I am implementing nested join statement using sub-queries. I am able to get the result for 3 tables but unable to join it further for four or n tables .
SELECT X.personCityId
, X.name
, X.age
, X.cityId
, X.state
, Y.age
, Y.name
FROM (SELECT Person.cityId AS personCityId
, Person.name
, Person.age
, CityDetails.cityId AS cityId
, CityDetails.state
FROM Person
LEFT JOIN CityDetails
ON Person.cityid = CityDetails.cityid ) AS X
LEFT JOIN (SELECT name , age, lastname FROM PersonalDetails) AS Y
ON X.age=Y.age
Let say if i have to join result of above query with 4th table by left join on age column
LEFT JOIN (SELECT age,height, weight from PersonMedicalRecords ) as D ON Z.age = a.age
I want to know how this can be done through sub-queries only.
You can use "common table expression" to achieve this and maintain level wise hierarchy
Like this
;
WITH cte AS (
SELECT Person.cityId AS personCityId
, Person.name
, Person.age
, CityDetails.cityId AS cityId
, CityDetails.state
FROM Person
LEFT JOIN CityDetails
ON Person.cityid = CityDetails.cityid )
, ct AS (
SELECT * ----- here on * use your required column
FROM (SELECT * ----- here on * use your required column
FROM cte) AS x
LEFT JOIN (SELECT name
, age
, lastname
FROM PersonalDetails) as y
ON X.age=y.age )
, ct2 AS (
SELECT * ----- here on * use your required column
FROM (SELECT * ----- here on * use your required column
FROM ct) as y
LEFT JOIN (SELECT height
, weight
, age ---- added from our side considering it is available for implementing join on age
FROM PersonMedicalRecords) as z
ON y.age=z.age )
SELECT * FROM ct2 ----- here on * use your required column
Here output of one left join will take as input table with next join and similarly you can maintain your hierarchy of join.
You are unnecessarily nesting your queries. You should write your query as:
SELECT p.cityId as personCityId, p.name, p.age,
cd.cityId, cd.state,
pd.age, pd.name
FROM Person p LEFT JOIN
CityDetails cd
ON p.cityid = cd.cityid LEFT JOIN
PersonalDetails pd
ON pd.age = p.age;
Note the use of meaningful table aliases (abbreviations for the table names) rather than arbitrary letters. Also, no subqueries.
If you want to add another JOIN, just add another JOIN, following the pattern of the other joins.
**I tried this and it works
SELECT X.personCityId, X.name, X.age, X.cityId, X.state, Y.age FROM (SELECT Person.cityId AS personCityId, Person.name, Person.age, CityDetails.cityId AS cityId, CityDetails.state FROM Person LEFT JOIN CityDetails ON Person.cityid = CityDetails.cityid) AS X LEFT JOIN (SELECT age, lastname FROM PersonalDetails) AS Y ON X.age=Y.age LEFT JOIN (SELECT age, height, weight FROM PersonMedicalRecords)AS Z ON Y.age = Z.age
Related
i'm trying to get a inner join from two select sentences but it doesn't work, what i am doing wrong?
i cant work with internal tables because inner join doesn't permit it.
clear: it_spfli.
refresh: it_spfli.
select
spfli-cityto
spfli-cityfrom
into TABLE it_spfli from(select spfli-cityto COUNT( * )from spfli group by spfli-cityto) as t1
INNER JOIN(select spfli-cityfrom COUNT( * )from spfli group by spfli-cityfrom) as t2
ON t1-cityto = t2-cityfrom.
i expect a table of more frequency city to and city from order by city to with table spfli.
First of all i don't think you are doing the right SELECT to get what you want.
I answer this question from the technical perspective. You can use WITH.
WITH +spf1 AS (
SELECT spfli~cityto AS cityto, COUNT(*) AS count FROM spfli GROUP BY spfli~cityto ) ,
+spf2 AS (
SELECT spfli~cityfrom AS cityfrom , COUNT(*) AS count FROM spfli GROUP BY spfli~cityfrom ) ,
+spf3 AS (
SELECT s1~cityto, s2~cityfrom FROM +spf1 AS s1 INNER JOIN +spf2 AS s2
ON s1~cityto = s2~cityfrom )
SELECT * FROM +spf3 INTO TABLE #DATA(lt_result).
I have two query to combine two results into one. However; my challenge is to get the second query look into the first query if it doesn't exist in the first query.
I changed my post to the actual query
SELECT Name.CO_ID, Name.FULL_NAME, Name.ID, rpt.date AS StartDate,
vw_Coords.TARGET_ID AS CoordID, vw_RegDirs.TARGET_ID AS
RDID
FROM Name INNER JOIN
Tops_Profile ON dbo.Name.ID = Tops_Profile.ID left
outer JOIN
vw_mz_rpt_leader_log rpt ON Name.CO_ID = rpt.ID LEFT
OUTER JOIN
vw_RegDirs ON Name.CO_ID = vw_RegDirs.CHAPTER LEFT
OUTER JOIN
vw_Coords ON Name.CO_ID = vw_Coords.CHAPTER LEFT OUTER
JOIN
Tops_Chapter ON Tops_Chapter.ID = Name.CO_ID
WHERE (Name.MEMBER_TYPE = 'm') AND (Tops_Profile.LDR = '1') and
LOG_TEXT like '%LEADER Change%'
union
SELECT Name.CO_ID, Name.FULL_NAME, Name.ID,
YEAR(dbo.Tops_Chapter.PST_DATE_LEAD) AS StartDate,
vw_Coords.TARGET_ID AS CoordID, vw_RegDirs.TARGET_ID AS
RDID
FROM Name INNER JOIN
Tops_Profile ON Name.ID = Tops_Profile.ID left outer
JOIN
vw_mz_rpt_leader_log rpt ON Name.CO_ID = rpt.ID LEFT
OUTER JOIN
vw_RegDirs ON Name.CO_ID = vw_RegDirs.CHAPTER LEFT
OUTER JOIN
vw_Coords ON Name.CO_ID = vw_Coords.CHAPTER LEFT OUTER
JOIN
Tops_Chapter ON Tops_Chapter.ID = Name.CO_ID
WHERE (Name.MEMBER_TYPE = 'm') AND (Tops_Profile.LDR = '1')
the scope is if the record exists in the first query don't bring it from second query.
Here's a quick and dirty way...
select *
from
(select id, Name, log.Date
from Name
inner join Log on Name.id = log.id
where log.text_log like '%Leader%'
union
select id, Name, Profile.Date
from Name
inner join profile on Name.id = profile.id
where profile.Leader = '1') d
order by row_number() over(partition by x.id order by x.Date asc)
Note, this doesn't care where John came from, it's simply finding the first occurrence based on the date which seems to be what you want.
You have altered your request. Suddenly both queries select from the same tables and a UNION (or UNION ALL for that matter) doesn't seem a good solution anymore.
There are very few differences between the two queries even. And looking at the whole it boils down to: select records for member_type = 'm' and tp.ldr = 1 and then keep only one record per name, preferredly one with log_text like '%LEADER Change%'. This is mere ranking, as already shown in my other answer. You only need one query to select all records in question and use TOP (1) WITH TIES to keep the best matches per name.
select top(1) with ties
n.co_id,
n.full_name,
n.id,
case when log_text like '%LEADER Change%' then rpt.date else year(tc.pst_date_lead) end
as startdate,
c.target_id as coordid,
rd.target_id as rdid
from name n
inner join tops_profile tp on n.id = tp.id
left outer join vw_mz_rpt_leader_log rpt on n.co_id = rpt.id
left outer join vw_regdirs rd on n.co_id = rd.chapter
left outer join vw_coords c on n.co_id = c.chapter
left outer join tops_chapter tc on tc.id = n.co_id
where n.member_type = 'm'
and tp.ldr = 1
order by row_number() over (
partition by n.id
order by case when log_text like '%LEADER Change%' then 1 else 2 end);
As you said you just want only one record per name, I am using ROW_NUMBER. If you want more, use RANK instead.
It's not clear why you are joining the tops_chapter table. Is log_text a column in that table? (You should use a table qualifier for this column in your query.) If it isn't, then the join is superfluous and you can remove it from your query.
Use row_number and select id's with least date
with cte as
(select id, Name, log.Date
from Name
inner join Log on Name.id = log.id
where log.text_log like '%Leader%'
union all
select id, Name, Profile.Date as log.date
from Name
inner join profile on Name.id = profile.id
where profile.Leader = '1'
) , ct1 as (select id,name,log.date, ROW_NUMBER() over (partition by id order by log.date) rn from cte )
select id,name,log.date from ct1 where rn = 1
where profile.Leader = '1'
and id not in ( select Name.id
from Name
inner join Log
on Name.id = log.id
where log.text_log like '%Leader%' )
You can use NOT EXISTS in the second query to filter out already existing Name records:
select id, Name, log.Date
from Name
inner join Log on Name.id = log.id
where log.text_log like '%Leader%'
union
select n1.id, n1.Name, Profile.Date
from Name as n1
inner join profile on n1.id = profile.id
where profile.Leader = '1' and
not exists (select 1
from Name as n2
inner join Log on n2.id = Log.id
where Log.text_log like '%Leader%' and
n2.id = n1.id and n2.name = n1.name)
The query below finds logdate and profiledate for each name. If there is a logdate, the logdate will be diplayed else the profile date will be displayed. If both don't exist the Name won't be displayed.
select id, Name, coalesce(log.Date,profile.date)
from Name
left join Log on Name.id = log.id and log.text_log like '%Leader%'
left join profile on Name.id = profile.id and profile.Leader = '1'
where coalesce(log.Date,profile.date) is not null
You can add a rank to your two queries. Then per ID you keep the record(s) with the better rank (using ORDER BY with TOP (1) WITH TIES).
select top(1) with ties
id, name, date
from
(
select n.id, n.name, log.date, 1 as rnk
from name n
inner join log on name.id = log.id
where log.text_log like '%Leader%'
union all
select n.id, n.name, profile.date, 2 as rnk
from name n
inner join profile on name.id = profile.id
where profile.leader = '1'
) data
order by rank() over (partition by id order by rnk);
I have 4 Tables ( Cattle , Farm , Vaccine , vReminder )
I want to select from Vaccine Reminder table all reminders to be shown as
( 2 ( Cows ) have ( Vaccine Name 1) from ( Farm Name 1) on this Date )
( 3 ( Horses) have ( Vaccine Name 1) from ( Farm Name 1) on this Date )
( 1 ( Cow) have ( Vaccine Name 5) from ( Farm Name 2) on this Date ) and so On
I wrote this Query But it is not Grouping the same Vaccine Type that are located for the same Farm if the cattle is of the same type :
My Query :
SELECT
(Select v.vName from vaccine as v where v.vID= vr.[vID]),
vr.[Type],
vsD,
COUNT(vr.[Type]),
f.farmName
FROM [QNFARM].[dbo].[vReminder] as vr inner join
[cattle] as c on c.RFID = vr.RFID inner join
farm as f on f.farmID = c.fID
Group by
vr.vID,
vr.Type,
vsD,
vr.RFID,
f.farmName
But as you See in the screen shot that it is Vname Pinkeye for to same breeds and same Dates and same Farm it does not Group Them .
The Problem that I was grouping also by RFID of the cattle that was preventing the group function to collect the Same vaccine id , so the correct query is :
SELECT f.farmName,vr.[Type],
(Select v.vName from vaccine as v where v.vID= vr.[vID]) as vName,vr.vsD
,COUNT(*) as Num
FROM [QNFARM].[dbo].[vReminder] as vr inner join [cattle] as c on c.RFID=vr.RFID inner join farm as f on f.farmID=c.fID Group by f.farmName,vr.Type,vr.vID,vr.vsD
I just remove the RFID from the group by statement and the result now
Don't use a subquery to get the vaccine name. Just use joins:
SELECT v.vName, vr.[Type], vsD, COUNT(*), f.farmName
FROM [QNFARM].[dbo].[vReminder] vr INNER JOIN
[cattle] c
ON c.RFID = vr.RFID INNER JOIN
farm f
ON f.farmID = c.fID INNER JOIN
vaccine v
ON v.vid = vr.vid
GROUP BY v.vname, vr.Type, vsD, f.farmName;
I have a tricky query. I need to select all recent versions of 2 types of members of administrator groups. Here is the query:
SELECT refGroup.*
FROM tblSystemAdministratorGroups refGroup
JOIN tblGroup refMem ON refGroup.AttributeValue = refMem.ObjectUID
This query will return all the administrator groups. The next step will be getting the members of these groups. Since I have 2 types of memberships (Explicit, Computed), I will have to use a LEFT JOIN to make sure that I am not excluding any rows.
SELECT refGroup.*
FROM tblSystemAdministratorGroups refGroup
-- The JOIN bellow can be excluded but it is here just to clarify the architecture
JOIN tblGroup refMem ON refGroup.AttributeValue = refMem.ObjectUID
LEFT JOIN tblGroup_ComputedMember cm ON refMem.ObjectUID = cm.GroupObjectID
LEFT JOIN tblGroup_ExplicitMember em ON refMem.ObjectUID = em.GroupObjectID
The last piece in the puzzle is to get the latest version of each member. For that I will have to use JOIN to exclude older versions:
JOIN (
SELECT MAX([ID]) MaxId
FROM [OmadaReporting].[dbo].tblGroup_ComputedMember
GROUP BY ObjectID
) MostRecentCM ON MostRecentCM.MaxId = cm.Id
and
JOIN (
SELECT MAX([ID]) MaxId
FROM [OmadaReporting].[dbo].tblGroup_ExplicitMember
GROUP BY ObjectID
) MostRecentEM ON MostRecentEM.MaxId = em.Id
The full query will be:
SELECT refGroup.*
FROM tblSystemAdministratorGroups refGroup
JOIN tblGroup refMem ON refGroup.AttributeValue = refMem.ObjectUID
LEFT JOIN tblGroup_ComputedMember cm ON refMem.ObjectUID = cm.GroupObjectID
JOIN (
SELECT MAX([ID]) MaxId
FROM [OmadaReporting].[dbo].tblGroup_ComputedMember
GROUP BY ObjectID
) MostRecentCM ON MostRecentCM.MaxId = cm.Id
LEFT JOIN tblGroup_ExplicitMember em ON refMem.ObjectUID = em.GroupObjectID
JOIN (
SELECT MAX([ID]) MaxId
FROM [OmadaReporting].[dbo].tblGroup_ExplicitMember
GROUP BY ObjectID
) MostRecentEM ON MostRecentEM.MaxId = em.Id
The issue is clear: The 2 JOIN to exclude old versions are also applied to the select statement and clearly no rows are returned. What would be the best solution to escape such situation and to return the intended values?
SELECT refGroup.*
FROM tblSystemAdministratorGroups refGroup
JOIN tblGroup refMem ON refGroup.AttributeValue = refMem.ObjectUID
LEFT JOIN (
select GroupObjectID, ID, max(ID) over (partition by ObjectID) as maxID
from tblGroup_ComputedMember
) cm ON refMem.ObjectUID = cm.GroupObjectID and cm.ID = cm.maxID
LEFT JOIN (
select GroupObjectID, ID, max(ID) over (partition by ObjectID) as maxID
from tblGroup_ExplicitMember
) em ON refMem.ObjectUID = em.GroupObjectID and em.ID = em.maxID
where cm.ID = cm.MaxID
What about using LEFT join in your last two joins?
LEFT JOIN (
SELECT MAX([ID]) MaxId
FROM [OmadaReporting].[dbo].tblGroup_ComputedMember
GROUP BY ObjectID
) MostRecentCM ON MostRecentCM.MaxId = cm.Id
And then in Where clause filter values as:
WHERE MostRecentCM.MaxId IS NOT NULL
OR
MostRecentEM.MaxId IS NOT NULL
I have tried a lot to figure how to get the count from two tables with respect to master table
I have three tables
Using these table values I need to get this output..
Tried but could get the desired result
http://en.wikipedia.org/wiki/Join_(SQL)
SQL - LEFT OUTER JOIN and WHERE clause
http://forums.devshed.com/oracle-development-96/combination-of-left-outer-join-and-where-clause-383248.html
You have to first GROUP BY in subqueries, then JOIN to the main table:
SELECT
a.AttributeId
, COALECSE(cntE, 0) AS cntE
, COALECSE(cntM, 0) AS cntM
FROM
AttributeMaster AS a
LEFT JOIN
( SELECT
AttributeId
, COUNT(*) AS cntE
FROM
EmployeeMaster
GROUP BY
AttributeId
) em
ON em.AttributeId = a.AttributeId
LEFT JOIN
( SELECT
AttributeId
, COUNT(*) AS cntM
FROM
MonthlyDerivedMaster
GROUP BY
AttributeId
) mdm
ON mdm.AttributeId = a.AttributeId
SELECT AttributeId,
(SELECT COUNT(Eid) FROM EmployeeMaster WHERE AttributeMaster.AttributeId = EmployeeMaster.AttributeId) as master_eid,
(SELECT COUNT(Eid) FROM MonthnlyDerivedMaster WHERE AttributeMaster.AttributeId = MonthnlyDerivedMaster.AttributeId) as monthly_eid
FROM AttributeMaster