I have a table that has 3 columns, ID, Record and signed.... ID is unique but RecordID duplicates because each row is identifying if someone signed off on something in the record. The 3rd column is if they signed off on it or not.
Below is an example of what the table could look like.
What I'm trying to do is return a 1 if the record is completely signed off on or or a 0 if the record isn't completely signed off on....
Here is an example of the table
My output should be like this 5099 =0, 5100 = 0, 5101 = 1, 5102 = 0
I've been racking my head on it
I've tried the following code and it seems to work on items that have more than two rows. But if they have two rows and one signed is yes and the other no I'm getting a 1
select
(case
when not exists(
select *
From Table
Where signed<> '' no) then 0
Else '1'
end);
my output should be like this 5099 =0, 5100 = 0, 5101 = 1, 5102 = 0
SELECT RecordID, CASE WHEN n_signed=n THEN 1 ELSE 0 END FROM
(
SELECT RecordID, SUM(CASE WHEN signed='yes' THEN 1 ELSE 0 END) as n_signed, COUNT(*) as n
FROM table
GROUP BY RecordID
) a
You probably need something like this
select
recordid,
floor(avg(case when signed='yes' then 1 else 0 end)) as signed_status
from your_table
group by recordid;
Demo
Related
The table 1 is as follows,
ID
FK1_ID
FK2_ID
1
1
1
2
1
2
3
1
3
The table with FK2 is as follows,
ID
Type
Status
1
Type1
True
2
Type2
True
3
Type1
False
The FK2_ID column is the ID column of table 2.
The expected result is, for any FK1_ID(which I have as a list of IDs), need to check all its FK2 entries in the 2nd table of Type1 and status True.
For example:
Here, I want to return YES, if all the Type1 entries are True for the specific FK1_ID. Else NO.
So, for FK1_ID with 1, the FK2 table has 3 records. Of which Type1 has 2 records. I should return YES, if both Type1 records are True, else NO.
I want accomplish this using SQL.
Any help is appreciated?
Looks like you just need to compare a conditional count of Status to the full count, with a CASE for the final result.
SELECT
t1.FK1_ID,
Result = CASE WHEN COUNT(*) = COUNT(CASE WHEN FK2.Status = 'True' THEN 1 END)
THEN 'Yes'
ELSE 'No' END
FROM table1 t1
JOIN FK2 ON FK2.ID = t1.FK2_ID
AND FK2.Type = 'Type1'
GROUP BY
t1.FK1_ID;
A slightly shorter but less understandable version
CASE WHEN COUNT(*) = COUNT(NULLIF(FK2.Status, 'False'))
Alternatively
CASE WHEN COUNT(NULLIF(FK2.Status, 'True')) = 0
I'm not totally following your logic (how these two tables are joined) but sounds like you want to compare a total count with a conditional count so maybe something like
with t as (select type, count(status) as cnt,
sum(case when status ='True' then 1 else 0 end) as truecnt
from FK2
group by type)
select type, case when truecnt > 0 and cnt = truecnt then 'Yes' else 'No' end as MyResult
from t
I had a query where i am trying to get the results of a query, the query can have multiple rows or it can be empty, i am trying if it is empty, it should return me 0 for a column i am looking which is called as sequence
My query is like this:
select CASE WHEN COUNT(1) > 0 THEN 1 ELSE 0 END AS Sequence
from dbo.mytable
it returns me the either 1 or 0, for 1 i want that column should return me values or it should combine all the rows and return me the value of that column as list like 1,2,3,4,5,6,7
This should work.
SELECT
CASE WHEN MY_COUNT > 0 THEN 1 ELSE 0 END AS SEQUENCE
FROM
(SELECT COUNT(*) AS MY_COUNT
FROM
DBO.MYTABLE);
If you want only one row in the result set, simply do:
select (case when count(*) > 0 then 1 else 0 end) as sequence
from mytable;
If you care at all about performance, the more efficient method is:
select (case when exists (select 1 from dbo.mytable) then 1 else 0
end) as sequence
I have a SQL query which returns :
id | value
1 a
1 a
1 b
2 a
2 a
I want to get only id who have only the value a. So the id 2
How to do this ?
You can use aggregation and having clause to check if all the rows have value 'a' for a given id:
Using Count:
select id
from t
group by id
having count(*) = count(case when value = 'a' then 1 end);
Or using Sum
select id
from t
group by id
having SUM(case when value = 'a' then 0 else 1 end) = 0;
Use the next code:-
Select id
from #test
group by id
having sum (case when value = 'a' then 0 else 1 end) = 0
The clue is passing 0 for 'a' and pass 1 for other, then having sum equals 0
This is slightly slower than #Gurwinder Singh's answer but can be more readable if performance is not your top priority.
CREATE TABLE tmp (id int, [value] char(1))
INSERT INTO tmp values (1,'a'),(1,'a'),(1,'b'),(2,'a'),(2,'a')
SELECT DISTINCT id
FROM tmp a
WHERE [value] = 'a'
AND id NOT IN (
SELECT id FROM tmp
WHERE [value] <> 'a')
My table structure is this
id last_mod_dt nr is_u is_rog is_ror is_unv
1 x uuid1 1 1 1 0
2 y uuid1 1 0 1 1
3 z uuid2 1 1 1 1
I want the count of rows with:
is_ror=1 or is_rog =1
is_u=1
is_unv=1
All in a single query. Is it possible?
The problem I am facing is that there can be same values for nr as is the case in the table above.
Case statments provide mondo flexibility...
SELECT
sum(case
when is_ror = 1 or is_rog = 1 then 1
else 0
end) FirstCount
,sum(case
when is_u = 1 then 1
else 0
end) SecondCount
,sum(case
when is_unv = 1 then 1
else 0
end) ThirdCount
from MyTable
you can use union to get multiple results e.g.
select count(*) from table with is_ror=1 or is_rog =1
union
select count(*) from table with is_u=1
union
select count(*) from table with is_unv=1
Then the result set will contain three rows each with one of the counts.
Sounds pretty simple if "all in a single query" does not disqualify subselects;
SELECT
(SELECT COUNT(DISTINCT nr) FROM table1 WHERE is_ror=1 OR is_rog=1) cnt_ror_reg,
(SELECT COUNT(DISTINCT nr) FROM table1 WHERE is_u=1) cnt_u,
(SELECT COUNT(DISTINCT nr) FROM table1 WHERE is_unv=1) cnt_unv;
how about something like
SELECT
SUM(IF(is_u > 0 AND is_rog > 0, 1, 0)) AS count_something,
...
from table
group by nr
I think it will do the trick
I am of course not sure what you want exactly, but I believe you can use the logic to produce your desired result.
I have a table that has a column called 'status'. This can be set to 0 or 1
Is it possible for me to count both the 0's and 1's in a single query?
Thanks in advance
James
Yes, just group on the value of status:
SELECT status, COUNT(*)
FROM yourtable
GROUP BY status
That will give you exactly two rows since the value can only be 0 or 1, and the COUNT(*) column will be the number of times each status value appears in the table.
SELECT SUM(CASE WHEN status = 0 THEN 1 ELSE 0 END) AS 'number of zeroes',
SUM(CASE WHEN status = 1 THEN 1 ELSE 0 END) AS 'number of ones'
FROM yourtable;