i'm trying to get a inner join from two select sentences but it doesn't work, what i am doing wrong?
i cant work with internal tables because inner join doesn't permit it.
clear: it_spfli.
refresh: it_spfli.
select
spfli-cityto
spfli-cityfrom
into TABLE it_spfli from(select spfli-cityto COUNT( * )from spfli group by spfli-cityto) as t1
INNER JOIN(select spfli-cityfrom COUNT( * )from spfli group by spfli-cityfrom) as t2
ON t1-cityto = t2-cityfrom.
i expect a table of more frequency city to and city from order by city to with table spfli.
First of all i don't think you are doing the right SELECT to get what you want.
I answer this question from the technical perspective. You can use WITH.
WITH +spf1 AS (
SELECT spfli~cityto AS cityto, COUNT(*) AS count FROM spfli GROUP BY spfli~cityto ) ,
+spf2 AS (
SELECT spfli~cityfrom AS cityfrom , COUNT(*) AS count FROM spfli GROUP BY spfli~cityfrom ) ,
+spf3 AS (
SELECT s1~cityto, s2~cityfrom FROM +spf1 AS s1 INNER JOIN +spf2 AS s2
ON s1~cityto = s2~cityfrom )
SELECT * FROM +spf3 INTO TABLE #DATA(lt_result).
Related
I am implementing nested join statement using sub-queries. I am able to get the result for 3 tables but unable to join it further for four or n tables .
SELECT X.personCityId
, X.name
, X.age
, X.cityId
, X.state
, Y.age
, Y.name
FROM (SELECT Person.cityId AS personCityId
, Person.name
, Person.age
, CityDetails.cityId AS cityId
, CityDetails.state
FROM Person
LEFT JOIN CityDetails
ON Person.cityid = CityDetails.cityid ) AS X
LEFT JOIN (SELECT name , age, lastname FROM PersonalDetails) AS Y
ON X.age=Y.age
Let say if i have to join result of above query with 4th table by left join on age column
LEFT JOIN (SELECT age,height, weight from PersonMedicalRecords ) as D ON Z.age = a.age
I want to know how this can be done through sub-queries only.
You can use "common table expression" to achieve this and maintain level wise hierarchy
Like this
;
WITH cte AS (
SELECT Person.cityId AS personCityId
, Person.name
, Person.age
, CityDetails.cityId AS cityId
, CityDetails.state
FROM Person
LEFT JOIN CityDetails
ON Person.cityid = CityDetails.cityid )
, ct AS (
SELECT * ----- here on * use your required column
FROM (SELECT * ----- here on * use your required column
FROM cte) AS x
LEFT JOIN (SELECT name
, age
, lastname
FROM PersonalDetails) as y
ON X.age=y.age )
, ct2 AS (
SELECT * ----- here on * use your required column
FROM (SELECT * ----- here on * use your required column
FROM ct) as y
LEFT JOIN (SELECT height
, weight
, age ---- added from our side considering it is available for implementing join on age
FROM PersonMedicalRecords) as z
ON y.age=z.age )
SELECT * FROM ct2 ----- here on * use your required column
Here output of one left join will take as input table with next join and similarly you can maintain your hierarchy of join.
You are unnecessarily nesting your queries. You should write your query as:
SELECT p.cityId as personCityId, p.name, p.age,
cd.cityId, cd.state,
pd.age, pd.name
FROM Person p LEFT JOIN
CityDetails cd
ON p.cityid = cd.cityid LEFT JOIN
PersonalDetails pd
ON pd.age = p.age;
Note the use of meaningful table aliases (abbreviations for the table names) rather than arbitrary letters. Also, no subqueries.
If you want to add another JOIN, just add another JOIN, following the pattern of the other joins.
**I tried this and it works
SELECT X.personCityId, X.name, X.age, X.cityId, X.state, Y.age FROM (SELECT Person.cityId AS personCityId, Person.name, Person.age, CityDetails.cityId AS cityId, CityDetails.state FROM Person LEFT JOIN CityDetails ON Person.cityid = CityDetails.cityid) AS X LEFT JOIN (SELECT age, lastname FROM PersonalDetails) AS Y ON X.age=Y.age LEFT JOIN (SELECT age, height, weight FROM PersonMedicalRecords)AS Z ON Y.age = Z.age
I am trying to implement an inner join to compare values of two tables, however failing for some reason and the query is returning zero columns.
I have two tables security and security_his and trying to join them on columns SECURITY_ID and INVESTMENT_OBJECTIVE. Query is as follows
SELECT *
FROM SECURITY origin
INNER JOIN (
SELECT *
FROM SECURITY_HIS t2
WHERE DATED = (
SELECT MAX(DATED)
FROM SECURITY_HIS t1
WHERE t1.SECURITY_ID = t2.SECURITY_ID
)
) history ON origin.SECURITY_ID = history.SECURITY_ID
AND origin.INVESTMENT_OBJECTIVE = history.INVESTMENT_OBJECTIVE;
WITH cte as (
SELECT S.*,
row_number() over
(partition by S.SECURITY_ID ORDER BY SH.DATED DESC)
FROM SECURITY S
JOIN SECURITY_HIS SH
ON S.SECURITY_ID = SH.SECURITY_ID
AND S.INVESTMENT_OBJECTIVE = SH.INVESTMENT_OBJECTIVE
)
SELECT *
FROM cte
WHERE rn = 1
You have no GROUP BY on the innermost query, so only a single value, maxed over the entire table, is returned. However your query can also be simplified for easier understanding:
SELECT origin.*, history.Dated
FROM SECURITY origin
INNER JOIN (
SELECT
SECURITY_ID,
INVESTMENT_OBJECTIVE,
MaxDated = MAX(DATED)
FROM SECURITY_HIS t2
GROUP BY
SECURITY_ID,
INVESTMENT_OBJECTIVE
) history ON origin.SECURITY_ID = history.SECURITY_ID
AND origin.INVESTMENT_OBJECTIVE = history.INVESTMENT_OBJECTIVE
I'm trying to print out the results from the "GermanDB" Database first, while also showing everything from the Boston DB that was not in the German database. Can this be done in one query?
My query (the bold part functions but does not order the way I want)
select * from (
SELECT DISTINCT a.ProductRef
FROM GERMANDB.dbo.LOCATIONS AS a INNER JOIN GERMANDB.dbo.ITEMS AS b ON a.ProductRef = b.ProductRef
WHERE b.ACTIVE=1
) ta
UNION select * from
SELECT DISTINCT c.ProductRef
FROM BOSTONDB.dbo.LOCATIONS AS c INNER JOIN BOSTONDB.dbo.ITEMS AS d ON c.ProductRef = d.ProductRef
WHERE c.ACTIVE=1 (c.ProductRef NOT IN
(SELECT ProductRef FROM GERMANDB.dbo.ITEMS where ACTIVE=1))
) tb
order by ta.ProductRef** , tb.productRef
Just add one field to signal the priority. Like this:
select *, 0 as Priority from (
SELECT DISTINCT a.ProductRef
FROM GERMANDB.dbo.LOCATIONS AS a INNER JOIN GERMANDB.dbo.ITEMS AS b ON a.ProductRef = b.ProductRef
WHERE b.ACTIVE=1
) ta
UNION select *, 1 as Priority from
SELECT DISTINCT c.ProductRef
FROM BOSTONDB.dbo.LOCATIONS AS c INNER JOIN BOSTONDB.dbo.ITEMS AS d ON c.ProductRef = d.ProductRef
WHERE c.ACTIVE=1 (c.ProductRef NOT IN
(SELECT ProductRef FROM GERMANDB.dbo.ITEMS where ACTIVE=1))
) tb
order by Priority, ProductRef
Sigh ... can anyone help? In the SQL query below, the results I get are incorrect. There are three (3) labor records in [LaborDetail]
Hours / Cost
2.75 / 50.88
2.00 / 74.00
1.25 / 34.69
There are two (2) material records in [WorkOrderInventory]
Material Cost
42.75
35.94
The issue is that the query incorrectly returns the following:
sFunction cntWO sumLaborHours sumLaborCost sumMaterialCost
ROBOT HARNESS 1 12 319.14 236.07
What am I doing wrong in the query that is causing the sums to be multiplied? The correct values are sumLaborHours = 6, sumLaborCost = 159.57, and sumMaterialCost = 78.69. Thank you for your help.
SELECT CASE WHEN COALESCE(work_orders.location, Work_Orders_Archived.location) IS NULL
THEN '' ELSE COALESCE(work_orders.location, Work_Orders_Archived.location) END AS sFunction,
(SELECT COUNT(*)
FROM work_orders
FULL OUTER JOIN Work_Orders_Archived
ON work_orders.order_number = Work_Orders_Archived.order_number
WHERE COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = '919630') AS cntWO,
SUM(Laborhours) AS sumLaborHours,
SUM(LaborCost) AS sumLaborCost,
SUM(MaterialCost*MaterialQuanity) AS sumMaterialCost
FROM work_orders
FULL OUTER JOIN Work_Orders_Archived
ON work_orders.order_number = Work_Orders_Archived.order_number
LEFT OUTER JOIN
(SELECT HoursWorked AS Laborhours, TotalDollars AS LaborCost, WorkOrderNo
FROM LaborDetail) AS LD
ON COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = LD.WorkOrderNo
LEFT OUTER JOIN
(SELECT UnitCost AS MaterialCost, Qty AS MaterialQuanity, OrderNumber
FROM WorkOrderInventory) AS WOI
ON COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = WOI.OrderNumber
WHERE COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = '919630'
GROUP BY CASE WHEN COALESCE(work_orders.location, Work_Orders_Archived.location) IS NULL
THEN '' ELSE COALESCE(work_orders.location, Work_Orders_Archived.location) END
ORDER BY sFunction
Try using the SUM function inside a derived table subquery when doing the full join to "WorkOrderInventory" like so...
select
...
sum(hrs) as sumlaborhrs,
sum(cost) as sumlaborcost,
-- calculate material cost in subquery
summaterialcost
from labordetail a
full outer join
(select ordernumber, sum(materialcost) as summaterialcost
from WorkOrderInventory
group by ordernumber
) b on a.workorderno = b.ordernumber
i created a simple sql fiddle to demonstrate this (i simplified your query for examples sake)
Looks to me that work_orders and work_orders_archived contains the same thing and you need both tables as if they were one table. So you could instead of joining create a UNION and use it as if it was one table:
select location as sfunction
from
(select location
from work_orders
union location
from work_orders_archived)
Then you use it to join the rest. What DBMS are you on? You could use WITH. But this does not exist on MYSQL.
with wo as
(select location as sfunction, order_number
from work_orders
union location, order_number
from work_orders_archived)
select sfunction,
count(*)
SUM(Laborhours) AS sumLaborHours,
SUM(LaborCost) AS sumLaborCost,
SUM(MaterialCost*MaterialQuanity) AS sumMaterialCost
from wo
LEFT OUTER JOIN
(SELECT HoursWorked AS Laborhours, TotalDollars AS LaborCost, WorkOrderNo
FROM LaborDetail) AS LD
ON COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = LD.WorkOrderNo
LEFT OUTER JOIN
(SELECT UnitCost AS MaterialCost, Qty AS MaterialQuanity, OrderNumber
FROM WorkOrderInventory) AS WOI
ON COALESCE(work_orders.order_number, Work_Orders_Archived.order_number) = WOI.OrderNumber
where wo.order_number = '919630'
group by sfunction
order by sfunction
The best guess is that the work orders appear more than once in one of the tables. Try these queries to check for duplicates in the two most obvious candidate tables:
select cnt, COUNT(*), MIN(order_number), MAX(order_number)
from (select order_number, COUNT(*) as cnt
from work_orders
group by order_number
) t
group by cnt
order by 1;
select cnt, COUNT(*), MIN(order_number), MAX(order_number)
from (select order_number, COUNT(*) as cnt
from work_orders_archived
group by order_number
) t
group by cnt
order by 1;
If either returns a row where cnt is not 1, then you have duplicates in the tables.
I have tried a lot to figure how to get the count from two tables with respect to master table
I have three tables
Using these table values I need to get this output..
Tried but could get the desired result
http://en.wikipedia.org/wiki/Join_(SQL)
SQL - LEFT OUTER JOIN and WHERE clause
http://forums.devshed.com/oracle-development-96/combination-of-left-outer-join-and-where-clause-383248.html
You have to first GROUP BY in subqueries, then JOIN to the main table:
SELECT
a.AttributeId
, COALECSE(cntE, 0) AS cntE
, COALECSE(cntM, 0) AS cntM
FROM
AttributeMaster AS a
LEFT JOIN
( SELECT
AttributeId
, COUNT(*) AS cntE
FROM
EmployeeMaster
GROUP BY
AttributeId
) em
ON em.AttributeId = a.AttributeId
LEFT JOIN
( SELECT
AttributeId
, COUNT(*) AS cntM
FROM
MonthlyDerivedMaster
GROUP BY
AttributeId
) mdm
ON mdm.AttributeId = a.AttributeId
SELECT AttributeId,
(SELECT COUNT(Eid) FROM EmployeeMaster WHERE AttributeMaster.AttributeId = EmployeeMaster.AttributeId) as master_eid,
(SELECT COUNT(Eid) FROM MonthnlyDerivedMaster WHERE AttributeMaster.AttributeId = MonthnlyDerivedMaster.AttributeId) as monthly_eid
FROM AttributeMaster