I'm looking to create a recurring date calculator that will correspond to EVENTS on a specific calendar date. Each event has its own rule.
For example, for EVENT A rule is "Occurs Tuesday monthly with the start date Tuesday 9-17-2019. I'm using a time dimension table with every date populated until 2025. Using these dates I was using in the WHERE clause
WHERE dayname = 'tuesday' and ( DATEDIFF(DAY, '2019-09-17', Calendar_Date) % 28 ) = 0 to get monthly tuesdays.
But I'm running into issues when there are two 5 Tuesdays in a month. 3-3-2020 and 3-31-2020. Need date populated to be 4-7-2020 instead of 3-31-2020.
Can anyone help with a solution?
With your query, you're pretty close. All you need to do is to then sub-select
SELECT MIN(CalendarDate) AS CalendarDate
FROM (your query goes here) AS d
GROUP BY YEAR(CalendarDate), MONTH(CalendarDate);
Related
I have a below query that I run to extract material movements from the last 7 days.
Purpose is to get the data for the last calender week for certain reports.
select
*
From
redshift
where
posting_date between CURRENT_DATE - 7 and CURRENT_DATE - 1
That means I need to run the query on every Monday to get the data for the former week.
Sometimes I am too busy on Monday or its vacation/bank holiday. In that case I would need to change the query or pull the data via SAP.
Question:
Is there a function for redshift that pulls out the data for the last calender week regardless when I run the query?
I already found following solution
SELECT id FROM table1
WHERE YEARWEEK(date) = YEARWEEK(NOW() - INTERVAL 1 WEEK)
But this doesnt seem to be working for redshift sql
Thanks a lot for your help.
Redshift offers a DATE_TRUNC('week', datestamp) function. Given any datestamp value, either a date or datetime, it gives back the date of the preceding Sunday.
So this might work for you. It filters rows from the Sunday before last, up until but not including, the last Sunday, and so gets a full week.
SELECT id
FROM table1
WHERE date >= DATE_TRUNC('week', NOW()) - INTERVAL 1 WEEK
AND date < DATE_TRUNC('week', NOW())
Pro tip: Every minute you spend learning your DBMS's date/time functions will save you an hour in programming.
SQL server DATEPART function has two options to retrieve week number;
ISO_WEEK and WEEK. I Know the difference between the two, I want to have week numbers based on Sunday start standard as followed in the US; i.e. WEEK. But it doesn't handles partial weeks the way I expected. e.g.
SELECT DATEPART(WEEK,'2015-12-31') --53
SELECT DATEPART(WEEK,'2016-01-01') --1
SELECT DATEPART(WEEK,'2016-01-03') --2
gives two different week numbers for a single week, divided in two years. I wanted to implement something like in the following link for week days.
Week numbers according to US standard
Basically I would like something like this;
SELECT DATEPART(WEEK,'2015-12-31') --1
SELECT DATEPART(WEEK,'2016-01-01') --1
SELECT DATEPART(WEEK,'2016-01-03') --2
EDIT:
Basically I am not good with the division of a single week into two, I have to perform some calculations based on week numbers and the fact that a single week to be divided isn't acceptable. So if above isn't possible.
Is it possible that the week number one would start from 2016-01-03. i.e. what I would in that case would be something like this:
SELECT DATEPART(WEEK,'2015-12-31') --53
SELECT DATEPART(WEEK,'2016-01-01') --53
SELECT DATEPART(WEEK,'2016-01-03') --1
If you want the US numbering, you can do this by taking the WEEK number of the end of the week rather than the date itself.
First ensure that the setting for first day of the week is in fact Sunday on your system. You can verify this by running SELECT ##DATEFIRST; this should return 7 for Sunday. If it doesn't, run SET DATEFIRST 7; first.
SELECT
end_of_week=DATEADD(DAY, 7-(DATEPART(WEEKDAY, '20151231')), '20151231'),
week_day=DATEPART(WEEK, DATEADD(DAY, 7-(DATEPART(WEEKDAY, '20151231')), '20151231'));
Which will return 2016/01/02 - 1.
If you wish generate week number of a date, it will return the week number of the year(input date)
Thus, I think sql server treat '2015-12-31' as the last week of 2015.
I have an SSRS report with parameters for Created On Start and Created On End. Users run this manually and choose the date range to display records for. I need to display in two different columnns the records for the month the user entered in the parameters and the previous month for the dates used in the parameters.
For example the user uses the the following dates in the parameters:
Start Date: 03/01/2016 EndDate: 03/31/2016
The Report should display in one column the records for march 2016 and next to it the records for february 2016
You could write one query which queries both months.
Add a field that will act as the column label eg format the date as the first of the month.
Then create a pivot table to show the two months as the columns with the usual rows .
EDIT - new details
So:
dateStart = '2016-03-01'
dateEnd = '2016-03-31'
These could be less than the whole month, but should be in the same month. prevStart = DATEADD(month, DATEDIFF(month, '2000-01-01', dateStart)-1, '2000-01-01')
the first day of the previous month.
Use similar for the prevEnd to calculate the last day of previous month.
OK. Now build your select:
SELECT xxxx, yyyy, zzzz
, DATEADD(month, DATEDIFF(month, '2000-01-01', createdOnDate), '2000-01-01') as MonthCol
FROM tables
WHERE (createdOnDate>= prevStart and createdOnDate<=prevEnd)
OR (createdOnDate>= dateStart and createdOnDate<=dateEnd)
Build a pivot table style grid with monthCol as the heading of the columns and your usual data as the rows. That way you can get your "previous Month" columns as well as the date range that you selected
I need to run a weekly report based on the arrival date. How can I set the arrival date in the where clause so that I can get the result only for each week. The hard part is I DO NOT want to modify the dates each week. I need the permanent where clause for the date. I have to provide a list of customers who arrived every week and I just want to run the same script without changing the week dates.
Please assist.
Thanks.
SELECT * FROM TABLE WHERE
(ARRIVAL_DATE>DATEFROMPARTS(YEAR(GETDATE()-7), MONTH(GETDATE()-7), DAY(GETDATE()-7)))//7 days before starting at midnight
AND
(ARRIVAL_DATE<DATEFROMPARTS(YEAR(GETDATE()), MONTH(GETDATE()), DAY(GETDATE()))) //NOW in the YYYY, MM,DD format
This will get everything that happened in the current calendar week (Mon-Sun)
SELECT * FROM Table1
WHERE ArrivalDate BETWEEN
CAST(DATEADD(dd,(((DATEPART(dw,getdate())+##DATEFIRST) % 7)+5) % 7 ,getdate()) as date) AND
CAST(DATEADD(dd,6+((((DATEPART(dw,getdate())+##DATEFIRST) % 7)+5) % 7 ),getdate()) as date)
Edit - Removed extra E in BETWEEN
I'm currently running the following sql statement in JasperReports Server to bring back my data using derived tables.
Select count(createddate) as ModulesCreatedDuringPastWeek,
count(updateddate) as ModulesUpdatedDuringPastWeek,
createddate,
updateddate
from merchendisingmodule
group by merchendisingmodule.createddate, merchendisingmodule.updateddate
However when grouping my data, I am only able to do it in Year, quarter, month and day. However for my report I'm needing the data to be group weeks, and so I was wondering what I will need to add to my code to do this.
DATEADD(D,-DATEPART(weekday,createddate)+1,createddate)
I use this method to prevent issues around the year transitions (week 53 in first days of januari and also in the last days of december, will group days together that are 360 days apart).
I use the first day of the week, instead of week numbers. I can use these dates to group by.
Also this will ensure that every week is 7 days long, instead of the last week of the year being only 3 or 4 days long.
Btw, in this example the first day of the week is sunday.
If your dates include time, use:
CAST(FLOOR(CAST(createddate AS FLOAT)) AS DATETIME)
instead of createddate in the above SYNTAX