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I have a table listing people along with their date of birth (currently a nvarchar(25))
How can I convert that to a date, and then calculate their age in years?
My data looks as follows
ID Name DOB
1 John 1992-01-09 00:00:00
2 Sally 1959-05-20 00:00:00
I would like to see:
ID Name AGE DOB
1 John 17 1992-01-09 00:00:00
2 Sally 50 1959-05-20 00:00:00
There are issues with leap year/days and the following method, see the update below:
try this:
DECLARE #dob datetime
SET #dob='1992-01-09 00:00:00'
SELECT DATEDIFF(hour,#dob,GETDATE())/8766.0 AS AgeYearsDecimal
,CONVERT(int,ROUND(DATEDIFF(hour,#dob,GETDATE())/8766.0,0)) AS AgeYearsIntRound
,DATEDIFF(hour,#dob,GETDATE())/8766 AS AgeYearsIntTrunc
OUTPUT:
AgeYearsDecimal AgeYearsIntRound AgeYearsIntTrunc
--------------------------------------- ---------------- ----------------
17.767054 18 17
(1 row(s) affected)
UPDATE here are some more accurate methods:
BEST METHOD FOR YEARS IN INT
DECLARE #Now datetime, #Dob datetime
SELECT #Now='1990-05-05', #Dob='1980-05-05' --results in 10
--SELECT #Now='1990-05-04', #Dob='1980-05-05' --results in 9
--SELECT #Now='1989-05-06', #Dob='1980-05-05' --results in 9
--SELECT #Now='1990-05-06', #Dob='1980-05-05' --results in 10
--SELECT #Now='1990-12-06', #Dob='1980-05-05' --results in 10
--SELECT #Now='1991-05-04', #Dob='1980-05-05' --results in 10
SELECT
(CONVERT(int,CONVERT(char(8),#Now,112))-CONVERT(char(8),#Dob,112))/10000 AS AgeIntYears
you can change the above 10000 to 10000.0 and get decimals, but it will not be as accurate as the method below.
BEST METHOD FOR YEARS IN DECIMAL
DECLARE #Now datetime, #Dob datetime
SELECT #Now='1990-05-05', #Dob='1980-05-05' --results in 10.000000000000
--SELECT #Now='1990-05-04', #Dob='1980-05-05' --results in 9.997260273973
--SELECT #Now='1989-05-06', #Dob='1980-05-05' --results in 9.002739726027
--SELECT #Now='1990-05-06', #Dob='1980-05-05' --results in 10.002739726027
--SELECT #Now='1990-12-06', #Dob='1980-05-05' --results in 10.589041095890
--SELECT #Now='1991-05-04', #Dob='1980-05-05' --results in 10.997260273973
SELECT 1.0* DateDiff(yy,#Dob,#Now)
+CASE
WHEN #Now >= DATEFROMPARTS(DATEPART(yyyy,#Now),DATEPART(m,#Dob),DATEPART(d,#Dob)) THEN --birthday has happened for the #now year, so add some portion onto the year difference
( 1.0 --force automatic conversions from int to decimal
* DATEDIFF(day,DATEFROMPARTS(DATEPART(yyyy,#Now),DATEPART(m,#Dob),DATEPART(d,#Dob)),#Now) --number of days difference between the #Now year birthday and the #Now day
/ DATEDIFF(day,DATEFROMPARTS(DATEPART(yyyy,#Now),1,1),DATEFROMPARTS(DATEPART(yyyy,#Now)+1,1,1)) --number of days in the #Now year
)
ELSE --birthday has not been reached for the last year, so remove some portion of the year difference
-1 --remove this fractional difference onto the age
* ( -1.0 --force automatic conversions from int to decimal
* DATEDIFF(day,DATEFROMPARTS(DATEPART(yyyy,#Now),DATEPART(m,#Dob),DATEPART(d,#Dob)),#Now) --number of days difference between the #Now year birthday and the #Now day
/ DATEDIFF(day,DATEFROMPARTS(DATEPART(yyyy,#Now),1,1),DATEFROMPARTS(DATEPART(yyyy,#Now)+1,1,1)) --number of days in the #Now year
)
END AS AgeYearsDecimal
Gotta throw this one out there. If you convert the date using the 112 style (yyyymmdd) to a number you can use a calculation like this...
(yyyyMMdd - yyyyMMdd) / 10000 = difference in full years
declare #as_of datetime, #bday datetime;
select #as_of = '2009/10/15', #bday = '1980/4/20'
select
Convert(Char(8),#as_of,112),
Convert(Char(8),#bday,112),
0 + Convert(Char(8),#as_of,112) - Convert(Char(8),#bday,112),
(0 + Convert(Char(8),#as_of,112) - Convert(Char(8),#bday,112)) / 10000
output
20091015 19800420 290595 29
I have used this query in our production code for nearly 10 years:
SELECT FLOOR((CAST (GetDate() AS INTEGER) - CAST(Date_of_birth AS INTEGER)) / 365.25) AS Age
You need to consider the way the datediff command rounds.
SELECT CASE WHEN dateadd(year, datediff (year, DOB, getdate()), DOB) > getdate()
THEN datediff(year, DOB, getdate()) - 1
ELSE datediff(year, DOB, getdate())
END as Age
FROM <table>
Which I adapted from here.
Note that it will consider 28th February as the birthday of a leapling for non-leap years e.g. a person born on 29 Feb 2020 will be considered 1 year old on 28 Feb 2021 instead of 01 Mar 2021.
So many of the above solutions are wrong DateDiff(yy,#Dob, #PassedDate) will not consider the month and day of both dates. Also taking the dart parts and comparing only works if they're properly ordered.
THE FOLLOWING CODE WORKS AND IS VERY SIMPLE:
create function [dbo].[AgeAtDate](
#DOB datetime,
#PassedDate datetime
)
returns int
with SCHEMABINDING
as
begin
declare #iMonthDayDob int
declare #iMonthDayPassedDate int
select #iMonthDayDob = CAST(datepart (mm,#DOB) * 100 + datepart (dd,#DOB) AS int)
select #iMonthDayPassedDate = CAST(datepart (mm,#PassedDate) * 100 + datepart (dd,#PassedDate) AS int)
return DateDiff(yy,#DOB, #PassedDate)
- CASE WHEN #iMonthDayDob <= #iMonthDayPassedDate
THEN 0
ELSE 1
END
End
EDIT: THIS ANSWER IS INCORRECT. I leave it in here as a warning to anyone tempted to use dayofyear, with a further edit at the end.
If, like me, you do not want to divide by fractional days or risk rounding/leap year errors, I applaud #Bacon Bits comment in a post above https://stackoverflow.com/a/1572257/489865 where he says:
If we're talking about human ages, you should calculate it the way
humans calculate age. It has nothing to do with how fast the earth
moves and everything to do with the calendar. Every time the same
month and day elapses as the date of birth, you increment age by 1.
This means the following is the most accurate because it mirrors what
humans mean when they say "age".
He then offers:
DATEDIFF(yy, #date, GETDATE()) -
CASE WHEN (MONTH(#date) > MONTH(GETDATE())) OR (MONTH(#date) = MONTH(GETDATE()) AND DAY(#date) > DAY(GETDATE()))
THEN 1 ELSE 0 END
There are several suggestions here involving comparing the month & day (and some get it wrong, failing to allow for the OR as correctly here!). But nobody has offered dayofyear, which seems so simple and much shorter. I offer:
DATEDIFF(year, #date, GETDATE()) -
CASE WHEN DATEPART(dayofyear, #date) > DATEPART(dayofyear, GETDATE()) THEN 1 ELSE 0 END
[Note: Nowhere in SQL BOL/MSDN is what DATEPART(dayofyear, ...) returns actually documented! I understand it to be a number in the range 1--366; most importantly, it does not change by locale as per DATEPART(weekday, ...) & SET DATEFIRST.]
EDIT: Why dayofyear goes wrong: As user #AeroX has commented, if the birth/start date is after February in a non leap year, the age is incremented one day early when the current/end date is a leap year, e.g. '2015-05-26', '2016-05-25' gives an age of 1 when it should still be 0. Comparing the dayofyear in different years is clearly dangerous. So using MONTH() and DAY() is necessary after all.
I believe this is similar to other ones posted here.... but this solution worked for the leap year examples 02/29/1976 to 03/01/2011 and also worked for the case for the first year.. like 07/04/2011 to 07/03/2012 which the last one posted about leap year solution did not work for that first year use case.
SELECT FLOOR(DATEDIFF(DAY, #date1 , #date2) / 365.25)
Found here.
Since there isn't one simple answer that always gives the correct age, here's what I came up with.
SELECT DATEDIFF(YY, DateOfBirth, GETDATE()) -
CASE WHEN RIGHT(CONVERT(VARCHAR(6), GETDATE(), 12), 4) >=
RIGHT(CONVERT(VARCHAR(6), DateOfBirth, 12), 4)
THEN 0 ELSE 1 END AS AGE
This gets the year difference between the birth date and the current date. Then it subtracts a year if the birthdate hasn't passed yet.
Accurate all the time - regardless of leap years or how close to the birthdate.
Best of all - no function.
I've done a lot of thinking and searching about this and I have 3 solutions that
calculate age correctly
are short (mostly)
are (mostly) very understandable.
Here are testing values:
DECLARE #NOW DATETIME = '2013-07-04 23:59:59'
DECLARE #DOB DATETIME = '1986-07-05'
Solution 1: I found this approach in one js library. It's my favourite.
DATEDIFF(YY, #DOB, #NOW) -
CASE WHEN DATEADD(YY, DATEDIFF(YY, #DOB, #NOW), #DOB) > #NOW THEN 1 ELSE 0 END
It's actually adding difference in years to DOB and if it is bigger than current date then subtracts one year. Simple right? The only thing is that difference in years is duplicated here.
But if you don't need to use it inline you can write it like this:
DECLARE #AGE INT = DATEDIFF(YY, #DOB, #NOW)
IF DATEADD(YY, #AGE, #DOB) > #NOW
SET #AGE = #AGE - 1
Solution 2: This one I originally copied from #bacon-bits. It's the easiest to understand but a bit long.
DATEDIFF(YY, #DOB, #NOW) -
CASE WHEN MONTH(#DOB) > MONTH(#NOW)
OR MONTH(#DOB) = MONTH(#NOW) AND DAY(#DOB) > DAY(#NOW)
THEN 1 ELSE 0 END
It's basically calculating age as we humans do.
Solution 3: My friend refactored it into this:
DATEDIFF(YY, #DOB, #NOW) -
CEILING(0.5 * SIGN((MONTH(#DOB) - MONTH(#NOW)) * 50 + DAY(#DOB) - DAY(#NOW)))
This one is the shortest but it's most difficult to understand. 50 is just a weight so the day difference is only important when months are the same. SIGN function is for transforming whatever value it gets to -1, 0 or 1. CEILING(0.5 * is the same as Math.max(0, value) but there is no such thing in SQL.
What about:
DECLARE #DOB datetime
SET #DOB='19851125'
SELECT Datepart(yy,convert(date,GETDATE())-#DOB)-1900
Wouldn't that avoid all those rounding, truncating and ofsetting issues?
Just check whether the below answer is feasible.
DECLARE #BirthDate DATE = '09/06/1979'
SELECT
(
YEAR(GETDATE()) - YEAR(#BirthDate) -
CASE WHEN (MONTH(GETDATE()) * 100) + DATEPART(dd, GETDATE()) >
(MONTH(#BirthDate) * 100) + DATEPART(dd, #BirthDate)
THEN 1
ELSE 0
END
)
select floor((datediff(day,0,#today) - datediff(day,0,#birthdate)) / 365.2425) as age
There are a lot of 365.25 answers here. Remember how leap years are defined:
Every four years
except every 100 years
except every 400 years
There are many answers to this question, but I think this one is close to the truth.
The datediff(year,…,…) function, as we all know, only counts the boundaries crossed by the date part, in this case the year. As a result it ignores the rest of the year.
This will only give the age in completed years if the year were to start on the birthday. It probably doesn’t, but we can fake it by adjusting the asking date back by the same amount.
In pseudopseudo code, it’s something like this:
adjusted_today = today - month(dob) + 1 - day(dob) + 1
age = year(adjusted_today - dob)
The + 1 is to allow for the fact that the month and day numbers start from 1 and not 0.
The reason we subtract the month and the day separately rather than the day of the year is because February has the annoying tendency to change its length.
The calculation in SQL is:
datediff(year,dob,dateadd(month,-month(dob)+1,dateadd(day,-day(dob)+1,today)))
where dob and today are presumed to be the date of birth and the asking date.
You can test this as follows:
WITH dates AS (
SELECT
cast('2022-03-01' as date) AS today,
cast('1943-02-25' as date) AS dob
)
select
datediff(year,dob,dateadd(month,-month(dob)+1,dateadd(day,-day(dob)+1,today))) AS age
from dates;
which gives you George Harrison’s age in completed years.
This is much cleaner than fiddling about with quarter days which will generally give you misleading values on the edges.
If you have the luxury of creating a scalar function, you can use something like this:
DROP FUNCTION IF EXISTS age;
GO
CREATE FUNCTION age(#dob date, #today date) RETURNS INT AS
BEGIN
SET #today = dateadd(month,-month(#dob)+1,#today);
SET #today = dateadd(day,-day(#dob)+1,#today);
RETURN datediff(year,#dob,#today);
END;
GO
Remember, you need to call dbo.age() because, well, Microsoft.
DECLARE #DOB datetime
set #DOB ='11/25/1985'
select floor(
( cast(convert(varchar(8),getdate(),112) as int)-
cast(convert(varchar(8),#DOB,112) as int) ) / 10000
)
source: http://beginsql.wordpress.com/2012/04/26/how-to-calculate-age-in-sql-server/
Try This
DECLARE #date datetime, #tmpdate datetime, #years int, #months int, #days int
SELECT #date = '08/16/84'
SELECT #tmpdate = #date
SELECT #years = DATEDIFF(yy, #tmpdate, GETDATE()) - CASE WHEN (MONTH(#date) > MONTH(GETDATE())) OR (MONTH(#date) = MONTH(GETDATE()) AND DAY(#date) > DAY(GETDATE())) THEN 1 ELSE 0 END
SELECT #tmpdate = DATEADD(yy, #years, #tmpdate)
SELECT #months = DATEDIFF(m, #tmpdate, GETDATE()) - CASE WHEN DAY(#date) > DAY(GETDATE()) THEN 1 ELSE 0 END
SELECT #tmpdate = DATEADD(m, #months, #tmpdate)
SELECT #days = DATEDIFF(d, #tmpdate, GETDATE())
SELECT Convert(Varchar(Max),#years)+' Years '+ Convert(Varchar(max),#months) + ' Months '+Convert(Varchar(Max), #days)+'days'
After trying MANY methods, this works 100% of the time using the modern MS SQL FORMAT function instead of convert to style 112. Either would work but this is the least code.
Can anyone find a date combination which does not work? I don't think there is one :)
--Set parameters, or choose from table.column instead:
DECLARE #DOB DATE = '2000/02/29' -- If #DOB is a leap day...
,#ToDate DATE = '2018/03/01' --...there birthday in this calculation will be
--0+ part tells SQL to calc the char(8) as numbers:
SELECT [Age] = (0+ FORMAT(#ToDate,'yyyyMMdd') - FORMAT(#DOB,'yyyyMMdd') ) /10000
CASE WHEN datepart(MM, getdate()) < datepart(MM, BIRTHDATE) THEN ((datepart(YYYY, getdate()) - datepart(YYYY, BIRTH_DATE)) -1 )
ELSE
CASE WHEN datepart(MM, getdate()) = datepart(MM, BIRTHDATE)
THEN
CASE WHEN datepart(DD, getdate()) < datepart(DD, BIRTHDATE) THEN ((datepart(YYYY, getdate()) - datepart(YYYY, BIRTHDATE)) -1 )
ELSE (datepart(YYYY, getdate()) - datepart(YYYY, BIRTHDATE))
END
ELSE (datepart(YYYY, getdate()) - datepart(YYYY, BIRTHDATE)) END
END
SELECT ID,
Name,
DATEDIFF(yy,CONVERT(DATETIME, DOB),GETDATE()) AS AGE,
DOB
FROM MyTable
How about this:
SET #Age = CAST(DATEDIFF(Year, #DOB, #Stamp) as int)
IF (CAST(DATEDIFF(DAY, DATEADD(Year, #Age, #DOB), #Stamp) as int) < 0)
SET #Age = #Age - 1
Try this solution:
declare #BirthDate datetime
declare #ToDate datetime
set #BirthDate = '1/3/1990'
set #ToDate = '1/2/2008'
select #BirthDate [Date of Birth], #ToDate [ToDate],(case when (DatePart(mm,#ToDate) < Datepart(mm,#BirthDate))
OR (DatePart(m,#ToDate) = Datepart(m,#BirthDate) AND DatePart(dd,#ToDate) < Datepart(dd,#BirthDate))
then (Datepart(yy, #ToDate) - Datepart(yy, #BirthDate) - 1)
else (Datepart(yy, #ToDate) - Datepart(yy, #BirthDate))end) Age
This will correctly handle the issues with the birthday and rounding:
DECLARE #dob datetime
SET #dob='1992-01-09 00:00:00'
SELECT DATEDIFF(YEAR, '0:0', getdate()-#dob)
Ed Harper's solution is the simplest I have found which never returns the wrong answer when the month and day of the two dates are 1 or less days apart. I made a slight modification to handle negative ages.
DECLARE #D1 AS DATETIME, #D2 AS DATETIME
SET #D2 = '2012-03-01 10:00:02'
SET #D1 = '2013-03-01 10:00:01'
SELECT
DATEDIFF(YEAR, #D1,#D2)
+
CASE
WHEN #D1<#D2 AND DATEADD(YEAR, DATEDIFF(YEAR,#D1, #D2), #D1) > #D2
THEN - 1
WHEN #D1>#D2 AND DATEADD(YEAR, DATEDIFF(YEAR,#D1, #D2), #D1) < #D2
THEN 1
ELSE 0
END AS AGE
The answer marked as correct is nearer to accuracy but, it fails in following scenario - where Year of birth is Leap year and day are after February month
declare #ReportStartDate datetime = CONVERT(datetime, '1/1/2014'),
#DateofBirth datetime = CONVERT(datetime, '2/29/1948')
FLOOR(DATEDIFF(HOUR,#DateofBirth,#ReportStartDate )/8766)
OR
FLOOR(DATEDIFF(HOUR,#DateofBirth,#ReportStartDate )/8765.82) -- Divisor is more accurate than 8766
-- Following solution is giving me more accurate results.
FLOOR(DATEDIFF(YEAR,#DateofBirth,#ReportStartDate) - (CASE WHEN DATEADD(YY,DATEDIFF(YEAR,#DateofBirth,#ReportStartDate),#DateofBirth) > #ReportStartDate THEN 1 ELSE 0 END ))
It worked in almost all scenarios, considering leap year, date as 29 feb, etc.
Please correct me if this formula have any loophole.
Declare #dob datetime
Declare #today datetime
Set #dob = '05/20/2000'
set #today = getdate()
select CASE
WHEN dateadd(year, datediff (year, #dob, #today), #dob) > #today
THEN datediff (year, #dob, #today) - 1
ELSE datediff (year, #dob, #today)
END as Age
Here is how i calculate age given a birth date and current date.
select case
when cast(getdate() as date) = cast(dateadd(year, (datediff(year, '1996-09-09', getdate())), '1996-09-09') as date)
then dateDiff(yyyy,'1996-09-09',dateadd(year, 0, getdate()))
else dateDiff(yyyy,'1996-09-09',dateadd(year, -1, getdate()))
end as MemberAge
go
CREATE function dbo.AgeAtDate(
#DOB datetime,
#CompareDate datetime
)
returns INT
as
begin
return CASE WHEN #DOB is null
THEN
null
ELSE
DateDiff(yy,#DOB, #CompareDate)
- CASE WHEN datepart(mm,#CompareDate) > datepart(mm,#DOB) OR (datepart(mm,#CompareDate) = datepart(mm,#DOB) AND datepart(dd,#CompareDate) >= datepart(dd,#DOB))
THEN 0
ELSE 1
END
END
End
GO
DECLARE #FromDate DATETIME = '1992-01-2623:59:59.000',
#ToDate DATETIME = '2016-08-10 00:00:00.000',
#Years INT, #Months INT, #Days INT, #tmpFromDate DATETIME
SET #Years = DATEDIFF(YEAR, #FromDate, #ToDate)
- (CASE WHEN DATEADD(YEAR, DATEDIFF(YEAR, #FromDate, #ToDate),
#FromDate) > #ToDate THEN 1 ELSE 0 END)
SET #tmpFromDate = DATEADD(YEAR, #Years , #FromDate)
SET #Months = DATEDIFF(MONTH, #tmpFromDate, #ToDate)
- (CASE WHEN DATEADD(MONTH,DATEDIFF(MONTH, #tmpFromDate, #ToDate),
#tmpFromDate) > #ToDate THEN 1 ELSE 0 END)
SET #tmpFromDate = DATEADD(MONTH, #Months , #tmpFromDate)
SET #Days = DATEDIFF(DAY, #tmpFromDate, #ToDate)
- (CASE WHEN DATEADD(DAY, DATEDIFF(DAY, #tmpFromDate, #ToDate),
#tmpFromDate) > #ToDate THEN 1 ELSE 0 END)
SELECT #FromDate FromDate, #ToDate ToDate,
#Years Years, #Months Months, #Days Days
What about a solution with only date functions, not math, not worries about leap year
CREATE FUNCTION dbo.getAge(#dt datetime)
RETURNS int
AS
BEGIN
RETURN
DATEDIFF(yy, #dt, getdate())
- CASE
WHEN
MONTH(#dt) > MONTH(GETDATE()) OR
(MONTH(#dt) = MONTH(GETDATE()) AND DAY(#dt) > DAY(GETDATE()))
THEN 1
ELSE 0
END
END
declare #birthday as datetime
set #birthday = '2000-01-01'
declare #today as datetime
set #today = GetDate()
select
case when ( substring(convert(varchar, #today, 112), 5,4) >= substring(convert(varchar, #birthday, 112), 5,4) ) then
(datepart(year,#today) - datepart(year,#birthday))
else
(datepart(year,#today) - datepart(year,#birthday)) - 1
end
The following script checks the difference in years between now and the given date of birth; the second part checks whether the birthday is already past in the current year; if not, it subtracts it:
SELECT year(NOW()) - year(date_of_birth) - (CONCAT(year(NOW()), '-', month(date_of_birth), '-', day(date_of_birth)) > NOW()) AS Age
FROM tableName;
Is there a way to calculate how old someone is based on today's date and their birthday then display it in following manners:
If a user is less than (<) 1 year old THEN show their age in MM & days.
Example: 10 months & 2 days old
If a user is more than 1 year old AND less than 6 years old THEN show their age in YY & MM & days.
Example: 5 years & 3 months & 10 days old
If a user is more than 6 years old THEN display their age in YY.
Example: 12 years
This is basically what you are looking for:
DECLARE #date1 DATETIME
, #date2 DATETIME;
SELECT #date1 = '1/1/2008'
, #date2 = GETDATE();
SELECT CASE
WHEN DATEDIFF(YEAR, #date1, #date2) < 1 THEN CAST(DATEDIFF(mm, #date1, #date2) AS VARCHAR)+' Months & '+CAST(DATEDIFF(dd, DATEADD(mm, DATEDIFF(mm, #date1, #date2), #date1), #date2) AS VARCHAR)+' Days'
WHEN DATEDIFF(YEAR, #date1, #date2) BETWEEN 1 AND 5 THEN CAST(DATEDIFF(mm, #date1, #date2) / 12 AS VARCHAR)+' Years & '+CAST(DATEDIFF(mm, #date1, #date2) % 12 AS VARCHAR)+' Months'
WHEN DATEDIFF(YEAR, #date1, #date2) >= 6 THEN CAST(DATEDIFF(YEAR, #date1, #date2) AS VARCHAR)+' Years'
END;
Result for when a user is less than (<) 1 year old THEN show their age in MM & days:
Result for when a user is more than 1 year old AND less than 6 years old THEN show their age in YY & MM & days:
Result for when a user is more than 6 years old THEN display their age in YY:
from this previous question
How to calculate age in T-SQL with years, months, and days
you can do procedure like this
CREATE procedure [dbo].[proc_datediff]
(
#date datetime
)
as
begin
DECLARE #diff varchar(70)
DECLARE #tmpdate datetime, #years int, #months int, #days int
SELECT #tmpdate = #date
SELECT #years = DATEDIFF(yy, #tmpdate, GETDATE()) - CASE WHEN
(MONTH(#date) > MONTH(GETDATE())) OR (MONTH(#date) =
MONTH(GETDATE()) AND DAY(#date) > DAY(GETDATE())) THEN 1 ELSE 0 END
SELECT #tmpdate = DATEADD(yy, #years, #tmpdate)
SELECT #months = DATEDIFF(m, #tmpdate, GETDATE()) - CASE WHEN
DAY(#date) > DAY(GETDATE()) THEN 1 ELSE 0 END
SELECT #tmpdate = DATEADD(m, #months, #tmpdate)
SELECT #days = DATEDIFF(d, #tmpdate, GETDATE())
select #diff=
case
when #years < 1 then
concat( #months,' Months ',#days,' days ' )
when #years >=1 and #years < 6
then
concat(#years,' year ', #months,' Months ',#days,' days ' )
when #years >= 6 then
concat( #years,' years ' )
end;
select #diff
end
execute proc_datediff '1/1/2016'
go
CREATE FUNCTION [dbo].[FindDateDiff](#Date1 date,#Date2 date, #IncludeTheEnDate bit)
RETURNS TABLE
AS
RETURN
(
SELECT
CALC.Years,CALC.Months,D.Days,
Duration = RTRIM(Case When CALC.Years > 0 Then CONCAT(CALC.Years, ' year(s) ') Else '' End
+ Case When CALC.Months > 0 Then CONCAT(CALC.Months, ' month(s) ') Else '' End
+ Case When D.Days > 0 OR (CALC.Years=0 AND CALC.Months=0) Then CONCAT(D.Days, ' day(s)') Else '' End)
FROM (VALUES(IIF(#Date1<#Date2,#Date1,#Date2),DATEADD(DAY, IIF(#IncludeTheEnDate=0,0,1), IIF(#Date1<#Date2,#Date2,#Date1)))) T(StartDate, EndDate)
CROSS APPLY(Select
TempEndYear = Case When ISDATE(CONCAT(YEAR(T.EndDate), FORMAT(T.StartDate,'-MM-dd')))=1 Then CONCAT(YEAR(T.EndDate), FORMAT(T.StartDate,'-MM-dd'))
Else CONCAT(YEAR(T.EndDate),'-02-28') End
) TEY
CROSS APPLY(Select EndYear = Case When TEY.TempEndYear > T.EndDate Then DATEADD(YEAR, -1, TEY.TempEndYear) Else TEY.TempEndYear End) EY
CROSS APPLY(Select
Years = DATEDIFF(YEAR,T.StartDate,EY.EndYear),
Months = DATEDIFF(MONTH,EY.EndYear,T.EndDate)-IIF(DAY(EY.EndYear)>DAY(T.EndDate),1,0)
) CALC
CROSS APPLY(Select Days = DATEDIFF(DAY,DATEADD(MONTH,CALC.Months,DATEADD(YEAR,CALC.Years,T.StartDate)),T.EndDate)) D
)
Sample:
Select [From] = '2021-01-01',[To] = '2021-12-31',IncludeEndDate='Yes',* From dbo.FindDateDiff('2021-01-01','2021-12-31',1)
Select [From] = '2021-01-01',[To] = '2021-12-31',IncludeEndDate='No',* From dbo.FindDateDiff('2021-01-01','2021-12-31',0)
Select [From] = '2015-12-15',[To] = '2018-12-14',IncludeEndDate='Yes',* From dbo.FindDateDiff('2015-12-15','2018-12-14',1)
Select [From] = '2015-12-15',[To] = '2018-12-14',IncludeEndDate='No',* From dbo.FindDateDiff('2015-12-15','2018-12-14',0)
Probably not the most efficient way to go about it, but here's how I did it:
I had to first get the date difference between today's date and person's birthdate. I used it to get years, months, days, etc by combining it with ABS(), and Remainder (%) function.
declare #year int = 365
declare #month int = 30
declare #sixYears int = 2190
select
--CAST(DATEDIFF(mm, a.BirthDateTime, getdate()) AS VARCHAR) as GetMonth,
--CAST(DATEDIFF(dd, DATEADD(mm, DATEDIFF(mm, a.BirthDateTime, getdate()), a.BirthDateTime), getdate()) AS VARCHAR) as GetDays,
CASE
WHEN
DATEDIFF(dd,a.BirthDateTime,getdate()) < #year
THEN
cast((DATEDIFF(dd,a.BirthDateTime,getdate()) / (#month)) as varchar) +' Months & ' +
CAST(ABS(DATEDIFF(dd, DATEADD(mm, DATEDIFF(mm, a.BirthDateTime, getdate()), a.BirthDateTime), getdate())) AS VARCHAR)
+ ' Days'
WHEN
DATEDIFF(dd,a.BirthDateTime,getdate()) between #year and #sixYears
THEN
cast((DATEDIFF(dd,a.BirthDateTime,getdate()) / (#year)) as varchar) +' Years & ' +
CAST((DATEDIFF(mm, a.BirthDateTime, getdate()) % (12)) AS VARCHAR) + ' Months'
WHEN DATEDIFF(dd,a.BirthDateTime,getdate()) > #sixYears
THEN cast(a.Age as varchar) + ' Years'
end as FinalAGE,
dc.DayMarker = cast(getdate() as date)
DAYmarker is your date field.
i try compare date now and start date working from master_employee.
but i failed...
if at line i write
select #date = date_start
from Master_Employee
where id = '2'
its succes.
but i hope, can view all result in table Master_Employee.
can you help me ?
thank's very much..
DECLARE #date DATETIME
,#tmpdate DATETIME
,#years INT
,#months INT
,#days INT
SELECT #date = date_Start
FROM Master_Employee
SELECT #tmpdate = #date
SELECT #years = DATEDIFF(yyyy, #tmpdate, GETDATE()) - CASE
WHEN (MONTH(#date) > MONTH(GETDATE()))
OR (
MONTH(#date) = MONTH(GETDATE())
AND DAY(#date) > DAY(GETDATE())
)
THEN 1
ELSE 0
END
SELECT #tmpdate = DATEADD(yyyy, #years, #tmpdate)
SELECT #months = DATEDIFF(mm, #tmpdate, GETDATE()) - CASE
WHEN DAY(#date) > DAY(GETDATE())
THEN 1
ELSE 0
END
SELECT #tmpdate = DATEADD(mm, #months, #tmpdate)
SELECT #days = DATEDIFF(dd, #tmpdate, GETDATE())
SELECT #years AS Years
,#months AS Months
,#days AS Dayss
,GETDATE() AS Date_Now
This will give you how many days, months, years have passed in aggregate for all employees, As far as I can tell this is what you are tying to do.
DECLARE #Today as datetime = CONVERT(Date,GETDATE())
SELECT SUM(DATEDIFF(day,ISNULL(convert(datetime,#date),Today),#Today)) [Days]
,SUM(DATEDIFF(MONTH,ISNULL(convert(datetime,#date),Today),#Today)) [Months]
,SUM(DATEDIFF(Year,ISNULL(convert(datetime,#date),Today(,#Today)) [Years]
FROM Master_Employee
The reason that
SELECT #date = date_Start
FROM Master_Employee
is failing is because you are trying to assign all the start dates to the same variable.
If you want separate lines for each employee try:
DECLARE #Today as datetime = CONVERT(Date,GETDATE())
SELECT Id
,SUM(DATEDIFF(day,ISNULL(convert(datetime,#date),Today),#Today)) [Days]
,SUM(DATEDIFF(MONTH,ISNULL(convert(datetime,#date),Today),#Today)) [Months]
,SUM(DATEDIFF(Year,ISNULL(convert(datetime,#date),Today),#Today)) [Years]
FROM Master_Employee
GROUP BY ID
Be careful, month and year can be misleading, if the person started 12/31/14 and you ran this on 1/1/15 you will see 1 day, 1 month, 1 year. You might be better off using only days and figuring your own math for how long that is...
I am stuck with my query. I have a table called Patient. In this table a column has patient DOB. Actually I want to display the exact age of the patient.
For example:
PatName DOB (MM/dd/yyyy) Age
a 06/02/1947 65 Years 1 Month/s 3 Days
b 07/10/1947 64 Years 11 Month/s 25 Days
c ----------- -----------------------
I want to display the age of the above format.
I have already googled about this but nobody helped.
If you have any query regarding this pls post that.
Thanks
Hi Check the query below.
--DROP TABLE patient
CREATE TABLE patient(PatName varchar(100),DOB date, Age varchar(100))
INSERT INTO patient
VALUES('a','06/02/1947',NULL),('b','07/10/1947',NULL),('c','12/21/1982',NULL)
;WITH CTE(PatName,DOB,years,months,days) AS
(SELECT PatName,DOB,DATEDIFF(yy,DOB,getdate()),DATEDIFF(mm,DOB,getdate()),DATEDIFF(dd,DOB,getdate()) FROM patient)
--SELECT * FROM CTE
SELECT PatName,DOB,
CAST(months/12 as varchar(5))+' Years'+CAST((months % 12) as varchar(5))+' month/s '+CAST(CASE WHEN DATEADD(MM,(months % 12),DATEADD(YY,(months/12),DOB)) <= GETDATE() then DATEDIFF(dd,DATEADD(MM,(months % 12),DATEADD(YY,(months/12),DOB)),GETDATE()) ELSE DAY(getdate()) END as varchar(5))+' days' as Age
FROM CTE
If you follow this link, you'll find a function doing exactly that:
create function dbo.F_AGE_YYYY_MM_DD
(
#START_DATE datetime,
#END_DATE datetime
)
returns varchar(10)
as
/*
Function: F_AGE_YYYY_MM_DD
This function calculates age in years, months and days
from #START_DATE through #END_DATE and
returns the age in format YYYY MM DD.
Years is the number of full years between #START_DATE and #END_DATE.
Months is the number of full months since the last full year anniversary.
Days is the number of days since the last full month anniversary.
*/
begin
declare #AGE varchar(10)
declare #AGE_IN_YEARS int
declare #AGE_IN_MONTHS int
declare #AGE_IN_DAYS int
-- Return null if #START_DATE > #END_DATE
if #START_DATE > #END_DATE begin return #AGE end
select
#AGE_IN_YEARS = AGE_IN_YEARS,
#AGE_IN_MONTHS = AGE_IN_MONTHS,
#AGE_IN_DAYS =
datediff(dd,
dateadd(mm,AGE_IN_MONTHS,
dateadd(yy,AGE_IN_YEARS,START_DATE))
,END_DATE)
from
(
select
AGE_IN_MONTHS =
case
when AnniversaryThisMonth <= END_DATE
then datediff(mm,dateadd(yy,AGE_IN_YEARS,START_DATE),END_DATE)
else datediff(mm,dateadd(yy,AGE_IN_YEARS,START_DATE),END_DATE)-1
end,
*
from
(
select
AGE_IN_YEARS =
case
when AnniversaryThisYear <= END_DATE
then datediff(yy,START_DATE,END_DATE)
else datediff(yy,START_DATE,END_DATE)-1
end,
*
from
(
select
AnniversaryThisYear =
dateadd(yy,datediff(yy,START_DATE,END_DATE),START_DATE),
AnniversaryThisMonth =
dateadd(mm,datediff(mm,START_DATE,END_DATE),START_DATE),
*
from
(
select START_DATE = dateadd(dd,datediff(dd,0,#START_DATE),0),
END_DATE = dateadd(dd,datediff(dd,0,#END_DATE),0)
) aaaa
) aaa
) aa
) a
select #AGE =
right('0000'+convert(varchar(4),#AGE_IN_YEARS),4) + ' ' +
right('00'+convert(varchar(4),#AGE_IN_MONTHS),2) + ' ' +
right('00'+convert(varchar(4),#AGE_IN_DAYS),2)
return #AGE
end
go
select [Age] = dbo.F_AGE_YYYY_MM_DD('2004-04-07','2006-02-03')
select [Age] = dbo.F_AGE_YYYY_MM_DD('2006-02-03','2006-02-03')
select [Age] = dbo.F_AGE_YYYY_MM_DD('2006-02-05','2006-02-03')
select [Age] = dbo.F_AGE_YYYY_MM_DD('1950-09-13', getdate())
DECLARE #date datetime, #tmpdate datetime, #years int, #months int, #days int
SELECT #date = '06/02/1947'
SELECT #tmpdate = #date
SELECT #years = DATEDIFF(yy, #tmpdate, GETDATE()) - CASE WHEN (MONTH(#date) > MONTH(GETDATE())) OR (MONTH(#date) = MONTH(GETDATE()) AND DAY(#date) > DAY(GETDATE())) THEN 1 ELSE 0 END
SELECT #tmpdate = DATEADD(yy, #years, #tmpdate)
SELECT #months = DATEDIFF(m, #tmpdate, GETDATE()) - CASE WHEN DAY(#date) > DAY(GETDATE()) THEN 1 ELSE 0 END
SELECT #tmpdate = DATEADD(m, #months, #tmpdate)
SELECT #days = DATEDIFF(d, #tmpdate, GETDATE())
print cast(#years as varchar(4)) + ' years, '+ cast (#months as varchar(2))+' months, '+ cast(#days as varchar(2)) + ' days'
Here is the solution
DATEDIFF(year, DOB, getdate()) - (CASE WHEN (DATEADD(year, DATEDIFF(year, DOB, getdate()), DOB)) > getdate() THEN 1 ELSE 0 END) as Years,
MONTH(getdate() - (DATEADD(year, DATEDIFF(year, DOB, getdate()), DOB))) - 1 as Month/s,
DAY(getdate() - (DATEADD(year, DATEDIFF(year, DOB, getdate()), DOB))) - 1 as Days
I am developing Time management system for employees.
I want the duration how much duration employee come late , or he went early.
i have following structure.
**Attendace**
AutoId --uniqueidentifier
EMployeeId --uniqueidentifier
Date --datetime
InTime -- varchar(50)
OutTime -- varchar(50)
ActualInTime--datetime
ActualOutTime--datetime
I want Late Coming Report ( i.e. who came late in morning after ActualInTime and how much duration in hh:mm:ss ) and also want early going(i.e who went early in the evening before ActualOutTime in duration in format hh:mm:ss )
So can you please help me..???
I came across an easier way of solving this issue.
First, a quick example of turning a "number of seconds" into the "hh:mm:ss" format.
DECLARE #NumberOfSeconds int
SET #NumberOfSeconds = 3843 -- 1 hour, 4 minutes, 3 seconds
SELECT #NumberOfSeconds AS 'seconds',
CONVERT(varchar, DATEADD(second, #NumberOfSeconds, 0), 108) AS 'hh:mm:ss'
This will give us this output:
And we can easily take this a step further, calculate the number of seconds between two datetimes, and display it in hh:mm:ss format:
DECLARE
#NumberOfSeconds int,
#StartTime datetime = '2017-09-14 14:16:11',
#EndTime datetime = '2017-09-14 14:23:13'
SET #NumberOfSeconds = DATEDIFF(second, #StartTime, #EndTime)
SELECT #NumberOfSeconds AS 'seconds',
CONVERT(varchar, DATEADD(second, #NumberOfSeconds, 0), 108) AS 'hh:mm:ss'
Which gives us this output:
Simple, hey ?
(And yes, you can simplify it further by putting the DATEDIFF directly into the DATEADD function.)
You can do it in a very simple way:
declare #date1 datetime, #date2 datetime
set #date1=DATEADD(s,-638,getdate())
set #date2=GETDATE()
select convert(char(8),dateadd(s,datediff(s,#date1,#date2),'1900-1-1'),8)
... the result is 00:10:38 (638s = 600s + 38s = 10 minutes and 38 seconds)
Another example:
select distinct convert(char(8),dateadd(s,datediff(s, CRDATE , GETDATE() ),'1900-1-1'),8) from sysobjects order by 1
It will works until the difference of 86399 seconds (23:59:59):
select convert(char(8),dateadd(s,datediff(s
, DATEADD(s,-86399,GETDATE())
, GETDATE()
),'1900-1-1'),8)
... after that it will return to zero:
select convert(char(8),dateadd(s,datediff(s
, DATEADD(s,-86400,GETDATE())
, GETDATE()
),'1900-1-1'),8)
Because they are the same day (you don't have to worry about number of hours >24), you can just use a combination of DATEDIFF(second,time1,time2) and DATEADD(second,0,) to get a datetime value.
To format to hh:nn:ss, use convert(char(8),answer,8) but this is something better done by the reporting front end against the datetime result.
-- Late report
select *, dateadd(s,0,datediff(s,intime,actualintime)) late_by
from attendance
where intime < actualintime
this code might help you...
DECLARE #First datetime
DECLARE #Second datetime
SET #First = '04/02/2008 05:23:22'
SET #Second = getdate()
SELECT DATEDIFF(day,#First,#Second)*24 as TotalHours,
DATEDIFF(day,#First,#Second)*24*60 as TotalMinutes,
DATEDIFF(day,#First,#Second)*24*60*60 as TotalSeconds
well, yes, you need to use DATEDIFF, and yes, all that posted above works, but, if you want to show 07:07:07 instead of 7:7:7, you have to do something like this:
Declare #starttime datetime, #endtime datetime, #seconds int, #minutes int, #hours int
Set #starttime ='2013-10-01 05:05:17'
Set #endtime = '2013-10-01 23:10:18'
set #hours = DateDiff(hour, #starttime, #endtime)
set #minutes = DateDiff(minute, #starttime, #endtime);
set #seconds = DateDiff(second, #starttime, #endtime);
select case when DateDiff(minute, #starttime, #endtime) > 60
then CASE WHEN #hours >= 10 THEN cast(#hours as varchar(3))
ELSE '0' + cast(#hours as varchar(3)) END +':' +
CASE WHEN #minutes - (#hours * 60) >= 10 THEN
cast((#minutes - (#hours * 60)) as varchar(3))
ELSE '0' +cast((#minutes - (#hours * 60)) as varchar(3)) END
+ CASE WHEN (#seconds - (#minutes *60)) >= 10 THEN
+':' + cast(#seconds - (#minutes *60) as varchar(10))
ELSE ':0' + cast(#seconds - (#minutes *60) as varchar(10)) END
ELSE '0' + cast(#minutes as varchar(3)) +':' + cast(#seconds as varchar(10))
end
It may not look very nice, but it gave me what i wanted.
How about using CAST.
,CAST (Table1.DateTimeLatest-Table1.DateTimeFirst as time) as [Elapsed Time]
The raw result from SSMS from an apparatus table:
SQL Return shows out to nanoseconds in this Data.
For the report, as pasted in formatted Excel sheet:
Formatted result column as hh:mm:ss.
SELECT id, pickupdateandtime, GETDATE() AS CurrentTime,
((DATEDIFF(day,GETDATE(),pickupdateandtime)) - 1) AS Days ,
convert(char(8),dateadd(s,datediff(s,GETDATE(),pickupdateandtime),'1900-1-
1'),8) AS 'Hours & Mins' FROM orders
Here's what worked for me. Thank you #lynx_74.
https://i.stack.imgur.com/hOmyJ.png
Create a stored procedure to do the work and then just call the procedure passing your start and end dates.
CREATE PROCEDURE [dbo].[GetOperationDuration]
#DurationStart DATETIME, #DurationEnd DATETIME,
#Duration VARCHAR(100) OUTPUT
AS
BEGIN
DECLARE #years INT, #months INT, #days INT,
#hours INT, #minutes INT, #seconds INT, #milliseconds INT;
-- DOES NOT ACCOUNT FOR LEAP YEARS
SELECT #years = DATEDIFF(yy, #DurationStart, #DurationEnd)
IF DATEADD(yy, -#years, #DurationEnd) < #DurationStart
SELECT #years = #years-1
SET #DurationEnd = DATEADD(yy, -#years, #DurationEnd)
SELECT #months = DATEDIFF(mm, #DurationStart, #DurationEnd)
IF DATEADD(mm, -#months, #DurationEnd) < #DurationStart
SELECT #months=#months-1
SET #DurationEnd= DATEADD(mm, -#months, #DurationEnd)
SELECT #days=DATEDIFF(dd, #DurationStart, #DurationEnd)
IF DATEADD(dd, -#days, #DurationEnd) < #DurationStart
SELECT #days=#days-1
SET #DurationEnd= DATEADD(dd, -#days, #DurationEnd)
SELECT #hours=DATEDIFF(hh, #DurationStart, #DurationEnd)
IF DATEADD(hh, -#hours, #DurationEnd) < #DurationStart
SELECT #hours=#hours-1
SET #DurationEnd= DATEADD(hh, -#hours, #DurationEnd)
SELECT #minutes=DATEDIFF(mi, #DurationStart, #DurationEnd)
IF DATEADD(mi, -#minutes, #DurationEnd) < #DurationStart
SELECT #minutes=#minutes-1
SET #DurationEnd= DATEADD(mi, -#minutes, #DurationEnd)
SELECT #seconds=DATEDIFF(s, #DurationStart, #DurationEnd)
IF DATEADD(s, -#seconds, #DurationEnd) < #DurationStart
SELECT #seconds=#seconds-1
SET #DurationEnd= DATEADD(s, -#seconds, #DurationEnd)
SELECT #milliseconds=DATEDIFF(ms, #DurationStart, #DurationEnd)
SELECT #Duration= ISNULL(CAST(NULLIF(#years,0) AS VARCHAR(10)) + ' years,','')
+ ISNULL(' ' + CAST(NULLIF(#months,0) AS VARCHAR(10)) + ' months,','')
+ ISNULL(' ' + CAST(NULLIF(#days,0) AS VARCHAR(10)) + ' days,','')
+ ISNULL(' ' + CAST(NULLIF(#hours,0) AS VARCHAR(10)) + ' hours,','')
+ ISNULL(' ' + CAST(#minutes AS VARCHAR(10)) + ' minutes and','')
+ ISNULL(' ' + CAST(#seconds AS VARCHAR(10))
-- UNCOMMENT THEFOLLOWING IF YOU WANT MILLISECONDS INCLUDED
--+ CASE
--WHEN #milliseconds > 0
--THEN '.' + CAST(#milliseconds AS VARCHAR(10))
--ELSE ''
--END
+ ' seconds','')
SELECT #Duration
END
GO
Then just call using:
DECLARE #return_value int, #Duration varchar(100)
EXEC #return_value = [dbo].[GetOperationDuration] #DurationStart, #DurationEnd, #Duration = #Duration OUTPUT
SELECT #Duration as N'#Duration'
Thought I'd share my 2 cents. This fixes the overflow problems but only works with datetime not datetime2. It probably does not work with leap years or when clocks go backwards/forwards. I haven't tested with either.
declare #startTime datetime = getdate()
declare #endTime datetime
select [StartDate] = #startTime,
[EndDate] = #endTime,
[DD:HH:MM:SS.MS] = right( '00' + convert( varchar(20), datediff(hh, 0, #endTime - #startTime ) / 24 ), 2) + ':' +
right( '00' + convert( varchar(20), datediff(hh, 0, #endTime - #startTime ) % 24 ), 2) + ':' +
substring( convert( varchar(20), #endtime - #startTime, 114 ),
charindex( ':', convert( varchar(20), #endTime - #startTime, 114 ) ) + 1,
len( convert( varchar(20), #endTime - #startTime, 114 ) ) )