I am trying to query some records and am looking to return only records that have a date of today, but also are before the current time.
I have the first part sorted out by using the following clause to return only records for today.
WHERE TRUNC(my_date_time) = TRUNC(sysdate)
How would I modify this to only get records before the current system time as well?
How about inequalities?
WHERE my_date_time >= TRUNC(sysdate) AND
my_date_time < sysdate
Try this.
Select * from table Where
TRUNC(my_date_time) =
TRUNC(sysdate) And
TO_CHAR(my_date_time,
'HH24:MI:SS' ) <=
TO_CHAR(sysdate,
' HH24:MI:SS' )
If column "my_date_time" is of type DATE, and need compare using SYSDATE function then you only need:
WHERE my_date_time<=sysdate
If column "my_date_time" is of type DATE, and need compare with other variable or column of type DATE for example named "other_date"
where my_date_time>=trunc(other_date)
and my_date_time<trunc(other_date)+1
Related
I have below select query where i am trying to get the data only for today date but its not returning anything:
select * from V_TER
where SYSTEM_INSERTED_AT = SYSDATE;
The SYSTEM_INSERTED_DATE is of Date datatype and the value is stored in this fields as for example 2021-01-15 15:17:13
The problem in Oracle is that dates can have time components both in the data and sysdate itself.
I would recommend checking for any time on the current date:
where system_inserted_at >= trunc(sysdate) and
system_inserted_at < trunc(sysdate) + interval '1' day
This is generally optimizer-friendly. If you don't care about that, then:
where trunc(system_inserted_at) = trunc(sysdate)
I'm querying a table to get some date, like so:
SELECT date - INTERVAL '10 day' AS date
FROM example_table
WHERE username = 'Bob'
LIMIT 1;
The date column in the example_table does not have a timestamp. All dates in the column are stored in the following manner:
YYYY-MM-DD
The query above will return a result like so:
2016-11-20 00:00:00.000000
It takes the date found, goes back 10 days, and returns that date. But I want it to return the date without adding the timestamp, like so:
2016-11-20
If I use INTERVAL it always seems to add a timestamp. Is there a way to only get the date?
Your query is fine (but can be simplified, as demonstrated by a_horse_with_no_name). What you are seeing is a display issue. You can format your date to a string in the relevant format using to_char():
SELECT to_char("date" - INTERVAL '10 day', 'yyyy-mm-dd') AS "date"
FROM example_table
WHERE username = 'Bob'
LIMIT 1;
Note: LIMIT without an ORDER BY does not make sense: if there is more than one record in the resultset, you actually get a random record out of them.
You can use the interval notation and convert back to a date:
SELECT (date - INTERVAL '10 day')::date AS date
You can subtract (or add) an integer from a date. That integer represents the number of days:
SELECT "date" - 10 AS "date"
FROM example_table
WHERE username = 'Bob'
LIMIT 1;
I'm in PostgreSQL.
I need to print all mailing with creation date strictly more that 2015-04-04. I tried the following queries:
SELECT *
FROM mailing.mailing
WHERE creation_date > '2015-04-04';
and
SELECT *
FROM mailing.mailing
WHERE creation_date >= '2015-04-04';
But they produced the same result set(including '2015-04-04'). Is it possible to write such a query without explicitly saying WHERE creation_date >= '2015-04-05';
UPD: The column's type is timestamp without time zone.
If your creation_date field is of type datetimetry comparing it to '2015-04-04 23:59:59' instead, as '2015-04-04 08:30:00' seems to be greater than '2015-04-04'.
Assuming your default date format for your database is 'YYYY-MM-DD' and creation_date field is a date type, your query will actually be converted automatically to something like:
SELECT *
FROM mailing.mailing
WHERE creation_date > to_date('2015-04-04', 'YYYY-MM-DD');
The date value you have provided represents the first second of that day, that's why you see no difference between your queries. (Your first query would exclude the first second of the day though.)
What you could do to avoid this is:
where creation_date >= to_date('2015-04-05 00:00:00', 'YYYY-MM-DD HH24:MI:SS')
or
where date_trunc(creation_date-1) = '2015-04-04'
I have a table with date column in it. I need to fetch the records from it based on
the given date.
Currently when i used the query:
select * from workingemployee_data where created_date like '20-Jan-2012'
I am getting those records which have created_date on 20-Jan-2012
But i want to get the records those were created 10 days earlier to a given
date (i.e) 20-Jan-2012.
Please suggest me on this.
This gives all records between today and 10 days ago:
SELECT *
FROM workingemployee
WHERE created_date BETWEEN sysdate - INTERVAL '10' DAY
AND sysdate
This gives all records entered exactly 10 days ago:
SELECT *
FROM workingemployee
WHERE created_date = sysdate - INTERVAL '10' DAY
Replace sysdate with exact date if you want.
Why do you use like and not = ?
Assuming that created_date is of type DATE, it's bad practice to rely on implicit conversion according to NLS_DATE_FORMAT (this is what happens when you compare a date and a string)
dd-mon-yyyy isn't a good format for querying since it deffers according to NLS_LANGUAGE better use mm for months numbers
So, either use #mvp's answer or do something like this:
SELECT *
FROM workingemployee
WHERE trunc(created_date) = to_date('20-01-2013', 'dd-mm-yyyy') - 10
SELECT *
FROM workingemployee
WHERE created_date > sysdate - INTERVAL '10' DAY;
I'm trying to retrieve records from table by knowing the date in column contains date and time.
Suppose I have table called t1 which contains only two column name and date respectively.
The data stored in column date like this 8/3/2010 12:34:20 PM.
I want to retrieve this record by this query for example (note I don't put the time):
Select * From t1 Where date="8/3/2010"
This query give me nothing !
How can I retrieve date by knowing only date without the time?
DATE is a reserved keyword in Oracle, so I'm using column-name your_date instead.
If you have an index on your_date, I would use
WHERE your_date >= TO_DATE('2010-08-03', 'YYYY-MM-DD')
AND your_date < TO_DATE('2010-08-04', 'YYYY-MM-DD')
or BETWEEN:
WHERE your_date BETWEEN TO_DATE('2010-08-03', 'YYYY-MM-DD')
AND TO_DATE('2010-08-03 23:59:59', 'YYYY-MM-DD HH24:MI:SS')
If there is no index or if there are not too many records
WHERE TRUNC(your_date) = TO_DATE('2010-08-03', 'YYYY-MM-DD')
should be sufficient. TRUNC without parameter removes hours, minutes and seconds from a DATE.
If performance really matters, consider putting a Function Based Index on that column:
CREATE INDEX trunc_date_idx ON t1(TRUNC(your_date));
Personally, I usually go with:
select *
from t1
where date between trunc( :somedate ) -- 00:00:00
and trunc( :somedate ) + .99999 -- 23:59:59
Convert your date column to the correct format and compare:
SELECT * From my_table WHERE to_char(my_table.my_date_col,'MM/dd/yyyy') = '8/3/2010'
This part
to_char(my_table.my_date_col,'MM/dd/yyyy')
Will result in string '8/3/2010'
You could use the between function to get all records between 2010-08-03 00:00:00:000 AND 2010-08-03 23:59:59:000
trunc(my_date,'DD') will give you just the date and not the time in Oracle.
Simply use this one:
select * from t1 where to_date(date_column)='8/3/2010'
Try the following way.
Select * from t1 where date(col_name)="8/3/2010"