XSLT 1.0 multiple call of a template - xslt-1.0

Question

I need to replace strings in an XML file. I'm trying to use XSLT to do it. I want to use call-template for each string I need to replace.
When I make multiple call to the template, only the last call works fine.
The XML file I need to change : I want to replace the strings
‘
and
—
by spaces
<?xml version="1.0" encoding="UTF-8"?>
<RAPPORT>
<reason>start test_145 : ‘ and test_ 151 : — _end_test</reason>
</RAPPORT>
The template I use :
<xsl:template name="globalReplace">
<xsl:param name="outputString"/>
<xsl:param name="target"/>
<xsl:param name="replacement"/>
<xsl:choose>
<xsl:when test="contains($outputString,$target)">
<xsl:value-of select="concat(substring-before($outputString,$target),$replacement)"/>
<xsl:call-template name="globalReplace">
<xsl:with-param name="outputString" select="substring-after($outputString,$target)"/>
<xsl:with-param name="target" select="$target"/>
<xsl:with-param name="replacement" select="$replacement"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$outputString"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
The multiple calls :
<xsl:template match="text()">
<xsl:call-template name="globalReplace">
<xsl:with-param name="outputString" select="."/>
<xsl:with-param name="target" select="'‘'"/>
<xsl:with-param name="replacement" select="' '"/>
</xsl:call-template>
</xsl:template>
<xsl:template match="text()">
<xsl:call-template name="globalReplace">
<xsl:with-param name="outputString" select="."/>
<xsl:with-param name="target" select="'—'"/>
<xsl:with-param name="replacement" select="' '"/>
</xsl:call-template>
</xsl:template>
Expected result :
<?xml version="1.0" encoding="UTF-8"?>
<RAPPORT>
<reason>debut test_test_145 et test 151 _fin test</reason>
</RAPPORT>
What I get in fact :
<?xml version="1.0" encoding="UTF-8"?>
<RAPPORT>
<reason>debut test_test_145**PUI** et test 151 _fin test</reason>
</RAPPORT>
PUI means an unexpected character instead of the needed space

Answer 1

You have two templates that match text(). Only the last of these is applied - see: https://www.w3.org/TR/1999/REC-xslt-19991116#conflict
In the given example, you could simply use the translate() function to do all the work at once, since the "strings" you want to replace are actually characters:
XML
<?xml version="1.0" encoding="UTF-8"?>
<RAPPORT>
<reason>start test_145 : ‘ and test_ 151 : — _end_test</reason>
</RAPPORT>
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="text()">
<xsl:value-of select="translate(., '‘—', ' ')"/>
</xsl:template>
</xsl:stylesheet>
Result
<?xml version="1.0" encoding="UTF-8"?>
<RAPPORT>
<reason>start test_145 : and test_ 151 : _end_test</reason>
</RAPPORT>

Answer 2

Many thanks !
It works fine this way !
I improved it inserting my result into a variable :
<xsl:template match="text()">
<xsl:variable name="premierePasse">
<xsl:value-of select="translate(., '‘—’',' ')"/>
</xsl:variable>
<xsl:value-of select="translate($premierePasse, 'œ', 'œ')"/>
</xsl:template>