I am trying to get the results from this query to only give me DISTINCT results by the concatenated column fullname. The results instead give me DISTINCT by both fullname and facilityname (which is 'name'). I've looked over other solutions to similar questions but don't understand them well enough to apply them to this situation.
I've tried to play with the code, but nothing worth noting.
USE country_club;
SELECT DISTINCT
CONCAT(mem.firstname, mem.surname) AS fullname,
fac.name
FROM
Bookings AS boo
JOIN
Members AS mem ON boo.memid = mem.memid
JOIN
Facilities AS fac ON boo.facid = fac.facid
WHERE
boo.facid = 0 OR boo.facid = 1
ORDER BY
fullname ASC;
No errors on this code to note. Just need to modify the conditions to arrive at the desired outcome.
If you want one row per group of columns, use group by, not distinct:
SELECT concat(m.firstname, m.surname) as fullname,
MIN(f.name)
FROM Bookings b JOIN
Members m
ON b.memid = m.memid JOIN
Facilities f
ON b.facid = f.facid
WHERE b.facid IN (0, 1)
GROUP BY concat(m.firstname, m.surname)
ORDER BY fullname ASC;
If you're using the mysql, before running your query, run this:
SET SESSION sql_mode=(SELECT REPLACE(##sql_mode,'ONLY_FULL_GROUP_BY', ''));
Related
How I can add two fields that belong to an inner join?
I have this code:
select
SUM(ACT.NumberOfPlants ) AS NumberOfPlants,
SUM(ACT.NumOfJornales) AS NumberOfJornals
FROM dbo.AGRMastPlanPerformance MPR (NOLOCK)
INNER JOIN GENRegion GR ON (GR.intGENRegionKey = MPR.intGENRegionLink )
INNER JOIN AGRDetPlanPerformance DPR (NOLOCK) ON
(DPR.intAGRMastPlanPerformanceLink =
MPR.intAGRMastPlanPerformanceKey)
INNER JOIN vwGENPredios P (NOLOCK) ON ( DPR.intGENPredioLink =
P.intGENPredioKey )
INNER JOIN AGRSubActivity SA (NOLOCK) ON (SA.intAGRSubActivityKey =
DPR.intAGRSubActivityLink)
LEFT JOIN (SELECT RA.intGENPredioLink, AR.intAGRActividadLink,
AR.intAGRSubActividadLink, SUM(AR.decNoPlantas) AS
intPlantasTrabajads, SUM(AR.decNoPersonas) AS NumOfJornales,
SUM(AR.decNoPlants) AS NumberOfPlants
FROM AGRRecordActivity RA WITH (NOLOCK)
INNER JOIN AGRActividadRealizada AR WITH (NOLOCK) ON
(AR.intAGRRegistroActividadLink = RA.intAGRRegistroActividadKey AND
AR.bitActivo = 1)
INNER JOIN AGRSubActividad SA (NOLOCK) ON (SA.intAGRSubActividadKey
= AR.intAGRSubActividadLink AND SA.bitEnabled = 1)
WHERE RA.bitActive = 1 AND
AR.bitActive = 1 AND
RA.intAGRTractorsCrewsLink IN(2)
GROUP BY RA.intGENPredioLink,
AR.decNoPersons,
AR.decNoPlants,
AR.intAGRAActivityLink,
AR.intAGRSubActividadLink) ACT ON (ACT.intGENPredioLink IN(
DPR.intGENPredioLink) AND
ACT.intAGRAActivityLink IN( DPR.intAGRAActivityLink) AND
ACT.intAGRSubActivityLink IN( DPR.intAGRSubActivityLink))
WHERE
MPR.intAGRMastPlanPerformanceKey IN(4) AND
DPR.intAGRSubActivityLink IN( 1153)
GROUP BY
P.vchRegion,
ACT.NumberOfFloors,
ACT.NumOfJournals
ORDER BY ACT.NumberOfFloors DESC
However, it does not perform the complete sum. It only retrieves all the values of the columns and adds them 1 by 1, instead of doing the complete sum of the whole column.
For example, the query returns these results:
What I expect is the final sums. In NumberOfPlants the result of the sum would be 163,237 and of NumberJornales would be 61.
How can I do this?
First of all the (nolock) hints are probably not accomplishing the benefit you hope for. It's not an automatic "go faster" option, and if such an option existed you can be sure it would be already enabled. It can help in some situations, but the way it works allows the possibility of reading stale data, and the situations where it's likely to make any improvement are the same situations where risk for stale data is the highest.
That out of the way, with that much code in the question we're better served with a general explanation and solution for you to adapt.
The issue here is GROUP BY. When you use a GROUP BY in SQL, you're telling the database you want to see separate results per group for any aggregate functions like SUM() (and COUNT(), AVG(), MAX(), etc).
So if you have this:
SELECT Sum(ColumnB) As SumB
FROM [Table]
GROUP BY ColumnA
You will get a separate row per ColumnA group, even though it's not in the SELECT list.
If you don't really care about that, you can do one of two things:
Remove the GROUP BY If there are no grouped columns in the SELECT list, the GROUP BY clause is probably not accomplishing anything important.
Nest the query
If option 1 is somehow not possible (say, the original is actually a view) you could do this:
SELECT SUM(SumB)
FROM (
SELECT Sum(ColumnB) As SumB
FROM [Table]
GROUP BY ColumnA
) t
Note in both cases any JOIN is irrelevant to the issue.
I have the following code, I am able to get the result I desire by using DISTINCT but is there a way to get the same result without using DISTINCT?
SELECT S.name, COUNT(DISTINCT R.peopleID) AS numathletes
FROM Sports S
JOIN Results R ON S.ID = R.sportID
WHERE R.result >= S.record
GROUP BY S.name;
as for the tables i'm using:
Table S has ID, name, record
Table R has peopleID, competitionID, sportID, result
Yes, it is possible.
Here is one variant
SELECT name, COUNT(*) AS numathletes
FROM
(
SELECT S.name, R.peopleID
FROM
Sports S
JOIN Results R ON S.ID = R.sportID
WHERE R.result >= S.record
GROUP BY S.name, R.peopleID
) AS T
GROUP BY name;
It is a more verbose variant which shows clearly how the calculations are done.
You should try and check with your data and hardware which variant is faster.
Quite likely that they will perform the same.
I have to obtain the male employee with highest number of requests in the second half of April 2014.
I have these tables:
Employee (EmployeeID, firstName, LastName, gender)
Workplace (CompanyID, EmployeeID, CompanyName)
Extras (ExtraID, CompanyID, Requests, Description, Date)
Extras.Requests is a string, not numerical.
My SQL attempt looks like this:
SELECT
Employee.FirstName, Employee.LastName,
SUM(COUNT(Extras.ExtraID)
FROM
Employee
INNER JOIN
(Workplace
INNER JOIN
Extras ON Workplace.CompanyID = Extras.CompanyID)
ON Workplace.EmployeeID = Employee.EmployeeID
WHERE
Employee.Gender = "male"
AND Extras.Date BETWEEN #4/15/2014# AND #4/30/2014#
SORT BY
SUM(COUNT(Extras.ExtraID) DESC;
LIMIT 1;
I'm not sure if my query is correct or not, thanks in advance.
There are several issues with your querySUM(COUNT(...)) nesting aggregate functions like this isn't permitted
You also need a GROUP BY clause to use aggregation function with non-aggregating columns (which are Employee.FirstName, Employee.LastName in your query).
Sorting is performed by an ORDER BY clause
Your original query includes a nested inner join which is likely to produce unexpected results.
FROM Employee
INNER JOIN(Workplace
INNER JOIN Extras ON Workplace.CompanyID=Extras.CompanyID
) ON Workplace.EmployeeID=Employee.EmployeeID
While nesting joins is allowed it is rarely used, I suggest you avoid it.
I would expect the query to look more like this
SELECT
Employee.FirstName, Employee.LastName, COUNT(Extras.ExtraID)
FROM ((Employee
INNER JOIN Workplace
ON Workplace.EmployeeID = Employee.EmployeeID)
INNER JOIN Extras
ON Workplace.CompanyID = Extras.CompanyID)
WHERE Employee.Gender = "male"
AND Extras.Date BETWEEN #4/15/2014# AND #4/30/2014#
GROUP BY
Employee.FirstName
,Employee.LastName
ORDER BY
COUNT(Extras.ExtraID) DESC;
LIMIT 1;
It's been years since I used access, I think it still wants parentheses in the from clause as I've shown above. In most SQL implementation they are not required, and it is more common for literals to use single quotes e.g. WHERE Employee.Gender = 'male'.
I have two tables, articles and log. I'm trying to join the two tables a look only for the articles that appear in the log. The only relation that the two tables have is articles.slug which shows the title of the article and log.path which shows the same text of articles.slug but with '/article/' at the beginning. Exmaple:
This is the log.path: '/article/bad-things-gone'
This is the articles.slug: 'bad-things-gone'
I'm trying to do this:
SELECT articles.title, count
FROM articles join
(SELECT path, COUNT(*) as count
FROM log
GROUP BY path
ORDER BY count desc
) as a
ON ('/article/' + articles.slug) = a.path
but it is not working as it says I can not add the string '/articles/' to the articles.slug.
Is there a way to do this? Thanks.
I suspect you want:
SELECT a.title, l.count
FROM articles a join
(SELECT l.path, COUNT(*) as count
FROM log l
GROUP BY l.path
) l
ON ('/article/' || a.slug) = l.path
ORDER BY l.count desc;
Notes:
Postgres uses the standard operator || for string concatenation.
Ordering in a subquery has nothing to do with ordering in the outer query.
Use table aliases that relate to the table name or subquery.
Qualify all column names.
use the CONCAT function
SELECT CONCAT('/article/', column);
I have a large SELECT query with multiple JOINS and WHERE clauses. Despite specifying DISTINCT (also have tried GROUP BY) - there are duplicate rows returned. I am assuming this is because the query selects several IDs from several tables. At any rate, I would like to know if there is a way to remove duplicate rows from a result set, based on a condition.
I am looking to remove duplicates from results if x.ID appears more than once. The duplicate rows all appear grouped together with the same IDs.
Query:
SELECT e.Employee_ID, ce.CC_ID as CCID, e.Manager_ID, e.First_Name, e.Last_Name,,e.Last_Login,
e.Date_Created AS Date_Created, e.Employee_Password AS Password,e.EmpLogin
ISNULL((SELECT TOP 1 1 FROM Gift g
JOIN Type t ON g.TypeID = t.TypeID AND t.Code = 'Reb'
WHERE g.Manager_ID = e.Manager_ID),0) RebGift,
i.DateCreated as ImportDate
FROM #EmployeeTemp ct
JOIN dbo.Employee c ON ct.Employee_ID = e.Employee_ID
INNER JOIN dbo.Manager p ON e.Manager_ID = m.Manager_ID
LEFT JOIN EmployeeImp i ON e.Employee_ID = i.Employee_ID AND i.Active = 1
INNER JOIN CreditCard_Updates cc ON m.Manager_ID = ce.Manager_ID
LEFT JOIN Manager m2 ON m2.Manager_ID = ce.Modified_By
WHERE ce.CCType ='R' AND m.isT4L = 1
AND CHARINDEX(e.first_name, Selected_Emp) > 0
AND ce.Processed_Flag = #isProcessed
I don't have enough reputation to add a comment, so I'll just try to help you in an answer proper (even though this is more of a comment).
It seems like what you want to do is select distinctly on just one column.
Here are some answers which look like that:
SELECT DISTINCT on one column
How can I SELECT rows with MAX(Column value), DISTINCT by another column in SQL?