SQL - joining 3 tables and choosing newest logged entry per id - sql

Question

I got rather complicated riddle to solve. So far I'm unlocky.
I got 3 tables which I need to join to get the result.
Most important is that I need highest h_id per p_id. h_id is uniqe entry in log history. And I need newest one for given point (p_id -> num).
Apart from that I need ext and name as well.
history
+----------------+---------+--------+
| h_id | p_id | str_id |
+----------------+---------+--------+
| 1 | 1 | 11 |
| 2 | 5 | 15 |
| 3 | 5 | 23 |
| 4 | 1 | 62 |
+----------------+---------+--------+
point
+----------------+---------+
| p_id | num |
+----------------+---------+
| 1 | 4564 |
| 5 | 3453 |
+----------------+---------+
street
+----------------+---------+-------------+
| str_id | ext | name |
+----------------+---------+-------------+
| 15 | | Mein st. 33 | - bad name
| 11 | | eck st. 42 | - bad name
| 62 | abc | Main st. 33 |
| 23 | efg | Back st. 42 |
+----------------+---------+-------------+
EXPECTED RESULT
+----------------+---------+-------------+-----+
| num | ext | name |h_id |
+----------------+---------+-------------+-----+
| 3453 | efg | Back st. 42 | 3 |
| 4564 | abc | Main st. 33 | 4 |
+----------------+---------+-------------+-----+
I'm using Oracle SQL. Tried using query below but result is not true.
SELECT num, max(name), max(ext), MAX(h_id) maxm FROM history
INNER JOIN street on street.str_id = history._str_id
INNER JOIN point on point.p_id = history.p_id
GROUP BY point.num

Answer 1

In Oracle, you can use keep:
SELECT p.num,
MAX(h.h_id) as maxm,
MAX(s.name) KEEP (DENSE_RANK FIRST ORDER BY h.h_id DESC) as name,
MAX(s.ext) KEEP (DENSE_RANK FIRST ORDER BY h.h_id DESC) as ext
FROM history h INNER JOIN
street s
ON s.str_id = h._str_id INNER JOIN
point p
ON p.p_id = h.p_id
GROUP BY p.num;
The keep syntax allows you to do "first()" and "last()" for aggregations.