XSL I need to remove space - xslt-1.0

Question

I need to remove the white space between "|"
Example:
|| 3.3 | A | 001 | 2017-03-03T16:57:51 | 01 *20001000000200001437 | Only free ||
I need this output:
||3.3|A|001|2017-03-03T16:57:51|01 *20001000000200001437|Only free||

Answer 1

This is rather awkward to do in XSLT 1.0.
Given the following input:
XML
<root>
<item>|| 3.3 | A | 001 | 2017-03-03T16:57:51 | 01 *20001000000200001437 | Only free ||</item>
</root>
the following stylesheet:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="item">
<xsl:copy>
<xsl:variable name="remove-left-spaces">
<xsl:call-template name="remove-spaces">
<xsl:with-param name="text" select="."/>
<xsl:with-param name="delimiter" select="' |'"/>
</xsl:call-template>
</xsl:variable>
<xsl:call-template name="remove-spaces">
<xsl:with-param name="text" select="$remove-left-spaces"/>
<xsl:with-param name="delimiter" select="'| '"/>
</xsl:call-template>
</xsl:copy>
</xsl:template>
<xsl:template name="remove-spaces">
<xsl:param name="text"/>
<xsl:param name="delimiter"/>
<xsl:choose>
<xsl:when test="contains($text, $delimiter)">
<!-- recursive call -->
<xsl:call-template name="remove-spaces">
<xsl:with-param name="text">
<xsl:value-of select="substring-before($text, $delimiter)"/>
<xsl:text>|</xsl:text>
<xsl:value-of select="substring-after($text, $delimiter)"/>
</xsl:with-param>
<xsl:with-param name="delimiter" select="$delimiter"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$text"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
will return:
Result
<?xml version="1.0" encoding="UTF-8"?>
<root>
<item>||3.3|A|001|2017-03-03T16:57:51|01 *20001000000200001437|Only free||</item>
</root>