xsl 1.0 muenchian sum to sum quantity field per compound key - xslt-1.0

For a SAP PO xsl 1.0 mapping I need to map an 'exotic' file coming from our warehouse where I need to group/sum per order (RECH) a QTY field on a combination of a line identifier (MASTER_PO_LINE_NO) and an Itemnumber (SKU). Each line (RECL) is in a header (RECH).
INPUT:
<?xml version="1.0" encoding="UTF-8"?>
<ns0:Messages xmlns:ns0="http://sap.com/xi/XI/SplitAndMerge">
<ns0:Message1>
<MARCXML>
<RCIC>
<RECH>
<SALESID>24000</SALESID>
<RECL>
<LINE_NO>1</LINE_NO>
<QTY_EXPE>1592</QTY_EXPE>
<SKU>11207-210</SKU>
<MASTER_PO_LINE_NO>10</MASTER_PO_LINE_NO>
</RECL>
<RECL>
<LINE_NO>2</LINE_NO>
<QTY_EXPE>1000</QTY_EXPE>
<SKU>11207-210</SKU>
<MASTER_PO_LINE_NO>10</MASTER_PO_LINE_NO>
</RECL>
<RECL>
<LINE_NO>3</LINE_NO>
<QTY_EXPE>175</QTY_EXPE>
<SKU>11207-210</SKU>
<MASTER_PO_LINE_NO>20</MASTER_PO_LINE_NO>
</RECL>
</RECH>
<RECH>
<SALESID>25001</SALESID>
<RECL>
<LINE_NO>1</LINE_NO>
<QTY_EXPE>440</QTY_EXPE>
<SKU>20000-210</SKU>
<MASTER_PO_LINE_NO>10</MASTER_PO_LINE_NO>
</RECL>
</RECH>
</RCIC>
</MARCXML>
</ns0:Message1>
</ns0:Messages>
Required OUTPUT (Qty for 11207-210 = 1592 + 1000):
<?xml version="1.0" encoding="UTF-8"?>
<ns0:Messages xmlns:ns0="http://sap.com/xi/XI/SplitAndMerge">
<ns0:Message1>
<MARCXML>
<RCIC>
<RECH>
<SALESID>24000</SALESID>
<RECL>
<LINE_NO>1</LINE_NO>
<QTY_EXPE>2592</QTY_EXPE>
<SKU>11207-210</SKU>
<MASTER_PO_LINE_NO>10</MASTER_PO_LINE_NO>
</RECL>
<RECL>
<LINE_NO>3</LINE_NO>
<QTY_EXPE>175</QTY_EXPE>
<SKU>11207-210</SKU>
<MASTER_PO_LINE_NO>20</MASTER_PO_LINE_NO>
</RECL>
</RECH>
<RECH>
<SALESID>25001</SALESID>
<RECL>
<LINE_NO>1</LINE_NO>
<QTY_EXPE>440</QTY_EXPE>
<SKU>20000-210</SKU>
<MASTER_PO_LINE_NO>10</MASTER_PO_LINE_NO>
</RECL>
</RECH>
</RCIC>
</MARCXML>
</ns0:Message1>
</ns0:Messages>
There are plenty of examples about muenchian grouping but I didn't manage to solve my requirement yet. To be honest I got as far as:
<?xml version="1.0" encoding="UTF-8"?>
<ns0:Messages xmlns:ns0="http://sap.com/xi/XI/SplitAndMerge">
<ns0:Message1>
<MARCXML>
<RCIC>
<RECH>5284</RECH>
<RECH>5284</RECH>
<RECH>5284</RECH>
</RCIC>
</MARCXML>
</ns0:Message1>
</ns0:Messages>
With the following xsl:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="kMSTR_PO_LN_SKU" match="RECL"
use="concat(MASTER_PO_LINE_NO, '#', SKU)"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="RECH">
<xsl:copy>
<xsl:value-of select="sum(//MARCXML/RCIC/RECH/RECL/QTY_CHECKED_IN)" />
<xsl:for-each select="/RECL[generate-id()=generate-id(key('kMSTR_PO_LN_SKU',concat(MASTER_PO_LINE_NO,'-',SKU))[1])]">
<xsl:copy>
<SKU>
<xsl:value-of select="SKU"/>
</SKU>
<Quantity>
<xsl:value-of select="sum(key('kMSTR_PO_LN_SKU',concat(MASTER_PO_LINE_NO,'-',RECL))/QTY_EXPE)"/>
</Quantity>
</xsl:copy>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Hope someone can help me on my way here

AFAICT, this produces the required output - but having only a single example with somewhat ambiguous rules it could be a coincidence. In any case, it should provide you with a starting point.
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="k1" match="RECL" use="concat(MASTER_PO_LINE_NO, '|', SKU)"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="RECH">
<xsl:copy>
<xsl:copy-of select="SALESID"/>
<xsl:for-each select="RECL[generate-id()=generate-id(key('k1', concat(MASTER_PO_LINE_NO,'|',SKU))[1])]">
<xsl:copy>
<xsl:copy-of select="LINE_NO"/>
<QTY_EXPE>
<xsl:value-of select="sum(key('k1', concat(MASTER_PO_LINE_NO,'|',SKU))/QTY_EXPE)" />
</QTY_EXPE>
<xsl:copy-of select="SKU | MASTER_PO_LINE_NO"/>
</xsl:copy>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Added:
In order to summarize every order (RECH) separately, you must add an identifier of the order to the key:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="k1" match="RECL" use="concat(MASTER_PO_LINE_NO, '|', SKU, '|', generate-id(..))"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="RECH">
<xsl:copy>
<xsl:copy-of select="SALESID"/>
<xsl:for-each select="RECL[generate-id()=generate-id(key('k1', concat(MASTER_PO_LINE_NO,'|',SKU, '|', generate-id(..)))[1])]">
<xsl:copy>
<xsl:copy-of select="LINE_NO"/>
<QTY_EXPE>
<xsl:value-of select="sum(key('k1', concat(MASTER_PO_LINE_NO,'|',SKU, '|', generate-id(..)))/QTY_EXPE)" />
</QTY_EXPE>
<xsl:copy-of select="SKU | MASTER_PO_LINE_NO"/>
</xsl:copy>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>

Related

ReturnTrue if node is found

I need to form new element if specific node is found, but if that specific node is present several times i need to form only one element, My code is forming the aifound element twice.
<root>
<ai>
<i></i>
</ai>
<ai>
<i></i>
</ai>
</root>
output xml
<root>
<ai>
<i></i>
</ai>
<ai>
<i></i>
</ai>
<aifound>True</aifound>
</root>
My xslt
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="ai">
<aifound>True</aifound>
</xsl:template>
</xsl:stylesheet>
Not clear whether you want to add aifound if there are no ais at all. The following xslt adds aifound only if ais exist.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="#*|node()">
<xsl:copy-of select="."/>
</xsl:template>
<xsl:template match="root">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
<xsl:if test="//ai">
<aifound>True</aifound>
</xsl:if>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
How about simply:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/root">
<xsl:copy>
<xsl:copy-of select="*"/>
<aifound>
<xsl:value-of select="boolean(ai)"/>
</aifound>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>

Remove Namespace on Element

I want to remove namespace at output structure. I prepared XSLT code
but it gives namespace on this element
My Input XML is this.
<?xml version='1.0' encoding='UTF-8'?>
<n0:Messages xmlns:n0="http://sap.com/xi/XI">
<n0:Message>
<ContactData>
<Data>
<information>
<Name>A</Name>
<Phone>123456</Phone>
</information>
</Data>
</ContactData>
</n0:Message>
</n0:Messages>
XSLT CODE implemented
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:n0="http://sap.com/xi/XI" exclude-result-prefixes="n0">
<!-- Output -->
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<xsl:copy-of select= "//ContactData"/>
</xsl:template>
<xsl:template match="//*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#*|node()"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Present output:
<?xml version='1.0' encoding='UTF-8'?>
<ContactData xmlns:n0="http://sap.com/xi/XI">
<Data>
<information>
<Name>A</Name>
<Phone>123456</Phone>
</information>
</Data>
</ContactData>
Output expected
<?xml version='1.0' encoding='UTF-8'?>
<ContactData>
<Data>
<information>
<Name>A</Name>
<Phone>123456</Phone>
</information>
</Data>
</ContactData>
Please help on this code
Thank you very much.
If you're able to use XSLT 2.0, you can achieve the required output simply by:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:copy-of select="*/*/*" copy-namespaces="no"/>
</xsl:template>
</xsl:stylesheet>
Demo: https://xsltfiddle.liberty-development.net/3NSSEuK
In XSLT 1.0, it takes a bit more work:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:apply-templates select="*/*/*" />
</xsl:template>
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#*|node()"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
Demo: https://xsltfiddle.liberty-development.net/3NSSEuK/1
Try this by using template * and # :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:math="http://www.w3.org/2005/xpath-functions/math"
xmlns:n0="http://sap.com/xi/XI"
xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs math n0" version="1.0">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="#*|node()"/>
</xsl:element>
</xsl:template>
<xsl:template match="#*">
<xsl:attribute name="{local-name()}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:template>
<xsl:template match="/">
<xsl:apply-templates select="/*:Messages/ContactData"/>
</xsl:template>
</xsl:stylesheet>

XSLT1.0 Remove repeat nodes

I am trying to apply Muenchian grouping to eliminate duplicate nodes, but I seem not to be able to make it work.
Input:
<GetUsersByRoleRspMsg>
<UserList>
<User>
<UserId>PPAUSER1</UserId>
<Email>xyz#gmail.com</Email>
</User>
<User>
<UserId>PPAUSER1</UserId>
<Email>xyz#gmail.com</Email>
</User>
</UserList>
</GetUsersByRoleRspMsg>
Required:
<GetUsersByRoleRspMsg>
<UserList>
<User>
<UserId>PPAUSER1</UserId>
<Email>xyz#gmail.com</Email>
</User>
</UserList>
</GetUsersByRoleRspMsg>
The critical part of my code is
<xsl:key name="userIdEmailPair"
match="User"
use="concat(UserId,' ',Email)"/>
<xsl:copy>
<xsl:for-each select="User[
count(. | key('userIdEmailPair',
concat(UserId,' ',Email))[1])
= 1]">
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:copy>
I don't see any problem with your grouping code. If you try:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="userIdEmailPair" match="User" use="concat(UserId,' ',Email)"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="UserList">
<xsl:copy>
<xsl:for-each select="User[count(. | key('userIdEmailPair',concat(UserId,' ',Email))[1]) = 1]">
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
you will get the result you're looking for.
Of course, you could shorten the last template to:
<xsl:template match="UserList">
<xsl:copy>
<xsl:copy-of select="User[count(. | key('userIdEmailPair',concat(UserId,' ',Email))[1]) = 1]"/>
</xsl:copy>
</xsl:template>

Remove Duplicates from a list XSLT 1.0 based on element value

I need help with writing a function in xslt 1.0 that I can pass a list and it'll return the list with duplicates removed. It needs to be a template that I can easily clone or modify for other lists since there are several lists that I want to be able to run this.
Here is one example:
Input list:
<Diagnoses>
<Code>444.4</Code>
<Code>959.99</Code>
<Code>524</Code>
<Code>444.4</Code>
</Diagnoses>
Desired Output, after the duplicate code value 444.4 is removed:
<Diagnoses>
<Code>444.4</Code>
<Code>959.99</Code>
<Code>524</Code>
</Diagnoses>
Here is what I have so far, but it doesn't seem to be working:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:math="http://exslt.org/math"
xmlns:exsl="http://exslt.org/common"
xmlns:data="http://example.com/data" version="1.0"
extension-element-prefixes="math exsl"
exclude-result-prefixes="math exsl data">
<xsl:output omit-xml-declaration="yes" />
<xsl:variable name="DiagnosesList" select="Diagnoses"/>
<Diagnoses>
<xsl:call-template name="DedupeLists">
<xsl:with-param name="Input" select = "exsl:node-set($DiagnosesList)" />
</xsl:call-template>
</Diagnoses>
<xsl:template name="DedupeLists">
<xsl:param name = "Input" />
<xsl:for-each select="$Input/*">
<xsl:if test="Code[not(preceding::Code)]">
<xsl:copy-of select="."/>
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
#lingamurthy,
Just
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:strip-space elements="*"/>
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Code[. = preceding-sibling::Code]"/>
</xsl:stylesheet>
This is one way:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:strip-space elements="*"/>
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="#* | node()">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Code[not(. = preceding-sibling::Code)]">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Code"/>
</xsl:stylesheet>

template not getting applied with XSLT

I am using xslt to convert xml to xml.
<root>
<elem>
<confs>
<conf1>1</conf1>
<conf2>2</conf2>
</confs>
</elem>
</root>
My XSL
<xsl:template match="elem">
<xsl:copy>
<xsl:attribute name="className">confs</xsl:attribute>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="confs">
<confs>
<xsl:for-each select="*">
<conf>
<value>
<xsl:value-of select="node()"></xsl:value-of>
</value>
</conf>
</confs>
</xsl:template>
desired output:
<root>
<elem className="confs>
<confs>
<conf>
<value>1</value>
</conf>
<conf>
<value>1</value>
</conf>
</confs>
</elem>
</root>
When ran each template individaully they are good. But I run both the confs template is not affected at all.
Any help?
I believe the most straightforward way to achieve your output would be by:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="elem">
<elem className="confs">
<xsl:apply-templates/>
</elem>
</xsl:template>
<xsl:template match="confs/*">
<conf>
<value>
<xsl:value-of select="."/>
</value>
</conf>
</xsl:template>
</xsl:stylesheet>