I would like to convert a date in yyyy-mm-dd (Date format, length 10) to mm-yy format.
I have so far tried "right", "Left" and "convert" functions to no avail.
What's the exact syntax I need to use?
SELECT
LEFT (day,7) as 'YYYYMM'
FROM bi_core.fact_campaign_device_stats_daily
WHERE DAY = '2019-07-01'
SQL Error [3457] [42883]: [Vertica][VJDBC](3457) ERROR: Function LEFT(date, int) does not exist, or permission is denied for LEFT(date, int)
In Vertical, use to_char():
SELECT to_char(day, 'MMYY') as mmyy
FROM bi_core.fact_campaign_device_stats_daily
WHERE DAY = '2019-07-01'
For SQL database:
SELECT FORMAT(day, 'MM-yyyy') AS 'new_format'
FROM bi_core.fact_campaign_device_stats_daily
WHERE DAY = '2019-07-01'
Or also, to get it numeric:
SELECT YEAR("day") * 100 + MONTH("day") AS yearmonth
FROM bi_core.fact_campaign_device_stats_daily
WHERE "day" = '2019-07-01'
Related
Just a general date filter question, what are the valid operators for me to filter a specific timeframe as I had this error:
Cannot apply operator: date <= varchar(8)
code:
where utc_date >= '2022-04-01'
data type = date
'2022-04-01' is a varchar literal, you need to convert it to date for example by prefixing it with date:
where utc_date >= date '2022-04-01'
How to add or sub a date?
SELECT DATEADD(month, -1, '2017-08-25') AS DATEADD
ERROR:
Msg 242, Level 16, State 3, Line 98
The conversion of a varchar data type to a datetime data type resulted in an out-of-range value.
Your query works fine in SQL Server (see here).
You may have arcane internationalization settings that do not treat '2015-08-25' as YYYY-MM-DD.
There are two choices. You can drop the hyphens:
SELECT DATEADD(month, -1, '20170825') AS DATEADD
SQL Server always treats date strings with eight digits as a date in the format YYYYMMDD.
Or do an explicit conversion:
SELECT DATEADD(month, -1, CONVERT(DATE, '2017-08-25', 120)) AS DATEADD
1- If you have date datatype of your column then you can directly do add or sub on date like below
select datecol -1 as sub_op , datecol+1 as sub_op2 from your_table
2- If you want to convert string to date in oracle you can use to_date function as below
select to_date('28-May-2019','DD-MM-YYYY') from dual;
or if mysql
STR_TO_DATE('2013-02-11', '%Y-%m-%d')
enter code here
SELECT convert (varchar(15),DATEADD(day, 1, '2017/08/25'),103) AS DateAdd; -- dd/MM/YYYY only
SELECT convert (varchar(15),DATEADD(DAY, -1, '2017/08/25'),103) AS DateAdd; -- dd/MM/YYYY
1.year, yyyy, yy = Year
2.quarter, qq, q = Quarter
3.month, mm, m = month
4.dayofyear = Day of the year
5.day, dy, y = Day
6.week, ww, wk = Week
7.weekday, dw, w = Weekday
8.hour, hh = hour
9.minute, mi, n = Minute
10.second, ss, s = Second
11.millisecond, ms = Millisecond
i have dates stored as chars in db (i know, but its not my db nor my idea..).
One of the dates is stored as MMYYYY (012016,022016...) and the second one is stored as YYYYMMDD (20160101,20160202...).
Is there a way to compare those dates? I need to take one date and select all of the second dates which are at least one year older then the first one...
Thank you for any help !
So for example i have Date1 field with values : 012014,012015,012016
and Date2 field with value: 20141005
And i need only Date1 which is at least one year older then Date2 so in this case it will return only 012016
I make two ctes to show how to work it out. I assume MMYYYY are stored as nvarchar or varchar and YYYYMMDD are the same type. If not - you will need one/few conversions on YYYYMMDD field.
;WITH cte AS (
SELECT '012016' as MMYYYY
UNION ALL
SELECT '022016'
), cte2 AS (
SELECT '20160101' AS YYYYMMDD
UNION ALL
SELECT '20160202'
)
SELECT *
FROM cte c
INNER JOIN cte2 c2
ON YYYYMMDD LIKE RIGHT(MMYYYY,4)+LEFT(MMYYYY,2) +'%'
Output:
MMYYYY YYYYMMDD
012016 20160101
022016 20160202
EDIT:
To find out differences in years use this:
DATEDIFF(year,CAST(YYYYMMDD as date), CAST(RIGHT(MMYYYY,4)+LEFT(MMYYYY,2)+'01' as date))
You can convert both fields into type DATE, then compare them.
For MMYYYY, you can use the function DATEFROMPARTS() to build a date. For example, convert 012014 into date:
-- DATEFROMPARTS(year, month, day)
DATEFROMPARTS(RIGHT('012014', 4), LEFT('012014', 2), 1)
For YYYYMMDD, it is easier, because this is the format ISO with Time Style 112. You can use the CONVERT() function to do the conversion :
CONVERT(DATE, '20141005', 112)
And here's how the final query looks like :
WITH casted AS (
SELECT
DATEFROMPARTS(RIGHT(date1, 4), LEFT(date1, 2), 1) AS d1,
CONVERT(DATE, date2, 112) AS d2,
-- ...
FROM yourTable
)
SELECT *
FROM casted
WHERE d1 <= DATEADD(YEAR, -1, d2)
try this
column1 is stored MMYYYY format and column2 is stored YYYYMMDD.
where column1= case when datepart(month,taskDuedate)>9 then convert(varchar,datepart(month,taskDuedate))else '0'+convert(varchar,datepart(month,taskDuedate))end+convert(varchar,datepart(year,taskDueDate))
I have a column that stores a date as char in the format 'YYYYMMDD'. Now I want to convert it to a real date.
I tried
select cast (DATEFIELD as DATE) as MyDate
But it only returns the old YYYYMMDD format labeled as 'DATE'. What am I doing wrong?
SELECT TIMESTAMP_FORMAT("DATEFIELD",'YYYYMMDD') as "MyDate"
Use the CONVERT function and the style 112 to get the output in YYYYMMDD
SELECT CONVERT(DATEFIELD, 112) as MyDate
FROM yourtable
Or style 100 for mon dd yyyy hh:mi
SELECT CONVERT(DATEFIELD, 100) as MyDate
FROM yourtable
Simply convert it.
SELECT TIMESTAMP_FORMAT("DATEFIELD",'YYYYMMDD') as MyDate
FROM <your_table>
I want to be able to select all database rows where the month and year are the same as what I am searching for. Since the DATE field has year, month, and day, how do I search with year and month?
SELECT *
FROM tblTableName
WHERE Month(ColumnDate) = Month(MyDate)
AND Year(ColumnDate) = Year(MyDate)
SELECT *
FROM myTable
WHERE ( YEAR(myfield) = '2009')
AND ( MONTH(myfield) = '1')
The most efficient is to create the start and end date of the range that you want, so that you compare the dates as a single value instead of extracting the year and month properties from each date.
Example:
select SomeField
from SomeTable
where SomeDate >= ? and SomeDate < ?
(Note that the first comparison is inclusive and the seond is exclusive.)
Create the start and end date to use as parameters: (example in C#)
DateTime start = new DateTime(date.Year, date.Month, 1)
DateTIme end = start.AddMonths(1);
In MySQL:
SELECT *
FROM mytable
WHERE date >= STR_TO_DATE(CONCAT(EXTRACT(YEAR_MONTH FROM #mydate), '01'), '%Y%m%d')
AND date < STR_TO_DATE(CONCAT(EXTRACT(YEAR_MONTH FROM #mydate), '01'), '%Y%m%d') + INTERVAL 1 MONTH
This will efficiently use an index on the date field.
That would depend on what database backend you are using. IN SQl Server I would use
where year(datefield) = #year and month (datefield) - #month
to do this.
or you could build a where clause by creating a date range
where datefield between 20090101 and 20090201
You will want to use MONTH() and YEAR() in mysql.