Remove Namespace on Element - xslt-1.0

Question

I want to remove namespace at output structure. I prepared XSLT code
but it gives namespace on this element
My Input XML is this.
<?xml version='1.0' encoding='UTF-8'?>
<n0:Messages xmlns:n0="http://sap.com/xi/XI">
<n0:Message>
<ContactData>
<Data>
<information>
<Name>A</Name>
<Phone>123456</Phone>
</information>
</Data>
</ContactData>
</n0:Message>
</n0:Messages>
XSLT CODE implemented
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:n0="http://sap.com/xi/XI" exclude-result-prefixes="n0">
<!-- Output -->
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<xsl:copy-of select= "//ContactData"/>
</xsl:template>
<xsl:template match="//*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#*|node()"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Present output:
<?xml version='1.0' encoding='UTF-8'?>
<ContactData xmlns:n0="http://sap.com/xi/XI">
<Data>
<information>
<Name>A</Name>
<Phone>123456</Phone>
</information>
</Data>
</ContactData>
Output expected
<?xml version='1.0' encoding='UTF-8'?>
<ContactData>
<Data>
<information>
<Name>A</Name>
<Phone>123456</Phone>
</information>
</Data>
</ContactData>
Please help on this code
Thank you very much.

Answer 1

If you're able to use XSLT 2.0, you can achieve the required output simply by:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:copy-of select="*/*/*" copy-namespaces="no"/>
</xsl:template>
</xsl:stylesheet>
Demo: https://xsltfiddle.liberty-development.net/3NSSEuK
In XSLT 1.0, it takes a bit more work:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:apply-templates select="*/*/*" />
</xsl:template>
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#*|node()"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Demo: https://xsltfiddle.liberty-development.net/3NSSEuK/1

Answer 2

Try this by using template * and # :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:math="http://www.w3.org/2005/xpath-functions/math"
xmlns:n0="http://sap.com/xi/XI"
xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs math n0" version="1.0">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#*|node()"/>
</xsl:element>
</xsl:template>
<xsl:template match="#*">
<xsl:attribute name="{local-name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
<xsl:template match="/">
<xsl:apply-templates select="/*:Messages/ContactData"/>
</xsl:template>
</xsl:stylesheet>