merge two column with date format - sql

I need merge two column to date format
input
month year
---- ----
7 2013
The result should be come date format like this (DD/MM/YYYY) :
New_Date
--------
01/07/2013


You can use for example this:
select convert(date, '01/' + convert(varchar(2), month) + '/' + convert(varchar(4), year), 101)


The output of your data is depended on the collation, not how you store it.
To get the date, try this:
SELECT DATEFROMPARTS(year, month, 1);


Check This: Suppose you have variable declaration as below and you can get the desired output in desired form by using CONVERT
DECLARE #year INT = '2017', #month INT = '7'
SELECT CONVERT(VARCHAR(10),DATEFROMPARTS(#year, #month, 1), 103) AS [DD/MM/YYYY]
OUTPUT:
DD/MM/YYYY
01/07/2017
You have so many date format which you can use to get output in various format please check this http://www.sql-server-helper.com/sql-server-2008/sql-server-2008-date-format.aspx


Try below code :
SELECT RIGHT('00'+CAST('1' AS VARCHAR(2)),2) + '/' + RIGHT('00'+CAST('7' AS
VARCHAR(2)),2) + '/' + CAST('2013' AS VARCHAR(4))

Related

Converting a FLOAT into DATE in SQL?

I wanted to know how to properly convert FLOAT value into a DATE?
The data we receive has a value oriented as such: YYYYMM ex. 201911 (today's Year + Month). However, all the values passing under the YYYYMM column signifies the first of the month ex. 201911 = 11/01/2019.
RIGHT([DATE],2) + '/01/' + LEFT([DATE],4) AS [DATE]
When I try converting it, it doesn't put it in a date format because I tried using it in a DATEADD function and it errored on the field I converted.

If your value is YYYYMM, then one simple method is to convert to a string and then a date:
select convert(date, convert(varchar(255), yyyymm) + '01')
Or, use datefromparts():
select datefromparts(floor(yyyymm / 100), yyyymm % 100, 1)

Please check this :
DECLARE #Date AS FLOAT;
SET #Date = 201911;
SELECT CONVERT(VARCHAR, CAST(CAST(LEFT(#Date,4) AS VARCHAR(4)) + '/01' + '/' + CAST(RIGHT(#Date,2) AS VARCHAR(2)) AS DATE) , 103) As CREATEDDATE
Will output 11/01/2019

Combining date , month , year columns in SQL Server

DD(10)-MM(05)-YYYY(2013)
I have a table with DATE, MONTH, YEAR in separate columns. How I can combine them into a single column Created date?
Output must be: 10-05-2013 (DD-MM-YYYY format)

SELECT RIGHT('00' + DAY, 2) + '-' + RIGHT('00' + MONTH, 2) + '-' + YEAR AS Date
FROM YourTable

I guess you want have a date field instead of a string. So use TO_DATE() function. You can format date anyway you want later.
TO_DATE(YEAR + '/' + MONTH + '/' + DATE, 'yyyy/mm/dd')

You can do it easily:
SELECT to_char(TO_DATE('10 01 2014', 'DD MM YYYY'),'dd-mm-yyyy') AS MYDATE FROM DUAL

To concatenate columns you just need to use "+" in your select statement
SELECT DATE + '-'+ MONTH + '-'+ YEAR FROM table

how to Select getdate () in yyyy/M format

I want to select getdate() in the format yyyy/M. I tried to write a query
SELECT FORMAT(GETDATE(), 'yyyy/M')
but it is throwing an error.
I am a beginner in SQL. How do I get the yyyy/m format if there is only single digit month? E.g. the query should return 2016/1 when there is only one digit month (it should not return 2016/01) and should return 2016/10 when the month has two digits

How about getting the YEAR and MONTH part of the date and just concatenate them:
SELECT
CAST(DATEPART(YEAR, GETDATE()) AS VARCHAR(4)) + '/' +
CAST(DATEPART(MONTH, GETDATE()) AS VARCHAR(2))

Try this:
SELECT FORMAT(GETDATE(),'yyyy/MM')
SELECT FORMAT(CAST('2015-11-15' AS smalldatetime),'yyyy/M'),
FORMAT(CAST('2015-01-15' AS smalldatetime),'yyyy/M')
Gives:
2015/11 | 2015/1

SELECT CONVERT(VARCHAR(7), GETDATE(), 111) AS [YYYY/MM]
OR
SELECT CONVERT(VARCHAR(7), GETDATE(), 111)

How do I get the month and day with leading 0's in SQL? (e.g. 9 => 09)

DECLARE #day CHAR(2)
SET #day = DATEPART(DAY, GETDATE())
PRINT #day
If today was the 9th of December, the above would print "9".
I want to print "09". How do I go about doing this?

Pad it with 00 and take the right 2:
DECLARE #day CHAR(2)
SET #day = RIGHT('00' + CONVERT(NVARCHAR(2), DATEPART(DAY, GETDATE())), 2)
print #day

For SQL Server 2012 and up , with leading zeroes:
SELECT FORMAT(GETDATE(),'MM')
without:
SELECT MONTH(GETDATE())

Use SQL Server's date styles to pre-format your date values.
SELECT
CONVERT(varchar(2), GETDATE(), 101) AS monthLeadingZero -- Date Style 101 = mm/dd/yyyy
,CONVERT(varchar(2), GETDATE(), 103) AS dayLeadingZero -- Date Style 103 = dd/mm/yyyy

Try this :
SELECT CONVERT(varchar(2), GETDATE(), 101)

Leading 0 day
SELECT FORMAT(GetDate(), 'dd')

SQL Server 2012+ (for both month and day):
SELECT FORMAT(GetDate(),'MMdd')
If you decide you want the year too, use:
SELECT FORMAT(GetDate(),'yyyyMMdd')

Select Replicate('0',2 - DataLength(Convert(VarChar(2),DatePart(DAY, GetDate()))) + Convert(VarChar(2),DatePart(DAY, GetDate())
Far neater, he says after removing tongue from cheek.
Usually when you have to start doing this sort of thing in SQL, you need switch from can I, to should I.

SELECT RIGHT('0'
+ CONVERT(VARCHAR(2), Month( column_name )), 2)
FROM table

Might I suggest this user defined function if this what you are going for:
CREATE FUNCTION dbo.date_code (#my_date date) RETURNS INT
BEGIN;
DECLARE #retval int;
SELECT #retval = CAST(CAST(datepart(year,#my_date) AS nvarchar(4))
+ CONVERT(CHAR(2),#my_date, 101)
+ CONVERT(CHAR(2),#my_date, 103) AS int);
RETURN #retval;
END
go
To call it:
SELECT dbo.date_code(getdate())
It returns as of today
20211129

Roll your own method
This is a generic approach for left padding anything. The concept is to use REPLICATE to create a version which is nothing but the padded value. Then concatenate it with the actual value, using a isnull/coalesce call if the data is NULLable. You now have a string that is double the target size to exactly the target length or somewhere in between. Now simply sheer off the N right-most characters and you have a left padded string.
SELECT RIGHT(REPLICATE('0', 2) + CAST(DATEPART(DAY, '2012-12-09') AS varchar(2)), 2) AS leftpadded_day
Go native
The CONVERT function offers various methods for obtaining pre-formatted dates. Format 103 specifies dd which means leading zero preserved so all that one needs to do is slice out the first 2 characters.
SELECT CONVERT(char(2), CAST('2012-12-09' AS datetime), 103) AS convert_day

DECLARE #day CHAR(2)
SET #day = right('0'+ cast(day(getdate())as nvarchar(2)),2)
print #day

use
CONVERT(CHAR(2), DATE_COLUMN, 101)
to get the month part with 2 characters and
CONVERT(CHAR(2), DATE_COLUMN, 103)
for the day part.

Declare #dateToGet varchar(10)
Set #dateToGet = convert(varchar, getdate(), 112)
This works fine for the whole date with leading zeros in month and day

select
right('0000' + cast(datepart(year, GETDATE()) as varchar(4)), 4) + '-'+ +
right('00' + cast(datepart(month, GETDATE()) as varchar(2)), 2) + '-'+ +
right('00' + cast(datepart(day, getdate()) as varchar(2)), 2) as YearMonthDay

Date Format conversion in SQL

I want to convert date format from 01/09 to January 2009 , 09/03 to September 2003 etc. Is this possible in SQL? Please let me know if there is a API for the same.

if you have a DateTime column in your table, it's possible
SELECT DATENAME(MM, YOUR_DATE_COLUMN) + ' ' + CAST(YEAR(YOUR_DATE_COLUMN) AS VARCHAR(4)) AS [Month YYYY]
http://www.sql-server-helper.com/tips/date-formats.aspx

You should look here.
It's rather simple.

You should first convert it to a datetime. Then you can easily apply any formating when you read it later.
declare #d varchar(10);
set #d = '01/09'
select
--cast(#d as datetime) as d1, --syntax error converting char string
cast('20' + right(#d, 2) + '-' + left(#d, 2) + '-01' as datetime) as d2
then convert it to mmm yyyy using rm's answer

select datename(month, GETDATE()) + ' '+ substring(convert(varchar, GETDATE(), 100),8,4)