ (for both month and day):
SELECT FORMAT(GetDate(),'MMdd')
If you decide you want the year too, use:
SELECT FORMAT(GetDate(),'yyyyMMdd')
Select Replicate('0',2 - DataLength(Convert(VarChar(2),DatePart(DAY, GetDate()))) + Convert(VarChar(2),DatePart(DAY, GetDate())
Far neater, he says after removing tongue from cheek.
Usually when you have to start doing this sort of thing in SQL, you need switch from can I, to should I.
SELECT RIGHT('0'
+ CONVERT(VARCHAR(2), Month( column_name )), 2)
FROM table
Might I suggest this user defined function if this what you are going for:
CREATE FUNCTION dbo.date_code (#my_date date) RETURNS INT
BEGIN;
DECLARE #retval int;
SELECT #retval = CAST(CAST(datepart(year,#my_date) AS nvarchar(4))
+ CONVERT(CHAR(2),#my_date, 101)
+ CONVERT(CHAR(2),#my_date, 103) AS int);
RETURN #retval;
END
go
To call it:
SELECT dbo.date_code(getdate())
It returns as of today
20211129
Roll your own method
This is a generic approach for left padding anything. The concept is to use REPLICATE to create a version which is nothing but the padded value. Then concatenate it with the actual value, using a isnull/coalesce call if the data is NULLable. You now have a string that is double the target size to exactly the target length or somewhere in between. Now simply sheer off the N right-most characters and you have a left padded string.
SELECT RIGHT(REPLICATE('0', 2) + CAST(DATEPART(DAY, '2012-12-09') AS varchar(2)), 2) AS leftpadded_day
Go native
The CONVERT function offers various methods for obtaining pre-formatted dates. Format 103 specifies dd which means leading zero preserved so all that one needs to do is slice out the first 2 characters.
SELECT CONVERT(char(2), CAST('2012-12-09' AS datetime), 103) AS convert_day
DECLARE #day CHAR(2)
SET #day = right('0'+ cast(day(getdate())as nvarchar(2)),2)
print #day
use
CONVERT(CHAR(2), DATE_COLUMN, 101)
to get the month part with 2 characters and
CONVERT(CHAR(2), DATE_COLUMN, 103)
for the day part.
Declare #dateToGet varchar(10)
Set #dateToGet = convert(varchar, getdate(), 112)
This works fine for the whole date with leading zeros in month and day
select
right('0000' + cast(datepart(year, GETDATE()) as varchar(4)), 4) + '-'+ +
right('00' + cast(datepart(month, GETDATE()) as varchar(2)), 2) + '-'+ +
right('00' + cast(datepart(day, getdate()) as varchar(2)), 2) as YearMonthDay
I want to convert date format from 01/09 to January 2009 , 09/03 to September 2003 etc. Is this possible in SQL? Please let me know if there is a API for the same.
if you have a DateTime column in your table, it's possible
SELECT DATENAME(MM, YOUR_DATE_COLUMN) + ' ' + CAST(YEAR(YOUR_DATE_COLUMN) AS VARCHAR(4)) AS [Month YYYY]
http://www.sql-server-helper.com/tips/date-formats.aspx
You should look here.
It's rather simple.
You should first convert it to a datetime. Then you can easily apply any formating when you read it later.
declare #d varchar(10);
set #d = '01/09'
select
--cast(#d as datetime) as d1, --syntax error converting char string
cast('20' + right(#d, 2) + '-' + left(#d, 2) + '-01' as datetime) as d2
then convert it to mmm yyyy using rm's answer
select datename(month, GETDATE()) + ' '+ substring(convert(varchar, GETDATE(), 100),8,4)