I want Hours,Min, second difference from two datetime - sql

Question

I am developing Time management system for employees.
I want the duration how much duration employee come late , or he went early.
i have following structure.
**Attendace**
AutoId --uniqueidentifier
EMployeeId --uniqueidentifier
Date --datetime
InTime -- varchar(50)
OutTime -- varchar(50)
ActualInTime--datetime
ActualOutTime--datetime
I want Late Coming Report ( i.e. who came late in morning after ActualInTime and how much duration in hh:mm:ss ) and also want early going(i.e who went early in the evening before ActualOutTime in duration in format hh:mm:ss )
So can you please help me..???

Answer 1

I came across an easier way of solving this issue.
First, a quick example of turning a "number of seconds" into the "hh:mm:ss" format.
DECLARE #NumberOfSeconds int
SET #NumberOfSeconds = 3843 -- 1 hour, 4 minutes, 3 seconds
SELECT #NumberOfSeconds AS 'seconds',
CONVERT(varchar, DATEADD(second, #NumberOfSeconds, 0), 108) AS 'hh:mm:ss'
This will give us this output:
And we can easily take this a step further, calculate the number of seconds between two datetimes, and display it in hh:mm:ss format:
DECLARE
#NumberOfSeconds int,
#StartTime datetime = '2017-09-14 14:16:11',
#EndTime datetime = '2017-09-14 14:23:13'
SET #NumberOfSeconds = DATEDIFF(second, #StartTime, #EndTime)
SELECT #NumberOfSeconds AS 'seconds',
CONVERT(varchar, DATEADD(second, #NumberOfSeconds, 0), 108) AS 'hh:mm:ss'
Which gives us this output:
Simple, hey ?
(And yes, you can simplify it further by putting the DATEDIFF directly into the DATEADD function.)

Answer 2

You can do it in a very simple way:
declare #date1 datetime, #date2 datetime
set #date1=DATEADD(s,-638,getdate())
set #date2=GETDATE()
select convert(char(8),dateadd(s,datediff(s,#date1,#date2),'1900-1-1'),8)
... the result is 00:10:38 (638s = 600s + 38s = 10 minutes and 38 seconds)
Another example:
select distinct convert(char(8),dateadd(s,datediff(s, CRDATE , GETDATE() ),'1900-1-1'),8) from sysobjects order by 1
It will works until the difference of 86399 seconds (23:59:59):
select convert(char(8),dateadd(s,datediff(s
, DATEADD(s,-86399,GETDATE())
, GETDATE()
),'1900-1-1'),8)
... after that it will return to zero:
select convert(char(8),dateadd(s,datediff(s
, DATEADD(s,-86400,GETDATE())
, GETDATE()
),'1900-1-1'),8)

Answer 3

Because they are the same day (you don't have to worry about number of hours >24), you can just use a combination of DATEDIFF(second,time1,time2) and DATEADD(second,0,) to get a datetime value.
To format to hh:nn:ss, use convert(char(8),answer,8) but this is something better done by the reporting front end against the datetime result.
-- Late report
select *, dateadd(s,0,datediff(s,intime,actualintime)) late_by
from attendance
where intime < actualintime

Answer 4

this code might help you...
DECLARE #First datetime
DECLARE #Second datetime
SET #First = '04/02/2008 05:23:22'
SET #Second = getdate()
SELECT DATEDIFF(day,#First,#Second)*24 as TotalHours,
DATEDIFF(day,#First,#Second)*24*60 as TotalMinutes,
DATEDIFF(day,#First,#Second)*24*60*60 as TotalSeconds

Answer 5

well, yes, you need to use DATEDIFF, and yes, all that posted above works, but, if you want to show 07:07:07 instead of 7:7:7, you have to do something like this:
Declare #starttime datetime, #endtime datetime, #seconds int, #minutes int, #hours int
Set #starttime ='2013-10-01 05:05:17'
Set #endtime = '2013-10-01 23:10:18'
set #hours = DateDiff(hour, #starttime, #endtime)
set #minutes = DateDiff(minute, #starttime, #endtime);
set #seconds = DateDiff(second, #starttime, #endtime);
select case when DateDiff(minute, #starttime, #endtime) > 60
then CASE WHEN #hours >= 10 THEN cast(#hours as varchar(3))
ELSE '0' + cast(#hours as varchar(3)) END +':' +
CASE WHEN #minutes - (#hours * 60) >= 10 THEN
cast((#minutes - (#hours * 60)) as varchar(3))
ELSE '0' +cast((#minutes - (#hours * 60)) as varchar(3)) END
+ CASE WHEN (#seconds - (#minutes *60)) >= 10 THEN
+':' + cast(#seconds - (#minutes *60) as varchar(10))
ELSE ':0' + cast(#seconds - (#minutes *60) as varchar(10)) END
ELSE '0' + cast(#minutes as varchar(3)) +':' + cast(#seconds as varchar(10))
end
It may not look very nice, but it gave me what i wanted.

Answer 6

How about using CAST.
,CAST (Table1.DateTimeLatest-Table1.DateTimeFirst as time) as [Elapsed Time]
The raw result from SSMS from an apparatus table:
SQL Return shows out to nanoseconds in this Data.
For the report, as pasted in formatted Excel sheet:
Formatted result column as hh:mm:ss.

Answer 7

SELECT id, pickupdateandtime, GETDATE() AS CurrentTime,
((DATEDIFF(day,GETDATE(),pickupdateandtime)) - 1) AS Days ,
convert(char(8),dateadd(s,datediff(s,GETDATE(),pickupdateandtime),'1900-1-
1'),8) AS 'Hours & Mins' FROM orders
Here's what worked for me. Thank you #lynx_74.
https://i.stack.imgur.com/hOmyJ.png

Answer 8

Create a stored procedure to do the work and then just call the procedure passing your start and end dates.
CREATE PROCEDURE [dbo].[GetOperationDuration]
#DurationStart DATETIME, #DurationEnd DATETIME,
#Duration VARCHAR(100) OUTPUT
AS
BEGIN
DECLARE #years INT, #months INT, #days INT,
#hours INT, #minutes INT, #seconds INT, #milliseconds INT;
-- DOES NOT ACCOUNT FOR LEAP YEARS
SELECT #years = DATEDIFF(yy, #DurationStart, #DurationEnd)
IF DATEADD(yy, -#years, #DurationEnd) < #DurationStart
SELECT #years = #years-1
SET #DurationEnd = DATEADD(yy, -#years, #DurationEnd)
SELECT #months = DATEDIFF(mm, #DurationStart, #DurationEnd)
IF DATEADD(mm, -#months, #DurationEnd) < #DurationStart
SELECT #months=#months-1
SET #DurationEnd= DATEADD(mm, -#months, #DurationEnd)
SELECT #days=DATEDIFF(dd, #DurationStart, #DurationEnd)
IF DATEADD(dd, -#days, #DurationEnd) < #DurationStart
SELECT #days=#days-1
SET #DurationEnd= DATEADD(dd, -#days, #DurationEnd)
SELECT #hours=DATEDIFF(hh, #DurationStart, #DurationEnd)
IF DATEADD(hh, -#hours, #DurationEnd) < #DurationStart
SELECT #hours=#hours-1
SET #DurationEnd= DATEADD(hh, -#hours, #DurationEnd)
SELECT #minutes=DATEDIFF(mi, #DurationStart, #DurationEnd)
IF DATEADD(mi, -#minutes, #DurationEnd) < #DurationStart
SELECT #minutes=#minutes-1
SET #DurationEnd= DATEADD(mi, -#minutes, #DurationEnd)
SELECT #seconds=DATEDIFF(s, #DurationStart, #DurationEnd)
IF DATEADD(s, -#seconds, #DurationEnd) < #DurationStart
SELECT #seconds=#seconds-1
SET #DurationEnd= DATEADD(s, -#seconds, #DurationEnd)
SELECT #milliseconds=DATEDIFF(ms, #DurationStart, #DurationEnd)
SELECT #Duration= ISNULL(CAST(NULLIF(#years,0) AS VARCHAR(10)) + ' years,','')
+ ISNULL(' ' + CAST(NULLIF(#months,0) AS VARCHAR(10)) + ' months,','')
+ ISNULL(' ' + CAST(NULLIF(#days,0) AS VARCHAR(10)) + ' days,','')
+ ISNULL(' ' + CAST(NULLIF(#hours,0) AS VARCHAR(10)) + ' hours,','')
+ ISNULL(' ' + CAST(#minutes AS VARCHAR(10)) + ' minutes and','')
+ ISNULL(' ' + CAST(#seconds AS VARCHAR(10))
-- UNCOMMENT THEFOLLOWING IF YOU WANT MILLISECONDS INCLUDED
--+ CASE
--WHEN #milliseconds > 0
--THEN '.' + CAST(#milliseconds AS VARCHAR(10))
--ELSE ''
--END
+ ' seconds','')
SELECT #Duration
END
GO
Then just call using:
DECLARE #return_value int, #Duration varchar(100)
EXEC #return_value = [dbo].[GetOperationDuration] #DurationStart, #DurationEnd, #Duration = #Duration OUTPUT
SELECT #Duration as N'#Duration'

Answer 9

Thought I'd share my 2 cents. This fixes the overflow problems but only works with datetime not datetime2. It probably does not work with leap years or when clocks go backwards/forwards. I haven't tested with either.
declare #startTime datetime = getdate()
declare #endTime datetime
select [StartDate] = #startTime,
[EndDate] = #endTime,
[DD:HH:MM:SS.MS] = right( '00' + convert( varchar(20), datediff(hh, 0, #endTime - #startTime ) / 24 ), 2) + ':' +
right( '00' + convert( varchar(20), datediff(hh, 0, #endTime - #startTime ) % 24 ), 2) + ':' +
substring( convert( varchar(20), #endtime - #startTime, 114 ),
charindex( ':', convert( varchar(20), #endTime - #startTime, 114 ) ) + 1,
len( convert( varchar(20), #endTime - #startTime, 114 ) ) )