SQL date selecting - sql

I want to be able to select all database rows where the month and year are the same as what I am searching for. Since the DATE field has year, month, and day, how do I search with year and month?

SELECT *
FROM tblTableName
WHERE Month(ColumnDate) = Month(MyDate)
AND Year(ColumnDate) = Year(MyDate)

SELECT *
FROM myTable
WHERE ( YEAR(myfield) = '2009')
AND ( MONTH(myfield) = '1')

The most efficient is to create the start and end date of the range that you want, so that you compare the dates as a single value instead of extracting the year and month properties from each date.
Example:
select SomeField
from SomeTable
where SomeDate >= ? and SomeDate < ?
(Note that the first comparison is inclusive and the seond is exclusive.)
Create the start and end date to use as parameters: (example in C#)
DateTime start = new DateTime(date.Year, date.Month, 1)
DateTIme end = start.AddMonths(1);

In MySQL:
SELECT *
FROM mytable
WHERE date >= STR_TO_DATE(CONCAT(EXTRACT(YEAR_MONTH FROM #mydate), '01'), '%Y%m%d')
AND date < STR_TO_DATE(CONCAT(EXTRACT(YEAR_MONTH FROM #mydate), '01'), '%Y%m%d') + INTERVAL 1 MONTH
This will efficiently use an index on the date field.

That would depend on what database backend you are using. IN SQl Server I would use
where year(datefield) = #year and month (datefield) - #month
to do this.
or you could build a where clause by creating a date range
where datefield between 20090101 and 20090201

You will want to use MONTH() and YEAR() in mysql.

Related

SQL Server: Getting "before two days" date

I have a select, and I need to limit data only for two last days. So today is 24th Aug 2016 so I need to get data for 24th Aug 2016, 23th Aug 2016 and 22th Aug 2016. How can I do that? I suppose I should use DATEADD function, or something similar. It needs to be done dynamicaly.
I need to get something like this:
SELECT * FROM TABLE_NAME WHERE
DATE = '2016-08-22'
The date must be updated each day
DateAdd, exactly
SELECT * FROM TABLE_NAME
WHERE DATE BETWEEN dateadd(d,-2,cast(getDate() as date)) AND cast(getDate() as date)
SELECT *
FROM TABLE_NAME
WHERE cast(DATE as date) BETWEEN cast(DATEADD(D, -2, GETDATE()) as date) AND cast(GETDATE() as date)
SELECT * FROM TABLE_NAME WHERE
cast(DATE as date) >= cast(GETDATE()-2 as date)
or
--For limiting future dates
SELECT * FROM TABLE_NAME
WHERE
cast(DATE as date) in (cast(GETDATE()-2 as date),cast(GETDATE()-1 as date), cast(GETDATE() as date))
Use GETDATE() function
If there are future dates in this table you can perhaps use this
select * from table_name
where date <= getdate()
and date >= dateadd(day,-2,getdate())
SELECT * FROM TABLE_NAME WHERE
DATE >=cast(getdate()-2 as date)--so this will be rounded off to midnight and it is sargable
First you have to make today's date in absolute by converting it in float then floor and then convert it into small date time. And then using dateadd subtract 2 days from today's absolute date.
SELECT * FROM
TABLE_NAME
WHERE
DATE >= (SELECT DATEADD(dd,-2,CAST(FLOOR(CAST(GETDATE() as FLOAT)) as SMALLDATETIME)))

retrieve day after tomorrow date query

I want to select day after tomorrow date in sql. Like I want to make a query which select date after two days. If I select today's date from calender(29-04-2015) then it should show date on other textbox as (01-05-2015). I want a query which retrieve day after tomorrow date. So far I have done in query is below:
SELECT VALUE_DATE FROM DLG_DEAL WHERE VALUE_DATE = GETDATE()+2
thanks in advance
Note that if you have a date field containing the time information, you will need to truncate the date part using DATEADD
dateadd(d, 0, datediff(d, 0, VALUE_DATE))
To compare 2 dates ignoring the date part you could just use DATEDIFF
SELECT VALUE_DATE FROM DLG_DEAL
WHERE datediff(d, VALUE_DATE, getdate()) = -2
or
SELECT VALUE_DATE FROM DLG_DEAL
WHERE datediff(d, getdate(), VALUE_DATE) = 2
Try like this:
SELECT VALUE_DATE
FROM DLG_DEAL WHERE VALUE_DATE = convert(varchar(11),(Getdate()+2),105)
SQL FIDDLE DEMO
SELECT VALUE_DATE FROM DLG_DEAL WHERE datediff(d, VALUE_DATE, getdate()) = -2
** I think you should try this**
SELECT DATEADD(day,2,VALUE_DATE) AS DayAfterTomorrow
FROM DLG_DEAL WHERE VALUE_DATE= GETDATE();
DATEADD(choiceToAdd, interval, date)
This function allows you to add or substract day,month, year,etc from date. In this interval is nothing but numeric value which you want to add or substract.

Comparing dates in SQL Server

I have a DateTime column named EXP_Date which contains date like this :
2014-07-13 00:00:00.000
I want to compare them, like this query :
SELECT COUNT(*)
FROM DB
WHERE ('2014-07-15' - EXP_DATE) > 1
I expect to see the number of customers who have their services expired for over a month.
I know this query wouldn't give me the correct answer, the best way was if I separate the Year / Month / Day into three columns, but isn't any other way to compare them as they are?
You can use DATEADD
SELECT COUNT(*)
FROM DB
where EXP_DATE < DATEADD(month, -1, GETDATE())
Try this
SELECT COUNT(*)
FROM DB
where DATEADD(month, -1, GETDATE()) > EXP_DATE
SELECT COUNT(EXPIRE)FROM
(Select CASE WHEN EXP_DATE < DATEADD(month, -1, GETDATE())THEN 1 ELSE 0 END)AS EXPIRE FROM DB
)tt
Another way using DATEDIFF
SET DATEFORMAT DMY --I like to use "dateformat"
SELECT COUNT(*)
FROM DB
WHERE (DATEDIFF(DAY,#EXP_DATE,GETDATE())) >= 30 --Remember, instead "Day" you can use week, month, year, etc
Syntax: DATEDIFF ( datepart , startdate , enddate )
Depart: year, quarter, month, day, week...
For more information you can visit MSDN

Comparing results with today's date?

Is there a way to use the Now() function in SQL to select values with today's date?
I was under the impression Now() would contain the time as well as date, but today's date would have the time set to 00:00:00 and therefore this would never match?
OK, lets do this properly. Select dates matching today, using indexes if available, with all the different date/time types present.
The principle here is the same in each case. We grab rows where the date column is on or after the most recent midnight (today's date with time 00:00:00), and before the next midnight (tomorrow's date with time 00:00:00, but excluding anything with that exact value).
For pure date types, we can do a simple comparison with today's date.
To keep things nice and fast, we're explicitly avoiding doing any manipulation on the dates stored in the DB (the LHS of the where clause in all the examples below). This would potentially trigger a full table scan as the date would have to be computed for every comparison. (This behaviour appears to vary by DBMS, YMMV).
MS SQL Server: (SQL Fiddle | db<>fiddle)
First, using DATE
select * from dates
where dte = CAST(CURRENT_TIMESTAMP AS DATE)
;
Now with DATETIME:
select * from datetimes
where dtm >= CAST(CURRENT_TIMESTAMP AS DATE)
and dtm < DATEADD(DD, 1, CAST(CURRENT_TIMESTAMP AS DATE))
;
Lastly with DATETIME2:
select * from datetimes2
where dtm2 >= CAST(CURRENT_TIMESTAMP AS DATE)
and dtm2 < DATEADD(DD, 1, CAST(CURRENT_TIMESTAMP AS DATE))
;
MySQL: (SQL Fiddle | db<>fiddle)
Using DATE:
select * from dates
where dte = cast(now() as date)
;
Using DATETIME:
select * from datetimes
where dtm >= cast((now()) as date)
and dtm < cast((now() + interval 1 day) as date)
;
PostgreSQL: (SQL Fiddle | db<>fiddle)
Using DATE:
select * from dates
where dte = current_date
;
Using TIMESTAMP WITHOUT TIME ZONE:
select * from timestamps
where ts >= 'today'
and ts < 'tomorrow'
;
Oracle: (SQL Fiddle)
Using DATE:
select to_char(dte, 'YYYY-MM-DD HH24:MI:SS') dte
from dates
where dte >= trunc(current_date)
and dte < trunc(current_date) + 1
;
Using TIMESTAMP:
select to_char(ts, 'YYYY-MM-DD HH24:MI:SS') ts
from timestamps
where ts >= trunc(current_date)
and ts < trunc(current_date) + 1
;
SQLite: (SQL Fiddle)
Using date strings:
select * from dates
where dte = (select date('now'))
;
Using date and time strings:
select dtm from datetimes
where dtm >= datetime(date('now'))
and dtm < datetime(date('now', '+1 day'))
;
Using unix timestamps:
select datetime(dtm, 'unixepoch', 'localtime') from datetimes
where dtm >= strftime('%s', date('now'))
and dtm < strftime('%s', date('now', '+1 day'))
;
Backup of SQL Fiddle code
There is no native Now() function in SQL Server so you should use:
select GETDATE() --2012-05-01 10:14:13.403
you can get day, month and year separately by doing:
select DAY(getdate()) --1
select month(getdate()) --5
select year(getdate()) --2012
if you are on sql server 2008, there is the DATE date time which has only the date part, not the time:
select cast (GETDATE() as DATE) --2012-05-01
Not sure what your asking!
However
SELECT GETDATE()
Will get you the current date and time
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()))
Will get you just the date with time set to 00:00:00
Just zero off the time element of the date. e.g.
SELECT DATEADD(dd, DATEDIFF(dd, 0, getdate()), 0)
I've used GetDate as that's an MSSQL function, as you've tagged, but Now() is probably MySQL or you're using the ODBC function call, still should work if you just replace one with the other.
Not sure exactly what you're trying to do, but it sounds like GETDATE() is what you're after. GETDATE() returns a datetime, but if you're not interested in the time component then you can cast to a date.
SELECT GETDATE()
SELECT CAST(GETDATE() AS DATE)
Building on the previous answers, please note an important point, you also need to manipulate your table column to ensure it does not contain the time fragment of the datetime datatype.
Below is a small sample script demonstrating the above:
select getdate()
--2012-05-01 12:06:51.413
select cast(getdate() as date)
--2012-05-01
--we're using sysobjects for the example
create table test (id int)
select * from sysobjects where cast(crdate as date) = cast(getdate() as date)
--resultset contains only objects created today
drop table test
I hope this helps.
EDIT:
Following #dwurf comment (thanks) about the effect the above example may have on performance, I would like to suggest the following instead.
We create a date range between today at midnight (start of day) and the last millisecond of the day (SQL server count up to .997, that's why I'm reducing 3 milliseconds). In this manner we avoid manipulating the left side and avoid the performance impact.
select getdate()
--2012-05-01 12:06:51.413
select dateadd(millisecond, -3, cast(cast(getdate()+1 as date) as datetime))
--2012-05-01 23:59:59.997
select cast(getdate() as date)
--2012-05-01
create table test (id int)
select * from sysobjects where crdate between cast(getdate() as date) and dateadd(millisecond, -3, cast(cast(getdate()+1 as date) as datetime))
--resultset contains only objects created today
drop table test
If you have a table with just a stored date (no time) and want to get those by "now", then you can do this:
SELECT * FROM tbl WHERE DATEDIFF(d, yourdate, GETDATE())=0
This results in rows which day difference is 0 (so today).
For me the query that is working, if I want to compare with DrawDate for example is:
CAST(DrawDate AS DATE) = CAST (GETDATE() as DATE)
This is comparing results with today's date.
or the whole query:
SELECT TOP (1000) *
FROM test
where DrawName != 'NULL' and CAST(DrawDate AS DATE) = CAST (GETDATE() as DATE)
order by id desc
You can try this sql code;
SELECT [column_1], [column_1], ...
FROM (your_table)
where date_format(record_date, '%e%c%Y') = date_format(now(), '%e%c%Y')
You can try:
WHERE created_date BETWEEN CURRENT_TIMESTAMP-180 AND CURRENT_TIMESTAMP
This worked for me:
SELECT * FROM table where date(column_date) = curdate()

SQL statement to select all rows from previous day

I am looking for a good SQL Statement to select all rows from the previous day from one table. The table holds one datetime column. I am using SQL Server 2005.
get today no time:
SELECT dateadd(day,datediff(day,0,GETDATE()),0)
get yestersday no time:
SELECT dateadd(day,datediff(day,1,GETDATE()),0)
query for all of rows from only yesterday:
select
*
from yourTable
WHERE YourDate >= dateadd(day,datediff(day,1,GETDATE()),0)
AND YourDate < dateadd(day,datediff(day,0,GETDATE()),0)
To get the "today" value in SQL:
convert(date, GETDATE())
To get "yesterday":
DATEADD(day, -1, convert(date, GETDATE()))
To get "today minus X days": change the -1 into -X.
So for all yesterday's rows, you get:
select * from tablename
where date >= DATEADD(day, -1, convert(date, GETDATE()))
and date < convert(date, GETDATE())
It's seems the obvious answer was missing. To get all data from a table (Ttable) where the column (DatetimeColumn) is a datetime with a timestamp the following query can be used:
SELECT * FROM Ttable
WHERE DATEDIFF(day,Ttable.DatetimeColumn ,GETDATE()) = 1 -- yesterday
This can easily be changed to today, last month, last year, etc.
SELECT * from table_name where date_field = DATE_SUB(CURRENT_DATE(),INTERVAL 1 DAY);
Its a really old thread, but here is my take on it.
Rather than 2 different clauses, one greater than and less than. I use this below syntax for selecting records from A date. If you want a date range then previous answers are the way to go.
SELECT * FROM TABLE_NAME WHERE
DATEDIFF(DAY, DATEADD(DAY, X , CURRENT_TIMESTAMP), <column_name>) = 0
In the above case X will be -1 for yesterday's records
This should do it:
WHERE `date` = CURDATE() - INTERVAL 1 DAY
Can't test it right now, but:
select * from tablename where date >= dateadd(day, datediff(day, 1, getdate()), 0) and date < dateadd(day, datediff(day, 0, getdate()), 0)
In SQL Server do like this:
where cast(columnName as date) = cast(getdate() -1 as date)
You should cast both sides of the expression to date to avoid issues with time formatting.
If you need to control interval in more detail, then you should try something like:
declare #start datetime = cast(getdate() - 1 as date)
declare #end datetime = cast(getdate() - 1 as date)
set #end = dateadd(second, 86399, #end)
Another way to tell it "Yesterday"...
Select * from TABLE
where Day(DateField) = (Day(GetDate())-1)
and Month(DateField) = (Month(GetDate()))
and Year(DateField) = (Year(getdate()))
This conceivably won't work well on January 1, as well as the first day of every month. But on the fly it's effective.
Well, its easier to cast the datetime column to date and than compare.
SELECT * FROM TABLE_NAME WHERE cast(COLUMN_NAME as date) =
dateadd(day,0, convert(date, getdate(), 105))
A simple alternative
Select GETDATE() - 1
Change 1 to go back that many number of days
PS : This gives you timestamp accuracy.
This worked a charm:
SELECT * FROM mytable WHERE date(mydate) = DATE_SUB(CURDATE(), INTERVAL 1 DAY);
subdate(now(),1) will return yesterdays timestamp
The below code will select all rows with yesterday's timestamp
Select * FROM `login` WHERE `dattime` <= subdate(now(),1) AND `dattime` > subdate(now(),2)